[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

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#include  *  * *** ***  

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* **    * * *  *   * *   * * **  * *  * ****   * **   **
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*** * * ***   ** 
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* *     **    return 0;
}

Comments

Case 0: Correct output

Answer 2

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#include  ***    ** *   ** 

int main() {
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  *  * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

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#include    ****   *****
#include     * *  * **  ****

/* run this program using the console pauser or add your own getch, ** ** ** * ** ** or input loop */

int main(int argc, char *argv[]) {
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** ***** *  *  ****  **  *   * = getchar();


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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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  * ********   ***
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int main(int argc, char *argv[])
{
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**  ** ***  *  *     ** **  *** ** ** *** *  *     ***  *  * ***  ***   
*      *    * *    **  *    * * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* **   **** * ** **   *  *  ** your input : ");
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** ** ****   **  *  ***   *****   **    ****  *  **** *   *
** * *  **  * **   * **  *

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
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* *  * *   * *  *  
int main(int argc, char *argv[])
{
***  *  * *  ** *  **      **   i, a;
*   **** * ** *  * ** * **  **   **   * * *  * your input:");
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  *  **   *  *     **   *  *   ***** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  **  * *** *  ****  
 * * *   ** ** *****  * 
int main(int argc, char *argv[])
{
    *     *  *    **** *    i, a;
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*  *   ***** *   * **   * ** ***** *    ***  * *  * *  * * ****  ** **
   * *   *   * **   ****  *  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

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**  * * ** *  *    *
*   * *  **  *  ***     

int   ** argc, char  ** * {

 * ***         *** int a=10;

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**  ***       ** *  ** **  ** **    ***  ***  **  * **    **   ** *
***       ********  ****        
 **** ** ** *  * *  **   a != 10 );
*     *  **     
   *   ****    * ****    ** 9 8 7 6 5 4 3 2 **   ** ** 
 * * *  *   *     **

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

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int *      argc, char *   {

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* *   *  * *  *  do{
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****     * * *  ****    ** ** * if( a      *  10)
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** ****** * **  *  
* * *  *  * * *     **   9 8 7 6 5 4 3 2  * ** * * * 
 ***   *   ** *  **** 0;
}

Comments

Case 0: Wrong output