0 like 0 dislike
3.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.2k views

49 Answers

0 like 0 dislike
Hidden content!
** * ** * * **


* * ** * *** *


*** * ** **


* *** * *** *** **




*** ** ( *
*
* * ** *
* * * * ** * * * * ** *** ** ** * *
** = d -
= c - *
= f * b - a * e ;
* = 0 -
* * *
*
** ** ******* ** ** ** * = * - * *
*


* ** * ** * ******* * *
**
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** * * *** * * *


** ** *
*** *** * * ** * ****** * * ** * t = 0, a, b, c, a1 , *


* ****** ** ** *** ** **** * *** %f %f ** *** **** * *** * *




* * * *** * * * * = ** - / * * y2 - x2 * ***
*** ** * * * *** * * ** = *** - * / * * * - * * *
* * ** ** **** * = - ** * * - * * *


* *** * * **** ** * ** ***** *** ** ** * ***** ** ** *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * ** ** * ** *





int main(void)

{
* ** ****** ** * ** *
* ** ** * * %f %f * * * * ****** ** * * * *** *** ** *
**** * - x2 == * *** *** != 0)
* ** *
** ** * ** * * = x1;
* * *** * *** * = 0;
* ** * *** ** * = -x1;
** ** * * ** ** * *** ** * ** * %f ** *** * * *
* * *
***** * if(x1 - x2 != * * ******* != 0)
** * *
* *** ***** * ** * = (y1 - y2)/(x1 - x2);
** *** * * * * *** * = y1 - (a * x1);
* ** ** ** ** ***** *** = -((a * x1) + c) / y1;
*** * * * * *** * * ** * * * %f ** ** * **
* ** **
* * ** if(x1 - x2 != ** ** * ** == 0)
* *
* ** * **** * ** * ** = x2;
* * * ***** *** * * = 0;
*** * ** ** ** ****** * *** = -x2;
*** * ***** ** * **** * ** * %f * * * *
**** ****
** * ** if(x1 - x2 == * ** * == 0)
*
* *** *** ******* * ** * = 1;
** ****** * ** * **** = 0;
** * * * * ****** **** * = 0;
* * * **** **** **** * ** %f ** ***

 }
***** ** * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ** ** ****


* ** ** * * ** **


**** * ** * *


* * ***** * **** ***




* ( **
**
*** *
*** * ** * * * ** * * ** * *** *
= d - *
** = c -
= f * b - a * e ;
** = 0 -
* * *

** * ** * ** ** ***** * ** = - * * *
*


* * * ** * * * *** * *
** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
***** ** *** * ****


** * *
** *** * ** * ** ** *** *** * ** * * t = 0, a, b, c, a1 ,


**** *** ** * * ****** * * * %f %f **** * ** ** * ** ** * * * * ***




*** * * * ** ***** = * - / ** * y2 - x2 * *
** ** **** * ** * * ** = - / ** * y2 - * * **
* * * * * * ***** ** ** = - ** * * - *** * *
**** *** * * * ** * = a * - *
****** *** * * *** = b * -
* * * **** * * * * * ***** * * * ***** * * ** * * * * * *


** ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** ** **


** *
* **** * ** ** * * *** * * *** * * t = 0, a, b, c, a1 ,


* * **** *** * * * *** %f %f * * * ** * ** * **** *** **




** * * **** * ** * ** ** * * * = - ** / ** * y2 - x2 *
* ** * ** **** * * * = * - ** / * * y2 - * * **
** *** * ** ** ** = - * * - * * *
* ** ** * * **** *** = a / -
** ** * ** ** *** * * = b / -
* ********* *** ** *** * *** * * * * **** * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * **** * * * *


* * ***
* *** ** * *** * ** ** * * ** * * ** * t = 0, a, b, c, a1 , *


** * ** ** **** *** ** * * ** ** %f %f ** ******* **** ** * *** * * * ***




* *** * **** * * * * * * = * - * / * * y2 - x2 * *
*** ** * * * *** ** = * - * / ** * y2 - * * *
* * ***** *** ** * ** = - * - * * *
** *** * * *** *** * * * * = a / - **
** * * *** ** *** = b / -
*** ** * ** * ***** *** ** * **** *** * * * * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** ** ** **** *





int ***

{
** * **** **** ** *
* *** * ** %f %f ** *** * **** ** * ***** ****
* ** * - x2 == 0,y1 != 0)
** *** ** ***
*** ** * * ** *** ** *** = x1;
* ** *** * * * * = 0;
* * **** * ****** ** = -x1;
*** * * * * ** * * ****** *** %f * * *
*** * ** **
* ***** if(x1 - x2 != 0,y1 != 0)
** *
* ***** **** ** = (y1 - y2)/(x1 - x2);
**** *** ****** ** = y1 - (a * x1);
******* *** * ** * = -((a * x1) + c) / y1;
* ***** * * ***** ***** %f *** ** *
**
* * *** if(y1 == 0)
* * ****
* * * * * * ** * *** * ** = x2;
*** ******** ** * *** = 0;
* * * ** * ** ** * = -x2;
**** *** * *** ** ** * * *** %f * ****
* * **
* * * **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** * *** * *


* **** * ****** *


*** * ** *


* *** * ** * **




* * * ( ** *

** ** * *
* * ** * * * **** *** **** *** * * ****
* = d -
* = c - *
* = f * b - a * e ;
* = 0 - *
* *****
*
* ** * ** * * * = * - * * * *
*


* ** * ** * ****** ***
** * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* * * * ***** ***** * * * x1,x2,y1,y2,m,a,b,c,c0;
** ** * * ** **** * * **** * *** **
*** * * *** **** *** ****** ** * * *** *** *******
****** *** * ** * * ** * ** * ***** * * ** *
** ** ***** *** * * ******* * ** * **** *

    m = (y1-y2)/(x1-x2);
* ** * * ******** ** **
* *** ** ** * ** * ** ****
* * ** *** *** *********** *********
* * ** **** *** * ** * ***** *
******* **** **** * *** * * *** * *
** * **** * * * * *** ** * * * * * ** * *** * * * %f %f",m,-1.000000,c0);
* ** * * * ** ** * * if((y1-y2)%(x1-x2)!=0.000000)
* * *** *** ** * * *** * ** * * * ** ** ** *** ** * *
* **** ** ** * * * * * ***** ** *** ***
* *** *** ***** * * * *** * * * **** * * ** * * * * *** * ** ** *
** ** * *** * * * *** ** **** *** * * *** **** ** * **** ***** ** * * * **** ** *
*** * *** * **** * * * ** ** ** ** * * * * ****** **** * *** * *** **** ** *** * * *** * *******
* *** ******* ** ** * * *** ** * ** ** *


* ** ** * ** * * * * * * **** ** * *** *


*** ** * *** * *** * *** ** * * ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.16
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users