0 like 0 dislike
6.5k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 6.5k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* *** * ** ** ** * * ** *** * ** * **
* ** *** *** * * **** * ** * *
** * ** ** * * * * * ** ** *
* * * * ** * * * ****** ** ***** ** ** *** **
**** *** *** * ** * ** *** ****** *


* ** * *** ** * ** * * *** (a-c!=0)
* * * ** *** * *** * * * *
*** * * * **** * ** *
* **** ** * * * ** * ***** * **
* * ** * * ** ** ** ***
** * * * *** ** ** * ** * *
***** * ** * * * **** * * * (a-c==0)
*** * ** ***** * * *** ** **
* *** * * * ****** ******** *** * ** * ** **** ** ******
* ***** ** * *********** * * ****** * * ***
** * **** * * * * * **** **** * *** * ** * *
* * * * * ** * ** **** ** *
* * ** * *** * *** * ("%.6f ",e);
* * * * * ** **** ** ("%.6f ",g);
* * * * * * * ** ("%.6f",f);






* * ****** *** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** ***** *****




* *

{
**** ********
* ** ** *** * %f %f * ***** *** *** ** ** *** * * * **
*** * - x2 == 0)
**** ******
* * *** ****** *** = x1;
* ** ****** **** ** * = 0;
* * ** *** *** ** = -x1;
* ** ***** * * * *** ** ** %f * ***** * **
** **** ***
**** * if(x1 - x2 != 0,y1 != 0)
** ****
* * ** * * = (y1 - - x2);
****** * * ** * * ** = y1 - (a * x1);
*** * ** *** *** * = -((a * x1) + c) / y1;
* * **** ** * * **** * * %f * * * * *
** **
** * **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * * * *

int main (void)

{
** *** * ******* * x1,y1,x2,y2;


* * * *** *** * * * *** a,b,c;


** ** ** ** *** ** * * **** %f * * ** *** * **** * ** * ***
** * ** *** * *** ** * * * **
* * * ** * ** * *** ** ** ** * * **
* * ** * ** * * *** * *** ** *




* ******** ** * * ****** * ** * %6f %6f",a,b,1);
* ** ** ** *** ****** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * *****
***** * ** * ** *

#include<math.h>



int main()

{
** * * * ** *** * ** x1,x2,y1,y2,m,a,c0;
* ** **** ***** ** *** * ** * * * * *
** * *** *** *** * ** ** * ** *** * * **
** ** * * *** * **** * ** * * * *****
* * * **** * *** * * * * *** ** ****
* * * * * * *** = (y1-y2)/(x1-x2);
*** * ****** * ******* **** * **
** **** ** *** * *** ** ** * **** * ** ** *
* ** **** *** * ** * * * **** * %f ** * ** **** * * * * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** * **** *


* * * *** * ***


** * ***** **


* * * ******




* *** ( * )

{
** ** *
** *** ** ** %f %f ******* * **** * ** ** ** * **** *** *
** = d -
* = c -
* = f * b - a * e ;
* *** * ***** * * * *********
* *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
***** * **** * *
***** * ** *** * **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
** *** ***** *** ** i, j, k, l;
* * **** ** a,b,c;
**** * ** * * ******* %4f %4f * * * ****** * *** ** ** *
* *** * **** * * ** * *** *** *** **
** * ** * *** * ** %6f ** ** * ******


** * * ** ** ** * *** ** ** * ** *
* *** * *** **** * 0;

}
***** ** *** ** * * rect(int x,int y,int z,int w,int *p1,int *p2)
******** * * * *** * ** a,b,c;


* ** ****** * * ** * * * ** ** * * * *
* * ** ** **** ***** * *** * *


* ***** ** ** * * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
** *** ** *** ****


*** *******
*** *** * * **** *** ** * * * * * a, b, c;


** *** *** * ** * * ** * %f %f * * * *** ** ***** * ** * ** *


** ** * * ** ***** ** ** = y2 - y1 / * * y2 - x2 * *
* * * ******* ** ** ** = x1 - / * y2 - x2 * *
**** *** * * ** **** * * = - * * ** - *
***** * ** ** ** * ** * * * *** * * *** ** * a, *




}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * ** *** * * *
* ** ** *
** ** * * ** * **
** ** * ******* *






* ** *

{


* ** ** * * * ** **** * * ** *****


*** ** * ** * ** * * * ** *** * ** ** ** ** * * ** ** * * *



**** * *** * dx = (x1 - ***


* ** ** * dy = (y1 - * *
**** ********

* * m = dy / *
*** *** *****

***** **** h = y1 - * **
** ** **

* * ** a = b * h;

* *****

* ** * * * b =



* ** * c = b * h;


** ** ** * ** * ** * * ** *** ** * * * * * * * ******




* ** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* ** ******



int main(void)

{
** ** * * **** * ** x1,y1,x2,y2;
******* ** ********** ** a,b,c;
*** **** ** *** * * * * **** ** * **** * * * *** * * * * * * ****
*** * **** **
*** ** ** * * ****** * *** *** ***** * * * * = y2 - y1;
* *** ** * * ** ** * * ** * *** *** = x1 - x2;
** ** * * *** **** * *** ** *** **** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * ** *** *
* ** * * ** *** ** *** * * %f %f",a,b,c);






** * * *** ** *** * ** *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* *** * ***** ** *
* * ** * **** ** ***

int main(void)

{
* * ****** ** * * ** x1,y1,x2,y2;
* * ** * * ***** ** a,b,c;
* ** * * * * ** * ** ** ** * ** * * * ** ***** *
** * *** * ***
* * ***** ** * * ** * * ** * ** * ** * ** * ** = y2 - y1;
* * *** ** * * * * ** *** * * * * = x1 - x2;
*** *** * * * * * * *** ***** ****** * * ** = -x1 * (y2-y1) + y1 * (x2-x1);
* **** * *** * *
* ** **** * * * ** * * ** %f %f",a,b,c);






* * * *** ******** * *** ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.242.60
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.5k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users