[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include * *** **  ** * 
#include   *  * *  * 

int main(int argc, char *argv[]) {
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* * *** *** *  *** * *  * * **  Your **   ** start from here
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**** * ******     *  * **  ** }
   ***     *  
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 *    *  * *** ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include * ***      ** * 
#include ** *  *    * *  * 

int main() {
*   *  *  *   * int a;

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 *      *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ***** **  * 
#include **  *** ****  * 

/* run this program using the console pauser or add your own getch,   ** ****     ** * **** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
** * ***** *  ** 
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int main(int argc, char *argv[])
{
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    ** *   * * * * *   **   *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* * *     *   ***

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
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***  *  *   **** ** 
int main(int argc, char *argv[])
{
*     * * ** ** *** *  *** ** ** i, a;
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* * *** **  * **** * *   (i=1)
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* ***  **   * * *  * ****** * ***    0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
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 * * * **  ****  * ****
int main(int argc, char *argv[])
{
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*** **   *  * ***  *   * ** *** a<i; i--)
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 *  * **    ***  **** *   (i=1)
*** **   ** *******        **  ***** ***   **     * *        ***  * *** **  * *
**   *** ** * *     * ** **  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
  ** * *   *  **  ** 
   *    ** *  * * * 

int **   argc, char ***    {

 * ***    ** * ** int a=10;

* *        ** do{
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**  * * * * *  * *  **   *   
***      * ****   *  * a != 10 );
  *      ** * 
**    *           ** ***  9 8 7 6 5 4 3 2  **  ** * * 
  **   **  ***      *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
  **     * ** * **** 
* ****  *  *** *  *  * * 

int    * argc, char *   {

 ***  * *    ** int *** *

**  **  ****  do{
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***  *   *  **      *  **   *  *  **   ** * *  ****  ** 
****  * ****  *  *  * * if( a * * *  10)
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**   *   *   *    a != 10 );
*** *    *** ** 
*  * * *** *   * ** *    * 9 8 7 6 5 4 3 2  ** ***** 
**  **  * ** ***    0;
}

Comments

Case 0: Wrong output