10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
          * ***  *   * *
int main (void)
{
int  ** ***   
* *  * *    **  *  *   ** ** *
****  **
 *    
 *   **
  *  *   
** ** 
 **     
  * 
*    *   
 * *   * *   * * * * *     *****  
if *  ** **  * *   **  * ****  ** 
 ***
else * * ** *   *    **   
f2=2;
else if ***** 
  **
else f2=4;
 *****  ****  * **** **    
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 *  *** *****      * **   * *  a,b,c,d,e,f;
*   *  **  *   * **** *   * count=1;
*** *     *   * *** **  * **    ** ***   ***    **  
** * ** * ***    ** ** * *    *  * 
*********  ***  ** **     ****  * 
** *    ** *       * ** *  ** *  ***  * ** * *
  **      ** * *****   *   ** **   **  * ***
*  ** * *  * ** *** *    ** ***
 *  *** *  **** *   *   *   *  ** *  *  
    {
 ** *     * *  * *  **     *  ** *** *   ***      ** ** * **** 
 *** ******* ** **** **    ** * * ** * ******* * *  * * *  **
    }

 **  * **  **  *****  ** ** * ***   ** * %d",count,f);
 ***  * ****      **  *    ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
****** *  *   *   * *
int main()
{
***   * *    ***** ** *    *  * n,digits = 0,sum = 0;
  **     **  * ****  * ****   * * *** * * *  *  ** **   
  ** ** ***  *** * **  *     {
*  *****  ***  *    ****    ** ***   * *    ********** = sum + n%10;
* *  *  *   ***  *    ***     * *    *  ** *   *       
   * *   *  **  * **   ***   ** ***  *** * ***  ***  ** * *****
 ** * **    *   **     *** ** while (n > 0);
***  *  ** ***         *   **   ***  * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include      *  **  *

int  ** **** ***  **  ***      **
int d=1000;

int main(){
  *   *  *  *    **** *** *** ***  **   ***   *
 *  *  *  ****   ** * ** *  *******  ** 

*  ***** ** *   * *  * * * ***  * * **** **   *  *     * *   = a/d;
****** ***  **    **  * * ***   ***  * **** *   *    **    * *   * * * * ** * *****
****    ** **   ** **  *    * **   **** ** *** *   * * * *  = sum + currentdigit;
*  * *   *   ** ** * *  *****  **    ** ** **** * ****** = a - (currentdigit * d);
  ***  *** * * **   ** *  ** ** * * *  *  *  *  *   

 *****     ***  ****     *  **    *  *   ** ** *  ** **  ***  * %d\n", numdigits, sum);

 *** **  **  **** ** **     * 
     * * ****       **** **  * * *** * %d", numdigits, sum);
 **  ***      * * * *  *  * ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
    **  **  ***** **  ** **  **    n,digits = 0,sum = 0;
  * * ** * * **    *    ****  ***  ***     * **  * **    
 **   ****  **   **  ** ** ** * {
* ***   *    ***   ******  ** **  ** ****   ** **  * = sum + n%10;
 *  *  *   ** *  **** *  *  * *   ** ****   ******   *** ***
  **   *   **   ****    ** ****    ****  * ** * * *
* **  ***      **    * ***  while (n > 0);
** ** ******    * *   * *** ******  *     * **     * **
  *  *    ** * * *  * *  * * ** * ****  *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
    ******      **  **  * *  a,digits=0,sum=0;
 *** **   *** **  *** **  ** * ** *  *    ******  
 **  * * *   **** *** *** *****   {
*   ****   ** ** ** *  *  ** **  *   ** *** *  ***   ******  ****
*** ** * ** *** * * * * *  *  * * ***  *  * * **  ** 
**  * **   *  **       *  ** * *  **   * **      * *  *  *******
    ** **    *** ****  *  ***
**    *** ** * **  ** *  **  ** ** (a>0);

****  * *   * **      *   * ***    **   *    * %d",digits,sum);
 * *  *** **    ** * * ***** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
   * * ** *   ****  
int main **** 
{
int    * *      
*   * * *** *  **** * **    ** *  
** ****
* *  
** * **
  ****
* *
 * * **** 
     * 
  *  **
*** * *    *      ** **  ** 
if  *  * *** ***   
****
else ***   * 
*** 
else if   *
** *
else f2=4;
    *     ***  * ********  
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*  ** *** * ** *  * *    n,digits = 0,sum = 0;
** ****   ***   ** *       *  ** ***     *  **  *  *** * *
  ****** * **** * * ****       * {
** **** * ** * *     * * **  *** *     *****  * * ** *    = sum + n%10;
*   ** * ** *   ** ****** * * ***   ** * ***** * *  *   * **  ***
  *  *** **  *   ***     ** * ***   ** *       *    **   ****
  ****  *    *  *  *** *  while (n > 0);
 *  *   *****  *    **  ******  *** *  ** ** ** *  **  *   
  ***   *  * **    * *  * **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* *  *  ** * * **** *     a=1,b,c,d,e,f,g;
  *   * *** *   * * ****    *     **** * *  *  ** **  *
 *  *  *    *  *  *     *** 
**  *   ***** *** * *  *** *   * 
*  *  *****  **        * *** * **
   ***   * *  **** ** * * * * * **
**  ** **    * *        * *  *
    }
 * **    **  ** *** *    * * **  *
*****  **    **** *   ** * * * *
**  *****  **  * ****  ** ** *  
**    ** ** ** * * * *   *    **
* *** *   *******  *  ******** * ** *  * *** %d %d %d\n",c,d,e,f);
* * *** *****   * * **   **  * *  *  *   * %d",a,c+d+e+f);
****  * ***         * * *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 *  * *** * * * ** **  * ***  * * ***   num,digits,sum=0;
 *  *******  **  * *  * ** *     **    *  ****  *  ****  * **    
   ***   *    * * *   ***  * *  **   *  ** * *  **   **  * * *  * ***  * * *  &num);
* *****  *   ***  **   * ** **  ****** **
 *** *  ****   ***   ** ***
 *** ***  *  *   ***    * *  *** * *****  *  * *   *** *** *   += num % 10;
   * *  * * ** **  * *       * ** ***** ***** *** * ** **  *       *  * = num / 10;
*** ******  ** ** ***  **** ** *  ****   *   ** **   ** **** ***  * ** ** 
    }
    *****  *  *  **       **  ** * *  * **  %d", digits,sum);

   **     ** ***** ** ***     *  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output