0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * * **** ** ***** * **** * **** * *
** * * * *** * * ** * * * ****
*** * **** * ****** *** **** * * * * *
** * * ********** ** *** *** * * * ** **
**** * * ** * ** * * * *** * * * ** ******* * * **


*** * * ** * * *** * * (a-c!=0)
*** * ** **** *** * * *
** ****** * * * ** ** ** * * * **
** *** ** ** * *** **** * *
* * *** * ** *** * ** * * **
** * ** * * * ** * **
* ** * * ** * *** ** *** * * (a-c==0)
*** * ** * * *** ****
* ** * * ** *** **** ** ****** * *** ***** * ** * ** ***
*** * *** **** * *** ** ** * *** * * * *
***** * * ** * **** ** * * ******* * ** ** * * ***
* ** * ** * ** * * * * ***
*** * * ** ** * * ***** ("%.6f ",e);
** ** * ** ***** ("%.6f ",g);
* * ** * ** ("%.6f",f);






***** * * * * * ** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * ** * ***** *




** *

{
** ** ** *********
** *** * * ** %f %f * * * ** * ** ***** * *** * *
* ** * * - x2 == 0)
******** **** *
* ** ** ******** ** ** = x1;
* *** * *** * * = 0;
*** * *** ** * *** **** = -x1;
**** *** ***** * * * * ** ** **** *** %f * * * **** *
** * * ***
** * **** if(x1 - x2 != 0,y1 != 0)
*****
** **** *** * * ** * = (y1 - - x2);
* ***** * * ** = y1 - (a * x1);
** * *** * * = -((a * x1) + c) / y1;
* * ***** *** *** **** * * %f * * * *
* * **
** ** **** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * ** ***

int main (void)

{
* * **** * *** *** **** **** * x1,y1,x2,y2;


* ** * ** **** ** ** * * * a,b,c;


** ****** ** * *** * ** * * * * %f ** * * ** * *** ** * * * * *
** * ** * * * ** **** ***
* ** * * **** * *** *** **** * ******
* * ** * ** * ** * ** ** **** * *




****** *** ** ** **** ** ***** ** ** ** %6f %6f",a,b,1);
** * * ** * ** ** * * *** * * 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** * *
* ** **** * * **

#include<math.h>



int main()

{
*** ****** * * **** *** ** x1,x2,y1,y2,m,a,c0;
** * * ** * * *** * ****** * * *****
*** ** * * ** * ***** **** ****** ***** ***
**** * * ** * ** ****** * * ** **
** ** ** * * ** * ** **** * * ** * ****** **
* * * *** * * * * = (y1-y2)/(x1-x2);
* ** *** ***** ** ** ****** **** * * ***
* ** * * ***** * * ***** ***** * * ** *
* * ** ** * *** * ** * * **** %f * ** ***** * ** * ** * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
*** **** *** * ***


* ** * * * * *


***** ** *


* * *** * ****




* * ( )

{
*** * **
* ** * * %f %f **** ** *** ** ************ * ** *
= d - *
* = c -
* = f * b - a * e ;
*** * * ** * * ** *** * *
** *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* *** * ** * * *
* ** * * ******

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* *** * * * ** ** ** i, j, k, l;
* * *** * * * ** * a,b,c;
* ** * ** * * ** * ** *** %4f %4f * ** * * * ** **** * * * * *
* *** *** ** * * *** * *** * ** *
* ** *** * **** * * * ** * ***** %6f * ** *****


***** * * ** * * * * ***
* **** * 0;

}
** * * ** * rect(int x,int y,int z,int w,int *p1,int *p2)
* ***** * * **** ** ** * * * a,b,c;


*** * * * ** **** ******* * *** ** ** **
** ** ** *** ** * *** * ** * * * * **


****** *** * ****
answered by (-114 points)
0 like 0 dislike
Hidden content!
****** ** * ** ******


*** *
** * * ** * * * **** ** ** * *** * * a, b, c;


** * ** ** * * * *** * %f %f **** * *** ** * * ** ***** * ******


* * ** * = y2 - y1 / * * y2 - x2 * * *
** ******* ****** * ** ** ** = x1 - * / ** * y2 - x2 * *
* *** ** * ***** * * *** = - ** * - * * *
* ** ** ******* * ** *** ** * ** * ** * * * a, *




}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * *** * *
** ** * * * * ** *
* * * * * * **
**** * **** *






**

{


* * * * **** * ***** * * ** ** ***


** * **** * * *** * * * * * * * ** ** **** ** * * * ****



* ** ** dx = (x1 - * *


* ** * * dy = (y1 -
** * * **** *

* * * * ******* m = dy / *
** ** **** *

** *** ** ** * h = y1 - *
* *** * * * *

* * *** a = b * h;

** * ****

* ** ** b =



* * * * ** c = b * h;


*** ** ** * * ** * * * ** ** ** *** * **




0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
*** * *** * ** **** *



int main(void)

{
* * * ** *** x1,y1,x2,y2;
* ** ******* * * * * a,b,c;
**** * * **** ** * *** *** * * **** ** ** * * * * * *
**** * ** *
* *** *** ** ****** ** ***** * * *** **** **** * = y2 - y1;
** * ***** ** ** * * * * * * * ** ** = x1 - x2;
* ** ** **** * ** * * * ** * ** *** * * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * * *****
** *** * **** *** * * %f %f",a,b,c);






** ******* * * * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * ** **** **
* * ** * ** * *

int main(void)

{
* *** *** * *** x1,y1,x2,y2;
* *** * * * ** * * * a,b,c;
* * * * ** * *** * ** **** * *** * *** * * * ** * ****** *** * **
* ** ** * ***
* * *** *** ** ** * ** * * * * ** *** * = y2 - y1;
** * ** ** *** * * * ** * **** ** * = x1 - x2;
* * *** *** * * *** * *** * ** *** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ****
* ** * ** *** ** ** * *** * %f %f",a,b,c);






** * *** * ** ** **** * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.250
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users