10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
  * ** *          *   
int main (void)
{
int    *  *  **
 *   * * ***  *  *****  
*   * 
  * ***  
***   *
** ** *  **
 *  ***
*    
*  *
* *   ** 
 *** * * * *    **** *    **  
if **** **  ** *   *  * * *   **  * * *  
 * *  
else *** ** *  ** * ** 
f2=2;
else if **** 
** *
else f2=4;
**  ** ** **      * *** * * * *  *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
* *   *     **  * * *   *  **  a,b,c,d,e,f;
 **** * *  *   * **    * ** count=1;
** *  **   * ** ** ***** * * * * ** **    ** ****   ****
  ***  *  *** *** *  * *   **    
*   *** *   **  ** **  **  ** * **
* * * ********  **    ** ******** ***** ****
** *** *            ** * ** ***  *   **** **
* ***** *****  ********* ********* 
*  **   **  **** * * * * ** * ** *  **  
    {
*  * *  * * ***** * **** **      *   ****       *   * * *
*   * ** ***** * *** * *   * **   ** **  ****    ** **
    }

***      *    * *   ** *    * ***   *  * %d",count,f);
 * **      *   *  ***  *   ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 ** **  ***   * **    *** 
int main()
{
* *** ** * ***      ** * *  * n,digits = 0,sum = 0;
*  * ******** *    **     ***   *  * *** *        ** *** * 
* **   **  * * *  *  ****  *  {
   * *  * *  * ** * *       * *  *** ***** *  * * *  * = sum + n%10;
  * * * *  ** **** ** * *    *   *** *      ** ** ** **
 * **        ***   * ** *  **     ** *    *    * **  *** *
*  *** * **  * * * *    while (n > 0);
 *   ***    *     ***     ** *        *******  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *    ** ***      

int  *     ***    * *    ***  **
int d=1000;

int main(){
   * **   **** * *   *** *   ** **    ** ******      
*  *  **   ***  ***  **** **** * * 

 * ****  * * ***** * ** ***** ** ** *      * ** * *   = a/d;
  *** *** * **  *****  ** *****   *   * **        **  * *   *   ** ***    **** **** * ** ** ** 
  * ** * **  * *  *  **** *  *   *  *  *   * ** = sum + currentdigit;
 * ** ** * **  ****** **  * * * *** **  ** *** **  = a - (currentdigit * d);
    ******** **  *  *    ****     *  * * ** **  *    *    **

  *  ** *   *  ******  * *** *  * *****    ***     *     *** ** ***** ** *    %d\n", numdigits, sum);

       *  * * *** *  ** *    *
** **   *  ** * *    **  *** ** ** *  ** %d", numdigits, sum);
**** * * **  ****  * * * ***** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* ** ***** * *   *      * ** * n,digits = 0,sum = 0;
 * **  * * * **  * **  *   *  * *   * ******* * **  **  
****** *** *  ***    *** * * * {
 *  * ** **** **  ******  *** *** **  ** **** **   * ****  = sum + n%10;
  *  *  * ***  *    ******  *   **  *** * ** ***   * ** *** *
   * * *  * *  * ****** **  * *  ** ***  **  ***    * *    *
******  * ** * *** *  * **** * * while (n > 0);
*   ** * **  *  ** * *** ******       *     * *  *
***** ** *        **  *** ** ****  *** *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
   **    *   * ***** **  ** * * a,digits=0,sum=0;
*** * *  *  *   *  *   * *** ** * **   ***   ** * * **   
* * * * ****   ***   **  * *** {
**      *   *  **     **     * *    ** * * * *** ***** ***
 *  * * * ** * *  **  ** *  ****    ** *   ** ** **   *  *** 
       **  ******* *       **** ***  * * **  ** ******  *  **
  **  *  *  ****     **
****   *    *   ***  ** ** **  * (a>0);

* **  *  **  **  *** *  * ** ***** *  %d",digits,sum);
******* *   **   * * *  *   *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
** * * * *** *  ***
int main   **
{
int     ****
  ***** *   * ***    *   * *   * 
** *   
**  * * 
 **** 
** *  *  
 * * 
 * *****
 * ** 
 ****** 
* *** * * *   ** ***** *   * ***
if    ****  
**  
else **     
  ** 
else if **** 
 **  
else f2=4;
**     * *  ** *     **
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
***    * **   * *   *** * **  n,digits = 0,sum = 0;
 ******* *  * ***      *   * ***  ** * *** *    *
   *  **  *      * *  * *  * * {
*     *** **** **        ** ** ** **** ** **     *  * = sum + n%10;
* * **    **** * ***  * *   ***  **        * ***** * ***
** *** *  * ** **  ** ****  * * **  *** * * *  **  *** **  ***
****  *    **  *  ** **** * * while (n > 0);
*   **   *  **  *  ***** * ** *** **** *********  ** *   
  *  *   *   *** ******  * *  **  * * ** ** *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* **  *** *****    *  *** a=1,b,c,d,e,f,g;
 * * *** ** **** *  **    *   ***      **** *
 * * *      *  **  **   * *
  ***  ** **   *  * *  * **    **    * * 
  * ** *  *  * *   **   **
* *     **  ** **   * * ***  
**      ** * *    * ***   ******
    }
 *  **  *  *** **  *    * *  
 *   *****  ** *     *  ******* *   *
****  *  **** *  *    *  *  ** * ** ***
*  *   **  **     *    * ** *** 
  **     **   *    ****  *  *   **     %d %d %d\n",c,d,e,f);
  ** **  *** *  * *** ** *****   ** * %d",a,c+d+e+f);
 *   ***  * * ** *** ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
   **     **  * *** ** **   **   * **  *   num,digits,sum=0;
*  * **  * * * **** * ****** **    **   *  ***  **   **    ***
**  * *   * **    **       **    * ***   *  * * * * ***   ****  **   * *    *  *   * ** * ** &num);
* *      ** *  **   **** * * ****   *  *   
  *  ***     * **   *   ***  
*  ** ***** * **  ** * **  *  **  **** * ****     ** *  * *** ** ** *   *   += num % 10;
* *  **  **** * *   ** *  * ** ****  * ** ***  ** *****    ** **   ** *** * * = num / 10;
      *  *** **   *    ** *   ****   **** * * ** * *    **  *     *****     ******** 
    }
  ****  ** * *   **  * **   **  * ** %d", digits,sum);

   *  ** *  *  **  *  **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output