0 like 0 dislike
961 views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 961 views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** * *** *** * ** *** ** ** *** * * ** *
** * * *** * * * * * *** * *
** * *** ** * ** * * ** *** * * ***** * ** **
* * ** ** * * ** * * * * ** ** *
** * * ** * * ****** ******* * **** *** ** ** **


**** * * ** ** * ** * * * ** (a-c!=0)
***** ** *** ** **** *
** *** * * ***** * ** ** **
*** * * * * * * * ** * ****** **
* ** * *** * * ** * **
* ** * ** * ** ** ** ** * **
* * *** * * * * * * ** * *** (a-c==0)
* *** * *** * * ** * ***
**** * * **** ** * * * * ** * ** *** * * *
* ***** ** * ********** * * * **** * * * * * *** ** *
* * * ** * * *** * *** * ******** ** **** *** ** **
** ** * * ******* ********* **
* ** *** **** * * * ("%.6f ",e);
*** *** * ** ** ** ("%.6f ",g);
* * * ***** * * ("%.6f",f);






*** * ** **** * *** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** * * **




*

{
** * * * ** * *
* ** **** * * %f %f ** * * * * * * * ** *** * ** * * ** **
*** - x2 == 0)
* * * * *****
* * ** * * **** * * ** = x1;
*** ** * * * * = 0;
* ** * ** * = -x1;
* * ** * * * ***** * ** * %f ** ** ** *
**** **** *
** * if(x1 - x2 != 0,y1 != 0)
** ** *
** *** * ** * = (y1 - ***** - x2);
*** ** ********** = y1 - (a * x1);
** * ** **** * = -((a * x1) + c) / y1;
* ** ** ** ** * * * ** ** %f * * ** * *
* **
*** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** **** ** * *

int main (void)

{
* ************* *** **** x1,y1,x2,y2;


*** ** * * ***** * * * a,b,c;


* ** *** * * *** ** * ** %f * * **** * *** ** ** ****** * * * * **
* * * * *** * * ***** *** *** * **
* * * **** ** * * * ** * ** ** *
* *** * **** * ** * * ** ** * * * * *




**** * ****** * * * ** * * ** %6f %6f",a,b,1);
** * * *** * * * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** *** * ** ***
*** * **

#include<math.h>



int main()

{
* * * ** *** ******* ** x1,x2,y1,y2,m,a,c0;
** * ** * *** * * ** ** * ******** *
* * *** * *** * * * * ******* * ** * *** ***
* **** ** **** * ** * * *** * ** *
* * * ** * * ******** * ** ** * *
* **** ** * ** ** = (y1-y2)/(x1-x2);
*** ** ****** ****** * * **
* ** * **** *** ** * **** * * ** * * *
** ** * ** ** ** * * ** * ** %f * * ** * ** * ** *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
*** ** * * ****


* * ******* * * **


* *** * * * *


*** * * ** * **




*** ** ( * )

{
* * * *
** * **** * %f %f ********* **** **** * ** * ** ***
= d -
** = c - *
* = f * b - a * e ;
* * * *** * *****
* * *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * ** * ****
*** *** * * *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
*** *** ** * ** * * * i, j, k, l;
* *** * **** * a,b,c;
** ***** ******** *** * ** %4f %4f * ** * * ** ** * * *****
** **** * * ****** * * **** **** * * * *
** ***** **** * * *** * * * * %6f * ** * ** *


** * * *** *** * **** ** ********
** ** **** * * *** ** 0;

}
** * ***** * * * * rect(int x,int y,int z,int w,int *p1,int *p2)
** ** * *** **** * * * * * * * * a,b,c;


** **** ** * ** * * * *** ** * * * **
** ** * ******* ********* * * *** *** ** ****** ****


** * * **** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** ** ****


* ** **
* * * * ***** * ** * * * ** * * ** a, b, c;


**** * * * * ** * * ***** *** %f %f * * * * *** ** * * *** * *****


* * * *** * *** * * * * ** = y2 - y1 / ** * y2 - x2 * * *
* * * * * * * ** = x1 - / * * y2 - x2 * *
* * ** * *** ** * ** = - ** * - * *
** * * * * ** * ** ** * ** *** ** * *** a, **


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
**** * **
* ** ** * * * *
** * * * *****
**** ****






** ** * **

{


*** *** *** * * * * ** * ** * ** **** *


**** * ***** * **** * * * * ** * ** * *** *** * * *** * * ***



** * *** ** ** dx = (x1 -


* ** *** dy = (y1 - **
** ** * * *

* * * * ** ** m = dy / ***
*** ** *

* * * ** h = y1 - * *
* * * *

**** * * a = b * h;

** * * * **

** **** ** b =



*** * ** *** * * c = b * h;


** * ** * *** * * * ******* *** *** *** * * *** ***




** * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * * ***



int main(void)

{
* * *** * ** *** * x1,y1,x2,y2;
*** * * ** * **** * * a,b,c;
*** * * * * * ** *** ** ** * * ** ** * * ** * ** *****
*** ** * ***** **
** * ** ***** *** * * * * * *** *** * * * = y2 - y1;
** * * *** * * * *** * * * * ***** ** *** = x1 - x2;
* ** * * * **** *** * ** * *** * ** * *** ****** ** = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * * **** **
*** **** * * *** * * %f %f",a,b,c);






* ** * * ** * * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* **** * *
*** *******

int main(void)

{
* ** ******* ** * ** x1,y1,x2,y2;
* ** *** * ** **** a,b,c;
**** * ***** ** ** ** * **** ***** * * * * * ** ** * *
** ** ** **** ** *
** * * * * ** * ******* * *** **** * = y2 - y1;
** ******* *** * * ******** ** * * * ** * * ** *** = x1 - x2;
* * * * * *** * * ** * * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * ** ** *
* ** *** ** ** *** ** * %f %f",a,b,c);






*** ** * ** ** *** * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.13
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 491 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 515 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users