[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include ***       * * *
#include **  * *  *   **

int main(int argc, char *argv[]) {
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**** * **     **   *    *    ***** 

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****     *  *****  *  ** *   *    = a; i >= 0; i--){
*  * *    * *** **        *  *** *   if(i == 0){
**    * ****  * * *  *   ***   *   *** *  ********  
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  * *    * **    **               *****   **  ***    * *
**   ****  ****   *    * *** }
 **  ** * ** * 
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****   **** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  * **** ***
#include *   **  ** ***

int main() {
  ***  ** ** * *  int a;

    *  ** *       **  ** * your  * *** ***** *
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***  ***   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include   ** *  * * ***** 
#include  ** *** * * * ** 

/* run this program using the console pauser or add your own getch, *** **    ****  **  *  or input loop */

int main(int argc, char *argv[]) {
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*  ** * *** **  *   * **   *  = getchar();
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*  *  **    * **  ** *  = getchar();


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****  * ** **   *  *** ** *  *** q >= 'a' * **   *  q <= 'z' )
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*   * ****    **   *  ** 
*   *     ** * **      *             0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
 *      *  *   ***   ** 
    * **  ** *** ** * * 
int main(int argc, char *argv[])
{
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*    **** ** ***  ***   *  *  * * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
    **    *  * *  * ** * ** *   * ***** * ***   
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
  *  * *** * **     **  **** **  *  your input : ");
* ***  ** ***   * **** *   ***     *  * * ** ** * *    **   *  ***  **  * **        **  * ** * *  * **
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* *     *   * ****  *  * * * *   ****  **  **  **** *  ***   * * **    *  ** *
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* *   * *   **      ********** ***  ** *    *  * ** *  * ** ***  
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***  *    * * ********

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  ** ******* *** *  
 **      **  *   * **   *
int main(int argc, char *argv[])
{
*** *      * *  *   * *  ** i, a;
**    **     *  **** ** **      * * **  **  * your input:");
 *** ***  ***  * *********  **** * ** **  ** &i);
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** ** * *   **        **  * **  * ***** ***   ** ***   **     *     * * * i);
**** ******* ***** *  *    *    (i=1)
    **   ** * ***** *     **  **        ****   *  **  ** * * * **  ** *** *  *
*    ** * ** ***    ******    *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 *** **  ** * ** *  
  *  ****  ***  
int main(int argc, char *argv[])
{
**  * ** * ******* ** i, a;
 * ** ** * *  **  * * *** *    ** *  ***   your input:");
* *** ***   ****** *    **   *  *****    **   * * &i);
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**  *****      *  *** ***  * ***** ** **      ***** *    **     ** *****   *  * i);
 ** * ** ** *** **  * **   *   (i=1)
**** ** *  *  ** * ***** * ***    *     * ** ** * **  **  *  * *  *  *** * 
   **   **  **** *** **   *  * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
**    *******  ** * ***
  **   ** **    *  *  *

int ** ** *  argc, char ** * * {

  **   *  *  **** int a=10;

**     * *    do{
**** ***     * **    * ** *              ** ***  * * your * *** * *** 
* * * * *  *  ** *             **   *** * *  ** *    *   ***
 **  **   *** **   **       *    
*   *  ***** *        a != 10 );
  *  * **  * ** 
*  *    *   **   ** *   **** * 9 8 7 6 5 4 3 2  ** *  *
   *   *    **  * * * **

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 ***    *     *  *  * 
  *  *   ** * * **** *

int  * *  argc, char     * {

    **   ** * int  *  *

 ** * **     *  ** do{
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**   *      ** *** ***** *  *   ** ***  **** **** * **   * 
*  * *  ***     **    * * if( a   *  * 10)
**  *     * **** **  *    *  * * *   *  *    * *** *   *  *** code is too low! *      
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*  ** *      *    ***  * *  * * if( a ***     10)
** *    **  ***       *****   *  * * *   ****    ** *  ***** is too high! *****  * **
*******  * * ** ** *  a != 10 );
   **  *   *   * 
* *   * *  *   *  * * ** * **   9 8 7 6 5 4 3 2  ***  * **    
  **    *       0;
}

Comments

Case 0: Wrong output