[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include **** *    *  * **
#include **    **   * **  *

int main(int argc, char *argv[]) {
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   ** * * *   **      *     **** **** 

* *   *  * * ** * *   ****  Your  *  *** start from here
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****** * *** ** *    * * * *  = a; i >= 0; i--){
*    **    *    * *** * ** ** ** *  *  ****    if(i == 0){
*   *  ** *   **   ***     *   *   **  ** **** *       **** **  
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******* ***     * *   * *  *   * * *******     *** ****  
*  **** **  *** *  * *   **  }
*  *  * **    ** 
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**    *   ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  * **** ** * * ***
#include     **  * *   

int main() {
***  ** * *  * int a;

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*    * * ***   * * *    **   *** }
****  * *    }

****    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include  * *       *
#include *   * ***   * *   

/* run this program using the console pauser or add your own getch,      ***    ****** * * or input loop */

int main(int argc, char *argv[]) {
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*****   *** **   *   *     **  = *    * 
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** ******  * *  ****   *  **  =     **
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******** ****     ** ***  = getchar();


** *   ** ** ***      ** *
* ** * *   * ** * ** * ****
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
* * **  ******    * * 
   * *  * **  **   * 
int main(int argc, char *argv[])
{
* **   **  *  *  *   **** *** i, a;
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**  ***** **  ***  ***  *****  *** *  *  *  *  *   &i);
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*   * **** *   ****    *  * * **  ****  * ****        *  * * * ** *** i);
  *** *******   ****** * * * (i=1)
*** *  *  ** **   ****  ***  ***    * * ** * ****   * *** **      *****  * **** 
 *  * * **   * *  * *  **   ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
    *** *    ** ***   **  *** ***  *** *******
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***  * ****      * *       **  ** ** ***  ***     ***  ** * * **   *** **** 
* *     * ** ** **  **** * **  **   * * * ******   * *
    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
  * * **** ****   * ***   **  ** your input : ");
 *  **    * ** * *        ******  * *  **   **  * * *** *  ** **  * * *   **   *     * *  * ** *
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* * ***  ** *   *     *  *  * *  *   *   * *  * *** ** ****  * * * ***    ** *  **  *
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    **  *** *  **   ** 

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
     *    ** *  *  ** * 
       * *  *   **     **
int main(int argc, char *argv[])
{
 * *  *  * ***  ***  ** *  ******  i, a;
* **    *  *  *   ******* ***  **   * your input:");
*** ***   ** *** ***    **  *   *    * *  **   ***  &i);
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*  ** *         ** * ** *     *     ***   **** * **  **  ***  ****  ****   ***** i);
**  ** *** **** * * ****   ***  (i=1)
  *      ** *    *** *      *******   *    ** * *   *** * * *****      **  ****   * 
***   ** *   *        *** ** ** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
**  **    *   ****
 ***  * ** ** * ** **  **
int main(int argc, char *argv[])
{
    * *       **  ** *   **** **  i, a;
 *   * ** * ** * **** ** **  **    ****      your input:");
 *****   **   * ** *  ****     *** * ** **  **** &i);
 ****   **  *  *   ***** **** **  * * a<i; i--)
   ** **    *     ** **  **     **** ***  ******** *  *  *  * *     i);
* * **** *** * *    ****  * (i=1)
*   *  ****    *** * *  *  *** **        * *** ** ****** ** **** * ***   
      *    **** **   *  ** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
 **     *  *  *** * *
  * *   * * * **** **

int  *   argc, char   ** * {

** ** * * ** **  int a=10;

 *  **       *** do{
* *    *   ** *** *      *      ***   ***** your * ***** *   
 **  **   ** *  ***     **      * * * ***         **     *****
****   ****  *      *   
 * **   *   *** ***    a != 10 );
** * * **  * *  
   *    ** *** **** **** ** 9 8 7 6 5 4 3 2 * **** * *** 
   **** ***  * ***

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
  * *   * * * * * ** *
* * *    ***     * *** *   

int *  * ** argc, char    * {

*** *    *    **  int *  

 * * ** *   **  do{
     *   ***  * *   *  *   * * **  * * * * your  * *     
* *  *   *  ***  ** *       ** **         *   * *  **    * *** 
 * ** *** * *     *  * * if( a  **    * 10)
* ****  * * **  *  * *        ***  ** ** *** ** **  **  *  *** code is too low! ** * ** 
      * ** *  * * *  ** ****  *  
  **  * *     **** *   * if( a         10)
 *    *** *  *     ***  *** **  *  **  *** *   *** *   ***  is too high! *****  ** *
* * *      ****   ** * a != 10 );
**   * *  * *  * 
  *  * *   *   ** * **    ** 9 8 7 6 5 4 3 2     ** ** * 
*        * *  *   0;
}

Comments

Case 0: Wrong output