[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  **  *** ** ** *
#include ** * ** *  * **

int main(int argc, char *argv[]) {
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*   * * *  **  ** *     **  Your     *  start from here
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**** *  * *  * 
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** *         **    return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *   * *  **     
#include * **   *** 

int main() {
**        *    int a;

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 *        return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * **    * *** ** 
#include  * *  ***  *  *  

/* run this program using the console pauser or add your own getch,  ** * **  * **  *   ****    or input loop */

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
    *****   *    *** 
** *   ***  ***** *   
int main(int argc, char *argv[])
{
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**   * * * ** **  **** *  **   * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* *  **   *** **   *   *** **  your input : ");
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**      ****   **
** **   * * *     ** * *
int main(int argc, char *argv[])
{
* **** * ***   *  * ****  ***  i, a;
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** *** * *** * **  * *  * ** * ** *** *  *****    ***** *   *****    
** ****** **** *  * *****  * * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*   * **       ***
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int main(int argc, char *argv[])
{
  *    *******   ******* * i, a;
 * * ****  **  * *    * ********* *    * *   *  *  your input:");
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* *  ******       **   * *  ***    *  ** *** *******  *  * *** ** ***  *  * **
  *** * ***   *   *  ***  *   **   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
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**  ** *  ***  *** * *

int   *  argc, char **** {

 * *   ***    ** *  int a=10;

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* *** *  * **  ** * ** * *  **   *** *  * **  * * **   ***  
**  *  *   * *  **           *** 
**  * **  *** *  *    a != 10 );
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** ** ***  * ** *   *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
     ****** ***** *
******      * * **** *

int *  *  argc, char  *  *  {

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*****     ** *   * *   ***  if( a **     * 10)
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**   * *      ***  *  a != 10 );
* * ** *  *  ** 
*******  ***    *   * * * **** * 9 8 7 6 5 4 3 2 ****       
   ** *   **     * **  ** 0;
}

Comments

Case 0: Wrong output