[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include **** ***  *   ***
#include  *  *   * ***  **

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** ** *     *  return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  ***     *     **
#include **** * *  ** * *   

int main() {
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   * * *    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **      * ** 
#include ** *** *  **** 

/* run this program using the console pauser or add your own getch, **    ******  ** * ** **** or input loop */

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
   **** * ** ** ****
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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**** *  * ***** **  
***  ***  **    **  
int main(int argc, char *argv[])
{
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***  * ** ***   *** * * *   (i=1)
**   * ** ***  ** **** *   * *    *   ****  * * ***  *  *  *  **  ****  *** 
***    **  **  *   * ***** ** * ***** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*  **  **      **  *
***** ***  * **  * * * *
int main(int argc, char *argv[])
{
 * ** ***  * **  ** *   *  ** i, a;
**** *   *  * * * * *  *   *   ** *   **  your input:");
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*   ****** * * * *** ** * * * ** *** ** * *    ***  *** *** ****** *
   *   * **  *** * ** ***  ***   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
        * *  *** * *  
* *** **  **  ** * *

int * *** argc, char  **  * {

***   *   * *   * int a=10;

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 ******     *        *   ** **   * 
  *     *      a != 10 );
* *  * **  **   
***     *  * *   *    9 8 7 6 5 4 3 2 * ** * **
******* *  * **  * ** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 **     * * ** * *   
  **  *******     *    * 

int   *  argc, char **    {

     * ****  int *

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* * **  *  *** **     * * ** 
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  ** ** *   *  *** a != 10 );
** *      ****** 
  **    * *   *  ******* * 9 8 7 6 5 4 3 2     * *** 
**   **   ** *  ****  0;
}

Comments

Case 0: Wrong output