0 like 0 dislike
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
Available when: Unlimited - Due to: Unlimited

reshown by | 369 views

49 Answers

0 like 0 dislike
Hidden content!
* ** * ** * *


********** ** * *


** * ** * *


**** ** ** * ****




* * ( * *

**
***** * * * * * * ** * ** ***** * ** * ** * * * *
= d - *
* = c -
= f * b - a * e ;
= 0 -
** ** * *
**
** * * * *** * ** * = - *** ** * *
*


* *** * ** * *** * *
* *
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * ***


** ***
* ** **** ****** * * *** * * ** * * t = 0, a, b, c, a1 , *


**** * ** ***** ** ** ** * ** %f %f *** * * * *** * * * ** * * * ** * **




** * * * *** * ** **** ** = *** - / * * y2 - x2 * ** *
***** * * ** * * *** * = - * / * - * **
* * * * **** * * = - * * * - *


* * * * ** ** ** * ** * *** * * ** ** * * *


**

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * ** * ** * * **





int main(void)

{
** ** * ** * ***
** * * ***** ** **** %f %f **** * ** ***** ** * ** ** *
* ** * - x2 == * * * != 0)
* * *****
*** * * **** ** * ** ** = x1;
* * * **** ** *** * * = 0;
*** * * * ** * * * * * = -x1;
* * **** * ** * * *** *** * %f ** * ** ******
* * ** *
* *** if(x1 - x2 != ** * * != 0)
* ***
* * ** * * * * = (y1 - y2)/(x1 - x2);
* *** * * * * = y1 - (a * x1);
** * **** **** ** * = -((a * x1) + c) / y1;
** *** * * ** * * * %f **** * ** *
***** *
* ***** ** if(x1 - x2 != *** ** **** *** == 0)
* * * *
** **** *** * * = x2;
** * * * * ***** * * = 0;
* * * ** ** * *** = -x2;
** * *** * * **** ** * * *** ** %f ** * * *
* ******
*** * ** if(x1 - x2 == * *** * *** == 0)
* ***
** ** ** *** * ****** ** = 1;
** * ** ***** * *** = 0;
** *** ** ** ** * * * = 0;
* * * * * ******* **** * * ** %f * **** * **

 }
* * * * 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** * ** *


* ** * *** * * **


* * ** ** *


* * * * * *




** * ( *
*
* *
* *** * * * ** * * * *** ** ** ** ****
** = d - *
* = c - **
= f * b - a * e ;
* = 0 - *
* * *
*
** * * ***** * = - * * **
*


* ***** ** ** ** * * **
* * **
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * * * * * ** *


***
* ** * *** * **** *** ** ** ** * ** * t = 0, a, b, c, a1 ,


*** ** * * *** * * ** * * * * *** * %f %f ** ** ** * * * * * **** ** ***




*** * * * ** **** ****** ***** = - * / ** * y2 - x2 * * *
* * * * ** **** ** *** = ** - ** / * * y2 - * * *
*** * * * ** ** = - * * - * *
*** **** * = a * - **
* * * **** * ****** *** ** * = b * -
* * * ** *** * *** * ** * ***** * * * ** **


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* *** ** **** ****


* *** *
* ** * * ** ** ** * * * * t = 0, a, b, c, a1 , *


** ** **** ****** * * ** ** **** * %f %f * * ** * ** * * * *** * *




*** ** ** * * ** * = * - ** / * * * y2 - x2 * *
* * * ** *** ** * *** * * = * * - * / ** * y2 - * * **
* * * ** * ****** = - * - ** * ***
*** * ** **** ** * * * = a / - **
* ** ** * ** * * * = b / -
* * ** * *** ** *** ******* ** * ** *** ** *** **


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * *** ** * * ** *


* ** ***
* * *** * *** ****** * ** * * * t = 0, a, b, c, a1 ,


* ****** ** ***** * ** ** * %f %f * **** * * * ** * * * * **




** * * ** * ***** * * = * - / * y2 - x2 * *
*** * * ***** ***** *** ** = - ** / * * y2 - ** * *
* ** **** ** *** * ** = - * * - * ***
** **** * ** *** ***** = a / -
* * * **** * * * * = b / -
* ** * ** * ** ***** * * *** ** *


* 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
*** * ** * * *





int ***

{
*** * * *****
** *** ****** ** * %f %f * * * ** * * * ***** ** * ***
**** *** - x2 == 0,y1 != 0)
* * * ** * *
* ** * * * ******* ** = x1;
** *** * * * ***** = 0;
* * ** *** ** *** = -x1;
* * * ** ** *** ***** *** ********* ** * * %f * *
* * *** * *
**** * * if(x1 - x2 != 0,y1 != 0)
* ***
**** ** * * ** * = (y1 - y2)/(x1 - x2);
* ** * * * ** * * = y1 - (a * x1);
*** * * * = -((a * x1) + c) / y1;
** ** ** * * * ***** * * %f * ******* * **
** *
* * if(y1 == 0)
** **
* * * * * * ***** **** = x2;
* ** * *** ** **** *** * ** * = 0;
* ** ****** * * ** **** * * = -x2;
** **** * *** * *** * ** %f * * **
** ****
*** ** ** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* ** * **** * *** *


* * * * **


* **** * * * *


* * **** * *** *




* *** ( ** *

* * * * ** *
*** * **** *** ** * * ** ** * * **
* = d - *
* = c - *
** = f * b - a * e ;
= 0 - *
** ****
*
** * * *** **** * = - * * * *



* *** ** * ** ******** *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
** ** * ** ** ***** ** * x1,x2,y1,y2,m,a,b,c,c0;
*** * * * * * * ** * ** * ** ** ** ** *
** * *** ** * * * * ** * ** * ** ** *** * *
** *** * ** * * * ** **** ** * * * * * *** * * **
* * **** * ** * * *** * * * ** * ***

    m = (y1-y2)/(x1-x2);
* ** * * * * * * * ***** ** ** ***
* * * * * * ** ** **
**** * ***** * * **** **** * * *
*** * ***** * ** * * **
**** ** *** * ** * **** * * * * * * *
** * * * * *** * *** * * ** *** *** * **** * * %f %f",m,-1.000000,c0);
* * * * * * ** * * * ** ** if((y1-y2)%(x1-x2)!=0.000000)
* * * * *** ** * ******* * * * ** * * ** * * *
** **** ****** ** * * *** ** ** ** ** * *** * *** * *
* ** * **** * * ** *** ** ***** **** * *** * ** *** **** ** * *** ** * ****
** * ** *** * * * * * * *** * ** * ** *** ** * *** * ** * * **** ** *
* *** ****** ** *** * *** *** **** ** * *** **** *** ***** *** ***** * *** * *** **** * *****
*** * **** ** *** *** * ***** ** ** * *** *


** *** ** * *** **** *** * * *


* ** * * * * * ** *** * ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:173.245.54.227
©2016-2020

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 223 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 626 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 381 views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 216 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
Available when: Unlimited - Due to: Unlimited
| 10 views
10,943 questions
124,821 answers
118,847 comments
3,819 users