0 like 0 dislike
2.3k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.3k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * * * * *** ** * *** ***** * * *
* ***** *** *** * * * *** * * * * *

    {
** *** * ** ** ** * * ** * ** *** *** ** * ********
* * *** * ***** ** ***** ** ** * * ** ** ***
* * ** * ** * * ** * **** ******* * *** ** * *** * ** *** ***** *****
** * * * * * * * * * * *** ** * ****** *** ** * *** *** ****** * * ** ***** ** * * * * ** ** = a[n] + b[n];
* * * *** ** * ** ** * * *** * * ***** * **** ** * ** *** ** * if(a[n]+b[n]>='10')
** * * * * * ** * * * * ***** ** * **** **** * ** ** ** *
* * * **** *** ** ** *** **** * ** * * ** * * * * * * * **** ** **** ** = a[n] + b[n] - '10';
* ** * ** * ** *** ** * * * **** * ** ** ** * *** **** ** * * ** ** **
*** ***** * *** ** * * * ** * * * ***** **** * * ** * ** * **
*** * ** *** ** ******* * * *** * * ** * ** *
* ** ** * * *** * * * ********* *** * * ***** if(t == 1)
*** ** * **** * * * * * ** *** ** *
** * * * * * * ** * * *** * * * * * ***** *** ** * * * * ** * ***
** * **** **** ****** ** *** * * * * **** * * ** * **** ** * * ** ** * ** * * * * * * * ** ** = a[n] + b[n] + '1';
* ** * * * *** ** * ** * **** *** ** *** ** * * ** * ** ***** if(a[n]+b[n]>='9')
* * * * ** * * * * * ****** ** * * * *** * * * * ** * ** * **
* ** ** ** *** * * * * ** * * * *** * **** * ** * * ** * ** ***** * **** * * *** * = a[n] + b[n] - '9';
** *** **** * * * * ** * ** **** ***** *** * ** ******** ******* * * * * **
* * ** *** * * ** ** ** *** * *** ***** * ** * *** * * **** * ** *
** ** * * ** * ****** * * ** * *

    }
** *** * ** *** *** ** ** *

    {
* ** ** ** ** ** * ****** * ** ** * **** * * * *** ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
*** * **** * * * ** *
* * * * * *** ***

int main ()

{

int ** *


* **** * * * *** ** * **
** ** **** * * *****


* ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** * **** **

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* ** * **** *** ** * a[100],b[100];
** * * *** * * *** sum[200];
* ** * *** *** * * *** * la,lb,lm,i,j,k;
* * * ** * ** *** ** *** ** * * %s",a,b);
*** * * ** * ** ** = strlen(a);
** * * *** * ***** *** = strlen(b);
*** ** ***** ** **** ***** * ***** *
*** * * * * ** ** * ** * * ** ** ******* * = a[i];
* * *** * * ** * ** * * * * *** * ** ** * * **** ** * *** * **
* * ** * * * *
*** * * **** * * **** *** * ** ** *** ** *
* ** * ** ** *** * ** * ** * *** ** * += b[i]-48;
* *** *** **** ** * * * * ** * * * ******* * *** *** * * * *
**** * * * * **** *
* ** ** *** ***** * = strlen(sum);
* * ** * * * ** *** ***** * ** **
** * ** * * * *** **** *** * ******* *** * * * * *
*** * * * *** * **
* *** * * ** * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* *** ******* **
*** ** * ** ** **





int main ()

{
* ** a , b ;
** * * * *** ** ** , *** **
** ** * ** , * * *
** * *** * *** ** ,a+b);
** ** ** * *** * * ** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
** * *** * ** * ***** ** * * ** * ** * **
** * * * **** * *********** ** * * * * *** * *

    {
* ** * * * **** ** ** ****** * * *** *
* **** *** * * * ***** ** ***** ** * *
* * ** *** *** ** ** ** * ******* * * ***** * **** *** ** ** **** * * **
* *** * ** **** ** * ****** **** * * * ** ** ** * ** ** *** ** * *** **** * ** ******** * * = a[n] + b[n];
****** ***** ** *** * ****** * ** * * * ****** * ** * ** ** ** ** ** if(a[n]+b[n]>=10)
** *** * * * * ** * * * * * ***** *** * * ** * * **
* ** * ** * ** * * ** ** ** * ** * * ** * ** * * *** ** * * * * ** * ** *** ** ** * * = a[n] + b[n] - 10;
** * ****** ** ** * ** * ** * * **** *** * ****** * * ** * ** ** ** *** ****
* * ** ** * * ** ** *** * * * *** ***** * * ** ** * * * *
** * * * * * **** * *** ** * *
***** ** ** ** * ** *** * ** ** ** *** * * * * if(t == 1)
* * ****** * * * ** ** * *** ***** *** *
*** * *** * * * * * * * * * * * * * ** ** ***** **** *** * ** * * *
* ** * *** *** * * ** **** * * * ** * * ** ** * ** **** * * * **** ** * ***** = a[n] + b[n] + 1;
* * * **** ** ***** ** * * ** * **** * ** ** * ** * ** * *** * ******* if(a[n]+b[n]>=9)
*** ** * ****** ***** * ** * *** * * * * * * ** *** **
* * ******** * ** ** ** * * *** * *** *** ** * *** * *** * * * * **** ** * ** *** = a[n] + b[n] - 9;
* * * * *** * ** **** * ** * ** *** ** * ** **** *** * * * ** ** *** *** ** *
* * * * ** **** * ***** * *** *** *** * * ** *** * *
* * ** * *** * ** **** * * *

    }
** ***** * **** * * ** *

    {
* ******* ** *** ** ** **** ** **** ** * * * * * * *** * **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* *** ** * * * data[2];
*** **** * * **** * * * ** sum;
** * ** * *** * * * i;
***** *** * ** * * * ** *
* *** ** **** * **
**** *** ***** * * ** *** *** ** ** * * ** ** ** * * * ** ** ** * *** * ** **
* ** *** ** * * ***
** ** * ** * * * * **** ** * ******
* ******** * * * * * * ** * ** * ***
* ** ******* **** **** *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ** * ***
** *
*** * ***** * *
** * * * ** ** *







int ** * **

{


** * * * int * * **
* ** ** * *

** * * * scanf ** ** ** ** **** ****
** * * ** *

* * * *** while (a[i]!= ' ')

{
* * ****

* * * ** * i++;
*** **** * *

** * * scanf **** * * * ** * ** * * ** ** * *

* ** **

}


* * ** ** * scanf * * ** ** *** * **


** while * * ** ** **** **** *
*** * * * * ****

* * **** {
** ** * * * *** * ****

* * ** * ** ** ** j++;
* *** * ******* ** * ** *

*** ** * * * * ** * scanf ** **** * ** * ** **** * * ***

* * * ** * **** ** ****

** * }
** **

}
* * ** * * *

* * ***** for (i = 0,j = 0;;i++)
** ** * ****

** * * *** * * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include ** * ** *

int main()

{
** ***** ** ** ** a,b,c;
** ** * ** * * *** * *** *** * ** **
** * ****** * ** = a + b;
*** * **** * * ** * ** ** * **** ** ** * *** * * ***
** * * * * * ** *** * ****** * *
** * ** * * ** ** * *
* *** ***** *** * * * * ** ** ** *
** **** * * ** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * * **** * * *

int * ** y=999999999;

int main()

{
* * * *** ** ** * ****** * *** *
****** * *** * ***
* * * *** ** * * ** * **** * * **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** **** **** ***** * *

int main(){
* * * * ** * *** *** * ** * a,b,c=0;
* * * * ** ***** *** ****** *** * * * * ** ** **
*** * * ** *** ** ****** ** * ******* ** **** **
** * * * ** ** ** *** *
* * *** *** * ** *** * * * * * * *
* *** * ** * ** * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.235
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users