[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include * * *    *  *  
#include   *** *     ***  

int main(int argc, char *argv[]) {
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*** * *         * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *     * *** *
#include    **  * ***  ** 

int main() {
* **   *  * ****   * int a;

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   ***   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **  *  **    *  
#include   *********       *  

/* run this program using the console pauser or add your own getch, * * *** ******    *** * or input loop */

int main(int argc, char *argv[]) {
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    **  **  * ***  * * 
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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*   * ***  *  **  * * **
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int main(int argc, char *argv[])
{
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      *****  ** * *** **  * **    *     * ****    *    * * *    *  * 
   * *** * *  *** * *** * * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**   *****  ***
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int main(int argc, char *argv[])
{
    * *   * ** * * **  * ** * i, a;
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**  *    **   * *   * * *** *  ** *    * *  ***  * *  * **** *** *** ***** *  * 
*   *** * *  *  *  ****  *  *  ** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
** **   **** *** *** 
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int main(int argc, char *argv[])
{
* ** *    *  *** *** * *  **** i, a;
*** ******  *** **     ** * * ****** **  * **  * your input:");
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********    **  * **  **** (i=1)
* ****** ****    **    **     * ***  ** *** ****   *** * *     *  *  *   *
 * * * *  ***  ** * ***  * * ** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* * *  * *  *** * ****
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int * ****  argc, char * **  {

*****  * ***  int a=10;

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* ** *    ** *    *      * * *  **  * *** * ***  ** * * 
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**** * * *     ** a != 10 );
*  ** ** ** * 
*   * * *  *  ** *******      9 8 7 6 5 4 3 2 ***  ** ***  **
**   * * *** ***      *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
***   * *  **  *      
* **    * *   *  ** 

int   * * * argc, char  ** * {

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** *   * **  **  *  * **      if( a     * 10)
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*** ** ****    * 
 *** * * *  **  * *** ***  9 8 7 6 5 4 3 2 *  *  **** 
   ***   ** *   *** 0;
}

Comments

Case 0: Wrong output