[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

內容已隱藏
#include   *    *****     *
#include       *  **   * *

int main(int argc, char *argv[]) {
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* *   *     **   * ***     Your  ***    start from here
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** * * *  ** **    ***   *    *  *** * **  ****  *** 
**       ****    * **     **  * }
 *      ** 
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  * ****  return 0;
}

Comments

Case 0: Correct output

Answer 2

內容已隱藏
#include   * * ***    *
#include **** ******* ** 

int main() {
 **  *   *** int a;

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*** ** * *    **** }

   * *    return 0;
}

Comments

Case 0: Correct output

Answer 3

內容已隱藏
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/* run this program using the console pauser or add your own getch,   ****  **    *  ***** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

內容已隱藏
****  ** *    *** 
** * * * *** *  **** 
int main(int argc, char *argv[])
{
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    *  * *      * **   *   ** * *  ** *** 0;
}

Comments

Case 0: Correct output

Answer 5

內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
   *  **  *   * ** **** *  * *  *** your input : ");
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    *  * ** **  

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

內容已隱藏
* ** *****  *    **
*  *  * *  **   * *   *
int main(int argc, char *argv[])
{
 *    * ** *      * ** ** *  i, a;
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 **  *  * *  ** ** **  *  * *****  * **     **  **  ** &i);
*  * *  *  ***  *  *   **   ** ****  a<i; i--)
   *    * *    * **    **  * ** **  ** ** *      * *  ***      ****  *** ** i);
*  ** ** * *  ** ** * * * (i=1)
* *  ** *   * *** *** * *  * *      *** * * ***  * ***   *  ********  ** ***** * * 
* *** **  ** *        ** * * *** *   0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

內容已隱藏
*  *****   **  * * **
    ** * ****    **    
int main(int argc, char *argv[])
{
 *    **  *  * ** * *** *    * i, a;
  ** *** *   * **** *    * **  ** ***  *    your input:");
  * *** * *  **     * *** * *  *   **  *   * &i);
   **    **        * * * **     * a<i; i--)
     *** *   **      **** *   ** *      *  ** ***  *** *  * ***    *  ** * i);
*  * ****** *   *  *    ** ** * (i=1)
    *** *  *     * * ** **     *  * ** ****  * * *** * *  **** * * 
   *** * *  *** *        ** ** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

內容已隱藏
**  *   **** *     **  
* *   * * *    

int  * ** argc, char *****  {

 *   ** ***** int a=10;

**   **   * *   do{
* **** *     **   **  ***** ** *** * *  *  **  your ** *  ** *
 *** **  * *    ** ***   *   * *  *  **   **     *     **
* *     **** * *    ******  
****** ** **      **   a != 10 );
* *** **     ** 
*   *      * *  ***    * ***** 9 8 7 6 5 4 3 2  *   **     * 
*   *     *** ** ***  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

內容已隱藏
  * * *   *** *** * * *  
*      * *  **  ***** * 

int  *  * argc, char  **    {

* * *      ** int * * 

****   ***  do{
* **   * ** **     *  * ***  ***   * *  ***  * your  *   *  *
***   *******  * * ***  *       * *    ***  **  ****   *     
       *  * * *   * *    *  *** if( a  ** *   10)
**  *     **    **  ***** *   *** *  ****   * ******  *    code is too low! ** **** **
 *   * *   *  *  **  *  *** *   
 ** ***   *     ***    *   *     if( a *  10)
 *   *** *      *   * *** **  *   *     *****     * *  **      * *** is too high! **    ** 
**** **   ** * * ****   a != 10 );
**  ** *    * *  
 * ***   * *          *  * *** 9 8 7 6 5 4 3 2   * ***** 
**  *** ** **   **  0;
}

Comments

Case 0: Wrong output