0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * *** * ** * * * * * * * * ** * * ****
** * * * * * ** * ** * *
* ** * * ** ***** ****** * * * ** * * * ***
** ****** ** ** ** * *** ** * ** ** ** **
*** ** ** * * * ** ** * ** * * ******** * *


* ** * * **** * * * * (a-c!=0)
* ** * * * ** * * * *
*** * * * ***** *** * * * * *
* * ** * *** * * * ** **
** ** * *** ** *** * *** * * ** ** **
*** * ** * * * **** * ******
* ** ** ** **** * * * ** ** ** ** (a-c==0)
** * ***** ** * ***** ** *
*** ******* * *** **** * ** *** ******* * *
* ****** *** * ** *** * * * * * *** ** ** *** * * *
**** ** * *** ** * * ** *** *** * ** ** * * *** * * * * *
* * * * * * * ****** * * *
* * * *** * * ** *** ("%.6f ",e);
** ** *** ** ** *** ("%.6f ",g);
*** ** * * *** ** * ("%.6f",f);






* ***** * ** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
*** * *** *




****

{
**** * **** ** *
* ** ** * *** * * %f %f * * *** **** ** * *** ** * * **** *
** ***** * - x2 == 0)
* ** ** * *
******** * * * *** = x1;
* ** ** ** * ** ** * = 0;
* ** * * = -x1;
* ** *** * *** * ** * * ** *** %f * ** ** ** *
** ** * * **
*** ** * if(x1 - x2 != 0,y1 != 0)
**
** * ** * * *** = (y1 - ** - x2);
*** ** * *** * * = y1 - (a * x1);
***** * ** * * = -((a * x1) + c) / y1;
* * *** ** ** * * * ** %f ** * *
*** **
****** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * ** **

int main (void)

{
** * * *** ******* ** x1,y1,x2,y2;


** ** * *** ****** a,b,c;


* *** ** * ** * * * ** *** %f ** ** * * * **** ***** *** * **
**** *** *** * * *** ** ******
* ** * * * ** * **** * * * *
** * ********** * *** ** * * ****** *




** ***** *** *** * * * ** ** **** * %6f %6f",a,b,1);
* * ** * * ** * * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * **** * *
**** * ** * * ****

#include<math.h>



int main()

{
***** * ** ** ** *** ** x1,x2,y1,y2,m,a,c0;
* * ***** * * *** * ** ****** ** ** * * ** *
*** * * * * * * * **** *** * ** ** *** * **
* * * **** * * ** * * ***** ** *
* ** *** * ******* **** * * ** ** * ***
* * *** *** ** * ** ** * = (y1-y2)/(x1-x2);
* ** *** ** *** ******* ** ** ***
*** * * * * ** * ****** *** * * **
** * * *** ** * ** **** * * %f * * * * * * **** * ** ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * * ** * **


* ** ** *


** *** * * ** *


** * * ** **




*** *** ( *** )

{
** ** ** *
* ***** * **** %f %f **** ** * *** * ***** * *** *
* = d -
* = c - *
* = f * b - a * e ;
* * *** * *** * *
* *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ** * ** *** *
** *** ****** * *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* *** ** * ***** ** * ** i, j, k, l;
***** *** * * *** **** * a,b,c;
* * *** ******* * * ** %4f %4f *** * * * * * *** **** * *** ** ***
*** * * ** * * *** * * * * ** ****
* * *** * * * ** * %6f ** * ** * *


* * * ** *** * * ** * ** **** * ** * *
* **** * * * ** ** 0;

}
* **** ** *** ***** rect(int x,int y,int z,int w,int *p1,int *p2)
* * * * * * * ** *** * ** * a,b,c;


* * * *** * ** ** * **** ***** ***** * * ***
* * * **** * * * * * ******* ** * ** * *


* *** * ** * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
*** * * **** * * *


** * * *
**** ** ** * * * * ** * * * * a, b, c;


** * *** * *** ** ** ***** %f %f * *** * * * * * **** * * ** * * ** ***


* * *** ** * * *** * * = y2 - y1 / * * y2 - x2 * **
* * *** * * * *** *** * = x1 - ** / ** * y2 - x2 * **
** *** * ** ** * **** = - * * ** - * *
** * *** ** *** ** *** * ** ** * ** a, *


****

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
** ****** *
* *** **** *** *
****** *****
* *** * * **






** * * **

{


** ** * ** * * * * ** ** **


* * ** * *** * ** * ** *** * **** *** ** * ** ***** *



** ** ** * dx = (x1 - *


*** * * * dy = (y1 - **
*** * *

** * * ** m = dy / *
* ** * * **

* * * * h = y1 - * ***
** * ** * **

** * * *** * * a = b * h;

* * *

* * * b =



** ** * ** ** c = b * h;


** * * ****** * * ** **** * ** * * * ** **** * * ** *** *




* *** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* **** ***** ** ***



int main(void)

{
* * * * *** x1,y1,x2,y2;
** ** * ** * ** * *** * a,b,c;
* *** * ** ** ** * ** *** ** * **** ** ** * * ** *
* * * * *
** *** ** * ** ** * ** * ** * *** * * ** ** = y2 - y1;
* * * * ** *** ** ** ** * ** * ** * * = x1 - x2;
* *** **** * **** ** ** ** ** *** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * *********
*** **** * ** **** * *** *** %f %f",a,b,c);






** * **** * *** ***** * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** ** * **
*** * * * * *

int main(void)

{
** ** **** * **** * x1,y1,x2,y2;
* * * * * ** ** * * a,b,c;
** ** * ** * * * * * * * * * * * ** * *** *** ** **
*** **** * * * **
***** * *** ** * **** *** ** * * ******** * = y2 - y1;
**** ** * *** ** * * ***** ** **** * * * = x1 - x2;
*** ***** ** * * * ** * ****** *** *** * * ** = -x1 * (y2-y1) + y1 * (x2-x1);
** * *** * ** *****
** * * ** ** *** **** ** %f %f",a,b,c);






** * ** * * * *** ***** * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.131
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users