0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
* * **** * * *** *


* ** * * *****


* * * * * *


*** ** * * ***




** ( ** *
*
* * ** *
*** * ** * * * * * ** ** *** * * ** * *
** = d - *
* = c - *
= f * b - a * e ;
= 0 - **
*** ****** *
*
* ** * * ** ** * * * * = - * * ** *



* * * * * * ** *
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * * * ***


* * * *
* * ** *** * ** * * * ** * * * t = 0, a, b, c, a1 , * **


**** * * ** ****** * * *** * ** %f %f *** * ** * * ** ** ** *****




* *** * *** * ** *** * = ** - * / * y2 - x2 * *
** * *** ****** * ****** * = ** - * / * * - * ***
*** * * ***** *** *** = - * - *


* ** * * *** * * **** *** ** * * **** *


***

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * *** ** *





int main(void)

{
* ** * ** * * * *
* *** ** * %f %f * * ***** ** ****** ***** ** *
* ** ** ** - x2 == ** * *** ** != 0)
** * * **
** * ** ** * * *** *** * = x1;
* *** ** ** * ***** = 0;
* * ** ** **** * * = -x1;
** ** * ** * **** * ** ** * ** %f * ** ** *
* ** ***
** ** ** * if(x1 - x2 != * ** *** != 0)
******
**** * *** ** * * = (y1 - y2)/(x1 - x2);
* * ***** * * = y1 - (a * x1);
** *** * * *** * * = -((a * x1) + c) / y1;
*** * ** **** **** * %f * * ** *
*** * *
* * ** * if(x1 - x2 != * *** ******* * == 0)
***
** *** * ** * = x2;
**** * * * = 0;
*** * **** *** *** * *** * = -x2;
* *** ****** *** ******* ****** * * %f * ** * *
* ****
* * if(x1 - x2 == ******* *** == 0)
* *
*** **** * * * ********* = 1;
** **** ** * ** * = 0;
*** * * ** *** = 0;
* * ****** *** * ** *** * ** ** * %f ** * *** *

 }
*** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** * *** ** **


* * *** ** * **


* * * * ***** ****


* ** * ****** ** **




* ( **

* ** *
***** * ** ** * * ***** *** ** *
* = d -
= c - *
= f * b - a * e ;
* = 0 - *
* *
**
** * * * * * * ** * = - * * * * * * *



**** * * * *** **
* ***
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * ***** ****


* *** * *
* * * * ** *** ** **** ** * * * ** ** t = 0, a, b, c, a1 , **


** **** * ********** * ******* * %f %f * ** ** ** * **** * * **




* ** ** ** * * * = * - * * / ** * y2 - x2 * *
*** * ********** * ** * * = - / ** * y2 - * * **
* * ****** * ** ** * = - * * * - * * *
*** ** ** * ** **** * = a * - *
** ** *** ** * ** * ** = b * - *
* ** **** ** *** ** ******* *** *** * ** * * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * **


** *
* * * * **** * * ** * * * ** t = 0, a, b, c, a1 ,


** **** * **** **** * ** * **** *** %f %f * ** * ******** * * *** * ***** ** * *




** ** *** ** ** ** ** = * - / * y2 - x2 *
*** **** ** * * * * *** *** = *** - * / ** * y2 - * * * *
* * * * ** * * * * * * = - * * - * *
* ** * * *** * *** = a / -
** ** * *** * * = b / - *
* ** ** ***** *** ** ** * ***** **** ** *** ** * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** ** * ** **


** * *
* * *** *** ** * ** **** ***** * ** *** * t = 0, a, b, c, a1 ,


* *** * ******* * * ** *** **** * %f %f * ***** *** * * * * * **** *




**** *** * * * ** * * *** = ** - ** / * y2 - x2 * *
* ** ** ********* * ** = - * / * * y2 - * *
* ** ** * * **** ** = - * - ** * *
* * * ** ** * ** * * = a / -
* * *** ** * * **** * * = b / - *
** *** **** * ** * **** * * * * * * * *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * * * **** * *





int * **

{
** ** **** * *** ***
** * ** ****** %f %f * * *** ** * ** ** * ****** **** *
*** * * - x2 == 0,y1 != 0)
* * * *** * *
* * * *** * * * ***** = x1;
* * * ***** *** ** ** = 0;
* **** * ** ****** ** * ** = -x1;
** ****** ****** * **** * * **** %f * * * * *
** * * *** ** *
* * **** if(x1 - x2 != 0,y1 != 0)
** ***
* ************* ** * = (y1 - y2)/(x1 - x2);
**** *** * * ** = y1 - (a * x1);
** ***** ** = -((a * x1) + c) / y1;
** ** ** ** ** * *** * * * %f *** *** **** *
*** *
* ** ** * if(y1 == 0)
** * *
***** ****** ** * * = x2;
*** ** * ** *** * = 0;
** * * * * ***** = -x2;
** * ** * ** * * * * *** *** * %f * ** * * *
* * *
* *** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * ** **** * *** *


* ***** ** **


* * * * **


*** ** * ***** **




* ( *

** * * ** * *
* * * ****** * * *** * * *** ** * ** *
* = d - **
* = c -
* = f * b - a * e ;
* = 0 - *
* * ** *
*
* * * **** * * * *** ** = * - * * * * * * *
*


** ** **** ** * *** * *** *
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** ** *** * * * * * * x1,x2,y1,y2,m,a,b,c,c0;
** * * ** * ** ** * * ** **** ****
** * * * ** ** *** *** ** *** *** ****** *** **
* ******* * * * ** * ******* ** ** ***
** *** * ***** * *** *** ***** * * * ***

    m = (y1-y2)/(x1-x2);
* *** * * *** * * * ** ** **** *
* ** * * * * * * *
* * ** * * * * * ***
* * ** * *** * * * *
****** * * ** * ** * * **** * * *** * *
* * *** ** ** ** * * * * ** ** ** * ******* * ** * %f %f",m,-1.000000,c0);
* * ** * * * *** ** if((y1-y2)%(x1-x2)!=0.000000)
* ** **** * ** ** ****** * * * * *** *******
* * ** ** ** * **** ** **** ******** **
* *** * * * ** ****** **** *** **** * * * * * *** **** ** * **
* * ** * ** * ** ** * * * *** ***** * * ****** ***** *** * * ****** ** **** ** *
* * * * ** *** * ****** * * ** ** ** ** ** * * * * * * *** *** *** ***
**** * *** * *** ** ** *** * ***** * **** * *


* ** ** ***** * * *** * * ** *** *


* * * * **** *** * ** * ****** ***** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.12
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users