[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include  ****   * *   **

int main(int argc, char *argv[]) {
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**      * ** * *   *  *     **  *****

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**  ***     *  ****** * **  * *****     *    if(i == 0){
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**       *   *  
**** **  * * *  



*     * **        return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *  ** **   
#include  * * * ***  ** 

int main() {
**  *** *  ***  int a;

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*  * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include   * *   * *  
#include ***    ****   

/* run this program using the console pauser or add your own getch, ** *  * ****      *  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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* *** * ***     *  
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int main(int argc, char *argv[])
{
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   **         *  * **** *  * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**  *  ***  * *   
* * ***      ***   *** 
int main(int argc, char *argv[])
{
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**  **  ****   *** ** * ******* *    ****     ** **   * **    *    **  **  i);
** *    **  ***  * * * **   (i=1)
*    **     **   ** ** **  *******    * ****  *  *   *  *  ***** *     * **    *
* *   * ***** * * **** ** **         0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
******  **  ***   ***
    *   **** * ****  
int main(int argc, char *argv[])
{
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***    * ***  *  *   *** *** * (i=1)
 *  *  ** * **** *   *  *       ****  *   * ** ** **   *******  *  * 
 * * ** ** ***  ****  * * *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

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int * ** argc, char   ** * {

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* *  *  **  do{
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**     *   * *** *   *   ** **  *   *****  *     **        *  
**   * *    *    **   *     * 
    ** * ****   ****  a != 10 );
**   *   **  
 ** *   * *       ** **** ** 9 8 7 6 5 4 3 2 ***** *******
    * * ***    ****

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
** ***   *   * * ** **  
* *   *  ** *** ** *  *

int   *   argc, char **** {

*** *       * *    int ** 

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*   *        * * **  **    *  
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   * ** * * 
** *** *  ** **  * *   ** *  * 9 8 7 6 5 4 3 2  ** ***   
 ** * *** *** * *    0;
}

Comments

Case 0: Wrong output