10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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* * *** * * *    *   *  *   ***   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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     * * **    *  *  *     *   *   * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include *  ***** *  **

int ** * * ***** **    **   *** 
int d=1000;

int main(){
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   **    *   ** ****  *  *  **  *  **** *   * *** * ****  * * * ***  %d\n", numdigits, sum);

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  ***   * ** *  * **** ****** * *  * * * %d", numdigits, sum);
 ** ** **   *     ** *  *  *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 *    * * *** **       ** * n,digits = 0,sum = 0;
**** *  *** * * * *** **  ** *   ****  ** * *  *      * **  
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****  ** *     * *  *  ** * *   *  *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
**** *******  * *  *  * * ******  a,digits=0,sum=0;
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* ***  *  **** * ***   *** **  * *  ***   *  %d",digits,sum);
 ** **       **     *    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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{
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* *  ***     ** ** *  **  n,digits = 0,sum = 0;
 *   *  *   *    ** * *** ****   *  ***   *  * *** *   **
**** *     ** ***   *  *  ** *** * {
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* **  *****   ** **  * *  while (n > 0);
  ***** *    *   *  ***    * ** **** *  ** * *     *  ** 
  ** * **    ** ***      * * * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* * *   *        *   ***  * a=1,b,c,d,e,f,g;
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 *   *       * * *****  *  *****      * %d",a,c+d+e+f);
   **   *  **  * **** * ** * * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  * * *  **** ***      **   ** **  num,digits,sum=0;
*   **    **      *  ***  ** * *  ** **** *** * * *   *   *  ** 
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** ******** ** *********  ** * *  *  ****  *** *** * * *  ***** ** **  ** = num / 10;
    *** **   **   ** *  ***  ***  ******* * ****  **   * **  ***  * *     *** 
    }
**  * * *** * ** *  ********* **     %d", digits,sum);

*  * **  *   **** **  *   **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output