[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
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#include *  ** ** *** **

int main(int argc, char *argv[]) {
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*  *   * **  * *   **** **   ** ** *  *

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* * * * ***** return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
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#include ** * **  * * ** *

int main() {
**  **   ** ** int a;

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** ****   return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
* **   * *    *****
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int main(int argc, char *argv[])
{
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*  *** **   **  *  * ****  * 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
*** *  * ** **** * 
 **     **  *  *   *  
int main(int argc, char *argv[])
{
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*** ***      *  *     ****  **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
* * *  * * * **  * *
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int main(int argc, char *argv[])
{
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**    * *** * *  ** ** * *  ** * *   ****** * your input:");
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*   *   **** * ** *** **   ** *    * *   ****  *  *   ****    *     * * i);
*  *    *     *  *   * * (i=1)
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 * *    * ***** *********      *  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
*     *   *   *** ****
**     ****   *  ** **

int  ** argc, char ***  {

      *   * ** int a=10;

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** ****   *      * * * * **** ****   * *     *  *   ***   *  
   * * *  *  **      *** *  **  ** 
* **   *  ***    *** a != 10 );
   * *  ** *   
 **     **** *       *   *** * * 9 8 7 6 5 4 3 2 *  ******* *
  ***  * *    **  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
*  *   **  *  **** *
** *   * *   * * ** 

int *     argc, char *   *  {

* *    * * * * * int    * 

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* **  ** ****    *  ** * ** *   * if( a **  *  10)
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*          * ***  *  *  *   ** **** if( a  **  10)
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 **    *** * *  ** * **   a != 10 );
       *  
*** **  * * *       * *** **  *  9 8 7 6 5 4 3 2 * * **  **   *
 ******* ** ****  *  0;
}

Comments

Case 0: Wrong output