10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 * ** **** *  *  * 
int main (void)
{
int  *** **  * *
*  **     * * **** * **
*   **  *
 *   ***
 ***  
* *   
    
* * **
   *
*   
********    * **  *******  * **    * *
if * ** ***** * *****   ** ****    ***   * 
    *
else ** *  **    * ***** 
f2=2;
else if ** 
  ***
else f2=4;
  **   * *  * ** **   * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
          ****** **  ** *****     a,b,c,d,e,f;
  ***         *  *   **  ***   * ** count=1;
* ** *  *** * ** *       * ** *  * *  *   *  **    * * ** *
   ** ******* * *   * * **  *
*  ** *******  *** ****  * * *   *  * *
  **  * **  ** ** **  **** *     *   *****     
 * * * * *  * *  * *  ** * ** ** *   **** ** *
*  **     **** *    **   ****  
* **  **   **** * ************  *  **** *
    {
*   *****  **      * *  **   ** * *  ****  ***   ***
 * *     *****     ** **     * **  *  * ** *   * **
    }

****        *  ** ******** *** %d",count,f);
 *** **  **       **  *   **** ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
***    * *  * ***
int main()
{
* *   *   **** *   *  *  *     *  n,digits = 0,sum = 0;
  * *  * *     *  *   **** * **  **   * *******  ** **  ***   *  *
* *  *     **    **   * **** *   {
*  * ***** ******  ** * * * * *    ** * **    * *   * * = sum + n%10;
* * ** ******** **** *   ** ***  *  **        **   **** *
   * * *  **  *** *    * * *   **  * * *    *******  **** 
*   * *  * **  **   * *    *  while (n > 0);
 ** **** * **  *   ****     * **** * * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include  **  **    **  **

int * **** * ** ****      *** 
int d=1000;

int main(){
* **  * ***    **   *  * * * *  * ** * ** **   *
*** **** *** **   *  ***    ***** *******

* ** * **  ***   **   * *       *    * *   * *** *** * ***  * * = a/d;
**    ** * ****** **  *** * ****  *************  *  *** *     *   **   *     **  ** ****   ****
    * **       ** *    * *     *    ***  ** ** *    **** = sum + currentdigit;
     * **  **   * ***  *       *******  *   ** *    = a - (currentdigit * d);
     **     ** * ** ***  ** *  * * * *  * ******   ***** * ***  *** 

**  * * *   * *       * ***  *** * **   * * * * ******   *  ****** %d\n", numdigits, sum);

*   *    * **** ** * **  **
 *** *  *   ** ** ** * *     * ****     %d", numdigits, sum);
 ** * *  ***        **   *****   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
   * * * *    * *    *    *     n,digits = 0,sum = 0;
 * *  * ** *** *      * ***** *** **  ** ***  **  *
 ** ** * * ** *     ** *  ** * {
 ****    * ** * * ** **   *  * * *   **   *****  **   *** *  *  = sum + n%10;
* *  *** ** * ***    * *  * **  *   * *    *        ******  ** 
***  * ** **  ******      *** ** * ** * ***  **    *   *** 
 ** **  ** *  **   **   **** ** while (n > 0);
*** * *** *   **  ***  *** *  * ***   **   **  
     * **  ** * **  *  *    *  ** ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  *      ** **** ***** ***   a,digits=0,sum=0;
* * **  ***   ***      * *** * ***  * * ** ** **
*  ***  * ** ** **** **   *  *    {
 * **     ** ** ** * **   **   **      ** * *  ***  *  * * 
 * *  **  *   **** * * ** * *    *    ***   * *   
**** **   ** *       **     * *   ***** *      *  *   ***
* * ** * *  *** *  *** * 
**** * ** * *  **  *  *  *  * (a>0);

** *  * *** * **   ** * * *       *  *** ** ** %d",digits,sum);
***  **     **   ****** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
* * *  *   **  ** *  * 
int main * *
{
int *** **  *** 
* *  ****  ** ****  **  ***** * 
   ** 
 * 
**  ** 
 *  * *
*    
*** **
 *    
* ** ***   
* *    ** *   * * ** ********* ** *
if ******** ***  
**    
else **      
 *  *
else if   * 
** 
else f2=4;
***   ***  * *  * *  *  
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 ***  ********* *  **      * * ** n,digits = 0,sum = 0;
  *  *** ** ****        **    ****   *    *** * *  
   *  *  **** * ** * **** ** {
  * ** * ****** **  ** * ***** *  **** ** ****    *  ** = sum + n%10;
  *****  ***     ** *** **    * * *      ** *** *******   
*  * ** *  *****   *  *    * * * *  **  ** *   *  **   ****
*  *   *  *******     ** * while (n > 0);
** ** * * * ** * ***  **      **  ******   * ***  * ***   
* * ** ****  ** ** * * **         * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**** *   *      ** **  *   a=1,b,c,d,e,f,g;
   *   **  ***    *  * *  ** *   * *   * * * * 
***** *** ** ** **   *    ** *
 *  *    **   ** *      * ** * **   
**  *  *   *  **** * *  **  
  ****       ***  *   ****
   * * * ** *** ** *** ****  **
    }
** ******  **  *  * **  ** *
**  ***    ***  ****  ** **  *     **
 ***    *** **   *   **     **     * ***
 * *     * *   * ***    *** **** **
*  *    *   * **   ** ******  **** * %d %d %d\n",c,d,e,f);
    ***** * ******      * * *   * ** %d",a,c+d+e+f);
**  **  ****  *   *  ** ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*  * ****  * * ** ** * *    * *  ***   *  num,digits,sum=0;
 * **        * *       * ** **   *****   *  *****  * *       *  
 * **  **  *  *** *  * ** ****   * *  * * * *    ** ** *  * * *        ** ***** * &num);
  ** **    *    * ***  **** * ** ** * *  
*     ***   *** **** **
* * **  ********* * * * **    *         * ****  **  ***    *  *** *  *       * += num % 10;
*  *** **** ** **** *  ** * **   * **  *** ***  * *****  ** *   * **  *** *  ** * = num / 10;
***  **      * *  ****  * * *******  ** ****   ** *   **  * *   *  *  *  **
    }
**   * *  **  *  *  *  ***  *** **** ****   %d", digits,sum);

** ** ***       * **  ******* 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output