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Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

[Exercise] Coding (C) - đã hỏi trong Chapter 3: Branching, Looping and Functions bởi (5.9k điểm)
ID: 30222 - Xem được từ: Không giới hạn - Hiệu lực đến: Không giới hạn
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20 Trả lời

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Case 0: Wrong output
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Case 0: Wrong output
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100/100 trả lời bởi (220 điểm)
0 0
Case 0: Correct output
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100/100 trả lời bởi (243 điểm)
0 0
prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in
0 0
prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in
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#include <stdlib.h>

int main(int argc, char *argv[]) {
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Input
10

Output
Enter your input:10
10987654321zero
50/100 trả lời bởi (269 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^
0 0
prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token
0 0
Case 0: Wrong output
0 0
prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~
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100/100 trả lời bởi (283 điểm)
đã sửa bởi
0 0
prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in
0 0
prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
0 0
prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Correct output
0 thích 0 k thích
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100/100 trả lời bởi (153 điểm)
đã sửa bởi
0 0
Case 0: Wrong output
0 0
I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'
0 0
Case 0: Correct output
0 thích 0 k thích
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trả lời bởi (153 điểm)
0 0
prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input
0 thích 0 k thích
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trả lời bởi (153 điểm)
0 0
Case 0: Wrong output
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