0 like 0 dislike
6.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.2k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* *** ** ** * ** ** ** * *** ** * * *
* ** * ** ** **** * * *** * *
*** ***** ** **** *** * ***** ** ** ** * * * *
* ***** * * *** * * * *** **** * * ** **** * ** *
*** ***** * ** * ** **** * ** **** ** * *


* *** * * * * * *** * * (a-c!=0)
* **** * **** *****
* ** ** ** * * * * * ***** * *
* * * *** * * * * * * * * **
*** ** * ** *** ** * ****** * ** * * *
* * ** ** ** * * * * * **** * *
* ****** *** ***** **** * * (a-c==0)
* ******* *** * * *
*** * *** *** * **** ** ** ** *** ** ** *** * **
*** *** ** * * * *** ** *********** * *
* *** ** ** * *** * **** * * *** * ** * *
* *** * * * * * * *** * * * * *
* * *** * ** ("%.6f ",e);
* * * ** *** ** *** ("%.6f ",g);
** * ** * ** * * * *** ("%.6f",f);






** ** ** *** ******* *** * * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* **** * ** ***




*

{
* ** * * * *
** *** * **** ** %f %f ****** * ***** * ** * ** ******
**** ** - x2 == 0)
* ** * *
**** * ** ** * * * = x1;
* ** * * * ** * *** = 0;
*** * ** ** * **** * = -x1;
* * ** **** ** ** ******* * * %f * ** ** **
* ** ** * *** *
* * if(x1 - x2 != 0,y1 != 0)
** ***
** * * **** * **** * = (y1 - * ** * - x2);
** ****** * ** = y1 - (a * x1);
* * * * * * = -((a * x1) + c) / y1;
* ** ** ***** * *** %f ** *** *** *
* ** **
** *** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** *******

int main (void)

{
* *** * *** * ** * ****** * x1,y1,x2,y2;


* * *** ** ** *** *** a,b,c;


** * **** * * * * **** %f *** * * * *** * * * ** ** *
** * **** * *** ** *** ***** ***
** * *** *** * *** ******* * * * **
* ** ** ** * * * ** * * * *****




** * * *** * ** *** **** ** * * %6f %6f",a,b,1);
** ** * * * **** ** * ** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** * ****
*** * **** **

#include<math.h>



int main()

{
* ** * * ** *** * ** x1,x2,y1,y2,m,a,c0;
* * ** ** ** ** ****** * * * **** * *** **** ** * * *
* ** ** *** * * * * * * * ** *** * ***
** *** * * ** *** * ** ** *** * * * *
***** * * ** * * * **** *** * ** * * **
* ***** * ** * * * *** = (y1-y2)/(x1-x2);
* *** * ** **** * **** * * * **
* **** **** ** * * ** **** ** ** ** ** * *
** * * * * **** **** ** *** * * %f *** ** * * ***** * * ** **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * ***** * *


* * ** **** ** *** *


****** * ** *


** ** ** ** * ***




** ( )

{
** ** * ** ***
** * * %f %f * * *** * ** * * **** **** * **
* = d -
** = c -
** = f * b - a * e ;
***** * ** * * ****
** **
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
**** * * *** *******
**** *** ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* * * ** * ****** * * i, j, k, l;
* * * * ** ** * * ** a,b,c;
* * *** * *** * **** ** %4f %4f **** * * ** *** * *** ** * * ***
* ** **** * ** *** * * * ** ** *
* **** * ***** *** * **** * * * %6f ** * **** *


* ** * * * ** ***** ** ** ** * * ** * ***
* * ** * * ** * 0;

}
* ** * ****** * *** rect(int x,int y,int z,int w,int *p1,int *p2)
** * * ** ** ** * * * a,b,c;


* *** * * ****** * * ** * * * * * **** * ** ***
*** * ** * * ** *** ** * *** *** * ** * *


*** ****** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** ******* * *


* ** *
* ** * ** ** * ** ** ** * * * ** a, b, c;


** * ** * ** ***** ** ** * ** *** %f %f * * * * ** * ** * * ** * * **


*** * * ********* **** = y2 - y1 / * * y2 - x2 *
* * *** * * ** *** = x1 - * / * * * y2 - x2 *
****** * * * *** = - * * * - * * **
* *** * ** * * ** ** * * * * * ** a, * * *


*

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** * ** **** * *
* * * ** *** *
* ** * ** *** * *
* **** * * ** *






** ** *

{


** ** *** * ** ** ** ** ** *


* ** * *** ** *** ** * * * ***** *** ** *** * * **** * * ** **



** ** dx = (x1 - ***


**** * * dy = (y1 - * *
* *** *** ** *

*** ** ** m = dy / *
* * * * **

*** * ** *** *** h = y1 - *** *
* ** * **

*** * * ** a = b * h;

* * * ***

* *** * ** b =



**** c = b * h;


**** * * ** *** *** ** * *** *** * * ***** **




** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** ** * * ** * **



int main(void)

{
***** * * ** ** * x1,y1,x2,y2;
*** * * ** * * * * a,b,c;
** * *** * ** **** * ** * **** * ** ** ** * *
* *** *** * * ** *
** * ***** ** *** ** *** ** * * ** * ** * * = y2 - y1;
***** * * * ** *** ** * *** * *** ** ** * ** * = x1 - x2;
* ** ***** ** * * * ***** * * * ** ** ** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
**** * ** * **
* * **** * * * ** * * **** *** %f %f",a,b,c);






** ** *** ** ***** * * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** ** ** *** * * * **
** * *** ** * ** *

int main(void)

{
* * * *** * * ** x1,y1,x2,y2;
**** * * * **** * a,b,c;
**** * * * * *** *** ** * ** * *** * ******** ** ** *** * ** *
* * *** * ** * **
* * * *** * *** ***** *** * * * * * **** * = y2 - y1;
* ** * ** *** * ** **** *** * ** * * = x1 - x2;
* * * *** * * ** * ** * * * ** * * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * * ** *****
* * **** ** ** *** %f %f",a,b,c);






** *** ** ** * *** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.51
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users