0 like 0 dislike
3.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.2k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * * * * *** ** * * * ******
**** ** * **** **** * * ** ***
**** * * * *** ****** * * ** * ** **
**** ** ** ** ** * *** * * ******** **
* ** * ** * ***** * ** * * * * * * * *** ******


* * *** **** * ** * * * ** (a-c!=0)
** *** *** * * ** *** * *
** ** *** * *** *** * * *******
* *** * * ** * *** ** ** * ** **
*** ** * *** ******* * ** ** ** * * ***
*** * * * *** ** * * *
* * **** * ** *** * * * * * (a-c==0)
* ****** * ** ** ** *** ** * * ****
*** * * * * **** * * *** * *** *** * * * **
*** * **** **** * *** * * *** * ** * * * ***
* ** ** ** * * **** *** * * * **** * *** * * * *** * * ***
* *** ** * **** * *
* * * *** **** **** ("%.6f ",e);
** ** *** * * ("%.6f ",g);
* * ** *** * * * * ("%.6f",f);






* * * *** * * * ** ** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** * ** ** **




*** *

{
* *** ******** *
** * **** * *** %f %f * * * *** ** *** * ** *** *
*** * - x2 == 0)
** ** ** *** * **
*** * * *** ** * ** = x1;
*** ** * * *** * ** ** = 0;
* * ***** ** * ** *** ** = -x1;
** * * ** *** * ** * * * ** * %f * * **** ***
** ** * ****
*** * * ** if(x1 - x2 != 0,y1 != 0)
* *
* ** * = (y1 - * *** - x2);
* *** ** * ** * = y1 - (a * x1);
* **** ** ** ** = -((a * x1) + c) / y1;
** ** * * * * * * * ** * %f * *** * ****
* ***
*** ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* **** * **

int main (void)

{
*** * *** ** * * x1,y1,x2,y2;


** *** * * **** ** ** *** ** * a,b,c;


** ** ** * * ** ** * ** *** %f * * * * * *** ** * ** * * **
* * * * * *** * * * *** * *****
** *** * * * ** *** **** *** **
* * * **** ** ***** * * **** ** * * *




* * ***** * ** * ** ** ** %6f %6f",a,b,1);
* * * ***** ** ** * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** ** *** * ** * **
** * ** * * * **

#include<math.h>



int main()

{
* ** * * * *** ** * * ** * x1,x2,y1,y2,m,a,c0;
*** * **** * ** ** ** * ** ******
** * * ***** * ** * ** * * * * *** **
** ** *** ** ** * **** * * * * * ** *** ** * *** *
***** **** * **** *** * ** *** * * ** * ****
***** * ** * ** * = (y1-y2)/(x1-x2);
* * *** * * * ** ** ***
*** * * ** * *** * * *** ** *
** * **** ** * ** ****** * * %f * **** * * ***** **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * * *** **** ***


* ** ***** **** *** **


*** *** **** * * ***


* ** * *** * ** ***




* ( )

{
** * ** *
** * * %f %f ** * ***** * * * ** *** ** * *
= d - *
* = c -
* = f * b - a * e ;
*** * ** * ** * ** * **
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * * *** ** ***
* * * **** ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* *** *** * ** * i, j, k, l;
* ** ** * ** ** * ** a,b,c;
*** * * *** ** *** * *** %4f %4f ** * * ** * ***** * * **** *
* ** * * * * *** *** * *** * ** **
****** * ** ** ** * * **** * %6f * ** ** ***


* ** * * ***** * **** ********* * ** *
***** ** * *** *** * 0;

}
** ****** ** *** * rect(int x,int y,int z,int w,int *p1,int *p2)
** * * * ** *** * * ** ** ** a,b,c;


* * ******* * *** * * * ** * **** ** **
* * *** * *** ** * * ** ** ** ** ** * * * *


* * ** ** ** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * * ** ** **


*
** * * * ** * ** ** ** *** ** ** * a, b, c;


* ** * ***** ** *** * * * * * * %f %f ***** * ** **** *** **


* ** * * * * * = y2 - y1 / * * y2 - x2 * **
* * ** ** * * * * ** = x1 - * / * * y2 - x2 * *
** **** **** *** * *** = - * * * - * * **
** *** *** * ** ** * ******* * ** ** * * **** ******* a, * *


* * *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** ** ** ** *
* *** ** * *
***** * *** * *
* ** * *** * * *






* * * **

{


** * * * * *** ** ***** * *** **** *


* *** * *** * * * ** * ** ** * * ****** ** *** * * * ***** * *******



** * * ** dx = (x1 - *


** *** ** dy = (y1 - *
*** * *** *

* ** * * m = dy / *
* **** ** ***** *

* * * * h = y1 - *
* ** ** ** ****

* *** * * a = b * h;

** * *******

* * * * b =



* * **** * c = b * h;


** * * * * * * **** ** ** * ** ** * * * *** ** **




* * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * ** * * * *



int main(void)

{
* **** ** * x1,y1,x2,y2;
* * * * ** * ** ** * a,b,c;
* * * * * * * * * * ** *** * * * ** *** ** *** * ** * **
*** * *** * *** *
* * *** * ** * * ********* * ****** * ** ** * = y2 - y1;
* * * * **** * ** *** * * * * *** * = x1 - x2;
* * * * *** ** ** * * ** * ** * * * ** ***** = -x1 * (y2-y1) + y1 * (x2-x1);
* ** ** ** **
** *** * * *** ** * * %f %f",a,b,c);






* ** ** ********** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** ***** * * *** **
* *** ***

int main(void)

{
* **** ** ***** * * x1,y1,x2,y2;
* * *** * *** ** a,b,c;
** ** * **** ** * * ** * * * *** *** *** * ** *
* ** * * * * * ***
* *** * * * * * *** * ** **** ** * ** * * = y2 - y1;
*** ** **** * ** * ** * *** * * ** ** ** ** * *** * = x1 - x2;
* * * * **** * *** ** * ***** * *** * ***** **** ** = -x1 * (y2-y1) + y1 * (x2-x1);
* ******* * *** *
***** **** * *** ****** %f %f",a,b,c);






* *** *** ** ** ** *** * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.53
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users