0 like 0 dislike
8.1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 8.1k views

49 Answers

0 like 0 dislike
Hidden content!
* * * * * * * *


* * * * * * *** * *


* * ****


* ** *** ** *****




** ** ( * *
*
* * *
** **** *** * * * ** * * *** * *** ****
* = d - *
= c -
= f * b - a * e ;
= 0 -
* * *** *

*** ** ** * ** ** *** ** = * - * * * *



* ** * *** ** * * ** * **
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * *** * * * **


****
* *** ******* ** *** ** *** * * ** t = 0, a, b, c, a1 , * * **


* ** *** * *** * ******** ** ****** * %f %f * * * *** * ** * *** **** * ** ** *




* ** * ** ****** * ** * = - ** / * * y2 - x2 * *
* * ** ** * * = * - * / * * * ** - * * *
** * * * * * * ** = - ** * - * * * **


* * ****** *** *** * * * * ** * * * *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * ****** *





int main(void)

{
* * ** * * ** *
*** ** * * %f %f * ** ** ** ** * * * * * *
* ** **** * - x2 == * * ** * * != 0)
* * ******
* * * ** ***** * * **** = x1;
***** * ** ** *** = 0;
** *** * * ** = -x1;
* * ** ** * *** ** * * %f *** * * **
* ** * *
**** * if(x1 - x2 != ** * ** != 0)
*****
** ** * * ** * * = (y1 - y2)/(x1 - x2);
** * * * *** * = y1 - (a * x1);
* ** * ********* * = -((a * x1) + c) / y1;
* ** ** ** * ** ** * ******** * %f ** * *
** *
*** if(x1 - x2 != * ** ***** * == 0)
**
***** ** ** * *** * * * = x2;
* * * * ** ** = 0;
*** *** * ***** ** * * = -x2;
* ****** ********* **** %f * * ** * * *
********
* * ** if(x1 - x2 == ** *** ** == 0)
* ***
** *** *** *** *** * * * = 1;
* ** * * ** *** * = 0;
* * *** * * ** * = 0;
* **** * **** * *** ** **** * ** %f * * ****

 }
** * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** * ** * ** * **


* * * * * ** *


* * * * * *** **


** ** * *




*** ( **
*
* *
* ** * * * * ** *** *** * ** ** ** * ***
= d - *
* = c -
= f * b - a * e ;
* = 0 - **
*** *

** * *** * ** * *** = * - ** * **



*** * ** ****** * ** * *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * * * * *


* * * *
*** * ** * * * * *** * ** * * * ** * t = 0, a, b, c, a1 , *


* *** * *** * ** * ** * ** *** %f %f *** * * * * * * * * ******* *




*** * ** * * = - ** / * * y2 - x2 * *
* ** ** * *** * *** = * - * / * y2 - * * *
* * * * * ***** = - * ** - * * *
* *** ** ** *** ** = a * -
* * ** *** * * * *** * = b * - *
** *** ** * ** * * * ** ******* * ** ** * ** ** *


* * * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ***********


* *
* ** ** * ** *** *** ** * * * ** t = 0, a, b, c, a1 ,


* ****** * * *** ** * ****** * ** * * * %f %f ** * * ********** ** ** * * **** * *




* ** * * ** * * = * - / * * y2 - x2 * *
* *** * * * * ** = * - / * * y2 - * * **
** * *** * * ** * ******* = - ** * - ** * **
***** * ** ******* = a / -
* ** **** * * * *** *** *** = b / -
** * ** * * ** * ** * ** * * *** ** * * * *


***** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * *** **


*** * **
* * *** ** * * *** ** ** ** * * t = 0, a, b, c, a1 , **


******* * ***** * ** ** *** ** *** %f %f * ** * * * *** * ** * * *** * **




* * * * **** * ** *** * = * - / *** * y2 - x2 * **
***** *** * *** *** * * = * - * / * * y2 - * * **
* ****** * ** * * ** **** = - * * - * *
**** * ** * * *** * ** = a / -
* * ** * * ***** * **** = b / - *
* ** **** * * *** *** * *** ********** * * * * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * *** *





int * *

{
* * ** * *** * **
*** * ** * * **** %f %f ** *** * * * ** * *** * * **
* ** ** - x2 == 0,y1 != 0)
* *** *
** * ** ** **** * * = x1;
* ** ** * *** * ** * ** = 0;
*** * ** * ** ** *** = -x1;
** * ** * *** * * %f * *** * *
* ** ** ****
* * ** * if(x1 - x2 != 0,y1 != 0)
*
** ** **** ** * = (y1 - y2)/(x1 - x2);
* * ***** * ** *** = y1 - (a * x1);
* *** ** * **** = -((a * x1) + c) / y1;
* *** * * * *** ****** %f ** * * ***
*** *
**** * * if(y1 == 0)
** ***
** ** ** *** *** = x2;
* * * ****** * * ***** = 0;
* *** **** * *** ** = -x2;
* * * * * * ** * * * * %f * * *
***
* ** * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * *** **** * *


* ** *** ** * **


** * ***** ** *


** * *** ** ****** * **




* * ( **
**
*** ** ** *
* * * * *** ******* * * ** * * ** ******* * *
* = d -
* = c - *
* = f * b - a * e ;
** = 0 -
** * ** * *
*
* * ** * ******* * = * - * * * *



* * * * * * * * *
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* * * ** * * * * x1,x2,y1,y2,m,a,b,c,c0;
***** *** * * * ** * *** * * *** * * *
*** * **** * * * * * * **** * *
* * ****** * * * *** * *** ****** * * * * ****
* ** * ** * * * ** ** * * * * * ** ** *

    m = (y1-y2)/(x1-x2);
* ** * * * *** * ****** * * *** * *
** * * ** * * *
**** * * ** * *** * * * *
*** ******** * * ** * ** *** ***
**** * * *** *** * ** ** * * *
** ** * * ** * *** * ** * * * **** * * * *** * ***** %f %f",m,-1.000000,c0);
*** * ** ** * * * * * if((y1-y2)%(x1-x2)!=0.000000)
* ** ** * * *** ** ** * ** *** *** ***** **** ** * * * ** * *
* * ** ** *** ** * * * **** * * ** *
******** * * * * * **** ** **** * *** * * * * **** ** * ***** *** *
* * ** * *** ***** * ** * ***** ** * * *** *** * * * * * * ** * ** ** *
*** ********* * *** *** **** ** * * ******* ** * ** * * * ** ** * * * * * ** * ** *
* *** * * * *** * * * *** ** * *** ***


*** **** ** ** ** * ** ** * * ** *


* * *** * ** * ****** * * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 14.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users