[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include           * *
#include * ****** ***** * * 

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** *  *   **  
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**  **   * *   return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include ***  * * *  **  
#include  ***    **** * 

int main() {
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**  * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **  *** * *   *  
#include * ** *  **    *   *

/* run this program using the console pauser or add your own getch, * ****  *    *  *     * or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
** *      * ****  * *** 
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int main(int argc, char *argv[])
{
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* * * ***** *  * *    * ****  **  * * * **** ****   *** ** ******  *  *   ******
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* *  *** *  *   *    * ** **   *** * ** *** *    *    **
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
* * * * *   ***   * *
* *     * ****  ** **
int main(int argc, char *argv[])
{
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**** * ** *    *   **  (i=1)
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 **  *** *** *  **  *****   **** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  ***   *    ** **
* **  **** * **     *
int main(int argc, char *argv[])
{
*** ** **   * *   *** * ** i, a;
**      *** * * ******* * ** *** *    * ***   your input:");
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   *  * ***** * * * **    * *  * (i=1)
**    *    ** ** * * ***** * * * ** *****  *** **     *  *   ** *     * * 
*    * **    ** * **  ****    ***   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* * ** **   **** *    *  
**** *  ***  **  ** **

int     argc, char  *   {

*  * **  **   int a=10;

* ***    ** ** do{
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****  ****    * ** ***  * ****    * *** **  ** *   *   ****
  **  *   *   *     **  *** * 
* ** * ** *** *** *  a != 10 );
*   *** *  ** *  * 
 * * *   *      **        9 8 7 6 5 4 3 2      * * 
  ***   ***  *   *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
   **   *  *  *   * *** *
 *****     * * ** * *     

int   **   argc, char ****  {

*     * ***   **    int    *

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** * **   **  * ****   *  ** **  if( a *   10)
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* *** *   ***    a != 10 );
 *****  * ** * 
**   *  **  ****  **    * 9 8 7 6 5 4 3 2 *    *** **   *
*****     * *** ** * 0;
}

Comments

Case 0: Wrong output