0 like 0 dislike
7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7k views

49 Answers

0 like 0 dislike
Hidden content!
* **** **** ******


** *** *** * ** *


* ******* * * * *


* ** * **** * * *




* ( *
*
* ** * *
* ** ** ** *** ** * ***** * ** * * * * *
= d -
= c -
= f * b - a * e ;
** = 0 - *
** * *

* * ** *** ** ***** **** = - * * * *
*


** * * *** * * **
* **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * ** ** * ***** * *


* ** *
***** * *** * * * *** ****** * ** ** * * * t = 0, a, b, c, a1 , **


** * * * * * ****** * **** ** *** %f %f * * ** * * * **** * * *******




* **** **** ***** ** = * - ** / * y2 - x2 * *
* *** ** * * * ***** = - * / ** * * - *
* * ** ***** ** ** * = - * * - *


* ** ** ***** * *********** * **** * ** ** * * * * **


** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ** ** * * *** *





int main(void)

{
* * *** ** *
*** * * ** %f %f ** * ** *** * *** * * * *
* * - x2 == * * * ** *** != 0)
** ** * **
** * * *** ** ** ** = x1;
* ** * **** ** * *** = 0;
** * * **** * * * ** = -x1;
* * **** ********** ** * * * * %f * * * *** *
* *** ** **
** ** * * if(x1 - x2 != ** * * * * != 0)
** * * **
* * ***** * = (y1 - y2)/(x1 - x2);
*** * * ******* * = y1 - (a * x1);
* * * * * ** * = -((a * x1) + c) / y1;
*** ** ** * * * ** * %f *** ** ** **
*** **
* ** * if(x1 - x2 != * * * ** == 0)
*** *
* * * * *** ** = x2;
* * * ** * * = 0;
* * * * ***** ** ** ******* = -x2;
** * *** * ** * * **** * ***** * * %f ** * *
**
* ***** if(x1 - x2 == * ** * == 0)
********
* ** * * *** ** = 1;
** * * * * * *** *** = 0;
* *** * * * *** ** * ** = 0;
*** **** *** *** * * * * **** ** * %f * ** * * * *

 }
* * *** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** * ** * **


* **** ** * * *


** **** * ** **


* * * ** *




* * ( *
*
* * ****
** * ** * * * ** ** ** * ** * * ***** * *
* = d - **
* = c -
** = f * b - a * e ;
= 0 -
* ** *

* ** * * *** **** = - * * * ** *
*


* ** * **** ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * ** * **


** * *
*** * ** *** ** ** * ** ** ** * ** t = 0, a, b, c, a1 ,


* * * * *** * ** * *** * *** * * %f %f * * ** * *** * * * * ***




* * * * *** ******* ** * = * - * / * * y2 - x2 * *
* **** ******* = - * * / * y2 - * * *
** *** * ** ** ** = - * * * - ** *
*** ** ** * * * * ** = a * -
*** ** * * = b * -
*** * ***** * * * *** * * * ** * **** ****** ** ** *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
********* * ** * *


* *
* ***** * * ***** * * ** * t = 0, a, b, c, a1 , *


* * ** *** * ****** * * * %f %f * *** * ** * * * **** ** ** * *** **




** * * * * ** **** * * = - / * * y2 - x2 * *
* ** * * *** ** * *** = - ** / *** * y2 - *
**** **** ** * * *** = - * - * *
* ** ** *** * ** * * ** * * = a / -
* ** ****** ***** ** * * = b / - *
** ** ** ** ** * ** ** * * * * **** * *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** *** ** *


* *
* * * *** ** ** ** ** * * ** * t = 0, a, b, c, a1 , *


* * ** * ** * *** ** ***** * %f %f * *** ** * *** ** ** * * * *** * ***




*** * ***** * ** * ** = * - / *** * y2 - x2 * *
**** *** **** * * = * * - * / * * y2 - * * ***
** ***** * * * * * = - * * - ** * *
******* ***** ** * = a / - *
* ******* ******** ** * = b / - *
* ** *** *** * ** ** ** * * ***** *** * ** ** ***


**** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** *** * *





int * **

{
* * * ** * ****
* **** * %f %f ****** * * ** * ****** *** * *
** **** ** - x2 == 0,y1 != 0)
** ****** *
* * ** * ** ** * * *** = x1;
* *** * * ***** * * = 0;
** ** * * ** *** * ** ** = -x1;
** *** *** * * ** *** * * ** %f ***** ***
** * ** *
** **** if(x1 - x2 != 0,y1 != 0)
** * *
* ** * * ** * ** *** * = (y1 - y2)/(x1 - x2);
** *** * * = y1 - (a * x1);
** * * * ** * = -((a * x1) + c) / y1;
** ** * *** * * * * %f * * *** ***
** * *
* ** ** if(y1 == 0)
*
*** *** *** ** ** * *** = x2;
* **** ** * ** *** = 0;
** * *** ****** * * *** ** = -x2;
** * **** ***** * ** ** * ** %f *** * * *
*
* ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ****** * * * *


* ***** **** **


* *** * *** *****


* ** ***** **** *




** (
*
* *** * * *** *
**** *** **** * ** * ** * * ** * * ** * *
* = d - **
** = c -
* = f * b - a * e ;
* = 0 - *
* * *** **
*
* * * ** * * * *** ** = - ** * * * * *



* *** * * ** ****
**** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
***** ** * ***** * * * * x1,x2,y1,y2,m,a,b,c,c0;
* * ***** ** * ******** * ** * * * * *** ** *
*** * * * ** *** * *** * *** * * * * * * ** * *
*** * **** *** ** * * * ** *** * * * **
* * ** **** * * * * * *** * ***** * * * *

    m = (y1-y2)/(x1-x2);
* **** * * ** ** * * ** ******
* ******* * ** **** * ** *
*** * **** ** * *****
* *** ****** ** * ** * ***
***** ***** ** * *** * * * *** ** * *
**** *** * * ** *** ** * * * * *** * ** * ** * ** * ** * %f %f",m,-1.000000,c0);
** * *** * * *** * if((y1-y2)%(x1-x2)!=0.000000)
* ** * *** * * **** ** *** *** ** *** * **** * ***
*** * * ** ** ** * *** ** ***** * ** **** * * *
* *** * *** **** ** ** *** ** * * * ** * * *** * **** ** ****
* ** ***** *** *** * ** * ** * *** * * * ******* ** * ** ** * * *
**** * ** ** ** ** * ***** * ** ** *** * ***** * * * ** ** * ** * ** * ** * ***
** * * * * * ** ** * ***** **** ** ** * * **


***** * * ***** * * *** * * ** *** *


**** * ** *********** * ** *** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users