0 like 0 dislike
1k views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 1k views

49 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <math.h>



int main()

{
* ** ***** * * *** *** * ** * *** * ****
** * * ** *** ************ * * * *
** * * * * ** *** *** * ***** * *
** ** *** * ** * * **** * *** * **** * **
* * * * * *** * **** *** ** ** ** * * ** **


* * * * ** * * * ** (a-c!=0)
** * ** *** *** ** ** * * *
* *** *** * **** * ** * *
*** ** * * *** ** ** * * ** *** **** **
* ** *** * * *** *** **** ** **
**** ** ** * * ****** ** * ***
* * * * * * ** * * * * **** (a-c==0)
* * ** * *** ** * ** * ***
** *** * * * * ** ** * *** *** ***** * *** *** **
** * ***** *** ** ** * * **** * * *** * * *
* *** * * ** * ** * **** * ** * * ** * *
* * ***** *** * ** ** *
* * * ** ** * *** * ("%.6f ",e);
**** * * * *** * ("%.6f ",g);
** * * * ** *** ("%.6f",f);






* * *** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
** ****** * * * **




*

{
* * * * ** ** * ***
* * ** * ** * * * %f %f *** * * ***** * * * *** ** ** **
** * * - x2 == 0)
*** ** * *
* *** * * ** * **** = x1;
** * *** * * * * * = 0;
*** * * *** ** = -x1;
*** * * * * * *** ** * * %f * * * *
* **
* * ** *** if(x1 - x2 != 0,y1 != 0)
** * *
* ** ** * = (y1 - ** - x2);
* * * *** * * *** = y1 - (a * x1);
***** * **** ** * * * = -((a * x1) + c) / y1;
** ** * ** * ***** * ** *** **** %f ** * *** **
* * *
** ** * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ***** * * ** **

int main (void)

{
* * ***** **** * ** ** x1,y1,x2,y2;


* * * ***** ***** * * a,b,c;


** **** **** ** ** * * ** *** %f ******* * *** **** * * ** ***
** * * * * * *** *** ** *** * *
* ******* ****** * ** *
** ** * **** * ****** ** ** *** * * * *




** * * ** ** ** * ** ** * * * %6f %6f",a,b,1);
*** ** * * * * * *** **** 0;



}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
***** * ** * * **
** * ** ** * * *

#include<math.h>



int main()

{
**** *** * ** * * x1,x2,y1,y2,m,a,c0;
********* * ****** ** * *** * * ** * ** * *** ** *
** * ** * ***** * * *** ** * **** * ** * ** **
****** **** * * ** ** * * ** * **** * * *
*** ** * ***** * * ** ******* * ** * *****
* ** ** ** **** * * ** * ** = (y1-y2)/(x1-x2);
**** ** ***** * ** *** **
* * * * * * * * * * ** * ** ** **** ***
** * * ****** * * * **** * %f * ***** * * * *

return 0;

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
* * * * *** * * **


* * ***** ** * *** *


***** * ** **** *


* *** * **** ****




** ** ( * )

{
* * * ** *
** ****** %f %f * * * * * ** * * ** ** *****
* = d -
** = c - *
= f * b - a * e ;
*** * ** *** *** *
* * *
answered by (-276 points)
0 like 0 dislike
Hidden content!
** ** ** * ** * *
* * ** * * **

void rect(int ,int,int ,int,int *,int * );

int main(void)

{
* * *** * * * * i, j, k, l;
** **** *** * *** a,b,c;
* ** * *** * ****** **** * %4f %4f * * ** * ** * ** * *** * ** *
* * ** ** * * *** * * * * * ** ** *** ***
* ***** * * ** **** * %6f *** ****


***** * * ** ** * **** * *** ** **** *
** *** * * ** 0;

}
* * * * ***** rect(int x,int y,int z,int w,int *p1,int *p2)
* *** * ** ** ***** * *** * *** a,b,c;


* ** * * ** *** **** ** ******* ** **
**** * * * * * *** *** * ***** * ***


* **** *** ** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
** * ****


* * **
* ** * * * ** ** * ** * * ** * a, b, c;


* * * * *** ** * * * * ** * *** %f %f * ** * **** * ** ******* * **** *


** * * **** * *** **** = y2 - y1 / * y2 - x2 * * *
* *** *** * ** ***** = x1 - * / * * * y2 - x2 * **
* * ** ** * * ***** ** = - ** * - * *
* ****** * * * * * * * ***** ** ** * * * *** *** a, **


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* ** ** * *** * * *
** ** * * *** **
** * * * * *******
**** * ***** * **






* * ** **

{


* *** * * ** ****** ***


* ** * * ** * * * ** **** * * * ** * * ** ******* * * * ******** * ***



* * * dx = (x1 - **


*** * ** * ** * dy = (y1 - ****
**** * ** ***

** * ** m = dy / **
* * * **

* * ** * h = y1 - *
** **** * **

*** * * ** a = b * h;

*** * * * ** *

* *** ***** b =



** *** * ** * * c = b * h;


* * ** * **** * * ** ** * * * * * ***** * * ***




** 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
* ** ** * *****



int main(void)

{
* * **** * * * * * x1,y1,x2,y2;
* * * * * *********** * a,b,c;
* ** *** * **** ** * * *** ** * * **** **** ** ***** *
* * * * ** ** *** *
*** ** * **** ** * * ** * * ** ** ***** * = y2 - y1;
* ** * ** * ** * * * ** ** ** ** * *** ** = x1 - x2;
**** * ** **** * ** ** * * **** * * = -x1 * (y2-y1) + y1 * (x2-x1);
* * * * *** ***
* ** * ** *********** ** * * ** %f %f",a,b,c);






*** ** * * ** ** *** * * *** 0;

}
answered by (-320 points)
0 like 0 dislike
Hidden content!
**** * * ** ******* *
** * ** * ** * **

int main(void)

{
**** *** **** x1,y1,x2,y2;
* * * * * * * * a,b,c;
*** * **** ** * *** **** *** **** *** * ****** * * * * *
** *** * * **
*** * * *** * * ** * * * * * *** ** = y2 - y1;
* *** ***** * *** *** * * * * ***** * = x1 - x2;
* * * * * ***** * **** * * ****** ** ***** = -x1 * (y2-y1) + y1 * (x2-x1);
* ** *** ***** ***
*** * ** ** * *** * * *** %f %f",a,b,c);






** * *** ***** ** * * * 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.30
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 507 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 541 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users