[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include *   * *  * ** **

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*  *  ** **  ** *   *** *   * **  ****  * *  *** 

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** *   *     *  
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**** * *    * *  return 0;
}

Comments

Case 0: Correct output

Answer 2

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#include *** * * * *  *  **
#include *** *  ****** ** 

int main() {
* *   *     ** int a;

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*  **   *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include     ***    ** *** 
#include  **     * ****   *  

/* run this program using the console pauser or add your own getch,  * ***  ********* **** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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int main(int argc, char *argv[])
{
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**     ** * *   ** * *         *******   *  *** ** *   *  ** **   * *   **
      ***** *    *  ** *   * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  ** * *    ****  *  *
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int main(int argc, char *argv[])
{
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**   *  ** * *   *****  ** * * * ******    *   *******    *** *   ***** * * 
  ****** *****  ****     * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
   *   * *  * * *** 
***  *  * ** * * *  
int main(int argc, char *argv[])
{
   ***    * *   *    *  *   ** i, a;
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** *  **  *  **  ** ***   *******  * ** ** ****     * ** **      * * *    * i);
* ****** **  *   * * **  (i=1)
**  ** * *   ****  *     *  * ** *** *****   ** *  * *** *** **  ** *   *** *
** **  **** *   ****   ** * **    0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*  *   * * ***  *   * 
   *  *     *     * 

int  ** **   argc, char ** ** {

 ** *   * * * int a=10;

*  **  ** ** do{
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*** *****  **  *  *    a != 10 );
  **** * * ***   
  *  *  * *       ***  9 8 7 6 5 4 3 2    * * ** *
*** * * *     *** * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
***  *  *  *  ***   *  **
*****  ** * * *   * *

int   *** argc, char *  **   {

**** *   * *  int * 

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*  *   *      *  a != 10 );
       **    *  
*       ** *  *    * ** *  ** ** 9 8 7 6 5 4 3 2      *   * *
**  *  *****  *** 0;
}

Comments

Case 0: Wrong output