0 like 0 dislike
4.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.2k views

49 Answers

0 like 0 dislike
Hidden content!
* ** * * * *


* * * ** *


* ****** * * * *


** * * * * *** **




* * ** ( *** *
*
* * * ***
* * ** * ** ***** ** ** *** *** *
** = d - *
* = c -
= f * b - a * e ;
= 0 - *
* * *
*
*** * **** * **** ** * = * - * * * ** *



* * * * * * * * **
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
****** * * * *


* **
** * * *** * ** *** * * * * * * ** t = 0, a, b, c, a1 , * *


** ***** * **** * * *** ** * * %f %f ***** * * *** * ** * ** * ** ****




* ******* * ***** ** = * - * / * y2 - x2 *
** * ***** * *** = * - ** / * * - * * * *
** * * * ** * = - * * - * *


**** * * * *** **** * * ** ** *** * * * * * *


** * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * ** * * *





int main(void)

{
*** * * * * * *
* * * ** **** * %f %f * *** ** * ** * * **
**** ** - x2 == * * *** != 0)
* * * * **
* ** ** ** ** * * = x1;
* ** * * ** * * * = 0;
* **** *** *** = -x1;
* * **** **** *** ***** * * %f * ******
***** ***
* * if(x1 - x2 != ******** * != 0)
********
* ** ** * ** * * = (y1 - y2)/(x1 - x2);
** * * *** ** * = y1 - (a * x1);
* * ********* * = -((a * x1) + c) / y1;
***** * ** * **** **** ** * * %f * * **** **
* * *
* * * *** if(x1 - x2 != * * ** == 0)
****
* * ******** ** ** * = x2;
* * * ****** ***** = 0;
* ** ** ***** * * = -x2;
* * * * ** * *** * *** * %f * *
* **
*** ** if(x1 - x2 == ** * == 0)
* **
** * * * * ** ** *** * * = 1;
* * * * * * * ***** = 0;
* ** * * *** * * * ***** * = 0;
** * * ******* ** * * * ****** * ** * %f *** ********

 }
* *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** **** * ** *


*** * *** * * ** * *


* ******* * ** * *


* * ***** * * *




*** * * ( * *

***** ** ****
* ** ***** *** ** * * ** **** ** ** *
= d -
= c - *
= f * b - a * e ;
* = 0 - *
* *** *
*
*** * * * * *** ***** = * - *



* * *** ** ** * * * * *** ** * ***
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
***** *** ** **** *


**
* * *** ** * ** ** * * ******* *** * * ** * t = 0, a, b, c, a1 , *


*** *** **** ** * * *** * *** ** * %f %f * *** ** * ** * * *** ** * * *****




**** * * * * * **** *** **** = * - * / * y2 - x2 * *
*** **** * * * ** * * ** = ** - / * y2 - * * ***
** * *** * * * * ** = - * - * *
* * * * * ** * ** * = a * - *
** ** ** * ** ** * = b * - *
* ** *** ** ** * *** * ********* * ** ** * * ** **


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** * * *** * *** **


* ***
* ** * ***** ****** **** ** * * ** t = 0, a, b, c, a1 , **


* * ** * ** * * * *** ****** ** %f %f * * * * * *** ** ** * *** * ***




** * ******* ** ** * = - * / * * y2 - x2 * ** *
**** * *** * * * **** * * * = * * - * / ** * y2 - * * *
* ** **** ** * * = - * * * - ** * *
* *** ** ** * ** * ** * = a / -
* ******** ** *** * = b / - *
** * ****** * * * **** **** * * ***** * ** * ** *


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * ** * ** ***


***
* * ** * ** ****** * * * * * t = 0, a, b, c, a1 ,


* ** * * * ** ********* * *** * %f %f * * ** ** * ** * **** ** ** * * *




* * * * ** ** = * - / ** * y2 - x2 * ***
* * *** ** = * - ** / * * y2 - * * ***
* * *** ** ** * ** = - * - ** * *
** ******* *** * * * ***** = a / - *
***** ** ** *** ** * = b / -
** **** ** ** * * * *** * * ** * * * ** * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* **** **** ***





int ** *

{
** * * ** *
* * * * ** * %f %f *** *** ** *** *** *** ** * * * *
** * ** * - x2 == 0,y1 != 0)
** **** * **
* * *** *** **** *** = x1;
* *** * ** * *** * * = 0;
*** **** ****** *** ** *** = -x1;
*** ** ******* * ** * * * *** %f * ** ****
* ** * * *
** * if(x1 - x2 != 0,y1 != 0)
* * * **
* ** **** ** **** * * = (y1 - y2)/(x1 - x2);
* **** *** *** **** = y1 - (a * x1);
* * * * *** ** = -((a * x1) + c) / y1;
* * * *** *** *** ** * ****** * %f * **
* *** *
******** if(y1 == 0)
*
**** * ***** ** ** = x2;
** ******* ***** * ** = 0;
* * * *** *** * *** * * = -x2;
** ** ** * * * **** *** * * %f * *** **
** **
** * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** ** *** * **


** *** ** *** *


*** *** * * *** *


** *** ** * *




*** ( *
*
* ** * *** * **
*** * ******* * * * * **** * *** *
* = d - *
* = c -
* = f * b - a * e ;
= 0 - *
* * **
*
* * * ** * **** * **** ** = - * *



* * * * * * ** *** * * **
** ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
**** ** * *** * **** x1,x2,y1,y2,m,a,b,c,c0;
* ****** ** *** * ** *** * ** ** *** *
* * **** * * ** * ** ** * *** **** * ** **
*** ** *** * * *** * **** ** ** *** ***** ****
* **** ** *** ** ** * ** * * ** *** *** *

    m = (y1-y2)/(x1-x2);
** *** * **** * ** ** ***** * *
* * * ** * * * ** * * ***
* ** **** ** * * * **** * ** * **
* * * **** * * *** **** ** * *
* ** * * * * *** * * * * ** *
* * * ***** * * ** ** *** ** ** * * * * * ** ** * ***** %f %f",m,-1.000000,c0);
*** ***** * * *** *** * if((y1-y2)%(x1-x2)!=0.000000)
**** *** *** * ** * **** * ** * * **** * * ** * ** * * *
* ** ** ** ** * ** * ** ** ** *** * * ** *
***** **** ** ******** ** ** *** * ** ** * ** * ** *** ** ****
*** *** * *** ** ** ***** *** ** * * ** * * * ** **** ** * ** * ** * * **
*** ** ** * * ** * * * ** ** ** * ***** * *** ******* ** ** ** ** ** * * * * *** * * ** * * **
** *** *** ** * * ****** * * * *


* * * ******** ****** ** * * ** ***


** *** * * * * * * ** * **** ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.43
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users