0 like 0 dislike
3.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.2k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
***** * *** ** * * * ** * * ** ** ***
** * ** * ** * * * * ** * * ****

    {
** ** * * * * ** * ** * * * * **** * * ** ** *** * ** *
* * *** * ** *** * * * * * * * ** * * * * *
*** *** * ** * ** ** * * ** * **** * * * ** * ** * * * * ***** ** **** * * *
*** ** * **** ** ** ** * * **** ** ** * **** ** **** * *** ** * * **** * * ** = a[n] + b[n];
** * * * *** ******* * * * ** * **** ** * * ** * *** * * **** *** * if(a[n]+b[n]>='10')
* **** ** ** ***** *** * * * * * * * ** * * ** ******** **** *
** **** * * ** ** ** * *** * * * * * * ** * **** ** * * * * * ** ** *** ** *** = a[n] + b[n] - '10';
* * ****** *** * * **** *** **** * ** **** ** * **** *** **** *** * **** ** * **** **
** ****** * ***** * ** ** ** * *** ** * * *** ** * ** * * ** *** *****
*** **** * **** ** ** * * ** * * * * * ******
* ** ** *** *** **** ** *** * ** ** ***** **** if(t == 1)
*** **** * * * * * * ** ** *
**** * ** * *** * * *** * * * ** ***** * * ** * * ** **** * * * ** ****
* * * * ** **** ** **** * * * * * ** * * ** ** **** ** * * * *** * * * * **** ***** * * ** = a[n] + b[n] + '1';
* *** ** * * * * *** ** **** ** *** * **** * ** * *** * if(a[n]+b[n]>='9')
** ** ***** ** * * * ** * ** ** ** * ** * *** ******* ** *** ** **
* * * * * ** ** ***** * *** * *** * ** * ** ***** * * ***** ** *** * ** * *** ** = a[n] + b[n] - '9';
* * ** * * * * * ** * * * * * *** ** ** * ** * * ** * * ** ** * **** ** ***** ***** * * **
** ** ** ******* *** * ******* * ** * * ** ** ** * *** * ** ** **
* * * * * * * * * **** * * * *******

    }
** * * *** * ** ***** ***** **

    {
* ** *** * * ********* ** * ** * **** *** * * * * ** * **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* ** * * * **
** **** *******

int main ()

{

int * **


*** * * ** ** *** * ** * * *
* * **** ** * **


* 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ** *** ** *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
*** * * ***** * *** a[100],b[100];
** **** * *** * *** ******* *** sum[200];
** * * **** * *** * la,lb,lm,i,j,k;
* * * * ** * *** * * ** * ** *** * %s",a,b);
*** * ** ** * * ** * * * = strlen(a);
*** * ** **** *** = strlen(b);
* *** * *** *** * * * ***** * *
* * ** ****** ** * ** ****** * ** ** * * = a[i];
**** * * ** *** * * * * * * ** ** * **** ***** * * * *** *** **
* *** * *** *** * * *
* * ** * *** ******** * *** ** * * *
*** * *** ***** * * *** * * ******* ** * += b[i]-48;
* ** ** * ***** * **** ** ** ***** * * * * * ** * * * * *
* * * ** ********* ** ***
*** * *** * ** * = strlen(sum);
** *** * * ** * * * * * **** * * ** **
* * *** **** ****** * ** * *** ** * * ** ** * ******* *****
** * *** * * *** ****
*** * ** **** * *** * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * * * **
** **** * **** **** * *





int main ()

{
* * a , b ;
** *** * **** , ** *
* ** * * *** * * , ***** *
* * **** * ** **** ,a+b);
* * ******** * ** * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * ** **** *** * * ****** *** ****
* ** *** * * * * * * * *

    {
*** ** * **** ** *** * * * ** * * * ****
***** **** * *** * ** * *** ***** * ** * *
** * ******** * **** * * ** * * * * * **** ******* * ** *** * **** *
* ** * ***** *** * *** ** * *** * * * ** * ** * **** * **** * * * * ** * * = a[n] + b[n];
*** **** ** * *** * ** ** * ** *** ** ** * ** *** * ****** if(a[n]+b[n]>=10)
* * *** **** ***** * * * **** ** * * ***** **** ** ** * * * *
* *** * *** ** ****** ** * ** * ** * *** * ** ** * * ** ** ** * **** * ** = a[n] + b[n] - 10;
** **** ** *** *** * ** * ** * ***** *** *** * * ** * * * * * * *** * *
* ** ** ***** ** **** * **** * ** * *** ** ** * * ** ** ** * *
**** * * ** ** **** * * ** * ***** * ** * ** * **
* * ** * * ** ***** * *** **** *** ***** ** ** * if(t == 1)
* ** * ***** *** ** ***** * * * * * ** * ***
**** ** * * * *** *** * * ** * ** *** ***** ****** ** * * ** *** ******** *
** * * *** * * * ** * ***** ** * ** * * * ** * ****** ** * *** * * ** ** = a[n] + b[n] + 1;
* * ** * ** ** * * ******* * * * * ** *** * * ** ** if(a[n]+b[n]>=9)
* ** * * * * ** * **** * ** * * ** * * *** ** * ****
* * * **** **** * ** * ** * * * ****** ** * ***** ** * * * * * * ** *** ** * * * * * ** **** = a[n] + b[n] - 9;
** * * ***** * *** * ** * **** * **** ** *** ** * ** * * * *** * * * * ** ** **
**** * * * * ***** **** * ** * * * * ** * * ** ** * ** **
* ***** ** ** * ** *** * *** * * ** ***

    }
* ** * *** * *** ** ** ***

    {
** ** ** * * * * * * ** ** * * * * ** ** * *** *** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* * * ** ** ** * data[2];
* ** * ** * ********* * ** sum;
* **** * * ** * ** ***** i;
* * * * * *** * * ** * ** ***** ** * * *
* * * * ** * * ****
******* * * ***** * ** **** ** * ** ** * *** * ** * ** * *** **
* * *** ** ** **** * * ** *
** * * **** ***** * * *** * ****** * **
* * * * *** ***** * * * ** **
** * ******** *** * * ***

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * *** *
** * * *** *
* * * * *
* ** **** ** * *







int ****

{


* * ** int * ** * *
* * **

* *** ** ** scanf * * * * ** ** * *
** * * ** *

*** * ** while (a[i]!= ' ')

{
* *** ****

** * * ** ** i++;
* * * * *

* **** ** scanf * ** * **** * ** * ** ** * * * *

* * *

}


** * * * * * scanf * * ** ** *** **** **** * *


**** ** ** while * * * **** * * ** * *
** * * * * *

* * ** * {
* * * * ** * **

* * * * *** * * *** j++;
** * *** * ** ** *

* * ***** ** * * **** scanf ** * * * ** ***** * * ***

* * * * *** * * *

* * *** }
* * ****

}
* *

* ** * * * for (i = 0,j = 0;;i++)
****** ** *

* * * ** ** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include ** * * * **

int main()

{
* * * **** ** a,b,c;
*** * ** * ** * *** ** ** *** * * * * * *
****** *** * * = a + b;
** ** * ***** **** **** ** ******* * * * ** ***** * ** *
** ** * * * ** *** ** * * ** *** * *
** * *** * * **
* ** * ******* * ** ** * *** * * * *** *
******* * ** * *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include *** *** *** *

int * * * y=999999999;

int main()

{
*** * * * * ** * *
*** ** ** * * ***
** *** *** * *** ** * ************

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * * *** * * **

int main(){
**** ****** ** ** ******* * a,b,c=0;
* * * *** * * * **** * ** **** ** * * ** * ** *
**** * *** * ** **** *** ** * ** *** ******
*** **** * ** *** ** ***
* * * ** * * ***** * ** ** ***** ** ****
* ***** ** * *** ** * ** * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.44
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.2k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users