0 like 0 dislike
5.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.2k views

49 Answers

0 like 0 dislike
Hidden content!
* ** * ** *** * *


* * * ** * **


** *** * * *****


**** * ** * *




* * ( *
*
** ** *** *
*** ** *** * ** * *** * * ** ** **
= d - **
= c -
* = f * b - a * e ;
= 0 - *
*** *
*
* * ** * ** * = * - * * * *



* * * * * ** ****
** * **
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * ** *** * *


* *
*** * ** *** * * * *** * * t = 0, a, b, c, a1 ,


* ** ** * * **** * ******* %f %f ******* * *** * * ** **** **




*** *** ** ** **** * = ** - * / * y2 - x2 * *
* * ** **** ** *** * ** = * - ** / * * - * **
* * * ** ** * ** *** = - * * - * *


* * ** ** * *** ** ****** * ** * * ** ** ** ** ** * * *


***

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** ** *******





int main(void)

{
* ** ** * * *
* ** ** * * %f %f ** ** * * * ** *** ** * * * *
** * * * * - x2 == ** * *** ** * != 0)
*** * ** * **
* **** ** ******** * = x1;
****** * * * * *** = 0;
* ******* * ** * * * = -x1;
* * * ** * ** ***** %f ** ** *
****** * ****** *
** ** ** if(x1 - x2 != * *** * * != 0)
** **
** * * ** * = (y1 - y2)/(x1 - x2);
** * ** * ** *** = y1 - (a * x1);
* ** **** * = -((a * x1) + c) / y1;
* * ** * * ****** * * *** * *** %f * *** * **
* * * *
*** ** if(x1 - x2 != ** ** ***** == 0)
*** ***
*** *** * *** * * = x2;
******** *** ********* ** = 0;
* ** * * * * * * ** = -x2;
* ** * ****** * * ** ** ** * * * ** * %f * * ** ****
* ***
***** if(x1 - x2 == ** * * **** == 0)
*** * *
* ***** ** * * * ** = 1;
* ** **** ***** * = 0;
** ** * * **** = 0;
* * ** * * ** **** * ** * ** * %f * * *

 }
** * * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** * * * * ** * *


** ***** ***


* * * **** *


* ***** * *** **




** * ( **
*
**** * * **
* ** ** * ** * * ** ******* * ** * ** * ***** ** *
* = d - *
** = c -
= f * b - a * e ;
= 0 - *
* *

* ** * * * ***** = * - * * * * * *
*


* * **** ** ** *** * ****
***
answered by (-276 points)
0 like 0 dislike
Hidden content!
** *** ** * *** **


* * *
** *** * **** * * ** * * * * * *** * * t = 0, a, b, c, a1 ,


* * ** * **** * **** * * * *** %f %f ** * ** **** **** ** *** ** * **** **




* * ** *** * ** ** * = ** - / * * y2 - x2 * **
*** ** *** ** * * ******* = * - ** / ** * y2 - *
**** * ** * * * ** = - ** * - * *
** * ********* *** ** * * * = a * -
* * * ***** * ****** *** = b * -
* **** ** * * *** *** * * **** * * * **


** * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * *** * ** ***


** **
** ** ** * * ** *** * ** * * * * * t = 0, a, b, c, a1 ,


* * ***** *** **** ** * * ** * %f %f ***** ** *** * ***** * * * * * *




*** * ** ** ** ** * = ** - / * * y2 - x2 * *
* *** * **** * *** ** = * - / * y2 - * * **
* *** * *** * ** * * * * = - * * - ** *
**** * *** * * *** * ** = a / - *
* * *** ******** * ** * = b / - **
* ******* * **** *** ** *** * * *** *** * ** * ** **


*** ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * ***


* ** ***
** **** * ** * * * **** **** * *** * t = 0, a, b, c, a1 ,


* **** * *** * * * ** * ***** %f %f * *** * * * ******* * * * ** ***




* *** * * ** **** = - / * * y2 - x2 * *
* ** * **** * **** = * - * / * y2 - *
* ** ***** ***** * * = - * * * - * *
**** * *** *** ** ** * ** = a / -
* *** * **** * * ** = b / - *
* **** **** * * * **** * * * ** * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** *** ***** * *





int * ****

{
* *** * ** *
* * ********* * %f %f ** ********* ****** * * ***** **
** ** - x2 == 0,y1 != 0)
** * ** ** **
** ** * ** ** ** * * = x1;
* * ** * ****** * ** = 0;
***** * * * * * * ****** = -x1;
* ** * * * ** * * * %f * * ** ** * *
* ** * *****
* ** if(x1 - x2 != 0,y1 != 0)
****
*** * ** * = (y1 - y2)/(x1 - x2);
*** ** ** * * * = y1 - (a * x1);
* ** ** *** * * = -((a * x1) + c) / y1;
* * * ** **** *** * * **** %f * ** * ***
* **
* * * if(y1 == 0)
* * *
**** * * * *** * * = x2;
** ** * * ** ****** * * = 0;
* * ** *** ** **** ** = -x2;
** * * * * * * * ** %f * ** *** *
* * *
***** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** * * * * * * *


* **** * ******


** ****** * **


* *** ***** * *** ****




* *** ( * *

**** * * * * **
* ** * * *** * * ** **** * ** **
* = d - *
* = c - *
= f * b - a * e ;
* = 0 -
* ***
*
**** ** *** *** * = * - ** ** * * *



* ** ** * ** *
** **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
***** ** * ***** * ***** * * x1,x2,y1,y2,m,a,b,c,c0;
** * * *** * * * * *** * * ** * * * ** **
* * * * * ** * * ** ** ** ** *** ** ** ***
*** * ** * ** * ** *** * * ** ** * ** ** *
* *** ** *** ** * * * *** ** * *** * **

    m = (y1-y2)/(x1-x2);
* * * ** * ** * ** * **** * ** * **
*** *** * ** *** ** * **
* * ****** ***** *** *****
* * * ** * ** * ** * *** *
* ** * * * ** * * * * *** **
* * * * ** ** ** * * * * * * *** * *** *** * ** ***** **** %f %f",m,-1.000000,c0);
* *** * * ***** ***** if((y1-y2)%(x1-x2)!=0.000000)
** ** * * * * *** * **** * * * *** ** * ****** **** * *** * ** ** * **
** * *** ** **** * *** ** ****** **
*** * ** * ** * * * * * * * *** ** ** * * * * * * * **
** **** * ** * ** * * ** ** ** ** *** * * ** *** ** * * * * * ***** ** ****
** * * *** * **** * * * ** *** ** ** *** * * * * ** *** * * * * * * * * **** * *
* * **** * * ** * * *** * ** * ** * * * ** * *


* * *** ** ** *** ** ** * *


* **** **** * * * *** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.150
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users