0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
***** * * **


* *** *** ** * *


* * * * ** ** *


*** * ** * ***




* * (

** * *
* * * **** * * * * *** * * ** * * * * * * ***
= d - *
* = c -
= f * b - a * e ;
* = 0 -
* * *
*
* **** *** ** * ** * * = - * * ** * * *
*


* ** * *** ** * * * *
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * * * ** ** **


*** *
* ** * ****** ** ** ** * * * * t = 0, a, b, c, a1 ,


** ** * * ** * ** *** ** ***** *** %f %f * ** * * * * * * ** *




* * ***** ** * * = * * - ** / * * y2 - x2 * *
** ** ** * *** **** * = * - * / * * - * * *
**** * * * **** * = - ** * * - * ***


**** * ** * ** ** * **** ** * * ** * ** ** * *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * *****





int main(void)

{
* ** **********
**** ** ** * %f %f * ***** * * **** *** ***** ***** ***** *
* ***** - x2 == * * ** *** * != 0)
** ** **
** * ** ***** **** * ** = x1;
**** ** * ** * ***** ***** = 0;
* *** * * * * * ** ** = -x1;
** * ** * * *** ** ** * ***** * %f ** **** *
* * ** **
** *** if(x1 - x2 != *** * * * * != 0)
**** *
* *** * * *** ** * = (y1 - y2)/(x1 - x2);
** **** * * * = y1 - (a * x1);
* * ** * * **** *** = -((a * x1) + c) / y1;
** * ******* * ** * * * %f * * ***** **
* *** *
**** **** if(x1 - x2 != ** * == 0)
* * *
* * * *** * ** ** * * = x2;
** *** * * * ** *** * = 0;
*** ** *** ****** * = -x2;
* * * ** ** * * * * * *** * ** * ** %f * ***
* *
*** ** *** if(x1 - x2 == * ** * * ** == 0)
* *
* * ** * ** * *** **** = 1;
** * * * ** ** * = 0;
** * * ** * **** = 0;
* **** * * * * ** ** * * * * * %f * * * * *

 }
*** * * ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * **** ****


* ***** **** * **


* * ** * *


** ** * * *** * * *




* *** ( *

** ***** ** *
* * * * * **** * * ** * * *** ** * * * *
= d -
* = c - *
** = f * b - a * e ;
** = 0 -


** * * * ****** * ** **** = * - * *** *
**


* * * *** * ** *** **
* ** **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * ** ** ******


* * **
*** ** ** ** *** *** * * * * * *** t = 0, a, b, c, a1 , *


* *** * * ** ** **** ** ** %f %f *** * ** * * * **** * * *




* * **** ***** ** * ***** = * - / *** * y2 - x2 * * *
** * *** *** **** * *** = * - * / * * y2 - * * * *
* ** * ** *** *** * = - ** * * - * * **
* * ** ** * **** *** = a * -
*** ******* * ** **** * = b * - **
* ** * *** *** * * * * ** **


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** *** * * * ****


* **
* ** **** * ******* *** ** *** *** ** ** * * t = 0, a, b, c, a1 ,


** ** ** * * * *** ** * * * %f %f * ** * * ** ** * * * * * *




* ********* * * = - * / * y2 - x2 * *
***** ** ******* *** * = ** - *** / ** * y2 - ** *
* ***** *** * **** * ** * = - *** * - * *
* * * * ** * * ** = a / - **
* ** * ** * ** *** ***** = b / -
* ** ** ** * ** * * * * * * ** * ** * * ****


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** * **** * *


* *
** *** ***** * * * * * * ** * * * t = 0, a, b, c, a1 , *


**** * *** * ***** ** ** * * * %f %f **** ** * * * * * * * * * * ** * * *




* * * **** ** * * * = *** - / * y2 - x2 * * *
***** **** ** * * * = ** - ** / * * y2 - * **
** * * * * ** *** = - * * * - * *
*** ** * * ** * * * * = a / - *
* * **** * * * * = b / -
* * * * * * ** ** **** * ** **** **** *** * ** *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * *** * **





int * ** **

{
* * * * ***
** *** * ********** %f %f * * ** * ***** * **** ** ** ***
** * * ** * - x2 == 0,y1 != 0)
** *** * ***
** ** * * * ** * ** = x1;
**** * *** ***** ** ** * = 0;
** ** * * ** * * * = -x1;
***** * * ** * ** * * ** %f *** * *
*** *** **
** * ** if(x1 - x2 != 0,y1 != 0)
** ** **
**** * * * ***** = (y1 - y2)/(x1 - x2);
*** * ** * * ** * = y1 - (a * x1);
* *** ** **** ** = -((a * x1) + c) / y1;
***** * * ******* * ****** ** %f ** * * * *
*****
* * if(y1 == 0)
** ***
**** *** * * *** = x2;
* * ** * ** ** * ******* * = 0;
* * * **** * ***** * = -x2;
**** ** * * ** * ** *** ***** %f * ** * *
* **
* ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * * * *** * **


* *** * * ** ****


** * ** * **


* * *** * ****




** * (

* * **** * ***
* * *** * * *** * * ***** *** **
= d - *
= c - *
= f * b - a * e ;
* = 0 - *
** * **
**
* * * ***** ***** ** = - * **
*


* * ** * ** ** *******
** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
***** * ** * *** * *** x1,x2,y1,y2,m,a,b,c,c0;
** ***** ** ** ** ** * * ** * ***
** **** * * * * * * ** ******* * * *****
** * * ** *** * * *** * *** * ** ******* * * ** *
* * * * * * * * ** ** **** *** ** *

    m = (y1-y2)/(x1-x2);
****** * ** * * ** * ** * * * **
*** ****** * * **** * *
** ** * * * ** * *** ** *
* ** *** ** * ** * ****** * * *
** * ** * ***** *** * ** * ** * *
* * ** **** * * * * * * * * * ***** ** ******** **** %f %f",m,-1.000000,c0);
*** ** ** ** * * ** if((y1-y2)%(x1-x2)!=0.000000)
* ***** * ** * * * * ** * ** *** *** * * * * *** ****
* *** * ******** * ** * * ****** * * * ****
** **** *** * * * * ** ** ******* * * * ** * * ******* * ** * * ** * **
* *** *** ** **** *** * * **** * **** * *** ***** * * ***** * ** * ****
* ** * ** * *** * **** * * * ** * **** * ** **** ** ** * **** **** * *
** ** * *** * ** ** * ** *** * * * * * *


* *** * * **** * * * ** ** * * **


** **** * *** * ** ** * ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.83
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users