[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include ****  *  ***  **
#include * * *  *    **

int main(int argc, char *argv[]) {
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* * **   * ***  **  * * **** your * ****  *  ****      **    ** **   *  ***  *  *   **  DO NOT change
** *    * *     ** *   *   *********  **  

  * *   **  **   ** * **   *  Your   *** * start from here
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*  ***   *** **  **  * *  ** ***   = a; i >= 0; i--){
*  ***   **   *  ** *   * ****   **** if(i == 0){
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* *    * ****   * * *** * * **   * else
* * **  * * *  ** *  *  ***  ** *    ***    * ***** * **  
** *** * ***  ** *  ***  * * }
*    * ** * *    
      *    *  ** 



     * *  * * ** return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include  **    *  ***  ***
#include *    **   **** * *

int main() {
     ** * * *** int a;

*   **   **  * *   ***   *   **** * your  ***  *** **  
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**** *     * **    
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        *   * * ** ** **   ***  ** *    *  * * **   * **  **  
* ****  ** ***  * *     * * }
* **  *   **        }

*** **   return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
#include ** ****  ***   
#include  ** *  * *   *** ** 

/* run this program using the console pauser or add your own getch, *** *****        *  or input loop */

int main(int argc, char *argv[]) {
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*** * * *  * *  * **  * ***** =   * 
  ** *  *** * ***** * ****** = getchar();


**  * ** ** ** **    ** *
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***** ** ** **  *  ********* 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
*  *   ***  * ** * 
* **  *   ***  *  * 
int main(int argc, char *argv[])
{
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*** * *    ******** *  * *  **       ** *   * ***  &i);
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* * *    *          *****  *      *** *  **   *   **** *  *     ** * i);
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*         *  *  *  ** * ** *******   ** * *  *** *** *  *  *   *** * ** ****
  **   **   *  **** ** ******* *  *** 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
   *  *  **  **  ****   *** your input : ");
*** * * * *** **  * * ** **** *   *   *   ***** * *   **** ** * * * *      ****   *****  *  ******* * **
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
 * **  * ***    *
  ** ** ** * *  **  * *
int main(int argc, char *argv[])
{
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   *    ** *   **** *** ** *  ** ***        * * your input:");
*** *** *** * *  ***    * **    * ***  ** * **   * &i);
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    ***** * *  *   **     **     *  **  *    *   *** *** ********  * ** *** *  i);
 **  **** ** ** ***** *** *  (i=1)
** *  * * * **** *  ** *  *   *    **  * * ** **  **    * *   * * ***    * 
**   ** **** *** *  **   *    **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
   ****  ***   ***  **   
 ***** ****    *  * *
int main(int argc, char *argv[])
{
    *  ** ***  * **    * *** i, a;
    * * ** * ** ***   *** * ***** *  *  **  your input:");
 *  ** *** *   *  ** *    ****    * **   *  * &i);
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*    * * * **  *  * *     *  *     **** *  **** *  *  * **** i);
**     **   * * ** * *  (i=1)
*** *** * *** ****    * *** *  **  * *   ** *** ** *** **   *     * ** *
   * * *   *  *** *   **  * ** *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
 *      *   ** ** *****
*  * *  * *  ***  *  *

int  *   argc, char * ** * {

****  ** *  *    *  int a=10;

*   *   *   ** do{
  * ***     *  * *  * * *** *** **     *  ** * **** your  ** * *  *
* **   *  ** * * **     *    *   * * **   **      * * ** 
****   *             ***  ****    
 *** * ** **   *  a != 10 );
**  ***  ***** 
  ***  *   *   ****   *** *   9 8 7 6 5 4 3 2 ******    ** 
    *** *  *    *      *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
 **    **** *****
 **  **     **     

int *** * argc, char  ** * {

*** * **** * *****  int **  

** *   **  ***** do{
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****  **  ***  *         * * * * * ***  ** *  *      **     *
 *    ** *    **    **   **    if( a   * **  10)
*****    ****  * *  ** ** * *  * **  *  *  *    ** * * *    *        * code is too low! * * *
**  *     **  ***** *     **  *  
 ****   *  *   ***    *       * * if( a *****  10)
** *  *   ** *  * ****  *   *   ** **  ***** *  *  ** ** **  * *  is too high!  * ****
     **      **   * a != 10 );
** *    ** *  
**    ****   **    * ***** * 9 8 7 6 5 4 3 2 * * *** *   **
   **** *    * ***** *  *  0;
}

Comments

Case 0: Wrong output