[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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int main(int argc, char *argv[]) {
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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include **** * *  *  *   
#include * **  * *   * 

int main() {
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* *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include  *   *   * **
#include **  ***  **** *

/* run this program using the console pauser or add your own getch,   ******** ** ***  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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**   ****** *      * *
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int main(int argc, char *argv[])
{
*  *  ***  ** * **  *** i, a;
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
** *** * *  ***  ***   
* *   *   * *  *  *     *
int main(int argc, char *argv[])
{
*  *  * ** **  *         * *    ** i, a;
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*    * *  ****** ** *** **  ** *  (i=1)
* **** *   *      ****    ** **  * ** *     *** * ** * ** ***       *** *  ***
 * * ** **   *     **  * *** * * *** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
   *** **   * *  
** **    * * ** ***  *  
int main(int argc, char *argv[])
{
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***  **  **** ** ******   * * ** *   *  **   * ***** **  ** *   *   ***    * *
    ******  *  ******   ** ***  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* *    * **** *** ***
 *    * ****  ** ***  

int *  *   argc, char  ** * {

* *    * **  ***  int a=10;

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*   *   *** * ** *    * ****  *       * *  * **   *  *** *
 **     ** ** *     *  **  ** 
       ** **** **   a != 10 );
 * *      **** 
**  *  **      ** * ***    9 8 7 6 5 4 3 2 *   *** *** *
      *    * * ***

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*** *  *  ** *  **   
****  *  * * * *  **  * 

int     ** argc, char *  * *  {

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* ** **  ** *   **   **   * ** *   if( a   *** 10)
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** ** ** * * ***  * * * a != 10 );
*   ***     ** * 
  * ****   ***  * *** **  *** ** 9 8 7 6 5 4 3 2   **  ** *
 *  ***     **  ** * 0;
}

Comments

Case 0: Wrong output