0 like 0 dislike
7.3k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7.3k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
** ** *** * * * ********* * * ** * * * * *** ***
** ** * * * ******* * ** * * * * **** *
** * * ** ** *** * * * ** * *** * **
** ** ********* * ****** ********** * ** **
***** ** * ** ** * ** ** * *** ** * * ** ** * **


* * *** * *** * * *** ** ** (a-c!=0)
*** ** *** **** * ** **
* * * ** ** * **** *** **** * * *
* ** * ******* *** * ** **
** ** * * * ** *** * **** *
*** * * * ** * * * * **** * *
** ** * *** * **** **** * * (a-c==0)
* ** * *** ** *** *
* * * *** ** ** * * * ** ****** * *** * * ** *
** ** * * ** *** *** * * * * * ** ** * ** **
* * ** * * * ** ** * * * **** *** * * * * ** *
* * ** * * **** *
* *** * ** * *** * ** ("%.6f ",e);
* *** * *** ** **** * * ("%.6f ",g);
* * * * *** ** * ** * * * ("%.6f",f);






** ******* * **** * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * * ** * **




**

{
**** * *****
** ** * * * * %f %f * * * *** * ** ** **** ** * * *
* ** * * - x2 == 0)
** ** * *
* * *** ** * * * * = x1;
* ****** ** * *** = 0;
*** ** * * *** * ** * = -x1;
* *** * ** * * *** **** * * * %f ***** * *
* ** **
* *** * * if(x1 - x2 != 0,y1 != 0)
* * *
**** * ** * ** * * = (y1 - **** - x2);
* ** * * * * * *** = y1 - (a * x1);
* ** **** = -((a * x1) + c) / y1;
* **** * ***** * ** * ** %f * ***** *
** **** ***
** ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * ** *

int main (void)

{
* *** * * * * ** *** *** x1,y1,x2,y2;


* * ***** * ** *** * * a,b,c;


* ** ***** * ** * ***** * %f ***** * ** * * ** * * * *****
* * * * ** ** *** * ** **** * * ****** *
* * * ** ** ** ****** ** ** ****
******* * * **** ** ** * * * * *




* * *** * ** **** *** * **** * * %6f %6f",a,b,1);
********* ** * ** * ** * ** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** *** * * *
* ******* * **** ***

#include<math.h>



int main()

{
* ** ***** * * * * x1,x2,y1,y2,m,a,c0;
** * * * * * * * * *** *** ****** * *** *
****** ** **** ** * ** **** *** * * * ** *
* **** * * * *** * ** ** ***** *** * * *
* *** * *** * ** * * ***** ***** * *
*** * * **** * * = (y1-y2)/(x1-x2);
** *** *** * *** * * * *** *** * * **
*** ** * * *** * *** ** * ** * * **
* * * ** * ** * ** * * * %f ** * * * * ** ********

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ***** * ***


* * * * * ***


** *** * * * *


** ***** *** **** ***




* ( * )

{
* ** **
*** ***** * ** %f %f * * ******* *** * ****** ** **
** = d -
** = c - *
= f * b - a * e ;
* ** ** * * * ** * * *
*** ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
** ** ** * * * **
* * *** ***** **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
**** * *** ** * * i, j, k, l;
** *** * ** * a,b,c;
* *** ** ** ** * *** * **** %4f %4f * * *** * ** ** ***** *******
*** * * * ** * ** * ** *
** * * ** *** * ** **** * %6f ***** *


*** * ** * **** * * * *** ** *** *
******* ** *** * 0;

}
** **** * *** * ** * rect(int x,int y,int z,int w,int *p1,int *p2)
* * ** ***** ** ** * * ** a,b,c;


** * ** * ********* * * *** ****** ** ** *
* * * **** ** * * * * * ** ** *


* **** * *** **
answered by (-114 points)
0 like 0 dislike
Hidden content!
* **** * *


* *******
* ** * *** *** * * ** * * * ** a, b, c;


* * * ****** * ********** * * %f %f *** * ** * ***** * ***** * ** **


* *** ** ** ** * * * = y2 - y1 / * * y2 - x2 * **
* * ** *** * * ** = x1 - / * * y2 - x2 * *
** **** *** ** = - * - * * **
* * ******** ** * * *** * * * * * * * ** a, * *




}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** * *** **
** ** * ** ***** **
** * * * *
* * * ** *






** *

{


*** * *** *** * *** ** * *** *


* ** ** * **** **** ** ** **** * ** * ** *** ** *** **** *



* * *** ** ** dx = (x1 - * *


* ****** dy = (y1 - *
* * ** * * *

** * ****** m = dy / *
* * *** * *****

* * * * * * h = y1 - **** *
* ** *** *

* * * ** * a = b * h;

* * *** * ***

*** ** ** * b =



* * ** *** c = b * h;


* ** * * ** * **** * ** ** * * * * *** ***** ***** * ** * *




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
****** * **** * *



int main(void)

{
*** * * * * * x1,y1,x2,y2;
**** * ** * ** * a,b,c;
* * ** ** ** * * * * * *** ********* * ** **** * ** * ******* * ** *** *
** ** ***** ** *****
* *** * *** *** * * * * * *** * *** ***** * = y2 - y1;
** ********** * ** * * * * * ** *** = x1 - x2;
* *** * ** ** **** ** * * ** * * * ** = -x1 * (y2-y1) + y1 * (x2-x1);
** **** *** **** ****
* * ** * * *** *** *********** %f %f",a,b,c);






* *** ****** ** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** ** * * ** ** *
* ** * ** ** * * ** *

int main(void)

{
** * ** ******* **** x1,y1,x2,y2;
* ***** *** * ** * * a,b,c;
*** ** ** * * *** * * * * * *** ** *** *** * * ***** ******
** * ** ** ** *
*** * *** * ** ** ** * ** * * ** *** * * = y2 - y1;
**** * ** * *** * * * ** *** * ** * * * = x1 - x2;
** *** * * *** * **** * * *** * *** * ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* *** * ******* **
* * * ****** * ** ** **** ** %f %f",a,b,c);






*** ** * * * ** ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 13k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 10.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users