0 like 0 dislike
5.8k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 5.8k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** * *** *** ******* * * * ****** ** *
**** ******* ** * * ** **** * *
* * ** **** **** ** * * ** ** **
* ** **** ** **** * *** * * *** *** * * **** ***
****** **** **** ** ** ** * * ** ** *** ** * *****


* * * * ** * * * * * * (a-c!=0)
**** * * ***** ** ** *** **
* ****** * ** **** * * * **
**** * ** *** * * * ******* *
* *** * * ** *** * **** ***
*** *** * ** * * ** * *
* * ** *** *** * ** (a-c==0)
* ** * * * ** * **** ***
** ** * ** * * ** **** * ** * * * * * * * **
*** * * * ** ** *** ** * ******* *** * ** * * **** *
* * **** * **** * * ** * **** ***** * ** * *
* *** * * * ** ** ** ********
*** * * * ** *** ** ** ("%.6f ",e);
** * ** ***** ** * * * * ("%.6f ",g);
*** ** ** **** * ** ("%.6f",f);






* ** * * ****** * * ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* *** ** **** *




*

{
**** *** **** * * ***
* * * * * * * %f %f ** * ** ** *** * * *** ** * ** **
* ** * - x2 == 0)
*** * *** **
****** ** ** * ** * * = x1;
** * * ******** * ** = 0;
** **** * * * = -x1;
* * * ** * ** * * * *** * * * ** %f *** ***** *** *
* ** **
* * *** if(x1 - x2 != 0,y1 != 0)
* ** * *
* ** *** ** ** **** = (y1 - * * - x2);
* ** ** *** = y1 - (a * x1);
* * *** *** ** = -((a * x1) + c) / y1;
** ** * * * *** %f * ** * * **
**
** *** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * *

int main (void)

{
* ** * ** * ** ** ***** * x1,y1,x2,y2;


**** * * * *** * *** a,b,c;


* ** * * ** * * * * * * %f * ** * ** * **** * *** ***
*** * ** ** ** * ** ** ******
*** *** * ** ** **** * * ** * ** * *
* **** * * ***** ** *** * * ** * **




* *** * * *** **** ** * ** * * *** %6f %6f",a,b,1);
* * * * * * ** *** *** ** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * *
** * *** *** *** *

#include<math.h>



int main()

{
*** *** * * **** * * x1,x2,y1,y2,m,a,c0;
***** *** * ** ** *** * * * * **** **
*** * * *** ******** * ** ** * * ** ** **
** ** **** * ****** **** *** ****** * * * ** ** * **
* * * *** ***** ** * *** * ** ***** **** **** * * ***
** * * * **** * = (y1-y2)/(x1-x2);
** * ******* * * ** **** *** *
* **** * * ** * * * * **** **
** * * * * ** * * **** ** * * %f ** *** * *** *** * * **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** *** * ** ** * **


*** ** * * ****


** ** **


* * ** ********




* * * ( *** )

{
** ** *
* ** * ** %f %f *** * *** * ** ** * ** ***
* = d -
* = c -
= f * b - a * e ;
* * *** * ** * ** ***
*
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * *
* * ** ** * * *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* * **** ** * i, j, k, l;
* ****** ** * * * a,b,c;
** ** ** *** *** * * * %4f %4f *** ******* **** *** ** * *
* * * * * *** ** * * ** * ***
* *** * * * * *** ** ** %6f ** *********


*** * * ** ** ** * ** ** * *
* ** * * * ** * 0;

}
** *** * ** * *** rect(int x,int y,int z,int w,int *p1,int *p2)
* ** * * ** * * * * * **** a,b,c;


** * * * * ** * * * ** * *******
** *** * * * * * *** ** ** *** * * ***


***** *** *** **
answered by (-114 points)
0 like 0 dislike
Hidden content!
** **** ** ** *


** ***
* ** *** * ** ** * ** * * * * * * a, b, c;


** * * ** * * *** * *** * *** %f %f **** * * * ** ****** * ** * ** *


**** **** * ** * * *** = y2 - y1 / * * y2 - x2 *
* ****** *** **** ** = x1 - * / * y2 - x2 *
** * * * * *** * ** * * = - ** * - ** * *
** * * * * * * ** * *** ** ** ** * *** ***** a, *


*** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * *
* ** * *** * **** ****
*** * * ****** *
** ** *** * *






* * ***

{


* *** * ***** * ** * * * ** * ** *


* ** ** **** * ** * * * *** *** **** * ** * * * * ** **



* * ***** dx = (x1 - ***


* * dy = (y1 - **
** *

* ** * *** ** m = dy / * *
*** *** *

* ** h = y1 - * **
* ***** * ***

* * * ** * a = b * h;

*** ** * * *

***** ** *** b =



* *** * c = b * h;


* * ** ** * * ** * ******* * *** * * * * *




*** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
***** * **** * * *



int main(void)

{
** * * *** ** * * *** * x1,y1,x2,y2;
****** * * ** ** **** a,b,c;
* *** * *************** ** ** *** * * *** ****** * * * **
* **** ** ** *** *****
* * ** * * * **** ** ** ***** * ** ** ** = y2 - y1;
* ****** ** * * * ***** * * *** * ** * * *** = x1 - x2;
* * ** *** * * * * * * **** * *** ** = -x1 * (y2-y1) + y1 * (x2-x1);
** ****** * * *** ** *
* ***** * ** *** ** *** * * * * %f %f",a,b,c);






** ** * * * * * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * * * * * *
* * ** * ***

int main(void)

{
*** * * ** *** * ** x1,y1,x2,y2;
* * **** *** * a,b,c;
* * * *** ** ** * * * ** ** * ** ** ** * ** * * *
**** ** ** *
*** ** *** * ***** *** ** ************* = y2 - y1;
*** * **** * ** ** *** ** ** ** *** *** * * = x1 - x2;
*** ** * * ** ** * ** ****** * *** * * * = -x1 * (y2-y1) + y1 * (x2-x1);
* *** * * * * ***
** ** ** * * ** * * ** * %f %f",a,b,c);






* * *** ** * **** * ** * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.169
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users