0 like 0 dislike
2.3k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.3k views

49 Answers

0 like 0 dislike
Hidden content!
**** * * * ** **


* * * * **** ****


* * **** **********


*** ** * * ** *




* * * * ( *
*
* **** *
**** ** ***** **** * * ** ***** * * *** * *
= d - **
= c - *
* = f * b - a * e ;
* = 0 -
** * * **
*
* * *** ** * * * * *** = * - * * * * *



* **** ** ** *** *** * *
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * * **


* *
* ** *** * * * * * ** * * * ** t = 0, a, b, c, a1 , *


** ** * * * * ****** ** * *** ** %f %f * * * *** ** * * * *** *** * * ** *




* ***** *** ** * * * * = - * / * y2 - x2 * *
* *** **** ** * * *** = * * - ** / * - ** * **
* ** ******* * ** * = - * * * - * *


* ***** *** * ** ***** * * * *** * * **** * * * * *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * * * ***





int main(void)

{
**** ** ** * *
*** *** * * * * %f %f **** ** ** * * * * ***** *** *
* ** * ** - x2 == * * ** * * != 0)
* * * **
* * *** **** **** **** * * = x1;
****** *** ***** * * = 0;
* * ****** ** * * ** *** = -x1;
* **** *** ***** * ***** * **** %f **** ** ** *
* * * *
* ** if(x1 - x2 != * *** ** * != 0)
*** *
** *** ** * * = (y1 - y2)/(x1 - x2);
** *** *** = y1 - (a * x1);
* ** * * ** ** ** **** = -((a * x1) + c) / y1;
* * ** * *** * * ** *** %f ***** * **
* *
** * **** if(x1 - x2 != * **** *** == 0)
* ** *
* **** ** ***** ***** * * = x2;
*** **** * ** ** = 0;
** * ************ ** * ** = -x2;
**** * * * * ** ** * ** * * * * * %f * * ***
** * ***
** *** if(x1 - x2 == **** ** ** == 0)
** * **
** *** *** ** ** * ** ** * = 1;
* ** ** ** = 0;
*** * * ***** *** ** *** = 0;
* ** *** * *** * * * ** %f ** ** * *

 }
* ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * ****** *** * *


** * * * * **** ** **


* *** *** * *


* * * * * * ****




* * * ( ** *

* * * * **
** ** * * * * ** ** ** *** *** ***** ** ** ***
= d -
= c -
** = f * b - a * e ;
= 0 - *
**** * **
*
*** * **** ** *** = * - * * * **
*


** ** * ** * * * * * **
* * * **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* *** *** *


* * ****
* *** * *** *** ** ** * * * t = 0, a, b, c, a1 , *


* * **** * * * ******* ** %f %f * ** * *** * * *** * * * * ** * **




* * ** * ** ** * * ** = * - ** / ** * y2 - x2 *
* *** * * *** * **** = - ** / ** * y2 - * * *
** **** * *********** *** = - * * - ** *
****** * ** ** *** ** * = a * - **
*** * ** * ** * = b * - *
** * * * ** ** * * *** ******* * * * ** *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *** * *** **** *


* *
* *** * * ** * ** * * * * ** * t = 0, a, b, c, a1 , *


* * ***** ***** *** * * ** ****** * %f %f * ** ** ** *** * ** *** ** ** * **




* ** *** * * * * * * = - / * y2 - x2 * *
** ** * *********** = - ** / * y2 - * ***
* * * *** ** = - * * - * **
****** ** ** *** * * = a / -
* **** * * ***** * *** = b / -
* * * * ** * * ** ** ***** * *** ** * ** * ** * **


0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ******* * *** *


* * ***
* * ** * * ** **** ** * * * *** * ** * * * t = 0, a, b, c, a1 , *


** ** * ***** * * * * * * * * ** %f %f * * * *** * * *** * *




* ** * * *** **** * = ** - * / * * y2 - x2 * ** *
*** * ****** **** *** * = - * / * y2 - * * *
***** * ** * ** **** * = - * * * - * *
* * ** ** **** ** * ** = a / - **
* * * *** ** * * * = b / - *
** ** ** * * *** *** ** ********* * * ** * ** * **


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *** * * ** * ** *





int ** ** **

{
*** * * * ******* *
** *** * * %f %f ** ** * * * * * * * * * ***
******* ** - x2 == 0,y1 != 0)
******** *
**** ** ** ***** * * * = x1;
* * ** **** * **** = 0;
*** **** * * * * * = -x1;
** * ** ** * ** *** ** ***** %f ** ** *
* * * ****
*** * * ** if(x1 - x2 != 0,y1 != 0)
**
* *** * * * * *** = (y1 - y2)/(x1 - x2);
* * **** * * = y1 - (a * x1);
** * ****** *** ** * = -((a * x1) + c) / y1;
** ****** * ***** * ** * * %f *** ***
* *
* *** *** if(y1 == 0)
**** ** *
***** ***** *** * *** ** = x2;
** * * * ** *** ** * ***** * * = 0;
** ** ** * *** * * * * = -x2;
* * *** ** ****** ** ** ** ** * %f * ** *****
* * *
** * ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
*** *** * *


** **** * ** **


** ** ** ** * *


* * ** *** * *




** * ( *
*
* * * * * *
* * * * * * * * ****** ****** *** **
= d -
= c - **
* = f * b - a * e ;
= 0 -
** ** *
*
*** * * * * * = * - *



* * ** * * ******* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
* *** * * * ****** * x1,x2,y1,y2,m,a,b,c,c0;
** * ** * *** * *** * *** ** ** ****
**** * *** * *** ** ** ** ** * *** *
* ** * ** *** * ** * *** * * **
*** * * ** ** * ** ** *** ** * *** *** *

    m = (y1-y2)/(x1-x2);
* **** ** * *** * * * *****
** * *** * **** * ** * *
** * ******* * * * ** ** ** *
****** ** **** ** ** ** *** ***** **
* *** ** **** * * * ** * ***** * ** * *
*** *** * ** ** * * * * * ** **** ****** * * * * %f %f",m,-1.000000,c0);
* *** * * **** * * ** * if((y1-y2)%(x1-x2)!=0.000000)
** * ** * ****** * * * ** ** * ** * ** * *
* ** * *** * **** *** * * * * *** * * *
**** ***** * * *** * * *** * * *** **** *** ** * *** * * * * *** * ** * * **
* *** * *** * * * ** ** ** * * ******* * **** ****** * ***** **
* **** ** *** **** * * * ***** * ** * ** ** ** ** ** ** * ** * ** ** **
** ** * * **** *** * *** * ******* ***


* * ** * * *** * ** * * *****


* * **** *** * *** * * * ** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.240
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users