10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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int main (void)
{
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f2=2;
else if   * **
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else f2=4;
***   **  *  *  *   *  * * 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

  * *  ***** **  ** * *   **  ** **  *** * %d",count,f);
 *   * *** ** *** **   **** **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*  * **  * * ** 
int main()
{
  *  * * *****  ****   ***    n,digits = 0,sum = 0;
***** *** *** * **   *  ****   **** * **   * * 
*   *** ***  *    * * *   {
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* *   ****  ****  *  *  **  * **  ** *  **   *   **   ** * 
******** * * * *      ****   *  ** * * * ** ***   * **  *  *
   ***  *   *  **  * *  *  while (n > 0);
***   * ** * * * *   ** *   **  * * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **  * ****     ** 

int ****     *  **** *  **  *   
int d=1000;

int main(){
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****  ***    **** *   * *    *   * **   *  * *** * ** = a/d;
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   ******  * * *      * * ****   * * ***  *     * * *     **  = sum + currentdigit;
 *   ****** * * *** *   ** ***** ** ***  ** **  ***  = a - (currentdigit * d);
 * *********  *   * ****  *  ****  ****   ** *****  * ****  * 

* * *      * *** **       * ** ** *    * *** * *** * *  ** * * * **  * *** %d\n", numdigits, sum);

**** *** *  * ***** *  
**   * ** ******** *  ***  *  **    ** *     * %d", numdigits, sum);
** ** *  *****  *    *  ***   *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  ***    **      ** * ***** n,digits = 0,sum = 0;
  * ** ****  *****  **** ***** * **    ****  ** *** 
 *** **** *    ******  **     *  {
*****  ** **  ** **    ***     *  * * * * *  ******   * *  ** = sum + n%10;
*    ***** ** ***  ** ***  ***    ** *  *   *** ***   ***  ***
    ** **** *** *   * ** **  *  ** * **    ***** *  ****
  *** ** *    * *  ** * *** while (n > 0);
   * *  *  ***  *** * *      ** ** *   ***** 
* *  ** * * ******** *    *********  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  *****  **  ** *  *  ** **** * a,digits=0,sum=0;
   ** *  *     * ****  *  *  *   *   * **   *** ** ****    *
*  **     ***  ******  *** {
  *****  *  *       * * * **** * *      **   * **  * ***  ***
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  * ** * * *   **   * **** *  *** **  **   * **    * ***** ******
**  *      *          ******** *
*        *  ** ***** *  *   *  (a>0);

* *    *   *  **** ** * * * * * *  * *** *  %d",digits,sum);
**  * **** * **   *     *  **  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*  ** *  *  ******** *  
int main  * 
{
int **  ** **
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if * ***  *** 
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else if    *
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else f2=4;
** * *  * *   ***  *  
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
*  * ***  ***  * *  *  *** n,digits = 0,sum = 0;
*    *    ** **  *  *  ** *** **    * * **** * ***   *
******   *  * *  *  ** {
 **   ***  ** *  * ** *  * ****   *  **** **  *   *** *** * * = sum + n%10;
 ** ***** * ** ***** * *  * ** *  ***  * * * * **** * **  * **
 **** * *** * *   ** *   ** **   *** * **   **   ** **   *
  * * * *** ** *  *** ***** while (n > 0);
 **** *  ** **** ** * *  **** ***  *  *  ***  ****  *   
** * ***  *  *** * ** *  ** * * ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 *** * *   *  *  * *      *** * a=1,b,c,d,e,f,g;
 **  * *** *  ** ** ** *** * *  *    * *   *   *  *   
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    }
*  * **    *   ******  *****   
*  *  **** **   * * *****   *  * ** *    
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 *  * *  ****  * *  **********  *
 ** **   *  * *  **** * * *  * * ** * * * * *  %d %d %d\n",c,d,e,f);
    * *** ** ******   ** *  ** ** ***  ** **   * %d",a,c+d+e+f);
*   **   * **   * ** *  *** *  * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ** * ***  *  *    *** *  *** **   num,digits,sum=0;
 * *** ****   *   ** ** ******** *** * *  *     ** *  * *  
*** * *  *  * * ** **  **   **    * **   ** ** *** *    * *   ** * ** * **   ***   * &num);
*    ****  * ****     * *** ******   ****
     * ** * **  *      ** 
 **  ***   *** **   * *** ****** *  ***   ** * *  *   * *** *** ** *** ** *   += num % 10;
   ****  *** *** * ** *** * *** ***  ** * **** * *** *   **    ******* ** * ** = num / 10;
* **  *** *  ******** **  **   ** * **   ***     *** *     ******** *****    **** * **
    }
* * ***    *  **         *  **  * *  %d", digits,sum);

 * **     **     *** *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output