0 like 0 dislike
7.5k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.5k views

49 Answers

0 like 0 dislike
Hidden content!
*** *** *** * * *


**** * *** **** ** ***


***** ** * *****


*** * * *** **




* ** ( **
*
* * ** **
**** ** * * * ***** ** ** *** ** * ***** * *
= d -
* = c -
* = f * b - a * e ;
= 0 -
* * **

** * * ** ** * * * = - *
*


** ***** * * * * *
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** ***** *** *


** *
*** ** * * * ***** * **** ** ** ** * * t = 0, a, b, c, a1 , *


**** **** ** * ***** * * * %f %f * ** ** *** ** * * * * ****




* *** * ***** *** ** ** *** = ** - * * / * y2 - x2 * *
* *** * * * ** * = * * - * / * * - * * *
**** * * ** * *** * * = - * * * - * *


* * *** * * * * * ** * * *** *** * ** * * **


* ** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * *





int main(void)

{
* ** ** *
** * *** *** * %f %f ***** ** ** * *** ** *** ** ** ***
*** * - x2 == ** * ** *** != 0)
* * ** *** * * **
*** * * * ** ** * ** * = x1;
* *** ** * *** * ** = 0;
* * * * * = -x1;
* * * * * *** * ***** * * **** * %f * * * * * *
** * *
** ** ** if(x1 - x2 != * * * *** != 0)
* * * *
*** **** * *** = (y1 - y2)/(x1 - x2);
** ** * ****** * ** = y1 - (a * x1);
***** ****** * = -((a * x1) + c) / y1;
* ** ** *** * * ** * ** %f ** *** ** *** * *
*** * *
* ** ** if(x1 - x2 != ** * * * == 0)
* ** ***
* ** ***** ** * * ***** = x2;
* **** ** ** *** *** * = 0;
** ** * *** ** = -x2;
** * * ** ** *** * ***** **** * * * * %f ***** * * **
* ** *
** ***** if(x1 - x2 == * ** ** * == 0)
* *
** * * * ** *** * ** *** = 1;
* * ** **** * *** * * = 0;
* *** * * * *** ** *** * = 0;
** * * * *** * **** * ** * %f ** ** ****

 }
** * *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** * ** ******


* **** *** ******


* * * * * **


** *** * *** * * * *




** ( * *

* * * * * **
* * **** * * * **** * * * ** * * ** ** *
* = d - *
= c - *
= f * b - a * e ;
= 0 - *
* *** *

** * **** * **** * = - * *** * * *
*


* *** **** * ** * *** *
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * *** ** ****** * *


*** *** *
** *** * * * * * * * ** ** * * * ** * t = 0, a, b, c, a1 ,


** ********** * * ** ***** ** %f %f ***** ** **** * ** * ** * ********




* * *** * ** ********* = - * / ** * y2 - x2 *
*** * * *** * *** = - * / * * y2 - ** * *
* **** ** * * * ** * = - * * - * *
* * * * ** *** **** = a * -
** * ** ** ** * ** *** = b * - *
*********** **** *** ** * ** * ** * **


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** ****


* *
* * ** * * * * * ****** *** * * *** ** t = 0, a, b, c, a1 , *


* * **** * * **** ** * * * %f %f ** * ** ** * * *** * ******




* * ** * * ***** * = * - *** / * y2 - x2 * **
* * **** *** ** = * * - * / * y2 - * *
**** ** ** ** * ** = - * - * **
*** * ** ** ** ** * ***** = a / - *
* ** ** *** *** * * * = b / -
* * * * * ** * * ********* ** ** * * * *


**** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ********* *


**** ** *
** * * * * * * ** * * * * * t = 0, a, b, c, a1 , *


* * *** **** ** * * * * ** ** ** %f %f * * ** * * * ** * * * *** * *




* *** * * ** *** * = * - * / *** * y2 - x2 * *
** ** **** *** * *** * = ** - / * * y2 - * ***
**** *** *** * ** * *** = - * * - *
*** *** ** * * * * * ** ** = a / - **
* * ** **** ** ** = b / -
** ** * * ** * *** ** ** * ***** ** * * * * ** * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * * ****** *





int *** *

{
** *** * * * *
* * ** * ** %f %f * * * ** * ****** * * * * ** * *
*** * *** - x2 == 0,y1 != 0)
** ***
* * *** * *** * **** ** = x1;
**** * * **** **** **** = 0;
** *** ** * ******* * = -x1;
** **** * *** *** *** ***** * ** %f * *** *** **
* *** ***
* * if(x1 - x2 != 0,y1 != 0)
** *
*********** * * = (y1 - y2)/(x1 - x2);
* * *** * = y1 - (a * x1);
* *** ** * * = -((a * x1) + c) / y1;
** * * **** ******* * * * %f ***** ** **
* * **
* **** ** if(y1 == 0)
* * *
** ** * ***** ** * = x2;
** ** * *** *** ** * = 0;
* ***** ** * ** * ** = -x2;
*** *** *** ** * **** ** * %f ** *** ****
* ** *
* * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
**** ** ***** * ** *


***** *** * **


* * *** ** *


* *** * * *** * *




* ( * *

* * *
*** * * ** * **** * **** * *** ***** ** *****
= d - **
= c - *
** = f * b - a * e ;
= 0 - *
* * * * **
**
* ** * * ** ** ** = - ** * *



* * ** ** * ***** **
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** * * * ***** * ** ** x1,x2,y1,y2,m,a,b,c,c0;
** *** *** * * * * * ******* ** * ** ** ****
** **** *** ** ** *** ** * * * ** * *****
* ** *** * * * * * *** ** * * * *****
*** * * *** * ** * ** * * *** * *

    m = (y1-y2)/(x1-x2);
* * * * *** * * ** * **** ** ****
****** **** ** *** * **** *** *** **
**** ** *** * ** * *** * **
* * ** * ** ** ** **** **
* **** **** **** ** *** * **** * * * ***
** * * * ***** * * * * * * * ** * ** * * * ** %f %f",m,-1.000000,c0);
* * *** **** ** * ** ** * if((y1-y2)%(x1-x2)!=0.000000)
* * * * ** ** ** * * * ** * **** * ** ** * *
* * ** ** * ***** * * * * ******* **
** * ** ** * ** ** * **** * * ** **** *** **** * *** * ***** ** **** * * *
** ** ** * ** ** * ****** **** * ** * * * ** * *** ** ** * *** ** *** * *
** * * ** ** **** * * * * * ** *** * ** * ****** ** ** * * ***** ******* ** ** *
*** * * * ** ** *** * * * *** * * * * * ** ***** *** **


* *** * * ** * * * ** **** * *** * *


** * ***** * **** *** * * * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users