10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
******  *     ****   ** 
int main (void)
{
int * **    * *
    *  *  ***  ************ *   **  
*   *
*  ** * 
 *  *
 * ** 
 * ** 
 * *****
* * *
   *  * *
  *  * ** **  * *  * ***   * *    **
if *  *   * * *** ***    * * ***   *** 
 * 
else *   ****** *  *  
f2=2;
else if  *** 
** *
else f2=4;
   *   *  *  * * *  * *  * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 ***  **  *  ** **     **           a,b,c,d,e,f;
*    *  * *    *** * * *** ** count=1;
 *  *  *   *  * ****** * * *   *** * * ***** **** ** ** * 
**   ***          **   * *** * *  
*   * ** *         *   ** * * * *  *   
  **  * * *** *** *  *** * *****     ** * *****  *
 ** **  ** * ***** * *  **  ***   ** **  * 
  *** *  * **   *  **** *  ***  *****  *
 * ***   *  ***  *******   ** **  **  *** **  *  
    {
**    *     **    **   * *  * ** ** ** * ** * ***  * **** 
** *   * * **  * * * * * *  ****   *  * *  ** *** *  **   * *
    }

  ***** * *** *  **   * * *  **     %d",count,f);
  * * *   *******   **  ***  *    *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 **     *  **** * * 
int main()
{
  *  * * ** *   ** ** ** ** *   n,digits = 0,sum = 0;
**** *** * *** *  *** * *  *** *  *** ******   *  *  **
  *    * ** ** * *  **  * {
 ******    **     ***    **   ***     * ********* *** * **  ** = sum + n%10;
* *   *  *  ** ****  *** * *   ***** *   ** * ***    *    *
*** *  ** *   * * *** ***   **    *  *  ** ***   *****    **
* * ****     ***** ** * * while (n > 0);
** **** * ***** *  * **  * *   ** **  **   d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  * **  * **  *

int ***  ** * * ** **    **  *
int d=1000;

int main(){
   * **  * ** *   *   * * *   ***  * *** *** **** * * ** 
 * * * *    ***     **  * ***   * * *   ***   

*** *  **** *    **   *  ***  ***   *     **  *    * ** *  = a/d;
* ***  * ******** *  *   *    **   ***  *** ****  * * *   **** *   ************ **
 ***    **   **  **  ** ******  **    *  ** ****   ****  = sum + currentdigit;
  * **  *   **** **** ** * * **        ** * **   * *****  ** = a - (currentdigit * d);
* **** * *     **  *  *  **  * ***   * * *  * * *** * *

*  **  *  *** * *** *  *  * ** *** *  *****  *  ** *  ** **  * ***      %d\n", numdigits, sum);

** *      *** **  *  *   *   ***
    ** *  **   * * ****  *  ***  * * **  %d", numdigits, sum);
*  ***     * *   * * * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  *** ** ******  *     * *   n,digits = 0,sum = 0;
  *** * * *   *   * ***** *     *  * **** * ***   * *  *
*     * * * **       ****  ***** {
* **   *** *     * * * **** * *     *  *  **    * = sum + n%10;
** * **     **  *** *   *  ** **   **  *   *****   *    *
 ** ** * ***** **  *  *** * *  * *     ** * **   **    *  
* * *    ***   ** *** ***** while (n > 0);
      **     *    *  ***** * **      **  *  **  ********
 **  *   **     *  ** ****** *** *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 *    ***  *       ******* **   a,digits=0,sum=0;
  * ****   * **   *  *  * ***    *****  *   *   *  
 ****  * ***** *     ** ********  {
* **  *  *  *          ****  ** * * ** *  * ** ** *  *** ****  
 *  * *  *     ** *** * **    * *  *** *  * *        *** *
 *** **  *  ***  * ** **      ***  *   * * ** **   * * ****  
  * * *     *  **  *  ** * 
   * **      * * ** ** ** (a>0);

**  * ****   * * * ****   * * * ***   ** %d",digits,sum);
  **  ******  ** * *****   **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*  *** ***  * * ***  *
int main  *   
{
int * ** * * 
   *   * *  *  *   ** ** 
 *** 
 *  **     *
**   *
*      **
  ** 
*   *
*  *  
***  
*   *   ** *    ***  **  ** * **
if *      *
*  * 
else   *  **
** 
else if  *  *
*  
else f2=4;
* * ** *  *  ** * * *    *    * *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*   ***       *****  **** ***   n,digits = 0,sum = 0;
 *  ** *  *    * * *   * ** **  *  *** ***  *  *  *****  ** *
    *  **    *** **        {
 ** *   *****  * **   **    * ***    ** ** *   **  = sum + n%10;
**  ** * * * **  ***     ** ****** * * *      *** * * * * **
* *   ***    *** * *  ** * *  *    **      * *** ****  ****
 *  **   * *** *  **     ** while (n > 0);
  ***  *** ****  ***    *    *** ********  **    *   
** * *   ******* ** ****    *       *  **    d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  * *  **  *   *  *  **   **  ** a=1,b,c,d,e,f,g;
     ***  ******** * **  * ***   *** **   * * *   ** *** ** *
****  * ** * * **   **  ** * * 
*  * ** **    **** ** ** * **  ***  * ** *   *
  ** **    * *  **  * *** * *
 ** *** * *  *  *  ** ** *  ****
* *   **  * *  ** **  *  ****    * *
    }
*  *  *   *   **   *  * *     ***
 * *  ** ***      **** ***  *  **   * 
 *    *** * **  *  ** * * **
**  *   ** *  ** **   **  
 *    *  * ** * * ** * * * *****   %d %d %d\n",c,d,e,f);
*   *       * * *****    *   ** ***  %d",a,c+d+e+f);
  *    * * ***   **   ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* ***    *      ***  * ***    *  *  num,digits,sum=0;
** ******  **  * *** **** *** *     *** *** * ***  * ****  * *   ***
*** * ***  ***** *    **** * *    * * ** * * * *  * * ** ** *    *****   **** * *   ***** &num);
* **  *   **** **   ** **  *** ** * * *    
* ***** * *****   * *  
* *   ****    *** ** * ** ** *  **** ***** **  *****     *    ***  * *     ** += num % 10;
*  ** * ** *   *  *     * *   **  ***   *** * *****  * *  ** *   *   ** * * = num / 10;
 * *** ***** ** ****    * * **** ** ***  *    *   *     ** **  ** ** ** **       
    }
** *  * *      **    * ** ** *  **** ***  %d", digits,sum);

    **   **       * ** * ** *  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output