10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
**** **  **   *   ****
int main (void)
{
int    ******
***** * ** ** *  *  **
 * * 
** *   *** *
 ***  
***    *
* * 
* ***** 
**  
    ** 
  *   ***  ** **   * **   *  
if  *     *  **  * *   ** *   ***  * 
 *  
else  * * ** *****   ** * **
f2=2;
else if ****
  
else f2=4;
*  * *  * **  * * ** * *** *  
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 ** * ***  *****  ** ***** a,b,c,d,e,f;
**        *     ** * *   count=1;
**  * *   *****   ** *  * * ****  *   ****        ** 
 ** **** *  ** *   ** * ***
**  * ** * * * *  **  * **  *     *****
***  *    * * *   *  *  ******  * * **  ***  
 * *  ***    *  ** ***  ** *  ***** *   * *  *
***    ** **   ***   * **** * *
* *** *********  ** **** ** * *  
    {
  * *    * *    **    *  **    *   * * *  **   * **   *   ** *
*  * ***  ****  **   *  * ****  **  **  *    *  **  * *  **
    }

** *** **    * **  *   * ** * *     ** %d",count,f);
   **     * ** * * ** *** *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
* * *  ** ** **    *  *
int main()
{
 **** * *   ***   *** * **** n,digits = 0,sum = 0;
 *** ** *  *  ***** *** *    *  *   ***  *  * *** ***
 ** * ** * **   ** *** * *  {
 * * *  *  * **   ** *  **  ****  ****  * ***  ****     = sum + n%10;
 *  * **  * ** ** ***** ***  * *  ***** *   **  *
***  *** *   **** *  *  **  *** ***   *****    *  **  *
**    ** * ***    ** *      while (n > 0);
****  *** ******   * **  **  * ***  **   **   d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **   **** * ** *** 

int *  ** * *  ***  **  * 
int d=1000;

int main(){
********  ****    *    ** ** * *    *  * **  **      
**  *  ***  *   *  *   * * * **      ** 

  *   *** * *  ** **   * ***   **  * *  *  **** *** *    *    *     = a/d;
* *****   **** * *  *** * *** * * *    ** ** * * **  ***** *  ** *  ** **  * *** * **  *
**  *** *      * *  **  *   ***  * * * * * ***  *  ** = sum + currentdigit;
   * ***  * * *    * * **    *   **   ** *  *** = a - (currentdigit * d);
** *     **** *  ** ***    * * * ** ** *** ***  * ****  * 

 **      **     ** **  **      * * ******   *  ***** * * ***  * *  %d\n", numdigits, sum);

*** ** **   **  *  * * ** 
 *  *  * ** * ** *   *   ***  * ** ***  *** *    %d", numdigits, sum);
**** *  * *****   **  ******     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 *  *  *** *    * *    **    n,digits = 0,sum = 0;
   * ** * ********* *** *  * ** **** *     *******
* ***** *  **  * *  * **   *   {
********     *   ***  *** *    ****  **   ** *      = sum + n%10;
 *  ** **   * *** *   *  *** * ****      * *** *       *
**        **   ** ** ** ** **    *  * * **** * **    *** * 
   * ** *     ** **  * *  while (n > 0);
***  *   *** ** *** **    *  *  **** *  ***
**** **    ****  *  **  ** *** * **   **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* ** * ****  **     * * *   ** a,digits=0,sum=0;
* **   ** *** **       *  ** **  ** *      **  **
  **  *    ***  *    * {
 * *  *   *** ***    * ** *        ** ** *   * **      **     *
  ** * **   ***  ***  **  *****  ** ****    *     ***  
*  *  * * *   * *  * *    *      *   *** * ** ** ******    
 *  *  * *  **    * * 
 * * **  ***     * *   **** *** (a>0);

   *** ***        **  *  ***   ** ***  ** %d",digits,sum);
* ******* **  * * ***   *   *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
***  ** **  *******
int main *** 
{
int  ****   *
* * *    ***   * * ** * *       
 *     
       ** 
 ***
 ***    
* * * 
* *** 
** *  
  * ** *
***** **   **   ** *  *** ***      
if ***** * * *
*** *
else  **  *  
* 
else if  ***
*  
else f2=4;
**     ****  *    * *  * *  * **
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**   * **  ***   *** *  **      n,digits = 0,sum = 0;
* *  * *** *****  * * ** * * *  *  ***  * ***  ****  * 
  *****   ** * *  *   {
 *  * * ** **   * ****   *** **   **    *** *  * * *** *** * = sum + n%10;
**   *   *  **  * ****     *** * **  * ** **** * ****** *  
 * *     ******    * *       ********* *  * * **  **** 
* *  **   **  **    ** **      while (n > 0);
* ***     *     *      *   *    *** *  ***     **   **  *** 
** **  ** ***  *     *   ****   ** ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
** *  * *  ****   *  *       **  a=1,b,c,d,e,f,g;
*   **   ****  ** *  * ********** *  * * **** * * *  
 *  *   * ****  * ** ** *  * * * **
*****     **  ***    *** *  *   *      *  
**** * **** *****   ** *    
* ** * * ** ** **
**  *      * ***** *** *   * ***
    }
** **       ** * ** * * *** * **
  ** * *  *   *   ** *  ** * ** **  ***
  ***** *  * ** *  ***   *  *  * 
     * ***  ** ***        *   ** 
 ***  ***    * ****    ***** * ** *** **  %d %d %d\n",c,d,e,f);
* ***     **** ***** *   *****    ** * %d",a,c+d+e+f);
*   **       *  **  * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 *** **  * ** * ** ***    *   *** num,digits,sum=0;
  * *  ** ***  *  *   ** ***** ***     ****   * *  ** ***   ****
* ** * ****** ***** *   *  **  *******  *  * * * * ** *** * **  *  * ***  ** ***  *  &num);
  * *  * **   **** *    * * ****** *  *  ***
  *****  *   * *** * * **
  **  * *****       * *  *** *  * ***  ***** *      *  ** * *   *  * ****       += num % 10;
  **  *       *** **** **** **** ****** *  *    *     *  *  *   *  = num / 10;
* **  *  * **  ***   ** * * *** * ** *     *   *   ******* *      * * * *  *
    }
 ** *   * **    *  * *  *** ** *****    * %d", digits,sum);

***** * **   * * ** *  ***   ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output