0 like 0 dislike
6.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.9k views

49 Answers

0 like 0 dislike
Hidden content!
* * * **** * *** **


* * * ** * **** *


** * ** * * ***


** ** * * **** * *




* * ( ****
*
* ** ***
*** * * * * * ** ** *** ** *** ** ** **** * *
* = d -
* = c - **
* = f * b - a * e ;
= 0 - **
* * * * * **

** * *** * * * **** * = -
*


*** * * * *** *
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ** * ****


** *** *
* ** * ** *** * * * *** ** *** ** * ** * * t = 0, a, b, c, a1 , * **


*** ** **** * ****** ** **** *** %f %f * * ** * * ** * ** *** * ** * * * *




* * **** **** * * ****** = - * / * * y2 - x2 * *
** * * * * *** ****** = - * / *** * - * * *
** ** ** * ** ** ** * = - * * * - * * *


* * * * *** ** *** ** ***** * ** * * * * * *


*** **

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** *** * ** **





int main(void)

{
** * * * ** * ***
* * ** ** ** %f %f * ** ** ** * * *** * ** ***
** **** - x2 == * *** * * *** != 0)
**** **** * *
* *** * *** * ***** = x1;
***** * ***** * * ** * * = 0;
* ******* * *** *** * * = -x1;
** * * ** * ** * * * %f * * * *
* *** ****
********* if(x1 - x2 != ***** * *** != 0)
*
* * * **** ** = (y1 - y2)/(x1 - x2);
** * * *** ** = y1 - (a * x1);
*** ** * * * * = -((a * x1) + c) / y1;
**** ** ** ** *** *** * %f * **** * *
**
* * ****** if(x1 - x2 != * ** * * == 0)
**** *
** *** * **** ** * * * = x2;
****** ***** ** *** * = 0;
** ** ******* **** = -x2;
* **** * ** * *** * * * * * * %f * * * *
* * ****
* ** * if(x1 - x2 == * * *** == 0)
* *****
*** *** ** * * = 1;
***** * ** ******* = 0;
** ** ** *** * * * = 0;
* **** * * * **** * * * * * **** * %f * * ***** * *

 }
* ** * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * * *


*** ** **** ** * **


**** ** * ***


** * ** *** ** *****




* * * (
**
****** *
**** ***** * ** * ** * *** *** **** * * * * **
* = d -
* = c -
* = f * b - a * e ;
* = 0 -
* * * *
*
* * * *** ** * **** **** ** = * - ** * ** *



** ** **** * **
*** * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
** *** *** *** *** *


** * ***
** * **** **** *** *** *** ** * * ** t = 0, a, b, c, a1 , **


* * ** ** * *** * **** ******* %f %f * ***** * ** ** * * **** * * ***




** ** * ** * = * - * / * y2 - x2 * *
* * * ** * * = ** - * / * y2 - * **
* * * *** *** * = - * - * * ***
*** **** * ** * * * = a * -
* ** * *** * ** ** = b * - **
*** ******** ****** ***** ** * ** ****** * * * * * *


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
****** * *


*** *
* ****** ** ***** ** ** *** * * * t = 0, a, b, c, a1 , *


** * * * * *** * * * * * * ** ** %f %f * *** * * * ** ** * * * * * ***




* ** **** **** *** = - * / ** * y2 - x2 * *
*** ** ** *** ** ** * = * - * / * * y2 - * * *
** *** * * ** ** * ** * = - * * - * * **
* ****** ****** *** * * = a / -
*** *** ** ** ** **** = b / -
** *** ****** ** * ************** * ** *** *** *** * *


** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
****** ** * *


* **
* ***** * * *** * * * ** * t = 0, a, b, c, a1 , *


**** **** ** ** ******* ****** * * %f %f * * *** *** * * *** * * ** * *




* ** * ***** * * = * - * / ** * y2 - x2 * **
******** *** * *** ***** = * - * / *** * y2 - * *
* ***** * ******* * * * * = - * * - * *
* * * **** * * * ** * = a / - *
* * * * * * * * = b / -
*** * ****** * * * ** **** * ** * **


* * 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** **** ** *****





int * ****

{
* * * * * * *
* * * **** ** %f %f ** * *** * ** ** * * * * *
* * **** * - x2 == 0,y1 != 0)
*** * * * * *
**** ** * ** * ** = x1;
* * **** ** ***** ***** = 0;
* * * **** **** * ** = -x1;
** * * * ******** ** * * *** ** **** %f *** **
* *** * ** * * **
** * * * * if(x1 - x2 != 0,y1 != 0)
**
** ***** ****** ***** = (y1 - y2)/(x1 - x2);
** * *** * *** = y1 - (a * x1);
* ** **** ** * * * = -((a * x1) + c) / y1;
** * ** ** * * * **** * ** ** %f *** * *
* * *
*** * * * if(y1 == 0)
*****
** * * *** ** = x2;
*** *** **** * * *** *** * = 0;
*** ** ****** ** ** *** ** * = -x2;
* ** * ** **** * * ** **** ********* * %f * * * **
*****
* ** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
******* ** *


* * ** * *** **


** ** * ** * * *


* * *** **




* * * ( * *

** *
* * * ** * **** * * ** *** ** ***
= d -
= c -
= f * b - a * e ;
** = 0 - *
***
*
** ** **** * *** ** * ** * = - * * * *



* ** * **** * * * ****
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
******** * * *** * **** * x1,x2,y1,y2,m,a,b,c,c0;
* * ** ** *** * **** * * **** * ****
* ** *** ** * **** ***** ** **** **
********* ** ** ** * *** ** *** * ** * * **
* * ** * ** * **** ******* * * * * *

    m = (y1-y2)/(x1-x2);
*** ****** * ** * * ******* ** * * * *
** ** ** * ** ***** * *
* **** * * ****** ** *
** * *** *** ********* * ***
******* * ** * ****** ** ** * *
* *** *** * ** * ** * ** *** * *** **** * *** * * ** %f %f",m,-1.000000,c0);
* *** ** * * ** *** * * if((y1-y2)%(x1-x2)!=0.000000)
* ***** *** *** * ** * *** *** ** *** * ** * * ** ** ** ** *
** * * * ** * ** * * * *** ***** * * * ** * *
** * **** * * * ***** * * * * ** ** * * *** * *** ** * ** ** * ** ****
* *** *** ** **** ** * *** * * * * * ** ** * **** * * * ** * * ** * * **
** *** * **** *** * * ** * **** ** ***** *** * * **** ******** **** ** ** ** * * ** ** *** ** *
** * * * ** * ** ** * *** ** ** ***


* **** * * * ** * ** * ** * * ***


* * **** ** ** ******** * *** * %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.6k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users