0 like 0 dislike
7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 7k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
*** * * * * * ****** * **** *** * *
* * * *** * * *** * ** **** *
** * * *** *** ** *** ** ** *** **
* ** * * ***** * * * *** * **** * *** * **** *
** * * *** * * ** * **** *** * ** ** ** **** ******* * *


* * **** * * ** ** * (a-c!=0)
* * ** ** **** *
*** **** *** ** ** * **** * * *
**** ** * * * *** ** **** *
* * * * ** *** * ** * * ****** ***
* * * ** ** ** ** **** * ***** *
** * ** * **** *** * (a-c==0)
*** ** * ** *** ** *** ***
** ** * * ***** * ** * * * * * ** *** * * * **
** **** ** ***** ** ** ** *** *** *** * * **
* *** * ***** *** *** ** **** * * * * ** * *** *
* *** ** ** *** *** * ***
* * * *** * ("%.6f ",e);
** * *** ** ** * *** ("%.6f ",g);
* *** *** * ** ** *** ** ("%.6f",f);






* ** * * * ** * * ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** * * ** *




**

{
* * ** *
*** * **** %f %f ** * ****** ** * * * ** *******
* **** - x2 == 0)
*** ** *** *
* ** ** * * * * * * ** = x1;
* ** * * * * * * * * * = 0;
**** * * * *** ** = -x1;
*** * * *** ** ** ** * * ** * %f *****
** * ***
** if(x1 - x2 != 0,y1 != 0)
* *
* * * ** * * * ** = (y1 - ** ** - x2);
*** ** ** ** *** = y1 - (a * x1);
* ** * * * * * = -((a * x1) + c) / y1;
* ** * **** * * * **** ** * * * %f * * * ***
*******
** * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * *** ** **

int main (void)

{
* *** * * *** * *** * **** x1,y1,x2,y2;


* ** * * *** ** * *** **** a,b,c;


* * * * ** ** ** * ** **** * * %f * * * * ** *** ***** ****** ****
** * ****** * * ******* ** ** * ** **
*** ** **** ** *** * * *** *** ** * ****
* * ** ** * ***** * *** **** ****




* * * * * ** ******* %6f %6f",a,b,1);
*** ***** ***** ** ** ** * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * ** **** **
** * * *** * *

#include<math.h>



int main()

{
* * *** * * * * *** *** * x1,x2,y1,y2,m,a,c0;
** ** **** * ** *** * ** **** **** ** * *
* ** * ** * ** ** * * * * ****
** * ** ** * * * * *** ** ****
***** ****** * * * * *** *** ** * *** ***
*** ** *** *** **** ** = (y1-y2)/(x1-x2);
** ** * *** ******* * * * ** * *
* ** *** * * ** * * * *** * *
* ** * ** ** * *** ** * **** * %f * ** * * ** * * * *** * **

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* **** * ** **


**** * ** ** ** **


***** *** **** * * *


** * * *** * * * ***




* * ** ( )

{
* * * **** *
* * *** ** * %f %f * ** * * ***** *** * ** *
** = d - **
= c -
* = f * b - a * e ;
* *** ** ** * ** * **** *

answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ** * * * **
*** *** * *** ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* ** * * * *** *** i, j, k, l;
*** *** * * ** ** ** a,b,c;
* * * * **** ** * %4f %4f * * ** * ** * ** **** * ** *
* ** ** ** * * * * * ** * * *
** ** ******* * * * * %6f * * * ** * ** *


* *** * * **** *** * * * * *
* ** * ** **** *** * 0;

}
* ** * ****** rect(int x,int y,int z,int w,int *p1,int *p2)
* ** * * ** * * * * * a,b,c;


* * * ** * * ** ** * * *** * ** *** * * **
***** ** * * ** ** * * * ** *** ***


*** * ** * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * ** **** * *


** *
* * ********* * * * **** * ** * * * ** * * a, b, c;


* ** * ** **** *** * * ** ** * %f %f *** ** ** * ** * * * * *** * *


* ** ** ** * ** * = y2 - y1 / * y2 - x2 *
** * ***** *** ** ** = x1 - / *** * y2 - x2 * *
** ** * ** *** * * ** * = - * * * - ** * *
* **** * *** * * * * * *** *** * * * ***** a, *


**** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * ***** *
* * ** *** * **
* * * ** * ** ***
**** *** *** * * **






** ****

{


** ** *** * ** * * * **** * *


* **** *** *** ** ** * * * ** **** * * ** * ** *** *** *** *



* * * * dx = (x1 - *


* * **** *** dy = (y1 - * *
* **** *

**** ** m = dy / *
*** ** *

*** *** * * h = y1 - **
** * *** *

*** * *** a = b * h;

* * ** *

*** * ** b =



*** * ***** c = b * h;


** * ** * * * **** * * * ** * ** ** * ** * *




* 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* * ** * *



int main(void)

{
** * * * ** **** *** x1,y1,x2,y2;
* * * * *** * a,b,c;
* * ** ** ** ** ** ** *** *** ** * ** ** ** * * ***** * ** ***
* * * * * *** * ***
* * * ***** **** ** *** ** **** ** ** *** = y2 - y1;
*** *** ** * *** * ** ** ** **** * ** * = x1 - x2;
* * * ** ** ** ** ****** * * *** * *** ** ** = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * ** * *****
* * * * *** ** *** * * ** * %f %f",a,b,c);






* ** ** * * * * *** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** **** * * * *
*** ** * ********* *

int main(void)

{
* * * * * **** x1,y1,x2,y2;
*** *** * * ** ** * a,b,c;
*** * ********* * ** **** * * ** * * ***** * ** ** *** *** * * **** *
** *** * ** ** *
** ** ** * ****** ** ******* ** ** * * ** = y2 - y1;
* ****** ***** ***** **** * * **** * = x1 - x2;
* * * ** * ** ** * * * * *** ** * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
*** *** * ** *
** *** ** *** ** * **** %f %f",a,b,c);






** * * ** *** ** ** ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.9k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users