[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include   *  * * *  * 
#include   ** ** * *** ** 

int main(int argc, char *argv[]) {
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 *   * * * ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include   * ***   *
#include *  *** ** **  * * 

int main() {
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* **** *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **  *** *   ** **
#include ***   *   *    

/* run this program using the console pauser or add your own getch, * ** ***  *  ** *    or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
**     * ****    ***** 
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int main(int argc, char *argv[])
{
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*** *** ** **   ** **    * ***    *  ** *          **    *  *** ** * **    * 
   *  * *      * *   **** * ** * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  *    *       
**** ***   **  **  * **
int main(int argc, char *argv[])
{
*** *  **        * *** **     i, a;
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 ** **  *  * **   * **  ** **** **  **   **  * *  **  ** *  * ****
*  *  * ***  *  ****     * * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* ***   *          * 
*   * * *  * *          
int main(int argc, char *argv[])
{
** **** *****    *   * * * *  * i, a;
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* * *  **       *    ** **** (i=1)
** * ***  **   * **  **  **   * **    *  ** * ** ** *  * *  ** ****** 
* **  * ***   ***  * *  **** * *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
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** *** * *    * **    *   

int  **  argc, char * ** {

*  *  *   ** int a=10;

****  *** *  do{
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*   * **  ** * * **    *     **    *   *** * *  *** *** ** 
 * *  **  ** ***  *   *  *   
 * **  * ** *     * * a != 10 );
* ***  *  **  *  
* **        *** * *** **  9 8 7 6 5 4 3 2    *  * * 
 * *  *  *    **  ** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

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**     * ***   ** ***

int  *  * argc, char ** ** {

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* * ** *   * **       *    **     ** * * * **  **      *     *** *   
****  *   *  ***  * *       *    if( a * * 10)
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**  *   * ***** *  **** ******** 
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***  **  *      * * ** * a != 10 );
 *  *** * *** 
** *   *  * *   * * *  * *   9 8 7 6 5 4 3 2 * *    ** 
**     ***    *   ** 0;
}

Comments

Case 0: Wrong output