0 like 0 dislike
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 923 views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
****** * ** * * * * * * * i=0;
***** ** * * * ** ****
** * * * * *** * ** * **** ***
* *** * **** * ** ** * *** * * *** ***** ** * * *** *** ** * **
** ****** * ** **** ** *** * * * **
**** ** * * * *** i;

}



int check2(char c)

{
** *** * * ****** j=0;
* * * * ** * * * * ****
** ** ** *** * * * *** * * **** ***
* * * **** ** ** * * * ***** ** * ** * * * * *** * * * *
** * ** ***** ** *** * ** ** * *
* * * * **** * j;

}

int main()

{
** * * ** ** * * * * c;
* *** ********* ***** i=0,j=0;
* ** *** *** * *** * ****** ** * **** ** **

    
**** * * *** * * * c!='.')
* *** *** *** ** *


* * ***** * * *** *** *** **** ***** * * * *
* **** * ** * *** * ******* ** ** *** * * ** * * *****
* * * *** ** * * ** * * * ** **** *** ** * ** * * ** *
* * ****** ** * ** **
** * ** * * ** * ** ** * * * * * * * **** ****** * **** * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** ** ** *
* * *** **

int main (void)
* *

char c;

int i = 0;

void * * c)

{
*** ******

i++;
* *** * *

i++;
* * * * ** * ***
*** * ** * * ** ****** * * ** * *
* * ***** *** *** *** **** * 0;

}
* ** ;

}
** ** * * * *** * ** * * * *****
** ** ***** ** * * * ** * *** *
* * *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
*** * * * * * ** * ** * a1=0,a2=0,a3=0,a4=0,in;
** * ** ** **** ** *** * ** * && c[in];in++)

    {
*** ** * * *** * *** * * * *** * * ** * * ** (48<=c[in] && c[in]<=57)
* * * *** * * ** * ** * ** *** *
* ***** *** ** * * ***** *** ** * * ** ** * * *** **
* * ** * ** * * * * ** *** * * * * ******* **
* * * * ****** * * ** *** * *** * ** * if(65<=c[in] && c[in]<=90)
* * * * *** ** * * ** * * *** ** * * * **
* * ****** * *** * * * * * * * *** * * * * * ** ** ** ** ** * *
******** ** ** * *** * ** ** * ** *** *** *****
*** ** * * * *** * * * ** * * * ** ***** * * * if (97<=c[in] && c[in]<=122)
** * * * ** * * * * **** * ** * * ** * ** * **
* * ** * * * ** *** * ** * * * ***** ** * * ** * ***** ** * ***
** ** * * *** *** ** * * * * ** ****
* * * **** * ** * ** ****** ** ** ***** if(39<=c[in] && c[in]<=46)
** **** * ** * ********** * *** * *** **** **
* ** ***** ** * * * *** ** **** ** **** * * ** * ** * * **
* * **** * **** *** * * **** * * ** * * * * ***** **
* ** *** * * * * * *** * ***** ** **** **** *
* * ****** * *** * * * * * ** * ** * ** ** ** ** **
** * * **** * ** * ** ** ****** * ** * *** * * *** *** *
** * ** * * * * **** *** * * * ** ** ** *** **
* * ***** * ** * * ***
*** * * ****** ***** ** * * * **** * **** * *

 }

 

 int main()

{
* ** * ** ***** * *** ** c[100];
* * * *** * *** * * **** * * * *
* * * * *** ** *** **

    
* * ******** * * * **** * 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** * * ** * * * * ** i=0;
* *** * * * *** * ** *
* * * * * * *** * * * * *** *** **
* * ***** ** ***** * *** ***** * * * ** * * ** *
* * *** * ***** * ** * **** ******** *****
* *** * * *** * * * ** ** * i;

}



int check2(char c)

{
* *** ***** ** j=0;
** * *** ** * ** ** *
*** * * * ***** * * * ******* ***
*** *** ** ** ***** * * ** * **** *** * * * **
****** * * * * * ** *** ** * * * * **
* * * *** * **** ** * j;

}

int main()

{
* ** ** * *** *** **** * c;
* **** * * * * i=0,j=0;
**** ** * ** ** * *** * **** ** * * * * *** * ***

    
* * * ** * *** *** * ** c!='.')
** *** **** ** *


* ** * ** * * ** *** ** * ***** * ** *
****** ****** ** * *** *** * *** * ** ** ** * *
* *** * * * * ** ******* ** * ** * ************* *** **** *** *
****** * ** *
* **** * *** * * * * **** * ** * * ******* * * ** ** ** * *** * * *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ***** ** * ** ** ** i=0;
***** * ************* * *** **
* * **** * * ****** * *** ** * ** **
*** ** * ***** * *** * ** * * ** ** * * *
***** ** ** * * ** *** * ** * * **
** * *** * * *** * ** ** ****** i;

}



int check2(char c)

{
**** * * * ** * ** j=0;
* **** * * * ** * ***** * **** *
**** ** * * * *** * ** *** * * * * * *
*** ** ***** ** * ** ****** * *** *** * **** * *
* * * * **** ** * * * * * *** ** **
* * * * ***** j;

}

int main()

{
***** ** * *** **** ** * c;
*** ** * **** * i=0,j=0;
* ** ** * *** ** *** ** * * ** * *** * ***
**** * * * * * ** *** * * * * ** to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
* * ** * * * ** **** *
*** ** ** * *** * *** * * * * **** * **** * * * ** **
* *** * * *** *** *
* *** * ** * * ** ** * c!='.')
** *** * ****** * * ** ** *


* **** ******* * * ** ** * * ** ** ***
** * * * * * *** ** ** * *** ***** ** *** *
** * * ** * ** * * **** * * * **** * ** ** * * * * *** **
***** ** ****** * ** * ***
* * * ** ** *** ** ** *** * ** * *** ** * ** * * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
***** ** *
* * * * * **

int main **
** **

char c;

int i = 0;

void * * c)

{
********
**
* **
*
*** ** *** * ***
** * * * * *** * * *** 0;

}
* * ;

}
* * * * **** *** * * *** *** *


}
** * * ** *** ** **
0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
** ** ** ** * ** * ** ** * *** c;


* ** * * * * * ** * i = 0,b = 0;


**** * ** ** *** * * **** * &c);
* * * * **** * * * ** c != '.')
****** *** * ** ** ** *** *
* **** * * * *** * **** *** ***** ***** * * ****






* * * ** ** *** * * ** * * * * * * *** ** ** += 1;


** *** * * ** * * *** ** * * * * * * * * ** ** ** &c);
**** **** ** * * **** * * * *** ** ** *
** * ** * * ** * ** *** * * * * *** ******** ** ** *


* *** *** ** * * ****** *** ** ** * * * * i);


** * ** **** * * ** * * * ** 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
* **** * * ** * ***
* * ** * **** *
** main ** **
* **** *
** c;

int i = 0;
* * c)

{
*** ** ** *
* *
** **** **
** *
*** ;

}
** * *** *** *** * * * * * ** *
** *

}








* * * * * * ** **
** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
***** ****** * *** **** * i=0;
*** * * ** * * * * * ****
*** ** * *** ** * ** ** * * *
* * *** * * ** * * * * * * **** *** * * * *
** * **** * ** * * ** * * ** ***
** **** ** *** * *** *** * * i;

}



int check2(char c)

{
* ** * ** * * j=0;
* ***** * * ** * * * * * *
*** * * * * * ** * * **** ** *
* ** * * * * ********* * * * ** ****** **
** * ****** *** ** * * * ** ***** *** * *
* **** *** * * * *** j;

}

int main(void)

{
* * * * * * ** * * c;
******* * **** ****** i=0,j=0;
** **** * * * ** ****** * ****** * *
**** * ***** *** * * ***** c!='.')
**** * * * ** ** * ** **


**** * * * **** ***** * * * ** *
* ***** ** ** *** * ** ***** * **** ** * *
** * * * * * ** ** *** ** * ** *** ***** * * ***** ** ** ** *** **

    }
** **** * * ** ** * * ** ****** *** * * ** ***** * ** *** ** ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* ** ** * ***
* * ** **** ** ** * *

int main ** *
* **
* * c ;

int i = 0;
* * ******* ******* ** * * ** *
***


* *** c)

{
** * **
*
* *** * **
* *
*** * ;

}




* ** * ** ** *
* 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:35.172.217.174
©2016-2021

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 300 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 567 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 654 views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 303 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,268 questions
164,383 answers
162,601 comments
4,640 users