0 like 0 dislike
3.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.7k views

49 Answers

0 like 0 dislike
Hidden content!
**** ** ** ** * * * ***


* ** ***** * * * * *


******* ** * ***


***** ** * ** *




* * * ( *
**
*****
*** * *** *** * **** * ** ** * *** ** ***
* = d -
* = c - **
= f * b - a * e ;
* = 0 -
* *** ** *

* ** **** ** * * ** ** = - * * * *
*


* *** * * ** **
***
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** ** * *** **


* * *
*** * *** * * ** ** * * ** * t = 0, a, b, c, a1 , ** *


***** *** * * *** ** ** ** %f %f * ** ** * ** * ** * * *** **** * ** ***




** * *** * ******* * *** * = * - ** / * * y2 - x2 * **
*** *** *** * * ** * ** = - / * * * - * * *
*** * * * * **** = - * * * * - ** * *


* ***** * ** ******** ** ***** **** * * *


** * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** *** *** *





int main(void)

{
** ** * *
* *** * %f %f ** * **** **** ******** * * ***
*** ** * * * - x2 == **** **** * * != 0)
* * ** **** ***
* ** * *** * ** *** = x1;
****** ** * * * ***** ** = 0;
* ** * ** *** **** * * = -x1;
**** **** * *** ** *** **** *** ** %f ** ***** **
** ***** *
** * *** if(x1 - x2 != * * * * * != 0)
* *
** * * **** * * ** ** = (y1 - y2)/(x1 - x2);
**** ***** ** * * * * = y1 - (a * x1);
* * *** * * * **** = -((a * x1) + c) / y1;
******* * **** *** ** * *** ** * %f **** ***
*
* * ** if(x1 - x2 != ** * ** == 0)
* * *
** ** ** ****** = x2;
**** **** ** * ** * = 0;
* * *** *** * * *** = -x2;
****** *** * ** ******* **** ** ** %f * ** * *
* **
* * * * if(x1 - x2 == * ** *** == 0)
***
* * **** * * *** * ******* = 1;
* *** ** * * * ** * ** * * = 0;
** ** * ** ** ** ** *** = 0;
* * * *** * ** **** * * * %f *** * ** ** *

 }
****** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
****** * * *** *


* * ***** * **** *


* ** * *** *


** * * * ***




** * * ( *
**
**** *** *
** * ** ** * ** * * * * ** ** ** * **
* = d -
* = c -
= f * b - a * e ;
= 0 - *
* ** **

* * * *** * * * = - * * * *



** * ** * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * ** ** *** **


* * *
* * ** ** * * * ** ** * *** *** * ** * * ** t = 0, a, b, c, a1 , *


* * * * * *** *** * * * %f %f * * ** * *** * ****** * * *** **




* * ** ******* * * **** = * - ** / ** * y2 - x2 * *
* * ***** ** * * ***** = ** - ** / * y2 - * * **
*** * * * * * * *** * = - * * * * - ** * *
* * ** *** * ** = a * - *
* **** *** ** * **** = b * -
**** ** ***** *** * ** * * * ** ** * ** * ** **


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** *** * *


* **
* **** ** * ** *** *** * * * ** * * ** t = 0, a, b, c, a1 ,


* * * ** ** ** * * *** ** *** %f %f **** **** ** * ***** * * * * *** *




* * * ** * ** * * ** = - ** / * y2 - x2 *
* * * * * ** * ** = ** - / * * y2 - *
* * * *** ** * ** = - * * - ** * *
* ** ** ** * * * *** * = a / -
* ** * ** * * *** *** *** * = b / - *
***** * *** ***** * **** ** ** * * * * *


* *** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *** ****


* * *
** * ** * * * ** * * * * * ** * * t = 0, a, b, c, a1 , * *


*** * ****** ***** *** ** * ** * %f %f * * * ** ** ** * **** * *******




*** ** * * * * **** * ** = * - ** / * y2 - x2 *
*** * *** * ** * **** = * - ** / ** * y2 - * *
* ** * ** * ** **** * = - * * * - * *
*** * * * *** = a / -
** * * ***** * * **** = b / - *
** * * *** ** **** **** *** * * * ******* * * ** *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** *** * * ** * *





int *

{
* ** *** * *****
** **** * ** ** %f %f ** ** * * **** * * ** * * * ** *
*** *** *** - x2 == 0,y1 != 0)
** * * **
* ** *** ***** ***** = x1;
*** * * * ** ** = 0;
* * ** * ** = -x1;
**** * * ** * * **** **** * ** * %f ** * * *
* * ** * * *
** * if(x1 - x2 != 0,y1 != 0)
*** * *
* * * ** * * = (y1 - y2)/(x1 - x2);
* * ** * *** = y1 - (a * x1);
* ** *** ** * * * = -((a * x1) + c) / y1;
** ***** * *** * * ** * %f ** ** ** **
** **
* *** ** if(y1 == 0)
*** *
* * * * ** *** ****** ** ** * = x2;
*** * * ** * *** * * ** * ** * = 0;
* **** ** ** ** *** * = -x2;
* * ****** * ******* ** * ** ** %f * ** * ** *
**** **
* 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** **** ***


** * ** * ***


***** *** * *** * * ****


*** * * **** * ** *




* ** ( *

** ** * ** *
*** ** **** * * **** *** ** ** ** **** * *
* = d - *
* = c - **
* = f * b - a * e ;
* = 0 -
* * ** * *
**
* * ** **** ** ** * * *** = * - * * * * *



* * ** * ** * ** * *
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
**** ** * ****** ***** * * x1,x2,y1,y2,m,a,b,c,c0;
** * ** * * * * * ** * ** * * **
** * * *** ** * *** * ** ** * * ** ** *** *
* ** * ** * * * * * ****** **** * * * ** *** *
* ** * * ** ** * **** * * *** * * *

    m = (y1-y2)/(x1-x2);
** *** ** * ** * ****** *
* ** *** **** * * * * ** * *
** ** * * * *** * * *** ***
* * * ** ** * * ** * * *
** *** * ** ** ** * *** * * * * *** ***
*** ** * * ** * ***** * ** ** * ** * *** * *** %f %f",m,-1.000000,c0);
** ** * ** * * * ** * if((y1-y2)%(x1-x2)!=0.000000)
**** ** * * *** * *** * ** ******** * ** * *** * * * ** ****** *
**************** * * * * * *** * ** * ***
*** * * * ** *** ** * * ** * * * ** ** * * * ***** * ** *** **
* * * * *** *** * * ****** **** ** **** * * * ******* * ***** * * * * * *** * *
* * *** ** *** * * * *** *** *** ** * ** * ***** * * ******** ** *** * * * ** *
* * ** *** * * ******** ** * * *******


* ** ** *** * *** * * * **** ** **** **** ***


* * * ***** * * * ** ***** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.131
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.1k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users