[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include  * **** **  ***   *
#include *     * * **     

int main(int argc, char *argv[]) {
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  * ** *   *  *  * ****      *   *   * *  *

  * * *   ** *  *** * * *  * **** Your *   ** start from here
* ** ** **** * * ** **    i;
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*  *   *  *   ** *   *** *      ***   *****  if(i == 0){
 *****    ***    ***** **     *  * *   ******* **    * *   * 
    ***  **** *   *   **  *   else
***     * ** ***   **   *     *   *     *   *  *   
 * **    **      **** ***** *** * }
** * * *   ** *  
**  *  *  *** 



 ** *   *   *** return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include     * ** ** *  *
#include  **** **  *  **

int main() {
    *****  *  *  int a;

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 *** * *  **   
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  * *  *** *** *     *** *   *** ** * * ****  * ****    **      *
 * ** * ***  *        *   }
 *  * *  * ** ** }

* **   *   return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
#include   *******  **
#include  *  * ** **** *** *

/* run this program using the console pauser or add your own getch,    * ***  * ****  *   or input loop */

int main(int argc, char *argv[]) {
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* ** *  *  ** *  ** = getchar();
* *  *   *   *   * ** ***   * =  **  * 
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*   * *** *  * * * *** = getchar();
   **   **  ****** *       * * *  = * ***
   *  ** * *   * ***  * ** * ** = * *   
*  **  *  *  ***   **   * * = getchar();


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**** **    **  *** ** *   ***
* * ** ** **   **** ** *** ** 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
** *   * **      
* ***  * * *** *  *    
int main(int argc, char *argv[])
{
 *  ******  *** ***** **** i, a;
 *   ** *  * **  ***  *  ** ***    * * * your input:");
 * **   *  ** *** ********* ****   *    * **  *** &i);
*  **  ** ** * * * * *  ** * * * * a<i; i--)
 *  * * **    *  ****  ****  ** *   ***   **  *    *** ** *   *   ****  i);
   * ** * *  **  ***   ** *  (i=1)
* *  ** *** *   *    **  *  *   *  *     * ***    **  *          * **   * **  *
 **  **  * ***  *   *  * ***   ***   0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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** *   **  *  *    ***** * * * ** * * **   *
    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
 * *    ** **** **  ****** ** your input : ");
** *    * ******  *   ******  **   **   **  * ** *  *** ** * * *   *  *   **  ********* * *** ****
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*** **  **   ***  ** ****   ** *   * ****  * * * ***  * **   *     *    *  * * * **  ** 
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*  * *  * ** ***** ** * *** **  *       **  **  **** * * *  *  ****** **   *** 
* **  ** ** *** * ** * * *  *** ** *  **  *   **  * *   * *** * ** ** *  ****
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****** * **** ** *   ** ** ** **  * * *   *  *   * *****
    *  *** **** * ***  *

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
  *  * ***  ** * * 
*  *** *   * *****   *
int main(int argc, char *argv[])
{
* **   **    ** ** **  * ** ** i, a;
*   ***** *   * * *    ***  * *     ******   your input:");
*  *       *     ***  *** **  * * **   *   ***    &i);
** ***   *     *  *  *** ****  ** * a<i; i--)
  ** * *  ** ****  **  ******* **  *  * ****** * ***  * *  *  ******* * ***** i);
   ***** ****  ***  **** * * (i=1)
  *** * ***    **  *******  * ****** * *     *   *  *****  *  *  ** ** **  *   **
***  *       ****** *  *** *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
 *****   *** ** ***
 * ** *  **   *  *   **  
int main(int argc, char *argv[])
{
 * * *  *** *   * *** **  i, a;
* *** *     **  * *   ****   **  **   * * your input:");
  **  **   *     ***   *  **     *** *   ***   * &i);
***  * **  ** * ** **********     ** a<i; i--)
 **   *** * *   *** *   ******* * * * *  **  * ** *   *** * **  * * * *** *  i);
     **    *   *****  * ****** * (i=1)
   * ***   ** *   *  **** ** **   *  * ****  * * ***   ***   * * *     *    * **   * *
** **  * * **          ***   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
      *  * ****  *   * 
*      **  * *  *     

int ** ***  argc, char ****  * {

*** ** * **  *** * int a=10;

*     *** ***  **   do{
** *  *  **   * * * ** *   *    **** * *  *  your    * **** *
 * ** **     * **  *      * *  **** *  *    *  ** ** *  ****** 
   *   *    *** * *    *   * 
   **  ****  * * ** a != 10 );
**  **   *   * * 
*  * *    ** *  * **** * ** 9 8 7 6 5 4 3 2 ** *  ** *
    **  ** * ** *  **

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
    *   *  *       * ** 
   **** ***     **  *  * *

int * *** argc, char   * ** {

 *   *  **** * int *** 

 * ** *** * *   do{
**** * * **  *  * **       ** *  ***       *** * your  **     * 
*      ***      * **  * * *  *   * *** ** *    ******  
 **   *  *  *  ** **     *  if( a * ** 10)
   ** **  *   *      **  *  * **  ** ** *  *  **       **  **  *  code is too low! ** ***  **
*  *   *  ****  ** *     * *   
****              *     *** if( a  * **  10)
*    ** * **           * *     **  *  *****    * ***   ** ** * * * * is too high! * ** ***
 * * **   *  *      a != 10 );
** *    ** * *  
   * * *  **** **  *   ***   * 9 8 7 6 5 4 3 2 * ** *  * *
   ** *   *  ** *   *  0;
}

Comments

Case 0: Wrong output