10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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** * *   ** *******   * **    **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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*  ***** * * ***      * * * *  while (n > 0);
****  ****** ***** * *  ** * *****  **  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include  * *  * * ** *  *

int ** * *   **        **
int d=1000;

int main(){
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****  ** *   **    *  *  * * *****   ** **** ***  = sum + currentdigit;
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****  *    * *  ***        ** * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*****     ****   *****    ** n,digits = 0,sum = 0;
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* ** *   **** * *  **    * * a,digits=0,sum=0;
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**  ****   **   * *** *  *  (a>0);

*** * ** * ** *******   *  *  *** * ***** %d",digits,sum);
*** **   * *** * * *    * **  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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*  **      ***** *  * *
int main ** **
{
int ** * *   
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
****   *     *** **    ** * n,digits = 0,sum = 0;
****  **  **  ****  *** *  **** ****  ***    **
*  ******* ***      *  * *  *   {
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*     * * *  * *      *  **    while (n > 0);
*  *** * *  ** **** *     * **  **  *    ******** ***  **
 ***** *** *    **  * *  *  *   * * *      * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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 ***  *   ** ****    ******* ** %d",a,c+d+e+f);
* **** * *    *** *   ****  *   *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
**    ******   *  **** *  *  **      * num,digits,sum=0;
*       ***** * **** * ****   * *  *   ** * **** *** * * *  **      *** 
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    }
 *  **  * * *** *  *  * * *   *    * *   ** %d", digits,sum);

*** *  *   ** *  **  ** **  * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output