0 like 0 dislike
4.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.9k views

49 Answers

0 like 0 dislike
Hidden content!
**** * * **** *


* * *** **** *


** ** *** * * ***


* * ** * ** * **




* ( ***

* * * ** **
**** *** ** * * * * ** ** ** ** **
* = d - *
* = c -
* = f * b - a * e ;
* = 0 - **
** *

*** * * * ** *** * = * - * *



* * * * * * ** *
* * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
****** *** * *


* * *
* *** * ** * * * * ** *** * ** * t = 0, a, b, c, a1 , * **


*** * ** ** * * * ***** ** %f %f * * * * * ***** * * * * ** * *** * *




* * * *** **** = ** - * / * * y2 - x2 * **
* *** * * ** * ** ** * = * - * / * * ** - * * **
* * * * * *** * *** = - * * - * *


*** ** * * * ** **** **** ** * * * **


*** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ***** *** ***





int main(void)

{
* * * * * * * *
** **** * * * * *** %f %f **** *** ** * ****** * *
* - x2 == **** * != 0)
* ** ***
* * * * * * ***** * = x1;
* *** * ** * * = 0;
* ** * **** **** * * = -x1;
* * * ** * * *** * *** *** * * %f * ** * * * *
* * * **
** if(x1 - x2 != * *** * != 0)
** * *
* * ** * = (y1 - y2)/(x1 - x2);
*** * * *** ** * = y1 - (a * x1);
* ** ** ***** ** = -((a * x1) + c) / y1;
* * * ** **** ** ** * * * %f * ***
* ** *
** * * if(x1 - x2 != ** ** ** == 0)
*****
***** * * **** * = x2;
* * ****** * * * ** ** * ** = 0;
* * * * ** *** * ** * **** = -x2;
** * * ******** ** ** * * **** * %f * * * ** *
*
* **** * ** if(x1 - x2 == * *** * * * == 0)
* * *
* *** *** *** *** ** = 1;
*** *** ***** * * ** ** = 0;
* * ** * *** * * * * = 0;
** * ** *** * * * ******* * %f * *** *

 }
* ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ******** ** *


** **** ** *** ***


* ** * * * *


** * **** ***




* * ( *
*
** ** ***** *
* ** ** * ** ** * ** * ***** *** ***
= d - *
* = c - *
** = f * b - a * e ;
= 0 -
* **

*** ** *** *** * * * = - * * *
*


* *** * * ** ** ** *
* **
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * * *** * * *


** * **
* * ** ** *** ** ** * ** * * t = 0, a, b, c, a1 ,


**** * * *** ** * * * * ** ******** * * %f %f ** * * *** *** ** ** ** * * ** *****




** ** ** * **** ** * **** * = - ** / * * y2 - x2 * *
** *** ** * * = * - ** / * * y2 - *
*** ** ***** * * * * = - * * - * * *
* ** * * ** * * **** * = a * - *
* * ** ** * * = b * - **
* * * **** * *** * * * *** * * * **** *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * ***


* *
* ** *********** ****** * ** *** *** * t = 0, a, b, c, a1 , **


* * ** * * * ** ** * * ** * * *** ** ** %f %f **** * * * * * *** ** * * *** ** *




* ** *** *** * * * * * = - ** / * * y2 - x2 * ** *
* ** *** * * * * * = - ** / * * y2 - * * *
** ** * ** * * = - * * - * * *
**** * * * * ** *** = a / - **
** * *** * * * ** * *** = b / -
* * ** * ** * *** * * ***** **** * *** * * ** ***


**** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
***** * * ** **


** *
* * ** * *** *** * ** * * * * * ** ** t = 0, a, b, c, a1 ,


** * ***** * ** * * ***** * ** ** %f %f * ** * * ***** * * ** ** ***** **




** * * * * * ***** * * * * = - / *** * y2 - x2 *
* *** ** *** * * **** = - * / * * y2 - * * *
* *** ****** ** * = - * - ** *
***** *** * *** ** * * = a / - *
** * * * ** * * * * ** = b / - *
**** *** ** * **** ** ** * ** * ** * * * *


******* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * * **





int ** ***

{
**** ** * * * * ** *
* * * ** * %f %f *** * * ** * * * * *
* * * ** - x2 == 0,y1 != 0)
** ***********
* *** ** ****** * * = x1;
* ** * ** ******** ** = 0;
** **** * ** *** * * ** ** = -x1;
* *** *** ** ** ** ** * *** ** * * %f *** * *
*** ** * *
* *** if(x1 - x2 != 0,y1 != 0)
** ***
* * **** ** *** * * = (y1 - y2)/(x1 - x2);
* ** * **** * = y1 - (a * x1);
* * *** * * = -((a * x1) + c) / y1;
* **** * *** **** ** * * * * * * %f * ***** **
**** **
* * * if(y1 == 0)
* *
* ******* * ***** * = x2;
* ** * * * *** = 0;
* * * *** * ** ** * *** = -x2;
*** * * * ****** * * * * ** **** %f *** * *
* * **
* ** ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
***** **


** ** **** ****


* * **


** *** * ** **** *




*** ** ( * *

* *** *
** * **** * * ** * ** ****** ******* * *
= d - **
= c -
* = f * b - a * e ;
= 0 - **
** * ** *
*
*** *** ** * *** ** = - * * **
*


* ** **** * *
** * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
*** * * * ** * * *** *** * * x1,x2,y1,y2,m,a,b,c,c0;
* * ** ** * * *** ** * *** *** ***** * * * ** *
** * ***** * ** * * **** * ** ** * * * * ** ** **
**** * * *** ** * * * *** **** ** * **
** * ** ** ** *** ** ** * * **** * * * *

    m = (y1-y2)/(x1-x2);
* * ********* ****** ** **** *** **** ***
** ** ********* * ** ** *
** *** *** * *** * *
* **** * * ****** *** ** * ** **
** **** * * * *** *** ** * *** **
* * * * * ** * *** * * * ** * ** ** *** *** ** * ** **** %f %f",m,-1.000000,c0);
* **** * **** * * * * * * if((y1-y2)%(x1-x2)!=0.000000)
*** * ** ** * * *** **** * ******* ***** * ** * * ** ***
* ** **** *** * * ** **** * * *** **
* * ** ** * * *** *** * **** ********** * ** ** * * **** * * ** *
** * ** *** * ** ** *** *** ** * **** * *** * * * * **** * ** * * * * *** * *
* *** * * ** * * * * * * * *** * *** * ** * * ** * * ***** * ** ** *** * ***
** * **** * * ** * ** ** *** * **


* * **** *** * * * ** * * **** *


* * *** * ** ** * ** * * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.125
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.6k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users