10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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{
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f2=2;
else if    
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

 * **   *   ** *   *** * ** * **  * %d",count,f);
       * *** ** **  ** **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
** * ***** *******  *    
int main()
{
  ** *   * * **** *     *    n,digits = 0,sum = 0;
*  ** * *       *      * ******* * *   *   ***   * 
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  * *   * * ***** * ***  while (n > 0);
 *  * ***  * * * * *    * **    ***    d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   ************  * 

int *  * * *    **  **  ** 
int d=1000;

int main(){
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* *     *** ***   *  **   * *          ***  *   *    *        **  *   * *** *****  * *  *      
*** ***   ******* ** *  *****  *      * *  **   ** *   *  = sum + currentdigit;
****   *****       * * *** *   ***    **** *   = a - (currentdigit * d);
 *** * *  *   *   *   ** *     *   **     ** *  **   *** ** ** 

****** ** *   **  *  *   * **  ***  *      ** *  * ***** *****  %d\n", numdigits, sum);

*** *** ** ** ** ****    *
*  * *  ******  **       ********   * * %d", numdigits, sum);
 *  *  *  * *    **  ** *   *  **** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  *    * ** * ****  ** ** *   n,digits = 0,sum = 0;
  **      **  ********** **  *  ***** * *  ** **** **  *  *
*****  **  * * * * *    **   {
 * *  *   **  *   * * *  * * *  ** *  * * * *** *** * ** = sum + n%10;
  ***** * **  * ***     **   * ** ** *          ****  *** 
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 *   **  ** ** * *  ** **   *** while (n > 0);
*  * ** ** **  ** *** *   *      *        **  ** * ***
**  **** ** ***  ***  *   *****    ***   ***  *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*   *  *  ****  ****          ** a,digits=0,sum=0;
*  **** ***  **   *  *    * * **** *    ***  * * ** * 
****  *    ***  ** * *    *****  {
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***  ***  ****** ** ** ** **  * * ******* *  *  *  * *  ** *
  ***   ** **** ***    **
 *  **   * *   *******  * *  *** (a>0);

***  * ** **  * *  ** *** *     *  *** %d",digits,sum);
 *** * * **   ** *      ** *   *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
   *   *  ****   **
int main    **
{
int    *  * * *
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else *    *
 
else if ** 
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else f2=4;
 ** ****    **     *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 *        *  * **** * ***  n,digits = 0,sum = 0;
           *    *  * ** * **   * *  ** **    *  * * 
 * * ***** ******* *  *  *** * {
 *****     ***    * * * ** **  ***    ****   *  ***  * * = sum + n%10;
  * **** ** *  *  ***  *  *    *   *** ** ***  
*     *** *  **  *****  **  ***  * *** ** ** **** ***** **** * ** 
 **  * * *** ******  **** * * while (n > 0);
 * *  ****** *      * *  **** *  * *** *    *  
* * ** ** ****  ***** * ** * *****  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*** * * * * *  *   **   * a=1,b,c,d,e,f,g;
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    }
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** *   * ***     *  * ***  ***   *
* ***   * *** **    ** ** * ** **   *  * *   %d %d %d\n",c,d,e,f);
*  *  *   *  **   *  ** ***** * ***   *   %d",a,c+d+e+f);
*  **   **    *******  ** *  * * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* ***** **      *  * *   **  * * *    num,digits,sum=0;
*  **  *   *   * *  *  ** * **  ***  *  *** **      **  **    * 
      **   * ** *  ** *** ** ** * *   **   * ****   ***   *     **   ***   * *** ** * &num);
***   **    ** ** * * * *  ** ***** **    *** 
*** *** * ***   ** **   *  *
 ** * *   * *  * **** * *     * ** ***  *     * ** **  ***  *  *** * ** ****** += num % 10;
 **  *   ****   * **       *   ****** *     * *    * * * * *    *  ** *  ** = num / 10;
*** ** ** * *  * *  ** *** *  * * ****  *   *   *  *  * **   *** ** *  * * **  ** 
    }
**  *        *****  *  ** *  *   *  * %d", digits,sum);

 *  * * ** ** **  ** **   *  *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output