[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include   * ** *  *    
#include   *  **    * 

int main(int argc, char *argv[]) {
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*  ****   ***** *  *   ** **   *   * else
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*           
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  ** *  * **   return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include * ****    * ***
#include *******   *  * ***

int main() {
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** *   *    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *  * * *   ***** 
#include ** *        * * 

/* run this program using the console pauser or add your own getch, *  *  ** **  **      or input loop */

int main(int argc, char *argv[]) {
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***  * **     *     * ***  *
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
 *  ****  * ***  ****  *
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int main(int argc, char *argv[])
{
* ** * ** ** **** *    * *  * i, a;
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* *    **  * ** ***     0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
** * ** *    ** * ***** * * *** * your input : ");
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******      * *  **  

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
*      * ** ***** * * * 
* ***  ******   **** *  **
int main(int argc, char *argv[])
{
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* **  * *   ** **  ***      * ** **     *  * ** * your input:");
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* *    * **** * *  *   **  (i=1)
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* ** **  ** ***** ****  *** *  * *** * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* ** * * *  *** 
*  *  ** ** ****  *   * ***
int main(int argc, char *argv[])
{
   **  ******* *** **          i, a;
* **  ***   **  *  *    * *** * ** *   *** *   your input:");
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**   *  * **  * ***    *  *    *** ** a<i; i--)
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   *    ** *    **   *   *   (i=1)
  **   ** ******** ** * * * *****    *      * ****   *** *      *** * *  *    *
*  **      **   * **   *   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
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 ***  **** * *  *** 

int  *   argc, char ***** {

  * * **  *** * int a=10;

* ***    * ***** do{
*    *     *   ****     *** ***   * **  your *  * * * *** 
* ** *  *** **  **** ***     *  *  * ***  ** * * *  * * ** 
* ** *   *  * **  ** **  ** *** 
  * **** ** * *  **   a != 10 );
  * *  *  ** *   
*    *** * **  * * **** ****  9 8 7 6 5 4 3 2   ***  ** *
* *   ** *  ** **  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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int **   argc, char   ****  {

** ** **  *  *  *  int  *

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*  ****  ***  * * **        ** *  if( a  *** 10)
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*** *  *  * *  *  
**  ** ** ** * **  **** 9 8 7 6 5 4 3 2  **** **  *
** ***   * **   * ***  0;
}

Comments

Case 0: Wrong output