10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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{
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f2=2;
else if *** 
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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*  ***   *** * ** * **** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
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int main()
{
* *    **** *     **   ***   *  n,digits = 0,sum = 0;
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* * * ** * * ***  *   *  * while (n > 0);
***  *** **  **** *   ***   *** * ***** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  *****  **  *

int ** ** **  *       ** 
int d=1000;

int main(){
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  * *** **  *    * ****  * * * *     **       *  *       ***   = sum + currentdigit;
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 *   ***** ***     * * *** **
*   *  **** ***  *   *  ** ***   * *****   ** %d", numdigits, sum);
    *  ***     ** *  *      *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
** **  ** ** *** * *  **     n,digits = 0,sum = 0;
**  ***  **** *** *      *** *  *  **  * ****  *  * * 
  *   ***** ***** **    ** {
******   **  ** * * ** ** **   ***  ****  **  ***  * = sum + n%10;
* ** *   *  * **   *    ** *   ***   * ***  ***   *
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* **   * *   *  * * *   **   ** *** ** ** *** *    ** ***
  * **  **    *   * ** **  *** ***    d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 *  *** **** ** *   ** *  * **** a,digits=0,sum=0;
 *** *  * *  ** * ***        * **  *       *   *  ***
*      * ** ***** ** * *   * *  {
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*   *** ****  * * *   ***** ** (a>0);

  ** *** *  * ***    ** * * ** * * *   %d",digits,sum);
   ******* * ***   * **   *  ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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       *   * *  **  **  
int main *  
{
int * *** ***
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else if *  *
  
else f2=4;
     * ** **  *  ** * ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
***  **   ** *    **    * **  *     n,digits = 0,sum = 0;
 ** ** ***** * * **   *   ****   *   *  ***   * * *   
****    **  **** * * ** *       {
* * *    **   *   *  *  *  *    *   **   *  **  *  *   ** = sum + n%10;
* *     ***  *  ****  ** ** * ** *  *** *    *    * * **
 **   *  **  *   * *    * *    *    *  ** ***** * * * * 
*  *   ** * **   * ** *  ** while (n > 0);
 **** * * **** *  ***  **** *  *****   *   *   *
*  * ** *  * *******  ** * *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**  * * *  * **   *   ***   * a=1,b,c,d,e,f,g;
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    }
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 ***   * ** ******** * **  *  * *    %d",a,c+d+e+f);
*** **  **   *  * ****   * **  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ** * *  ** ***  *  *  *  * **   *  num,digits,sum=0;
* ** * *   **       * *       *    *   ** * **      *  *****  *
* * ****  ***  *  * * * **   ****    *    *   **   *    * ** **   ***** * * &num);
 **   *               ****    *  ** * **  ****
 * * * **  ****** *  *** 
      * *****    * ****   *** * *****      * *****  **  *      * *   ** * **** += num % 10;
* ***   ***    * * * *   * * *   ******  ***** *   *  ** ** *  *  *  ** ***  ** = num / 10;
 * ** ** ** *       ** *     **   *** *    *  *     *     * * ***    **   *   **** **
    }
   *   ****  * *  ** *    * **   **   ***  * %d", digits,sum);

**   * ******   **    **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output