0 like 0 dislike
5.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.2k views

49 Answers

0 like 0 dislike
Hidden content!
***** * *******


** * * ** *


* **** ** *


** * * * ** * *




* (

***** ** ***
* **** * * * **** ** ** * * * *** * * **
= d - *
= c - *
= f * b - a * e ;
* = 0 -
* * ** **

*** ** *** * ***** ** * = * - * *



** * * **** * *** * ** **
** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** * * *** *** ****


* * *
*** * * ** ***** *** ** ** * * ** * t = 0, a, b, c, a1 , ***


* ** * ** ** ** * * * ** ** %f %f * **** *** * * ** * ** *** * ***** *




* * * * * * = ** - / * y2 - x2 * **
**** * * * * ** = * - * / * * ** - ** * *
** ** ** * * ** = - * * - * ***


* * ** *** ****** ****** * *** ** **** * *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** * *





int main(void)

{
**** * **** * *** ** * **
* * * ** ***** * * %f %f ** ** * *** ** ** * * ** ** ** *
* *** - x2 == *** * * * != 0)
** * *
* * *** * * ** * * = x1;
** * * ** **** * ****** * = 0;
*** ***** * * **** = -x1;
* ** * ** *** ** * * * *** ** * %f ** * **
* * **** *
* ** if(x1 - x2 != * != 0)
* *
**** * * ** * = (y1 - y2)/(x1 - x2);
*** * * ** = y1 - (a * x1);
* * * ** * = -((a * x1) + c) / y1;
** * * * * * * **** * %f *** * * **
***
** * * * if(x1 - x2 != * * **** * == 0)
* * *
* ** * ** * * **** * * * = x2;
** **** * * ** = 0;
** ** *** * * = -x2;
* ***** * ** * ******** * * %f * * ****
** ** *
**** ** * if(x1 - x2 == ** * * == 0)
*** * *
* ** * ** * **** = 1;
* * *** ***** * *** * *** = 0;
* * ** ** ** ** ** ** = 0;
** **** * * *** ** **** ** %f * * ** *** *

 }
* ** ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* **** ** * *


*** ** * ** *** *


*** **** ** ** ****


* ** * ** * *




* * ( ** *
*
* * ***
* ** ** * * * * * * *********** *** **** * * *
= d -
= c -
* = f * b - a * e ;
* = 0 -
*** *

**** * * **** * = * - * * * ** * *



* ** **** * * * ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * ** * ** *


** **
*** * ** * * * ** * * * * * t = 0, a, b, c, a1 ,


* * ** * * * ***** ** * * ** * * %f %f ** * * **** * * ** ** * * * *




* *** * * ** * ** = ** - * / * * y2 - x2 * *
**** ** * *** **** *** = ** - / * * y2 - * * *
* ** * * * * * * ** ** = - * - ** *
*** * * ** **** *** ** * = a * - *
********* ** ***** *** * = b * - *
** ** *** ******** * * **** * * *** * ***** * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * *** *****


**
* ** * ** * *** *** *** * * * ** * ** t = 0, a, b, c, a1 , **


* ** * ** * * ** * * ** ** ** %f %f * * * ** *** ****** * ** * * *** *




* * * * * * ** * = * - * * / ** * y2 - x2 *
****** * ** *** = * - * / * * y2 - *
*** ** ** *** * ** *** = - * * - * * *
****** ** *** * ** * * = a / - *
* *** * ** ** ** * = b / - *
* * * * * ** * ** *** * * ** * ** *** ** ** **


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
***** * ** *


* * *
**** * * * * * * * ** * * * *** t = 0, a, b, c, a1 ,


* ** * ***** ** * *** ** * * * %f %f * ***** * * * ** ** *** ** *** * **** **




* ** *** ** ** * = - * / * * y2 - x2 * *
** * ** ****** ** * = ** - ** / * y2 - * * *
**** **** ***** *** * * = - * * - *
**** * ******** **** = a / - *
*** * *** ** ** * * = b / -
* * * ** * ****** * *** * * * * * * *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
**** * * ** ****





int ** **

{
** * ** * * * **
* * * * **** %f %f ***** ** ** **** * ** * * ** * ***
* ** ** - x2 == 0,y1 != 0)
* * * * *
*** ** * *** ** ** * * = x1;
* *** * * * * * = 0;
***** * * * ** * * = -x1;
* * ** *** * * * ** ** * * * * %f ** *** * *
** * * * *
** ***** ** if(x1 - x2 != 0,y1 != 0)
* * * *
* ** * * ** * = (y1 - y2)/(x1 - x2);
** ***** *** * ** = y1 - (a * x1);
** * **** = -((a * x1) + c) / y1;
** * ** * * * **** ** * * %f *****
* *** ***
* **** ** ** if(y1 == 0)
****
***** *** ** ***** * * = x2;
* * * ***** ******* * = 0;
** * * * * * * * * * = -x2;
** * ***** * ** ** * *** *** * %f * * * **** *
* **
* ** * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * *** *** *


* * ** ** ** *


** * *** * *


* * * ** * * * * * **




** * ( *
*
* * ** *
* **** * * * * * * **** * *** ** * * *
= d -
= c - *
= f * b - a * e ;
* = 0 - *
* * * * **
**
** * ** * ** ** ** * ** = * - ** * * *



* * * * **
** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** * *** * * * ***** * *** x1,x2,y1,y2,m,a,b,c,c0;
* **** * * **** * ** ** * *** ***** * * * ****
* * ** * * * ** ******* ** * ** * * *
***** **** ** *** **** * ** ** * * ** ** **** * ** *
**** ***** * * * ** ** *** ** *** *****

    m = (y1-y2)/(x1-x2);
**** ***** * ** ** ** * **
* ** * ** **** * **** ** *** **
* ***** * * * **** * ** **** **
*** * * *** * ** * *** ** **
*** * * * * * * ** * * ** * ** ** *****
** * * * * * * ** *** * * ** * * * * **** %f %f",m,-1.000000,c0);
*** * * * *** * *** if((y1-y2)%(x1-x2)!=0.000000)
** * ** * *** * * *** ** * * ** * * * *** * * **
* *** ** ** * **** ***** * ** * * ****** **
**** * * * ** * **** * ** ** * * * ** *** **** * * * * * * * *
* * * * ** * * ** ** * *** * **** * ** **** ** **** * ** *
* ** ** * ******** ** ****** ** * ****** * * * **** * ** ** * ***** *** *
* * ******* * * * ** * *** *** ** ***


* *** *** ** ** * **** * * ** ** * ****


*** *** ***** ** * ** * * * * * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.192
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users