0 like 0 dislike
2k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
********* * ** * *** i=0;
* ** ** ** * * ** *
*** ***** ** *** ** ******
*** * * * *** **** * * * * ** ****** ** *
* ** ** ** * ** **** ** ** * * * ****
** * * ** * *** i;

}



int check2(char c)

{
* * ****** ** * * **** * ** j=0;
** ** * * **** * **** *
* **** ** **** * **** * **** ***** *
* ** ***** ** *** * ******** *** ********* * *** *** ** *
*** ** ** ** ** * * ** *** * *
* * * *** * * * * * j;

}

int main()

{
* **** * ** ** * ****** c;
** * ** * *** * ** * ** * i=0,j=0;
** * * * *** * * * * * * * * * ** * ** ***

    
* * * * ** * * ** ** c!='.')
* * * * *** * * *** *


** * * ** * **** * **** **** * ***** *
* *** * * * **** * * * *** *** *** **
** *** ** *** ** **** ** ***** * * * * ** * * *** **** ** * *** *
* * ***** * ** ** *
* ** * ** * * * * ***** * ** * ** ** * * * * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
* * ** * * ***
* *** * ** *** ***

int main (void)
**** *

char c;

int i = 0;

void * c)

{
****

i++;
* * **

i++;
* ***** *** * ** *
***** * ** * ** * * * * **
* * ******** ** *** *** 0;

}
** ;

}
* * ** * * *** * ****
**** * * ** * * ** ** * * ** *
* *

}



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 

 void judge(char c[100])

 {
* * * *** *** * * a1=0,a2=0,a3=0,a4=0,in;
* * ** ** *** **** * **** * ** ** ** && c[in];in++)

    {
* * ** *** **** ******* ** * * **** * ******* ** * (48<=c[in] && c[in]<=57)
*** ** * *** * * ****** *** ** * * * ******** *
** * *** ** *** **** ****** ** ** * ** * * * * * *** **** *** * * *
** * ** *** ** * ** ** ***** * * * *
**** *** * * * * ** * ** * **** *** * * if(65<=c[in] && c[in]<=90)
* * *** ** *** ** * * **** * ** **** **
******** **** ** * ** *** * ***** * * ** * ** * **** * ** * * **
* ** ** * ** * *** * * ** * ** * *** ** *
** ** *** * * * * * * * * * * * * * * if (97<=c[in] && c[in]<=122)
* * * * * ** * * ** * * * * * **** * * **** **
** ** ****** ** ** *** * * *** ** ** *** * * ** ** ***** **
* * ** ** ** * * *** * * ** * ** *** * * ***** *
* * * **** * **** ** *** * ** ** ** * if(39<=c[in] && c[in]<=46)
*** * ** * ** ******* * ** * * * * **
** * *** ** *** * * ** ** * ** * *** **** * ***** ****** *** *** *** *
* ** ** * * **** * ** ** * * * * * *
*** * * * ** * ********* ** ** **** * * ** * ***
* * *** * * * * ** * ****** ** ***** * ***
** * ***** *** * * *** * **** * * * *** * ** ** **** * * * * * *
** ***** * ***** **** * * **** * * * ** * **** **
* * * * *** * * ** * * *** **
**** *** * * ******* * ** *** ** ***** * * ** * *

 }

 

 int main()

{
** * * * **** * * *** * * c[100];
* *** ***** *** * *** **
*** * * ***** ********** * *****

    
* ** * * **** * * * ** * ** 0;

 }
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** *** ** * ***** ** * * i=0;
* * ****** ** *** *** * *
* * * ** ** * ** ** ** **
******** * *** **** *** * ***** *** ** * * ****** * * * *
* * ** * ** **** * ******** * * * * *
* * *** * ****** i;

}



int check2(char c)

{
* * * ** * ** ** ** j=0;
* * ** *** ** ** * * * * *
** * ** **** * *** * * ** * ** **
******** ** * * * * * ** * *** ** ** ***** ******
**** * ***** ** ** *** ** ** **
*** ** * ******* ** * j;

}

int main()

{
** * ** * * *** * * c;
*** ** * * *** * * * i=0,j=0;
* *** * * ** * * ******* * ** * **

    
* * * *** * * **** ** * c!='.')
*** * * * * *** *


* **** * * * ** **** * ** *** * *****
** ** * ** * ** * * **** *** *****
***** * * ** * * ** ** * ** ** ** * * * ** ***
** * * * ** * * *** * *
* * * * * ** ** ***** *** **** ** * ** ***** * **** ****



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** ** * * * *** * ****** i=0;
***** ** *** * ***** ** * *** * * ***
* * *** * * * *** * **** * ***
** ** ** **** * ** * * ** * * * * * *** * *
* *** ** * *** ** * * *** * * *** *****
*** * ** ***************** ** i;

}



int check2(char c)

{
*** * ** ** * * ** *** j=0;
* ** * ** ****** * **** ** * **
* * *** * *** * ** * *** * ** * *
* * * *** **** ** * ** *** * * * * *** * *** ***
*** * *** ****** ***** ** **** * * * **
** ** * ** * * * ** * ** * * j;

}

int main()

{
* * * *** *** *** ** c;
** * ** *** * * i=0,j=0;
* *** * ****** ** **** ****** ** ** * **
** *** ** *** ***** * ** * * * to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.)
** * ** **** * ** * *
**** * * ** ** **** *** * *** ** ** ** *** * ** *
** ** ** ** ** * * ***
**** * ** ** * * * * * c!='.')
* **** * **** * *


* * * * ******* ** * ** ** ** * *
**** ** ** *** ** ***** * ** ** * * *** ****
* ** * **** * *** ** * ** ** * * ** ** * ** * ** ** * * * * ****
* **** **** ** ****
**** * * ******* * * * * * * *** * ** **** *** ** * ** **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
*** *** * * ****
* ** ** * *** * *

int main **
** ****

char c;

int i = 0;

void *** ** c)

{
** * ** *
* **
*** * **
**
* * *** * **
* **** ** ** *** ***** * 0;

}
;

}
* ** *** *** ** * ** ** *
** * **

}
** ***** * * **
** *** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>



 int main()

 {
* * * * ** * ** *** * * * * * c;


* * ** *** ** * *** * ** i = 0,b = 0;


* * * * * * ** * * ** *** * * * * * *** &c);
* **** * ** *** * ** **** c != '.')
** * ***** ** *** ** *
* * **** ** * * * * * * ** * ** *** ***** * ***






** * * ** *** *** * * * ** *** *** += 1;


** * ** * ** * ** * * **** **** ** ** * ****** *** *** &c);
** ** ****** ** * * * ** ** * * ** ** *** **
* * ** * * * *** * * * * ***** **** ** * *


* ** * ** **** ** * * ***** * ** * ** i);


* * * **** * **** * ** * * * 0;



}
answered by (-158 points)
0 like 0 dislike
Hidden content!
*** ****** * * *
*** *** *** *
** main *
* * ** *
** c;

int i = 0;
** ** c)

{
* ****
* **
** *
***
** * ;

}
** **** * * * *** *** ** * *
* ****

}








* ** * * ** *
* ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** ** * * * * * * ** * * i=0;
* * ** * ** * ** * ** * ** * ****
** * * * ** *** ** ** *** ** * * *
* ****** ** ***** ******** *** *** * * *** * * ***
* * **** ** * * ** *** *** *** * ** * ** * ***
* * * * **** * * * **** i;

}



int check2(char c)

{
** *** * * ** ** **** j=0;
* * * * * * *** * *** * **
** * **** * * *** * *** * * * ** *** *
* * * ** ** * * ***** * ** * * * ** ****** ** *** * * * *
** * * *** ** ** * ** * * ** * ** * *
* * ***** ** ** * ** * j;

}

int main(void)

{
* ** * *** ** * * ** c;
* ******* *** * * i=0,j=0;
* **** * * *** *** ** * ** *** * ** * ** *
**** ** ** ** ** * *** * c!='.')
**** * * * ** * *


* * * * * * * ** *** * *** * * * ** * ** *
* * ****** *** * * * *** * ** * * **
* * * ** ** ****** * * * ** ** * ** * ** **** * * ** * *** * *

    }
* * *** * *** **** * * * ** * * **** ** * * *** *** * * **



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
** ******* *** ***
* * *** * **

int main * **
**
* * c ;

int i = 0;
** * ** *** ** * * *
* *


** ** c)

{
* ** *
* **
* * *
***
* ;

}




** ** * **** * ****
** * 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.175.181
©2016-2022

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 595 views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 623 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
14,113 questions
223,115 answers
200,607 comments
5,464 users