0 like 0 dislike
4.2k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 4.2k views

49 Answers

0 like 0 dislike
Hidden content!
** ** **** ***
****** **** * *

int main(void)

{
** **** *** * * * x1,y1,x2,y2;
* *** * *** a,b,c;
* ** ** ** ** * * * *** * * *** * **** * * ** ** * *** *
** * * * *** * *
*** ** ** **** * * * ** ** ** ** ** = y2 - y1;
* ** ** * **** * * * * * ** *** ***** ** * = x1 - x2;
* * * *** ** *** * *** **** ** *** ** = -x1 * (y2-y1) + y1 * (x2-x1);
*** * *** * * * *
*** *** *** ** * * * * ** * %.6f %.6f",a,b,c);






** ***** **** * **** ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** ** ** *

int main(void)

{
* * * * ***** * ** *** x1,y1,x2,y2;
******** ** *** * *** * a,b,c;
** *** ****** ** * * * * * *** * * **** * * * ** ** **
** ***** *
* * * ** * * * * * *** ** = y2 - y1;
* ** * * * *** **** ** * * * = x1 - x2;
* ** *** * * * *** * *** * * * * * * * = -x1 * (y2-y1) + y1 * (x2-x1);
** * * * **
** ***** *** *** * *** * * * ** **** * ***** * **






* ** **** **** * * *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* * * ** ***** **


** * **



{
** * * * * y2, a, b, c;
*** * * * *** * * *
* ** ****** *** * * * **
**** *** **** ** * ***
* ** * **** * * ** *** * *



a = (y1 - y2) / (x1 - * * *

b = ** * / *** *

c = * **
** * ** * ** **** * a);
* * * * ** ** * b);
**** ** * * * *** *
* * 0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * * *** * **** * x1,y1,x2,y2,m,b,c;
** * ** *** * * * * * n;
* ** ***** ** **** * ** * * * **** ** * ** * ***** *** * * *
** * ** * * * * * *

    {
**** **** * * *** * * **** ** * * * * = (y2-y1)/(x2-x1);
*** * ***** ** ** **** *** * ** ** * * = 1;
* *** ** * ***** * * * *** * * ** ** * * = m * x1 - y1;

    }
* ** * *** * ** ** * if (x2<x1)

    {
* ********* **** ** ** ** * * ** * ** * * = (y1-y2)/(x1-x2);
*** * * ** * ** * * * * * * *** ** *** ** * = 1;
* *** ** ** ** * * ** * ** ** * * = m * x1 - y1;
****** ** *** ** * ** *
** ***** * **** ** * **** * if (y1 == y2)

    {
* * ** *** * ** * * *** * * * * = 0;
* * * ******* * ** * *** * ****** *** * = 1;
** *** *** * **** ***** * * *** * ** * = -y1;
*** *** * ** *
** * ** **** * * ** * * if (x1 == x2)
*** ** * * * *
** *** **** ** * *** ** ****** * ** * ** ** * **** = 1;
** ***** * * * ** * * * *** ** * ** ***** * * * ** = 0;
** ** *** ** * * *** ** * * * * * ** * * * *** = -m;

    }
** * *** **** * * * * * * * ** **

    {
** * ** *** * * * *** * * **** * ** ** == b/n && m/n == c/n)
* ** * * ** * * ** * * *** ** * * * *** ****
* ** * ** * * **** ** **** * * **** * *** * ** * ****** ** * * = m/n;
** *** * **** *** **** ** * * * * ** **** ** * ** ** * *** * = b/n;
* * * * * * *** * * * * * *** *** * ** * ** * * * * = c/n;
* * *** *** * * **** * ** **** ** *** * * ** *
*** * *** * ** * * * * *** * * ****** **
* * ********** * * ** *** * * * * *** **
**** * * * * *** **** ** ** * * * ** ** ** *** * ** * * *** = m;
*** ******* ** * ** ** *** ***** * *** * * * ** * * *** ** ** ** * ** * = b;
** ** * * * ****** *** * * * * * * ** ** * *** * * * ** * * ** * * * *** = c;
* * * * * **** * **** ** **

    }
* * * * * ** ** * * * * * * ***** %.6f %.6f\n",m,b,c);
*** * * *** * * *** * * ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ***** ** ** *** * * ** x1,y1,x2,y2,m,b,c;
* * * *** **** *** * * * n;
* **** ** ** ** *** ** ** * * *** *** * * * * ***** * **** * * * * **
* ** ** * * * **** * *** * * **

    {
**** * ***** * ** ***** *** * ** * ** * * * = (y2-y1)/(x2-x1);
* ** **** * * ********** * *** **** ** * * = 1;
**** ***** ** *** * *** * * ** **** *** = m * x1 - y1;
* * * ** ** **
* * *** *** * if (x2<x1)
** ** * * ** *** * *
** * * ** * ** *** ** ****** ** * * = (y1-y2)/(x1-x2);
* ** ** **** * * * **** * ******** *** * * ** ** = 1;
** * ***** * ** * * ** * ** ** * ** = m * x1 - y1;
* ** ***** ***** *
* ***** * * ******** * if (y1 == y2)

    {
** ** * ****** *** *** * * *** ** * * * = 0;
** ** * * *** ** * * **** * * ** *** ** = 1;
******* ** ******* * *** * * *** * ** ***** *** = -y1;
* * * ** * *** ****
* ** * **** ** ** ** * if (x1 == x2)

    {
* ** ** ** **** ***** *** *** * *** ** * * * * = 1;
* *** ** ** * * **** * * * * ** * *** * * = 0;
* *** ** * * **** * ** ** * * ** * * ** * * *** * **** = -m;
* * * * * ** * ** ** **
* ** *** *** * ** ** * *** **** *** *

    {
** * ** * * *** ** ** **** ******* * ** *** * == b%n && m%n == c%n)
* ******** * **** * * **** ** * * * * *
*** *** * * ******* *** *** *** ** * * * *** ** * * *** *** = m/n;
* ***** * * * ** * ** * * *** *** * * * * ** * * *** ** * = b/n;
** *** ** * * ** * *** ** * ** ** * * ** *** **** = c/n;
*** ******************* ***** * * ***** **
** *** * * ** * ** ***** * ** * *** *
* ** * * *** ****** * ******** *** * * ** *** ***** ** * ***** * *** ** ** *** * * ** %.6f %.6f\n",m,b,c);

    }
**** * * * *** * *** ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include *** ** * ** * **

#include ** ** ** *

#include ***** * ** *** *



int main(void)

{
** **** * * ** **** ** ** a1,a2,b1,b2,a,b,c;
*** * ** ***** ** **** ** * * ** *** %f %f * ** * ******
* *** * **** *** ** *
*** * * *** * * * * * *
** * * * * * * * * * *** ** *** ** ****
* * *** ** * ** * * * * **** %.6f ******** * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** ** ** ** *
** *** * **

#include<math.h>



int main()

{
* * ** * ****** * * ** * *** x1,x2,y1,y2,m,a,c0;
*** *** ** *** ***** ***** * ** *** ** * *
***** * * * * *** ** ***** * * * ***** **** ** *
*** * ** *** ** ** ** **** * * *** * ** *
* *** * ********* **** ****** * *** ** * *
******* * * * ** * * * = (y1-y2)/(x1-x2);
* ********** * * * * * ** *
* * ** *** * * *** * * ** ****
** * ** * * * * ****** **** * %f * * * * * ** *******

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
***** **** * *
* **** ***** * *

int main()

{
* * ** * * **** * * x1,y1,x2,y2 ;
***** ****** * * * ***** * ** * *** * * * ** ** * * **** * * ;
* ***** ** ** ** a,b,c ;
* * * ** * * ** = y2-y1 ;
**** * * * ** * = x1-x2 ;
* * *** * * ** = -((a*x1)+(b*y1)) ;


* * * * *** **** ***** ** * %f * *** ** ;


** **** * * 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
***** * ** *** * * ** * x1,y1,x2,y2,m,a,b,c;
***** * ** ** * ** * ** * *** **** * * * ** ** * **
* * * ** *** ** ****** ***** *
* ** * ** * ** * *
* ** **** **** *** * * ** ** *** ** = (y2-y1)/(x2-x1);
* ** *** * * **** ** ***** * = 1;
* **** ** * * * * *** ** * ***** * *** = m * x1 - y1;
** *** ** ******* **
* *** ** *** * *** ** * if (x2<x1)
* **** *** * ***** * ** * *
* * *** * * * *** ** ** ** * ** * * * * ** * *** = (y1-y2)/(x1-x2);
* ** *** ****** ** * * *** ** * ** ** ** ** * = 1;
** ** * * * * * *** ** * ** ** *** ******* * = m * x1 - y1;
* * ** * * * * * ******
* ** * * * ** ******** * if (y1 == y2)

    {
* ** **** *** * * ** ** * * * * * ** = 0;
** * * * * ** * *** * * ******* * ********* * ***** = 1;
* * ** * * ** * *** * * ********* ** * = -y1;
* * * * * * *** * **
** ** *** ****** if (x1 == x2)

    {
***** **** ** ********* *** * ** ** * ** * = 1;
** * ** *** ******* * **** * **** *** ** **** = 0;
*** ** * * * * ** * * * * **** ** *** * = -m;
*** ** *** ** * ** *
** * **** ** *** ***** * * *** * * ** ** %.6f %.6f\n",m,b,c);
*** * * * ** * ** * ***** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* ** ** ** *
* * ** ** * **
*
i *
* ** , b , c , *** * ** *
* ; i **** * * ; *
* ****** * * **** , * * * * );




* == * ***

{ ****** * ** = 1;
*** *** ** **** * * * * = -

}


* * *** * **

{

a ***** * ******* * *

c = * ** ;

b = -1 ;

}
* * == 0)
* ***** * * 0 ;
* **** *
** ** * ** ** * 0 ;
**** *
****** * * ** *** *** 0 ;
* * *** ** * * * ** *


*** * * * * ***** *
** * * * ** ** *** ****** * * * * ** * *** ** ** *** h * , *




** * *** *** ** *** **
*


* * * * ** * * * a , b ,c *










0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.98
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users