0 like 0 dislike
3.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 3.7k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * *** ** ** * *** * * *** *** *
** * * * * *** ** * * * * **
** * ** * ** * * * * ** * ** **** **
** * ***** * * * *** ** * * ** ***** *
****** ***** ** * * **** ** * ** * * * * ** *** ** ****


* * **** ** * * * * ***** * (a-c!=0)
*** *** * ** * *** **** *
* ** ** ** **** * *** *** * *
** *** ** * ***** * ** *** * **
** * * ** **** * ****
** **** * * * * ** **
*** ** *** *** * * *** * (a-c==0)
*** ** * ***** * * **
* ***** * * **** **** * * * ** ****** * * * *** **
* ** * * ***** * ** * ** * *** * ***** * * ** *** ** ***
* * ** ** ******* * * ***** *** ** *** * ***** * * ** ***
* ** ** * ***** *** *
***** ** ** ** ** ("%.6f ",e);
** * **** * * ("%.6f ",g);
****** * ** * ("%.6f",f);






** **** ** * * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
*** * * * * *




****

{
* ** ***** * * ** *****
**** ****** ** **** %f %f ** ***** **** **** * * ** * * *
* *** - x2 == 0)
** * * * ***
* * * *** * ***** *** * = x1;
*** **** **** **** *** = 0;
* ** ** ** * * * = -x1;
* * ** * ***** * *** * * ** ** %f ** ** * ** *
** * ** ****
*** **** * if(x1 - x2 != 0,y1 != 0)
** *
* ***** ** ** * ** ** = (y1 - * - x2);
* * * * ** * * * = y1 - (a * x1);
* **** ******** * * = -((a * x1) + c) / y1;
* * * * * * ** ** ** * %f * **
**
* ***** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * **** * *** ** *

int main (void)

{
* * ** * ** * * **** * x1,y1,x2,y2;


*** ** * * * * * * * * a,b,c;


* * * ****** *** *** **** ** %f * * * ** **** *
** **** *** *** * ** **** * * **
* **** ** *** **** **** ** * * * **
* * ** **** * * ** * ***** * ** * *




* * ***** * ** **** ** * ** ** ** * %6f %6f",a,b,1);
** * ** * * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** * *
* **** * * ****

#include<math.h>



int main()

{
*** * ** * * **** ** * *** x1,x2,y1,y2,m,a,c0;
** * ********* ** * *** * * ** * ***** * **
** * *** * * * * * * *** * *** * ** *
** *** * *** ** *** * ***** **** ** * * * * *
* * * ** ** * * * *** * *** ** * ** *
* * * * * * * **** * * = (y1-y2)/(x1-x2);
***** * ** * * ** * * ****
*** * * * * ** ** ** * * * ** ***
** * * * * *** * *** ** * * * %f ** * * *** **** * *****

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** * *** ****


** *** * ** *


** *** * *


* ***** * **




* * * ( ** )

{
** * * *
*** ** ******** %f %f * ** * ***** ** * ** * * *
* = d -
* = c -
* = f * b - a * e ;
** ** * * * * * *
**
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ** ** * * **
* ** * *** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
**** * * * * * *** ** i, j, k, l;
**** * * * ** *** * * a,b,c;
* * * * ** ** ** *** * %4f %4f *** **** ****** * ** * * ** * * **
**** * ** * * ** ** * ***** * **
* * *** ** ** ** * * %6f * * * * *** *


** ** *** * * * * * * ** **
* ** ***** ** * * ***** * 0;

}
* *** * *** * rect(int x,int y,int z,int w,int *p1,int *p2)
* * *** * **** * * * ** * * a,b,c;


* * ** * *** * * *** * **** * ** * * * * **
****** * * **** * * * * * * * * * * *


** * * ** * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
***** * ** *


* * ***
* *** **** ** ** * **** * * * * a, b, c;


** * ** * * * ** * **** **** ** %f %f **** * * * * *** * * * * * *** ** *


* ***** * * * * ******** = y2 - y1 / * * * y2 - x2 *
* * ** * ***** * ** = x1 - * / * y2 - x2 * **
* * *** * ** * * ** = - * - * * **
* * * * *** * ** ** ** ****** a, * **


** ** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** *** ** ** ** *
* *** * ** ****** *
****** *** * **** *
** ** *






* * **

{


**** *** *** * * * ** ****** * * *


**** * * * * * ** *** *** * ***** **** ** ***** ****** *** * ** *



* ** *** * *** * dx = (x1 -


*** * ******* dy = (y1 -
* ** ** * * * *

*** * * * m = dy / *
* * *****

* * **** * h = y1 - **
* *** * * *

** * ** ** a = b * h;

* * * * ***

** * * * * b =



*** *** ** c = b * h;


* * ** * ** * * ** **** ** * * * ** ** ********************




** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** * ** ** **



int main(void)

{
* * *** * * ** * * * x1,y1,x2,y2;
** *** ** * * ** a,b,c;
****** * * * ****** ********* * * * * * * ***** * * * *
**** ** ****** ** *
* ** ** *** * ** *** * ** * * * *** = y2 - y1;
* ** * ** * *** * * * ** ** ** *** ***** ** = x1 - x2;
*** ** * * * * **** *** * * * ***** **** = -x1 * (y2-y1) + y1 * (x2-x1);
* * * ** * * * * *
* ** * * *** ** *** * ** ***** %f %f",a,b,c);






* ****** * ********* *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * ***** **** * ***
**** * ** **** *

int main(void)

{
** * ***** ** * * x1,y1,x2,y2;
* *** *** **** *** a,b,c;
* ******** * ** * * * ** * * *** ** *** * ** ** * **
* * * * *
* ** * * *** ****** ** * ** *** * * * ** = y2 - y1;
** ***** **** * * * * ** ** * *** ** ***** * = x1 - x2;
* ****** * ******** * ** * * *** * *** = -x1 * (y2-y1) + y1 * (x2-x1);
* * * *** * *
* *** * * * ** * ****** * %f %f",a,b,c);






** ** * ** ** * * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.130
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.1k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.2k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users