[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include **   *   * *  *
#include *** *  * * * ***

int main(int argc, char *argv[]) {
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 * *** *   **  *** *  *   *  your * *  *** **   *  ***** **  * ** ***   ****   *  ** *  DO NOT change
* *  * ***   *   *******  **    **  ***  *** *

  * ***** *    ** ** *** Your    *    start from here
**  ***  *****   *   *  *   ** i;
***      *   * ** ****   ***** = a; i >= 0; i--){
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 * **     * * **   * *  **  else
* **   **      *    ** *   *          *  * **    * * **  **  **
*****  * * * * **    **   *  *    }
  *  * * *   * *** 
 **  **  *  *  



  *     *** * * return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include  *   * *  * 
#include **     ****   * * 

int main() {
  * ** * ** * ** int a;

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*   * **  *****   * **   **  * }
* *  *   *****  }

*     *   return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
#include  *  *  *  *  ****
#include * *  *  * *** * * 

/* run this program using the console pauser or add your own getch,  *  *     ****   *** * *  or input loop */

int main(int argc, char *argv[]) {
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*  ** *  **** *  * * * = getchar();
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*  ** ** *  **  **  ** **         = getchar();
*  *  *  * *****   *  *      = getchar();
*    * *****     *** **   =    **** 
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    * **      * * * ** **  * * * = getchar();


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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
****      ****     
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int main(int argc, char *argv[])
{
** *   *  **   * ****** *   i, a;
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***  **  * *    * ** * ** * *    ** 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* ** * ** *** **** ***  **** *** *** **      *   ** ****** ***  * *    * **  * 
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**    **  ** ***  *  *  **** ****   * *   **   *  *    *   ** 
   ** * * *******

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
**    *  ** **   *
  **** * * *****  **
int main(int argc, char *argv[])
{
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***  *   ***  ***  **  **   * *       **** **  your input:");
 ** *   * *   **    * *  * * *  *  *   ** *    &i);
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*   * * *  *** ** *** *      * * * *     *  *********  * * *   ** **    i);
  *     *  *** * *   * *** (i=1)
 ** * *    **** *  * ******      *******  * ***** *  * * *  *  ***** **  ** * ** * 
 ** * **** * * *    *** ** * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
  *  *  *** ** * * *
 ** *  * ****   * * 
int main(int argc, char *argv[])
{
** ** *  ** *  ***  * *****     i, a;
**     ** * *  **   ****    ***  * your input:");
** ******* * ***** **** **** *** * *   *    * &i);
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 **  *  * * ** ***** **** * ** **    ** *  ** *   **  * ***  **  * i);
***    ***  *** ** **  *  * * *  (i=1)
* *  * ***** *    *  *   * * ** *** * * * *   * **** **   ***  ***   ** * * * 
* **   * * *    ** *** *  *   * *  * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
  * * * **********
*  ** *   *    ******    

int      argc, char *      {

  ** ***  **  * int a=10;

* **  *    **     do{
****   ** ** ** *** ** **** *   ****  * ***** your *    *** ***   
* *  * *   ***  *    * *********  *   *     *****    *  *  * 
**  ** * *  *  **    ***  ** *** 
*** **  *    ** * a != 10 );
 *  *  * ** * 
*** * *   ***      *** *** 9 8 7 6 5 4 3 2 **   ** **
* *   *  * *    *** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
**     * **  * * *    
***   **  * *   *     

int **** * argc, char  *** {

* *  * *   ** int  * 

   ** *  ** * do{
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 ** * * **  **   **  **  *  * * * ****  ** *  ***   
 *** **   *** ** ****    ** * if( a ***     10)
**** *  **   *  *     * * *   *   *  * * *  *  ** * **   *   * * code is too low! *  *   *
 * * *** ***  *  ***  *** * **** ** 
  ** *  *   ****   ** *  if( a *    * 10)
* *     * ** * *  *      ****     **** ****      **  *     ** **  *** is too high!   ****  
* ***** *   **   *  **  a != 10 );
*   * * *  **  
***    * * ** *   ***** * * 9 8 7 6 5 4 3 2 * * * ***  
 *     *  *    *    *  0;
}

Comments

Case 0: Wrong output