0 like 0 dislike
4.9k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.9k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* * ***** * * ** * * * ******* * ***
*** * ** ** ** ** ** ** *** ** *
* ** * *** * * * *** ** *** * * * **
****** * * * * * * * * ** * * * *** ***
* * * * * ** * * ** * * * * ** * * * * ***


**** * * *** * ***** ** ** (a-c!=0)
** * * * *** * ** ** ***
* * * * ** ** * ** ** *
* ** * * ** * * * ** * * * *
* * * ** ** * * ** * ***** * *
* **** ** * * * * ** ** *
* * **** **** ** * ** * (a-c==0)
* * * * ***** ** **** * * *
* * **** * * * *** * ** ***** * * * ** * ***
* ** ** ** **** ****** * *** * *** *** ** * ** *
* * * ** * * ** ** ** * * * * ** ****** * * **
** *** ***** * *
* **** * ***** **** ("%.6f ",e);
* ** ** ** * ("%.6f ",g);
*** ** * * ** * * * ** * ("%.6f",f);






*** * * * ** ** * ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ***** ** *




*

{
** ** ** * * ** * * **
** * *** ** %f %f * *** **** * * ** ** * * * * * *
** * *** * - x2 == 0)
* * * ***** *
* **** **** * * = x1;
**** ** * * * = 0;
* ** ** * ** * * = -x1;
** ** **** *** ** **** * * %f ** ** *
* **
* * * if(x1 - x2 != 0,y1 != 0)
*** *
** * ***** * = (y1 - - x2);
****** * * ** * = y1 - (a * x1);
*** ** * * ** = -((a * x1) + c) / y1;
* * * *** * ** %f *** *** * ** *
* * * *
* * *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** * * *** **

int main (void)

{
**** ******* *** ** * **** x1,y1,x2,y2;


*** **** * ** * * * * * a,b,c;


** ** * * ** ** * **** *** * * %f * * *** **** *** ** ** **
** * * *** * * * ** * *
* * * * ****** * **** * * * * *
* *** * * * * * * * * *** * ** *




** ****** * * *** * ** ** * %6f %6f",a,b,1);
* * ** * ** * ** ** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * **** ** *
**** ** * * *

#include<math.h>



int main()

{
* ** * * * *** * ** ** x1,x2,y1,y2,m,a,c0;
* * * * ** ** ** * * ** * * ** ******
** ** * * * ** *** * ** ** **** * * *** *
**** ** * **** *** **** *** * *** * * * ** **
* ** * ** ** * ***** ** * *** *** * ** ** *** ** * *
* * ** * ****** ******** * = (y1-y2)/(x1-x2);
* ** ** ** **** * * * **
* * * ****** ** * ** **** * * ** ***
** * * ** * * ** * ** ***** ** **** * * %f * ** ** * ****** ***

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** ** * ** * * *


* ************ **** *


*** * * * * * ** *


****** *** * **** * *** **




* **** ( )

{
** ******
* * * ** %f %f * * ** * **** ******* *** * * *
* = d - *
= c -
* = f * b - a * e ;
* * *** * * ***** *
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** ** * * * * **
**** * * * ** *

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* * ** ******** * * i, j, k, l;
** *** **** * * * a,b,c;
* ** ** **** * * *** * * %4f %4f *** * * **** * ** * * * * *
** **** ** * * ******* * * * ***** * ***
** *** * * * ** * * * * * * %6f ** **** * *


*** * *** * * **** ***
** * * * **** ** * * * 0;

}
* **** ***** * * * rect(int x,int y,int z,int w,int *p1,int *p2)
*** * ******* * * ****** *** ** a,b,c;


* * * * * ** * * * * * * * ** **
* **** * ** **** * * **** * * *** ***** *


** ****** *** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
* ** * *** **


*** * ***
**** * * * ** *** * ** * * * ** * * a, b, c;


* ** ** ** *** * ***** *** %f %f ** * ** * ** * * * * * * * * ** * ****


***** ***** *** ** ** = y2 - y1 / * y2 - x2 * ***
** *** * ** * * ** = x1 - * / ** * y2 - x2 * *
**** * **** ** ***** = - * * * - * * *
** * * * *** * ** ** * *** * * a,


*** *

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * ***
* ** *** ** *
** * ** * * ** *
*** * * *** *** * *






* * ** * **

{


* ** * * * * * *** * * ***


** *** *** * ** * * ***** * * **** * * * ****** * ** *



** ** * * dx = (x1 - **


**** *** * * * dy = (y1 - *
* * *** * ** * *

** ** ** m = dy / *
** * * *

**** * ** * h = y1 - * * **
**** * * *

* ** *** * a = b * h;

** ** * ** **

** * * * b =



* *** c = b * h;


* * *** * * ** * * * * ** * ********* ** ***** **




* * 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
** * ** * * *



int main(void)

{
* ** * * ** *** x1,y1,x2,y2;
*** * **** ** *** a,b,c;
* * ** * **** **** * * *** * *** *** **** * ******
* **** * * ** *
* * * * *** **** ** ** *** * * = y2 - y1;
* * ** * * *** * * * * * *** ** * * ***** = x1 - x2;
* *** ** *** **** *** ** ** *** * * ** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ** ** **** * *
* **** * *** * ****** * %f %f",a,b,c);






** * * ** ** **** ** * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* *** *** ** **** *
* * *** **** ****

int main(void)

{
*** ****** ** ** x1,y1,x2,y2;
* * **** ** * a,b,c;
** * * * ** * ** * * **** * * ** * * * **** **
* * ** * ***
*** * ** * * *** ** * * * * **** * * * **** **** * * = y2 - y1;
** * * ** * ** ** *** ****** ** *** ***** * *** = x1 - x2;
* * *** * ******* * **** * ** *** * ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** **** * * * ******
** *** * ** **** * **** %f %f",a,b,c);






*** *** *** ** * * ** ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.124
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.6k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users