0 like 0 dislike
947 views
直線方程式的通式為 ax+by+c=0 ,請設計一程式,由使用者輸入平面上兩點,程式會計算出直線方程式後輸出a, b, c。

輸入說明:輸入會包含四個浮點數,倆倆之間會用一個空白隔開,四個浮點數依序代表第一個點的x座標、第一個點的y座標、地按個點的x座標、第二個點的y座標。

輸出說明:請依序輸出 a, b, c 三個常數,每個數都需輸出到小數點後六位。請確保a, b, c 間的最大公因數為1。

輸入範例:

1.0 1.0 1.0 2.0

輸出範例:

1.000000 0.000000 -1.000000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited

reshown by | 947 views

49 Answers

0 like 0 dislike
Hidden content!
// *** ** by HoMingJui on 2016/11/3.

//



#include ** * ** ** *

#include * ** * ** ****

#include * * ** ****

#include ** * **** *





int main(){
*** *** ** * *** * ** x[2],y[2],a,b,c;
* *** * * * ** ** ********* %f %f *** ** ** * * *** ** ** * *** * * *
* *** * * ***** * * * ** * ** ***
* *** ** * * ** ** * ** * *
* * ***** * ** * * * * ** **** *
* ** ** *** ** * * ** %.6f ** * *** **
* * * * * * * ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
*** * * * *



int main()

{
* ** * * *** ****** a1,a2,b1,b2,a,b,c;
** * *** * * *** ****** * %f %f **** * * * * * *** ***** * ** ** *
*** ** ** * ** * *** **
* *** ** * * ** * * *
* **** ** ** * ** * ** ****
*** * * **** * ***** * * ** ** * %.6f %.6f",a,b,c);


*** * ** **** * ** 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
* * *** ***



int main()

{
* * * * * * * * a1,a2,b1,b2,a,b,c;
** ***** * ** **** * ** %f %f ****** **** *** *** * ** ** ** * * *
** *** *** **** ** * * *
* * * ** *** * ** **
* * *** ** * * * * * * **
* *** ** * * ** *** ***
** *** ** * * ** ** *** %.6f %.6f",a,b,c);


* * * * ** * * * 0;

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include **** * ** **



int main(void){


* * * * * ax , ay ,bx ,by ,a ,b * * *


** * **** * * ** * * * * * * * * *
* * ** * *** * * * ** ** ** * *** ******* ** *
* ** ** * ** * * ** * * * **** * * **** * * * **** * **** ** * ** *
** * ** * ***** *** ** * *** * * * * * * *** ** ** * * ** *** ***


* * *** * ** *** - bx) != 0){
** ** ** * *** * = (ay - ***
**** * *** * = -m*ax + ay;
******* * ****** * = m;
* * *** * * ** **** * = 1;
* *****
** * * * * **** *
*** * *** ** ****** = 0;
** ****** *** * * = 1;
* * * * * * *** = -ax;
* * *


* * ** * *** * * * = a;
* ***** ** = b;
* * * * * ** ******* = c;


* * ** ***** < 0)
* ****** *** *** ** ** * * = -i;
****** if (k < 0)
************ * ** ** ** = -k;


**** ***** (i < 1){
*** ** ** * * * * * = 1/i;
*** ** ** * ** * = a*g;
** * * ** * * * = b*g;
* ** ** *** *** = c*g;
** *
******* ** if (k < 1){
**** * **** ** ** = 1/k;
* * ** ***** * = a*g;
** * * * * * = b*g;
* * ***** = c*g;

 }
* * * *** * * *
*** * ** * ** ** **** *
** * * **** *** *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ********



int main(void){


*** *** ** * *** ** ax , ay ,bx ,by ,a ,b *** ** ***


** ***** ** *** * * ** * ** * *********
* * ** * ** ** * **** ****** ** ** *** *** ** ** *** *** *
** ** ** * * ** ***** * ** * ** * * ** * * * **
** ** * * * * ** * ** * * * * ** * * ** **** * ** ** * * * ** *


** ***** * **** - bx) != 0){
* * *** *** * * = (ay - ** *** ***
* * ** * ** = -m*ax + ay;
* * *** ** * ** ** = m;
* * *** ***** * * = 1.000000;
*
* * *** ** ***
* ***** * ***** ** * *** = 0.000000;
* * ** ** = 1.000000;
***** * ** * * * ** = -ax;
* *


* *** *** ** * * = a;
** * ** ** * * * = b;
* ***** ** * * *** * = c;


* ** ** * < 0)
* * *** ** * ** *** * * * = -i;
*** * if (k < 0)
* ***** *** ** * * * ** = -k;


* ** ** * (i < 1){
* ** * * * * * = 1/i;
********* ** ** * = a*g;
** * ***** * * *** = b*g;
** *** * = c*g;
* ***
* *** if (k < 1){
* * * * * * * = 1/k;
* * ** **** = a*g;
* * * * * * ** = b*g;
** ** * *** ****** = c*g;
* ***
** ** ** *
* *** * * * ***
* ** *** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* * * *** ** *
**** * * *
*
i *** ** *
* * a , b , c , ** * * * * * *
* ; i * ; *
* * * ** ** * , * * * );




* * * ** * *
* ** ** * ** = *
* * *** *** * **** * *** * = - * *



** * * *** * * **** ** **
*
******* *******
= * ****** ;
= ;

* * ** * **** * a , b **








** 0 ;






*
answered by (-87 points)
0 like 0 dislike
Hidden content!
** * **** * **
* ** * * ** *** * *

int main()

{
* *** *** ** * * ** ** a,b,c,d,m,x,y;
** * * ***** **** * ** ** * **** * %f %f ****** * ** * * ** **
*** ** * * ** * ** **** * **
** * *** ** * *** * * ** *

}
answered by (-103 points)
0 like 0 dislike
Hidden content!
#include ********* **



int main(void){


* *** *** *** * ** ax , ay ,bx ,by ,a ,b ,k,m,c;


** * * *** * ********* * * * *
* * * * * ** ** ** * * * ***** * **** * * *
* ** *** ****** * ** * ** ** * ** * ********* * ** * * * ** *
** ** **** ** *** ********* *** *** ** *** ** ** ** *** * * *** ** ***


** * ** * * **** * - bx) != 0){
** ** * ******** = (ay - *** * ***
** * ** * = -m*ax + ay;
* ** * **** ***** * = m;
** * ** ***** ** ** = 1.000000;

 }
* *** * ****
** * * ***** * ** *** = 0.000000;
******* * * * = 1.000000;
* ****** ***** ** * = -ax;

 }


* * * * ******
* *** * * * ** ***
** * * *** * *



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include *** *** **



int main(void){


** * * * ** * *** * * ax , ay ,bx ,by ,a ,b ,k,m,c;


* ** ** *** * * *** * ** ***** ** ***
* * * *** * ** * **** ** *** *** * *** * * * ** * *
*** * * * **** * * *** ***** * * * * * * * ** **
* * * ** ** * ** * * * * ** ***** ** * * * *** ** ** ** * **


* * ** * * ** - bx) != 0){
** * * * * * = (ay - ** **
** * **** **** * *** = m*ax + ay;
* * * * ** = m;
* *** * ***** = 1.000000;

 }
* ** **** *** **
** ** **** * *** = 0.000000;
* * *** ***** ** ** * = 1.000000;
* ** ** * * ** = -ax;

 }


* * ** ***** ****
* ***** *** *** * * *
* * * ** * ** *



return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.55
©2016-2024

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 477 views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.6k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 499 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users