0 like 0 dislike
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 233 views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * * * * * ** * ** * * * *** * * * *** *
** * * * ** ****** ** **** * * ***

    {
** * *** * ** ***** *** *** * * * *
** *** * ** *** ** * *** **** * * * **
* ** ** * ** * *** ** * ******* * * * * *** * ** * * ** ******* ***
* * * * *** * ** ** **** ** ***** *** ** * ** * * ** * ** *** * * *** ** ** * * * ****** *** = a[n] + b[n];
* * ***** * * * ***** *** *** **** ** * * ** ** * ** * * * ********* if(a[n]+b[n]>='10')
*** * *** * * ** * * * * ***** *** * *** ** * **** ** * ****
* ******* ***** *** * * ** ** * *** * *** ***** * * * *** * * * *** * ** * * ** = a[n] + b[n] - '10';
** * * * * ** ** ** * ** * * **** ** * * *** ** *** ** *** ** * * ** * **** * ** * ** ** ** *
* ** * * * * * * ** * **** * *** * *** ****** *** * * * *** * **** *
* *** * *** * * * *** * ** *** ** **
*** * * ** * * * * *** *** * *** * * ** ** if(t == 1)
* ****** *** ***** ** * * * *** * * * **
* ** * * * ** * * ****** * * **** * **** * * ** ** *** * * * *** *** ** **
* * * ***** *** ****** * * * * * **** * ** ** ** * * *** **** * ** ** ** * * *** * = a[n] + b[n] + '1';
* * * * * * ** * ***** ***** * *** ** * * *** ** if(a[n]+b[n]>='9')
** *** * ******** * *** ** * ** * *** * *** ***** * ******
* ** **** ** *** *** **** * * * * ** * ** ******* *** ** * **** ** ** ***** * * *** = a[n] + b[n] - '9';
* * * * * * ** * *** ** ** *** * * ** * *** ** **** * * ** **** * * * ** **
** * *** * **** * * * * *** * **** * *** * * * * * * * * * ** * * ***** *
* * * ** *** ** * ** * * ***** ** ** * * ***

    }
****** *** ** **** *** * * *

    {
**** * * ***** *** ** * **** * * * ***** ** * * ** **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* ***** *
* *** * *** * *******

int main ()

{

int **


* ** * * * **** *** * *** *
* * ***** ** ***** *


** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * *** *** *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
** * * * *** * *** * * a[100],b[100];
*** *** ** ** * * ** sum[200];
* * ***** ** * *** la,lb,lm,i,j,k;
** **** ** * *** ** **** %s",a,b);
** ** ** **** *** * *** * * * = strlen(a);
**** *** * * **** ** **** ** = strlen(b);
* ** ***** * ** * *** * * ** *
* ** ** * ** ** ** ** *** ***** * ** ***** * ** = a[i];
* *** ** ** * ******* * *** * * * ****** * * ** **** * * ** **
**** * * * * * **** ** *
** * ****** * ** * *** ***** *
*** *** *** * ** * ** ** * ** ****** * **** * * * ** += b[i]-48;
* ** *** ** ** ** *** * ** ** ** *** ** *** *** ***** *****
* * ** * ** *** ** * *
* * *** * * * * * * ** = strlen(sum);
* * ** * * ****** ** * * * ***** * * *****
******* * **** * ** ** ***** * * ***** * ** * ***** ** * * ** *
* * ** ** **** ** *
*** * * ********* * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * **** * * *
* * * ** ****





int main ()

{
*** a , b ;
*** **** * **** *** , ** *
** *** ** * ***** , * **
* *** * ** ,a+b);
* * * ** * ****** *** ** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * ** ** * * * * * *** ******** *
* ** * ** ** * **** ** * ** * *

    {
** ** ** * *** *** * * * ** * * ** * * ***
* * * * * **** * ** * * **** * ** * * **
*** *** ** **** *** * * **** ** **** ********** * * * * * * *** * *****
* ** *** * * ** * ** ** ** * * * * * *** * * * ** ** * * ** * * * ******* * = a[n] + b[n];
* **** * **** *** * ** ******* * ** ** ** ** * ** ** ** * *** * * if(a[n]+b[n]>=10)
* **** **** ***** **** * ** * * ** ***** ** *** ** ******
* *** * * *** * ** * ****** *** * ** ** *** **** * ** ** **** * ****** **** ** * * = a[n] + b[n] - 10;
********* *** * ** * ** ** ***** ** * * **** **** **** ** *** * * *** * ** *** * * * **
* * * * * * * * * * * ** ** ** * * * *** * **** ** **
*** * **** ** ** ** ******* * * ** *****
*** ** ** * ** ***** * * ** * * ** * * * ** ** if(t == 1)
* ** * * * ** * * ** * * * * * ** * *******
* ***** * * * ***** * *** * ** ** ***** * * * ** * * **** * * * **** *** * **
*** ** * ** *** * * * * * ** * *** ***** * * *** * * * ** * * * * * ** *** ** * = a[n] + b[n] + 1;
** * ** * * * ** ** *** * ****** * ****** ** * **** ** * if(a[n]+b[n]>=9)
** **** * * ** ** * ****** * *** * ** * * * * *** * *
*** ** * *** *** ** **** ** * * ** * ** ****** * * *** * * * *** ** *** * * = a[n] + b[n] - 9;
***** * * * * * *** ** *** * * * ****** *** ***** * ***** **** ****** ** ** * ** ** **** *
* ********** ** ** * * ** * ** *** * * *** **** * * *** * * **
** * *** ***** ** *** ** **** * * ** ***** *

    }
**** ** **** * ** *** ** ** * *

    {
** * ** ** ****** ** ** ** * ***** ** * * *** ** * * ****

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* * * **** ** ******* * * data[2];
* * ** * *** * * **** * * sum;
* * * * * ******** * i;
*** * * * * *** ** * ** ** **** *
* * * ** * ** *
* **** * ** ** * ***** ** ** * * *** * * **** * * * *** ** * **
* *** * ** ** * * ** **
* * ** *** ***** ****** ** **** * **
* * *** * * ***** ** * * ** **
* * ** * ***** * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** *****
* * ** ** * *** **
* ** ****** * ** *
****** * ** * * **







int * *

{


* ** **** int *** *
* * * * *

* * **** scanf ** *** *** * ** ** *
* * *** * *

** ** while (a[i]!= ' ')

{
** ** ** **

** * * * i++;
** *** *** * *

* *** scanf * * * ** ** * ** ** * ** ** * ** * *

*** * * *

}


* ** * * scanf * *** *** * * * ***


**** ** * * while * * * *** ***** *** *****
* * * *

** * ** {
** ** ** *** * ** * *

** * * * ** * *** * ***** j++;
*** * * * * **

* *** * ** ** * * ** ** scanf * * ** ** **** **** ** * * * *

** * ** * **** * **

** }
*** * *

}
* ***

* * * ** for (i = 0,j = 0;;i++)
* * *

*** ** **** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include *** * ** *

int main()

{
* ** * * ** * a,b,c;
* ** ******** * *** ** ** * * * ** **** ***
** * ** * ** * * = a + b;
* * * *** * * **** * *** * ** * *** *******
*** **** *** ** * *** *** * *
*** * * * *****
** * * ** * * * * ***** ** * ** * * *
** * *** **** *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * ** ** **

int *** * * * y=999999999;

int main()

{
* * * * * * *** * * ** * * *
* * ********** ****
* **** ** **** * * * *** ** ***** * ** * * **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * * * *

int main(){
* * ** * * *** ** * ** *** a,b,c=0;
* ** ** * *** * * ***** * ***
* **** * **** ** *** * * * * * * * ****
*** ** * * *** **
* ** * *** * * ** * * * ** *** * * ** ** *
* * ** ** ** *** ****** * 0;





}
answered by (-140 points)
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.63.158
©2016-2021

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 688 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: Unlimited - Due to: Unlimited
| 400 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 445 views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 229 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: Unlimited - Due to: Unlimited
| 10 views
11,257 questions
134,146 answers
132,336 comments
4,147 users