0 like 0 dislike
8k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 8k views

49 Answers

0 like 0 dislike
Hidden content!
* * ** * * *
*** * * * **** *

int main(void)

{
******** * * ******** x1,y1,x2,y2;
*** * * * * ** *** a,b,c;
* **** **** ** * * * ** * ******* * *** * **** * ***
** *** *** **
* * * ** ** *** **** * *** ** **** * * *** = y2 - y1;
** * ** ** ** ** ** * ** *** * **** * * * ** * = x1 - x2;
* ******** ***** ** ***** * * *** * ** ** **** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * ** ***** ** **
* * ** * ** * ** ** * * ** *** %.6f %.6f",a,b,c);






* * * * ** * **** * * * * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * **

int main(void)

{
* * * ** ** * x1,y1,x2,y2;
* * ***** * * a,b,c;
* * ***** *** ** * * ** * * ** * ********** * * ****
* ** * * *** *
* * * * *** * *** * * * * ** *** * * * = y2 - y1;
** * * * * * * * *** * ** ** *** * * * * ** = x1 - x2;
*** * * *** ******* * * ** *** * * ** * *** = -x1 * (y2-y1) + y1 * (x2-x1);
* *** *** * *
**** * * ***** *** * **** * ** ** * * ***






* *** * *** ** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
** * ** * ** * *


* * **



{
* ** * * * * y2, a, b, c;
* * * *** *** ** ***
* * *** *****
**** ** **** ** * **
* ***** * * * * **



a = (y1 - y2) / (x1 - * *

b = * / * * * *

c = * **
***** * * * **** a);
*** * * * ** b);
** * ** * ** * * *** **
** 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
******** * *** * *** * * x1,y1,x2,y2,m,b,c;
**** ** ** * ** * * n;
* * *** **** * * * ** * ** ** ***** ** * *** *** * ***** *
* * * ** * * **** ** ***

    {
* * ** ** * * **** * * ** *** * * = (y2-y1)/(x2-x1);
* * ***** * * **** * ****** ** * * *** * * = 1;
** * * ** **** ** * *** ** * *** * ** * ** = m * x1 - y1;

    }
* * *** * ** *** * ** * ** if (x2<x1)

    {
* *** *** ** *** ** ** **** * ****** * ***** * = (y1-y2)/(x1-x2);
***** ** *** * * * ** ** * ** * ***** * *** ** = 1;
** * *** ** *** ** * * ***** * ** * = m * x1 - y1;
*** ** ** * * * **
** ** ** * *** * ** *** ** if (y1 == y2)

    {
*** *** * ****** * * **** * ** ** ** ** ** = 0;
** *** * * ** * ** *** * ** * * *** ** ** * ** = 1;
** * ** ** ** *** *** *** ** ** ** ** ** *** ********** * = -y1;
** ** ****** ** *** * *
* * *** ** *** * * ** * if (x1 == x2)
**** *** * ***** *
** * * * **** ** * * *** ** ** * = 1;
*** *** *** * * ** * ** *** * * * * *** = 0;
*** **** ***** ** * *** ** ***** ** ***** ** * *** = -m;

    }
** *** ** * *** * ****** * ** ** *

    {
**** ** ** ** *** ** ***** * ** ** ****** * * ** * == b/n && m/n == c/n)
* ** * *** * * **** ** * ** ** ** *** **
* ** ** * *** ** ** * * * * **** ** ** ****** * * * ** * * * = m/n;
*** * * * ***** *** ** *** ** ****** * ** * ** ****** = b/n;
* * * ** ** *** ** ** ** ** * *** *** ** **** * * * = c/n;
*** * * * ** *** ***** * * *** * **
* * ** * ** ** **** * * * * ** * * * **
* * * ** ** ** **** * ** * *** * ***** * * * **
* ** * * ** * * * ** ** ** * * * **** * **** * *** * ** = m;
* * * ** ** ******** ** * *** * **** *** * ** * ** * * = b;
* *** * ****** * *** * * * * ** * * *** ***** ** * ** * ** **** * = c;
*** * * * ***** *** * * ** ** * * ******* *** * **

    }
* ** * *** *** ** ** * *** * %.6f %.6f\n",m,b,c);
** * * ** * * * ** *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * ***** * * ** x1,y1,x2,y2,m,b,c;
*** *** ** *** *** n;
*** * *** ** * * * * * *** *********** * *** ***** ** *** ************ ** *
** ** **** ** ** * ** * ***

    {
* ** * * * ***** ***** * * ** ** ** * ****** = (y2-y1)/(x2-x1);
* * *** **** ** *** **** * * *** * ****** = 1;
* * * ******* * * * ** ** * ** * * *** = m * x1 - y1;
* * ** *** * *** * ** * *
* * * ****** * *** **** **** if (x2<x1)
* ** ** ***** * *
* ** ** * * ** * ***** * * * * * * *** *** ** = (y1-y2)/(x1-x2);
** **** * ** ***** ** *** ***** * * ** * = 1;
* * *** ******* *** * * ** ** * * ** * = m * x1 - y1;
** * * ** **
* ** ** ** * * * ** * ** ** if (y1 == y2)

    {
** ***** * * * * * *** * ** ** = 0;
**** ** * ** ** * * * * ** ** ** * **** ** = 1;
* **** ** * * * *** * * * * ** ** ** = -y1;
*** ** ** * *** * ****
**** * **** *** * ** **** if (x1 == x2)

    {
***** ** * * *** *** *** **** ***** = 1;
* * ******** ** ** * ** * * * *** * ** * = 0;
*** * ** * * * ** * ** ***** = -m;
* * ** * *** ** * * *
* **** * * * * **** * * ** *

    {
* *** * ** ** ** ****** * * ** * * * * *** ***** * * == b%n && m%n == c%n)
* * * * * *** ** ** ** *** ** ** * ** **
* * * ***** ** ** *** *** * ** * * * * * ** * *** *** * * * ** = m/n;
** ** *** * ** **** **** * * * * ** *** * **** * *** * * = b/n;
*** * **** ** ***** *** * * * ******** ** * * ** *** * ** = c/n;
* * ** * ** ** * * * * ** ** * *** * *
* * * * ****** ** * **** ** ** ** * ** ****
*** ** ** * * *** * * * * **** **** ** ** ** * ** ** *** *** * **** ** %.6f %.6f\n",m,b,c);

    }
* * * * ** **** * *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include ** *** ** *

#include *** ** * * *

#include * * *****



int main(void)

{
** ** * * ** * ** a1,a2,b1,b2,a,b,c;
* * * **** * * * ** * * %f %f * * ********
* * * * * * * ****
* * * *** * * ******* *
*** ** ** ** * * ** ** * *
***** ** * ** * * * * ** *** %.6f * * * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
********* * * **** **
***** * * **** ** *

#include<math.h>



int main()

{
** * ** **** * * * * ** x1,x2,y1,y2,m,a,c0;
* * * *** *** ****** ** * ****** ******* *
******* ** * ****** * ** ** *** ** * *** *
***** * * *** * ** * *** ******* * ***
** *** ** ** * ********** ********** **
** *** * * * * *** * = (y1-y2)/(x1-x2);
* ** * * * * ** * * ** *
* ** *** ** * ******** * * * * *** * **
*** * ** * *** * *** *** ** ** %f ** * * * * ** * *** * * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* ** * *
*** ** **** *** *

int main()

{
* ******** * * ***** ** x1,y1,x2,y2 ;
** ** ** ** ** * ** *** * *** ** *** * ** * ** * ** **** * * * ;
*** **** * *** ** * * a,b,c ;
* **** * ** * = y2-y1 ;
* *** *** ** * * = x1-x2 ;
** * * * = -((a*x1)+(b*y1)) ;


** * * ****** * * **** * *** %f * ** * ** * ;


* ** **** *** * * *** 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** ** * ***** * ** * x1,y1,x2,y2,m,a,b,c;
* **** * * *** *** * * ** ** * * * *** * **** * *****
* * ******** * * *** **** *
* * **** ** ******* *
* * * * ** * ***** ******* *** * * ** = (y2-y1)/(x2-x1);
* * * ** ** ***** **** **** * * **** ******** = 1;
* * ** * * * * * * * ***** * **** ** *** * = m * x1 - y1;
** * * * *** * * **
*** ** ** * ** * if (x2<x1)
*** ** * * *** * *** *
* *** * ** * ** * * * ** **** ** * ** * * = (y1-y2)/(x1-x2);
* * * * *** *** * * ****** * * ***** *** * = 1;
* ** * * * * ****** * * ** * ** ** = m * x1 - y1;
* **** ** * ***
* * ** * ******* **** if (y1 == y2)

    {
* * * * **** ** ** ****** *** **** **** * ** = 0;
* ** * ** * ** *** * * * ****** ** * * ***** *** = 1;
* * ** ** * ** ** * ** * *** * * * * ** ** = -y1;
** * ****** *
***** ** * ***** *** if (x1 == x2)

    {
** * * * *** * * * *** * * ** *** * = 1;
*** ********* ** * ** * *** ** * *** * ** * = 0;
* * * * *** * * ** * * **** * ** = -m;
* * ****** ** *** ** * ** *
* *** **** * *** ** *** ** * ** %.6f %.6f\n",m,b,c);
* ***** * *** *** *** *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
****** ****** **
*** * * ** * ** *** **
* * **
* i ** ***
* * ** , b , c , * * * * ****
* * ; i *** ** ; **
* * ** * * , ** **** );




* ==

{ * * ** * = 1;
* ** * * * **** * ** ** * = - **

}


** *** *** * * **** ****

{

a ***** ***** *

c = ** * ** ;

b = -1 ;

}
* * * == 0)
* * *** ***** * 0 ;
** ** * *
** * ** * ** 0 ;
*** *
*** **** ** 0 ;
** ****** * * * *


* * * ** **
** ** ** * ** ** *** * * * * ** * **** * *** h ** , *




** *** *** ** ***** * *
*


** *** * * **** * ** a , b ,c










* 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.2k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 14k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 11.7k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.9k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users