[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include * ** ** **  * 
#include  **  *     *

int main(int argc, char *argv[]) {
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***  * *  * ** ** 



*  ***       **** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include     ** ****** *
#include *  *  ****  *  * * 

int main() {
* * *** **  * *  int a;

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 * * * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
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#include  * **   ** *** **  

/* run this program using the console pauser or add your own getch, ** ** * *       **** **** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
    * *  *     **** * 
*   ** *   **   *  ***    **
int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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* *** ***  ***  * **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
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* **  ***     ***       
int main(int argc, char *argv[])
{
*      **  * *    **** **     * i, a;
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*  ** **   * ** **    ****  *** *   **  * ** &i);
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*    ** **    * *** *   ***   * (i=1)
*** * **  ***  **   ** **        * *     *  ** * *  *   ** * * * *  *  
 ** *   * **   *  ***  * *   **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* *    *   ****   **
*       * ** ***** ** *
int main(int argc, char *argv[])
{
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***       **  *** *    *  * ** *  a<i; i--)
*** * *  ** * ** *  * *****  *    **  *******     * ***  *  ** *  ** ** * **   *  i);
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** **   *** ** ***  * ****        *  * ** ** *  ** *     ***** ***  *** **  ****
** ***** **   *   ******   * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
** * * * **     ** * ** 
*  * **  ** *   *     * *

int     * argc, char *  ** {

* * *   *** ** int a=10;

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* ***   *    ****  *    ***   ***   ******  *  ** *   **** ** * * *** *
  * ** ***     * **   ******   
 *  *    ***   ***  a != 10 );
 **      * * ** 
**  *   ****    *  ****    9 8 7 6 5 4 3 2  **** *  * * 
*  *** *   * *   * * * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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*** **       ***   

int   ***  argc, char *   **  {

 * * * *   * int  * 

  * **       ***  ** do{
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***  ****  ****    *  **   ****   
*  ** ** ** *** ***   *      if( a ** * *  10)
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  * *   * * *  *  ***   a != 10 );
*** **   * *** 
* ***  **  * *  * **    * ** * 9 8 7 6 5 4 3 2 ** ***** **
*    ** **     **** 0;
}

Comments

Case 0: Wrong output