[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include **  * **  **** 

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* * ** ** ** ** * * ** i;
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****   * * **  * return 0;
}

Comments

Case 0: Correct output

Answer 2

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#include ******  ** ****
#include *  * ** *  **  *

int main() {
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** * *     return 0;
}

Comments

Case 0: Correct output

Answer 3

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#include * **  **** *   *
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/* run this program using the console pauser or add your own getch, **  *   *** *    * ****  * or input loop */

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
****  *  ** **** *
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int main(int argc, char *argv[])
{
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***  **    * *** ****  *** *** * * * **  **    * *   *  ***   * * * ****
**** ***     *** *     ** *  *    0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*** * **  ***  * *  *
   ** ** * * ***** * 
int main(int argc, char *argv[])
{
**  *   * *    ***     ** *** *  i, a;
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* ** **  * * ** * *****  **     ** *  * *  *    * * ** ** ** **  *  ***    i);
*** * ***  *** *****  **** (i=1)
* *  *  ******      ***  ** **       *     ****** * **  *  * ** *  **
    * *  *  ** *    *    **** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
** *      * *    * *
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int * *** argc, char   **    {

     *  **     int a=10;

*  * * * * *    do{
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* **   *   * **      * * *  **  
*  * **  **  *  ** * *  a != 10 );
* * * *  * **     
 **  **   ***    * ** **  * * ** 9 8 7 6 5 4 3 2 ***** ****  *
 **   ****   **  ** * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 *  *   *** *   **** ** *
 * **  **     ****   **** 

int      argc, char * * *  {

* * * *    ***    int   

* **  * *       do{
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*  *    **   * **   *  * *  *  ** **  * * *  ** ***  ** **
*  *** ***** **  * *   * *    *** if( a *  *  10)
*  * ** *  ***       *  ** ** ** **  * * ******* *** * *  * code is too low! * *   *
* ** ***    ****    ****  * *** 
***  *** *      **   * * * if( a   ** *  10)
* **   **       *       *  *** *   * *  *   ***  * ***   **    is too high!   * ** 
 *    ***   **   a != 10 );
*** * *  *  *** 
  *    * *   *   *     *** *  9 8 7 6 5 4 3 2 **  **   ** *
   *  * * *  * **     0;
}

Comments

Case 0: Wrong output