10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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{
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f2=2;
else if ***
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else f2=4;
***  ***     **    ***
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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* ** **  *** *   * **   ********    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
**  **  * *   ** * 
int main()
{
****** *   *** *   *  * n,digits = 0,sum = 0;
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* **   **    **** ***    ** while (n > 0);
  *   **    ***  ****  ***  * ***   ** *  **** ** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include * **  * * * *   *

int **     *  ** ***** * *
int d=1000;

int main(){
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* *  *   **  ****   * ** * *** *****  **    %d", numdigits, sum);
 **** * *** * **   **   *      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 *****  * *  ** **     *     *   n,digits = 0,sum = 0;
**   ****** *   *****   * **   ** **  *  * * * *   *  ****
  *   ***     *  ** ** **   {
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*    * *  *     * * * **  **  *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 ** *  *   * ** *   *    * ** * *** a,digits=0,sum=0;
*  *  * **   ** *    **   ******  ** *    ***   **     
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**  **     *** *  * * * ** * 
 **     *   ****  **** **     *  (a>0);

  * ***************       *   * ********* %d",digits,sum);
*   *  *  * ** * ** *** * *  *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
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int main *  *
{
int **** * * ****
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* *     * ** ***   ****  **     n,digits = 0,sum = 0;
  ********  ** **  ** ** *** **     **  * ****  * **
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** * ***** *****  * *  * **   **  ***** *         ** *** *  = sum + n%10;
** *  ***  * *** * * ** * * *     * *** ** **** * *  * 
*    *    *      * **** **     **  * * * **    *   *****  
*** **   * ** *  ****       while (n > 0);
* *     * * *  *    *  * ***  **       *  * ** * 
**   ** *  * **   * ***      * *  **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
   ** * ** **    **    * *** a=1,b,c,d,e,f,g;
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 *  ***  **  ** *  * *    ** ** * * * *  *  %d",a,c+d+e+f);
*     ** *   * *** * * *   * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*  **   **  ***    *  * * *  * *   ** **  num,digits,sum=0;
 * *       *   * * ** *** *    **  * *    * ***  *  *      *****   
**      * *    *  *   **  *  ** *  **** * **   * * * * *  *   * ******* *** ***  * &num);
**  *    *  *  **     **     ***     
*  *   * ** **  **  
 * * * * * *   ******  ** * *  * * **** *****  **  *   *   * * * ***  *  *  * *  += num % 10;
 * ** * **     *   ** *****  ***    * **    ***  ** *  ******** ** = num / 10;
*  ****** *  **    *  ** *          ** * * ***  * ***     *  ** * *  *** **  *
    }
* *   ** ** **    **    **** ***  *  **  %d", digits,sum);

**** * ** ****   ** ***    **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output