0 like 0 dislike
2.7k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 2.7k views

49 Answers

0 like 0 dislike
Hidden content!
**** **** ***** *
********** ***

int main(void)

{
* ** * ** ** * * * * * x1,y1,x2,y2;
*** * * ** * ** * ** a,b,c;
** ** * * ***** * ** **** **** ** ** * * * * * ** ** * * * **
* ** * ** *** **
* **** ** * *** * **** ***** * *** * = y2 - y1;
* * ** ** ** * * * *** ** * * ** *** = x1 - x2;
** ** ** ** * * * ** ** * * *** * ***** * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * ** *
* ****** ** * ** ***** * ****** * %.6f %.6f",a,b,c);






** ***** **** **** * *** * * 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ***** ** *

int main(void)

{
* *** * ** * * x1,y1,x2,y2;
****** * ******** * ** * ** a,b,c;
*** ** * * ***** ** **** * *** * ** *** ****** * *** **** * ** **
* ** * * * ** *
* **** *** * ** ** * ** *** * ** * * = y2 - y1;
* * * * **** * ** * * * ** * * * = x1 - x2;
* ** ***** *** * ****** *** * * *** * = -x1 * (y2-y1) + y1 * (x2-x1);
*** ***** * * *
*** * ** ** * ** ** * * * * ** * * ** *






*** *** **** * * * ** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
* ** * ** * *


* **



{
** * y2, a, b, c;
* * * ** * * *** **
* * ***** *** *** ** * **
* * * ** **** * ** * * *
** * ** ***** ** * ** * ** *



a = (y1 - y2) / (x1 - **

b = ******* / ** **

c = ** * * *
* * * ****** * ** a);
* * ** *** *** * b);
* * * * * *** **
0;

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
****** ** **** ** *** * *** x1,y1,x2,y2,m,b,c;
* ** ** * * * * ******* n;
** * *** *** *** ******* * * ** * ** * * * ** *** * * ** ** *
** * **** **** * ** * * ***

    {
** *** *** **** * * *** ** ** *** * * = (y2-y1)/(x2-x1);
* * * * * *** * *** ******** * * * ** ** = 1;
* *** ** * * * * * * **** ** * **** ** ** = m * x1 - y1;

    }
* * * * *** * * *** * * * if (x2<x1)

    {
******* ** * ** ** **** ******* ** *** * ** = (y1-y2)/(x1-x2);
***** * *** **** ** * ** * ** * * * * *** = 1;
* ** * * * ** * ** *** ***** * ** * ** = m * x1 - y1;
*** ** * **** * ** **
* *** ** * **** *** *** * if (y1 == y2)

    {
* * ** * ** * * * * * * * * * ** **** * * * = 0;
* * ***** **** ****** * *** *** * * * * ** * * = 1;
* * **** * * * ** * ** ** ** * * * * * = -y1;
*** * ** *** *****
** ***** *** * *** ** if (x1 == x2)
*** * * * * ** **
**** * * * **** *** * * *** * * *** **** ** * = 1;
* *** * ** *** * * * ** * ** ****** * * = 0;
** ********* * ** * ** *** * *** * ** * ** * = -m;

    }
*** ** **** ** * **** * * * * **** *

    {
*** * * * * *** *** * * **** * ** * *** == b/n && m/n == c/n)
******** * **** *** * * ** * ** ** *** *** *** *
* ** ** * * * ** *** ** **** *** * ** ** * * ** ***** *** * *** * * ** *** = m/n;
* *** * ******* ** ** * * ** * ***** *** * * * ** ** **** = b/n;
*** **** * * ** * * * ** * *** *** ** ** * ** * *** * * * ** ** ** * = c/n;
* * * * ** ** * * * * * *** * **** * **** *
**** ***** * *** ** **** *** ****** * *
** * ********* ****** ** *** * * * * * *****
*** ***** ** * * * * ***** * * * * *** ** * **** * * * **** ** ** = m;
* * * * ****** * * ** ** * **** *** ** ** *** * ** * * ** = b;
******* *** ***** * * ** * * *** *** **** * * * * ** **** * ** = c;
** ** * * * **** ** * ** ** **** * ** * ********

    }
* * *** **** * **** ** * * ** **** ** %.6f %.6f\n",m,b,c);
* ** ** *** * ** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* **** ** ** ** *** x1,y1,x2,y2,m,b,c;
*** * * ** ***** ***** ** n;
* ** * ** **** * * **** * ***** **** *** *** ** * * * ** * **** * ** **
* ** * ** * ** *** * * ** ******* ***

    {
*** * ** ** ** ** * * * * ** ** * * ** * = (y2-y1)/(x2-x1);
* * **** * * ***** * *** ******* * = 1;
*** ** * ** * ** * * *** * * ** ** * ** ***** * ** = m * x1 - y1;
*** * * * * ** *** * ** **
**** * ***** * * * if (x2<x1)
* **** **** * ***** *
** * * **** *** *** *** ** ** **** * ** * = (y1-y2)/(x1-x2);
* ** * ** * *** * * * * * * ***** ** * * * = 1;
*** * *** * ** ** * ** **** * * ** * = m * x1 - y1;
** * ****** * ** ** *** *
* * * ** ****** if (y1 == y2)

    {
* ** ** * ** ***** * * ** * * ******* ** *** = 0;
* * * *** * * * * * ** * **** * * ** * ** * * = 1;
*** **** * * *** ** * **** ** ** **** * * * = -y1;
***** ** * * ** ** * *****
* *** * *** * * ** ** * if (x1 == x2)

    {
* ****** * * * ** * ** * * ****** * * *** * ** = 1;
* * ** ** * * * * ** *** ** * ** *** ** *** = 0;
*** *** * *** *** ** ***** * ** * * *** ** * = -m;
*** * * ** *** **
* **** * *** ** ** * ** ******

    {
* * * *** * ** * * * * * * *** ** ** *** * * * **** * == b%n && m%n == c%n)
*** * ** ****** *** * *** **** * * *** *
* ** *** *** * * ** ** * * **** * * *** ** *** * ***** ** = m/n;
* * ** **** ** * * **** ** * *** ***** *** ** ***** * * * *** = b/n;
* * ** * ** ** * * ** * * **** * * ** * ** ****** * * *** * *** = c/n;
*** ** ** ** * * *** ** * * * * * * ** *** **
* ** *** ** * * **** ***** * ** * * * ****
**** ***** * * ** ** * ****** * * * * * ** * * ** * * * *** *** ** * * * %.6f %.6f\n",m,b,c);

    }
** ***** **** * * *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include *** * ** *

#include * *** *** * *

#include * * ** **



int main(void)

{
** ** * ** ******** * ** a1,a2,b1,b2,a,b,c;
* * ** *** * ** ** * * ********* %f %f ** * * * *** *
***** * ***** ** ******* *
***** *** * * * * ** * *
*** ** ** * * * * ** ** **** * *** *
* ** * ** * **** *** ******* %.6f * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** *** ** * **
** * *** ** *** * * *

#include<math.h>



int main()

{
* *** ******* **** ** * x1,x2,y1,y2,m,a,c0;
* * * * ** * ** * *** * ***** *
* ** * **** * * ** ** ** *** * * **
* ******** *** * * * * *** ****** *** ** * *
** * ** * ** * * * ****** * * ** * * *
* *** * * **** ** * * = (y1-y2)/(x1-x2);
* ********* ** * ** * * *** ***** ** *
** ** ** *** * * ** * *** * * * * **
** * ** ***** * *** ** * ** * %f *** ** *** * * * *******

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
** ** ** * *
** *** * ** * ****

int main()

{
* ** ** * ***** **** * x1,y1,x2,y2 ;
*** * ** *** *** ******* * * **** * * * ** * ** * **** * ;
*** * * ** * ** ** a,b,c ;
* **** * * ** *** ** **** = y2-y1 ;
* * *** * = x1-x2 ;
** * ** *** * *** = -((a*x1)+(b*y1)) ;


* * * * * **** ** * *** *** %f * **** **** ;


** *** *** * * * 0 ;

}
answered by (-88 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
****** * ** ** *** * * ** x1,y1,x2,y2,m,a,b,c;
** * * ** * * *** *** ** ** *** * ** * *** *** * * **** * * * **
* * * ***** * * ***** * **
** ** * ** ** *** *** *
** ** *** **** * ** * **** * **** ** * = (y2-y1)/(x2-x1);
* ** ** * ** ** * *** ** * ** * ** * * ** ** = 1;
**** ***** * * **** *** * ** ** * * * ** * * **** = m * x1 - y1;
** *** * * ** ** * *
** ***** *** **** * *** ** * if (x2<x1)
* * * * * **
* * * * ** * * *** * * *** ** ** **** = (y1-y2)/(x1-x2);
*** * ** * * * ** ** * * * * * ******* ** * = 1;
* ** *** * ** ** *** ** **** * * * * *** * = m * x1 - y1;
** ** * *** **
* * *** * *** ** * *** * * if (y1 == y2)

    {
* *** * * *** ** ** ******* ** ** * * *** = 0;
*** * * **** ** *** **** * *** **** **** * * = 1;
*** * *** ** * * ** * *** ** **** ** *** = -y1;
* *** * * *** **
* * * * ** * * * **** if (x1 == x2)

    {
** ** ** * **** * * * *** * * ** * ** ** ******** = 1;
** ** * **** * * * ** ** ******* *** * ** * ** = 0;
** * * * * * ** * *** **** ** **** ** **** * * = -m;
* * * *** ** ** ** *
** * **** **** ** ** * ** * * %.6f %.6f\n",m,b,c);
** ** * * ** ** * * *** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** ** **** * ** *
** ** ** * * ***
*** ** *
* i *** *
* * * , b , c , ** ** * *
****** ; i * * ; *
* ** ** ***** * **** , * ** ** );




* * == *

{ ** ** * = 1;
* ** * * * **** ** = - * *

}


** * ***** ** **

{

a * * * * ***

c = * * ** ;

b = -1 ;

}
* * == 0)
** * * ** * * 0 ;

* ******* *** * 0 ;
* * *
** * * * * 0 ;
*** *** ** * * * * * *


** * *** **
** * * * * ** * * ** ** * * *** * h * , **




*** * ** *** * *
**


* * * * * ** * **** a , b ,c *










* 0 ;







}
answered by (-87 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.4
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users