0 like 0 dislike
2.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.2k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* ********* *** ** *** ** ****** * **
** * * *** * **** *** * * *** * *

    {
* **** * ** ******* * * *** * ** * * * * ***
** * *** * * ** * ** * *** *** ** * * ** ***
* ** * ** * ** ** * *** * * * *** * *** **** **** *** *** * * * **** * ****** *
* * *** * * * * ** * ** ** * * * *** * ** * * ** * * * * * * * * **** * * **** ** = a[n] + b[n];
** * ** ** ***** * *** * ** ** * * ** * ***** * * *** ** ***** * * if(a[n]+b[n]>='10')
* * * * *** * * ** * *** * ** ** * * * ** ** ** **
**** ** *** * **** * ** ** ********* * * ***** ** **** * ** ** ** **** * * **** * ** *** = a[n] + b[n] - '10';
**** * ****** ** ** ** ***** * *** * *** * ***** * * * * ** * ***** ** ** ** ** * * * * *
* * **** *** *** * * ** * **** ** ******* * ** * * *** * *
** ** * * ** * * ** * ** * ** **** *
** * * * * * * ** ** * *** * * if(t == 1)
* * *** *** * * **** * *** * ****** **
*** ** *** * * * *** * * **** ** *** * * * * ** * ** *** ** * ** ** ** **
* **** * * * ** ** ** ***** * **** ** ** ***** * * *** *** ** *** ** * *** * ** ** *** *** * *** = a[n] + b[n] + '1';
* * *** * *** ****** ** * *** **** *** ******* ** * * ** * * ** if(a[n]+b[n]>='9')
**** * * ** * ** * * ** * * * ** * * ** * ** * * **** * **
** * * ** ** ** * ** * * ** ** * * * ** *** * * * ** * * ** * ** ****** = a[n] + b[n] - '9';
** ** *** ** ** * * * * * **** * *** * ******** * * * ** ***** * * * * * *** ** *** * *
**** * ** ** * *** * *** *** * ** *** *** ***** * * *****
* ** ** ** ***** * * *** * * * * * * *

    }
* ** ***** * ** * * * ***

    {
* * *** * ** * *** * **** * * * ** * **** * ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * ** * **** * **
*** *** * * * * *

int main ()

{

int **


***** ** * * ** ** ** ** *
* * *** **** * ** * *


* * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * *** * * *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
****** ***** * *** ** *** a[100],b[100];
** ***** **** ** * * * * sum[200];
* *** ** * * ** * * ** la,lb,lm,i,j,k;
* * *** * ** * * ** ** ** * %s",a,b);
* ** ** ******* * ** ** ** = strlen(a);
* * * * * ** * * = strlen(b);
** *** * ** ** * ** ** ** * * ** *** ** ****
** ***** **** * * ** ** * ***** * * **** ** * ** = a[i];
* ** * ****** *** ** ***** * *** * **** **** ** ***
* ** *** **** *** *
* * * *** * * * * * * ** **** ** ** **
* ** * ***** * * * * * ** * * ** * **** ** * ** += b[i]-48;
**** * * * * ****** * ** * ** ** **** * ** * * * * * *
* *** * *** *** **** * * *
* * *** ** * * * ** = strlen(sum);
**** ***** *** * * * * ** *
** *** * ***** ** * ** **** ** *** ** ** ** * ** * ** * *
* ** * * * ******
* * * * ** **** * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
** ***** ** **
* *** ** *** * * *





int main ()

{
* * a , b ;
* ****** * ** , ** **
* ***** * * **** , ***
* * ****** * ,a+b);
* * * * **** * * ** * * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * * ** **** * ** * ** ** *
*** ******** ** * ** ** * * ** * * * * ****

    {
** *** ** * * *** * ******* * * ****
* ** * ** *** * * * *** ** * * *** * * ***
* ** * ** ***** ** * ** ** *** **** * ** * ** * *** * ** ***** * **** ** * * ** *
* * * * ** ** * * ** * * *** ***** * *** *** ****** ** * *** ** * ** *** ** * ** = a[n] + b[n];
* ** **** * * * * ** * * **** ** ** * * * ** * * ** *** ** *** if(a[n]+b[n]>=10)
** * ** ** * ** *** ** *** *** ** * * *** * *** **** * ** * * ** **
** * * * ** * *** **** ** *** **** * * *** **** * ** ** ***** * * * ** * = a[n] + b[n] - 10;
* **** * ****** **** * **** ** *** * * ** * * ** * * * **** * ** * **** * * * *
** * **** * *** * ** *** * * * **** * * ** * * ** ******* * *
* * ***** * * * ** * ** **** * *** *
* **** ** **** **** ** * ** * ** * **** ** ** *** ** if(t == 1)
******* * * * * ** ** ** ***** *** **** ***
*** ** *** *** * * ***** *** **** * * ** * ** ** * * * * * ** * ** ** * * *******
* * * * * * ***** ** ** * ** * ***** ** * * * **** *** ***** ** *** *** ****** * * = a[n] + b[n] + 1;
* * * * * ** * *** ** * *** * **** *** ** * ** *** * ** * ** * if(a[n]+b[n]>=9)
****** * * *** * * *** * ** **** * * **** ** ** * ** *
* * * * * * * * **** * *** * * * * ****** * **** * *** **** * * ** ** *** ** * *** * * * = a[n] + b[n] - 9;
* * *** *** * * * * *** * ** *** * *** * ** ** ** ** *** ** ** * ** ** ***** * * ** * ** **
*** ****** *** ** ***** ** * * * * ** ***** ****** * * * * * *
**** * ** *** * * * * ** * * * ** **

    }
** ** ** *** *** * * ***

    {
* * * ** * *** *** * **** * * **** *** * ** **** ** ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* * ** * * ** ** ***** * * data[2];
* * * * * sum;
** * * **** * * ******* i;
*** * *** ** *** * ** ** ** *** ***
** * * ****** * ** ***
** *** ** * ** * ** *** ** ** * * ****** ********* *** ** * *** *
* ***** ** * *** *
* *** * ** ***** ** ***** *
* ** ***** * ** ** *** ** * *** ** **** *
* * * ** * * **** *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * **
* * **** *** * *** **
*** * **** *****
* * * ** *







int ***** *

{


* *** ** int ** * *** **
* **** * *

** * * scanf * **** * ** ***
* * ***

*** * * ** while (a[i]!= ' ')

{
** *** *** **

* ** i++;
* * * * ** *

* *** ****** scanf * ** * **** * **** *** ** * *** *

* ** * **

}


* * * scanf * ** * *** * * * **


* ** * * while ** *** ***** ** * ****
** * * ***

* * * ** **** {
* ** **** ** * * ***

* ** * ** * * ** * ** j++;
** ** * ** * ***** * **

** * *** * *** scanf *** ** *** **** ** ** * * *

* ** ** * * **** ****

* * *** }
* * * ***

}
* * * **

** * * * for (i = 0,j = 0;;i++)
*** ** * * *

* *** * * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include * ** * ***

int main()

{
** * * * * ****** a,b,c;
*** * *** * * * * * *** * * * * * * ***** * *
** * ** * = a + b;
* ** ** *** ** ** ** ** *** * * * ** * * * *
* ** * * * ***** *** *** * * * * * ***
*** * **** * * ** * *
* * * * ** * * * * * ** **
*** * ** ** * ***** ** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include ****** ** * *

int * *** * y=999999999;

int main()

{
* * * * * * * * * * ** ***
* ** * **** * *
* ***** * *** ** **** *** * ** * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * ***** *** * *

int main(){
* *** ** * ** * * * a,b,c=0;
** ** * * ** ** **** * *** * * *** ** ** ** * *
*** * ***** ** * * * *** ** **** * * * * *
* * * *** ** ****
**** * ** * *** ** ** * *** *****
* * *** *** * * ** * ** * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.92
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 3.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.3k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users