0 like 0 dislike
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 1.2k views

49 Answers

0 like 0 dislike
Hidden content!
** ** * * ***


**** * *** * **


***** * * * * ** *


* * ** ***** * * ****




* * ( * *
**
* * * * * **
* * * *** * ***** * *** * ***** *** *** * *********
= d -
= c - **
= f * b - a * e ;
* = 0 - *
* **
*
* ** * *** ** ** ** ** ** = * - * * * * *
*


* ** ***** ** ** * *** ** * *
* *
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
* **** * * ***** ****


* *****
* * * *** ** * * ** ** ** * ** * * * t = 0, a, b, c, a1 ,


***** ** ** * * * * ****** ***** %f %f * ******* * ***** ** ** *** * * *




* ** * * **** ***** = ** - ** / *** * y2 - x2 * ***
*** * ** ** ** * * * = ** - * / * - * * *
**** * * **** * ** = - * * - *


** * * * ** ** ** ** *** ** ** * * * * * * * *


* **

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * *** *





int main(void)

{
*** **** ** ***
* ** * *** * *** %f %f ** * * ** *** ******** ** * *** ** **
** ** * * * - x2 == * * * *** != 0)
*** * * * *
*** ***** ** ** * = x1;
** * *** * * * = 0;
** * *** * *** = -x1;
* * * * ** ***** ** *** ***** %f * *** * * ** *
* *** ***
* **** if(x1 - x2 != *** * ** ** != 0)
* * * *
* *** * * = (y1 - y2)/(x1 - x2);
** **** * * *** *** = y1 - (a * x1);
*** * *** * = -((a * x1) + c) / y1;
* ** * ** * ** *** ** %f * **** * * *
**
* * if(x1 - x2 != * ******* **** == 0)
* ***
** ** * ** * * ** ** = x2;
** * * * ********* ** * = 0;
* * ** ***** ** * *** ** = -x2;
* **** * ** * * * * * * * *** * ** %f *** * * **
*
* ** ** * if(x1 - x2 == ** ** **** == 0)
** * ***
* ** * *** ** *** = 1;
******* ** ***** * * = 0;
** *** ** * * * ** ** = 0;
** **** **** ** * ** * * *** * %f ** * ** *

 }
* 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
** * ** ** ** *


** * * * ***


** ** ** * ** *


* ** * * ****** **




* * ( *** *

* ** ** **
* * * * * * * ** ** * * **** * ** * * *
* = d - *
* = c - **
* = f * b - a * e ;
* = 0 -
* *
*
** *** **** * * * **** * = * - * * * * ** * **



* ** * ** ** *
* ** *
*
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * * ** * **


* ***
* **** *** * * *** * * * ** * * ** * t = 0, a, b, c, a1 , *


* ** *** ***** *** ** * *** * * ** %f %f ***** * * * * * * * *** * * * *




* * ** * *** ** = ** - * / * y2 - x2 * ***
**** ** *** ** * * * * * = * - / *** * y2 - ** *
* * ** * ** * ** ** = - * * - * * * *
** * * **** ** *** ** * = a * -
* ** *** * *** ** * * = b * -
* * * *** *** ** *** **** * * * ** ***


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * *** * * * *


*
*** * ** ***** * ** ** * * * * * t = 0, a, b, c, a1 , *


** *** * **** * *** * ** * %f %f ** * * * *** ** * * * **




** * * *** ** * ****** * = ** - / *** * y2 - x2 * **
* ***** ********* * ** * = * - * / *** * y2 - * ***
** * * ** *** ** = - ** * - ** * *
* ***** ** ** = a / -
***** * * * * *** ** * = b / - *
** ** ** ** * * * * ** **** * * **


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * * * * ***


* ** *** *
* * ** * *** * ********** * * * * * * t = 0, a, b, c, a1 ,


*** * * * ** ** * ** ** * * %f %f ** * * ** *** ** ** *** * ** **** **** *




***** * * * *** * * * **** = - / ** * y2 - x2 * **
* * * ** * **** *** = * - * / * y2 - * *
* *** ** * *** ** ********* = - * - * * *
*** ** ** * * ** ** = a / -
* * * * **** ** ****** * = b / -
** *** * * *** *** *** ** * * * * *


* ** 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
* * **** **





int **

{
* ** ** * *** *** *
* *** ** * * ** **** %f %f **** * *** ** * ** * ** *
** ** - x2 == 0,y1 != 0)
*** ** **
*** * * *** * * * = x1;
* ** *** ***** * **** = 0;
*** **** **** *** = -x1;
*** *** ** * * * * * ***** * %f ** ** **
* * * * **
* * * * if(x1 - x2 != 0,y1 != 0)
**
*** ** *** ** = (y1 - y2)/(x1 - x2);
* *** ** ** = y1 - (a * x1);
*** ** * * *** * *** = -((a * x1) + c) / y1;
** * ** *** ****** ** * * %f * *** ***** *
** ** **
* ** * if(y1 == 0)
* *
* *** * * * * * * * = x2;
* ** * * * *** ** * = 0;
********** * * ** * * = -x2;
* * * **** ** ** * **** ** * %f **** ** *** *
**
*** *** 0;

}
answered by (-100 points)
0 like 0 dislike
Hidden content!
* * * *** * * **


* ** * * *** *


******* ** *** **


* * **** * * * *




** ( *

* ** ****
* ******* * ** * * * ** * * *** * ** * *
* = d -
= c - *
* = f * b - a * e ;
= 0 -
** **

* * ** * * * * * * = * - * * * *
**


*** * * * * * ** **
***
**
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

#include<math.h>



int main()

{
******* * * **** * * *** x1,x2,y1,y2,m,a,b,c,c0;
*** **** ***** * * ** * * * ** * *** * *
****** ** ** ** ** * **** * ** *** * * * *
*** * * * **** *** * * ***** *** *** **** ** * ***** *
* ** * * * * * * ** * * * * ** *****

    m = (y1-y2)/(x1-x2);
*** **** * ** * * * *** * * * *** *
* ***** * ****** *** ***** * *
* ** * ** **** ** * * ** *
***** * * * * ***** ** ** ** **
* * * * * *** *** ** ** * * ***
* * * * * * * ** * * ** ***** *** ** * ***** %f %f",m,-1.000000,c0);
** ** * * ** * ****** if((y1-y2)%(x1-x2)!=0.000000)
* * * *** *** * ** * * ** *** * ** * ** *** *** * **** * *
* * * * * * * ** * ***** **** *** * *
* **** **** *** *** **** ** ** **** ****** * ** ** * ** * ** * *** * * * * * ** * *
* *** *** * ** ** * * ***** ** * * *** **** * * *** * * ** * * ** * ** * ** * ** ** * **
*** * * * * ** * * ** *** ** ** * *** *** ** * * * *** ** * * ****
* ** * **** ** *** ** * * * *** ** ***


* ** * ** * * ** * * ***** *


* * ** *** * * **** * ** ** %f %f",m*i,-1*i,i*c0);

return 0;

}
answered by (-102 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.175.73
©2016-2022

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 549 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.9k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.4k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 573 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
13,769 questions
207,306 answers
186,853 comments
5,422 users