10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
 * *         * *   *** **
int main (void)
{
int       **** 
   * **    ** ***     
   * *
 *     
**   
 * *** * 
 *** 
     
  * *
** *  * *
 * * *  ** ** **  **  * * * ***   
if  *** **  * **  *   ** *** * *
**  
else *** * **  *** ***       
f2=2;
else if *** * 
****
else f2=4;
   *  * **   *  **  * ***    
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
  * ** ***  *  *** ****  **    * a,b,c,d,e,f;
*  * **   ***   **********    * count=1;
  *** * *** *** ** ** ***  ** *** * * **** * *  *   * * *  **  
  * *  *   *  *   *  *  *   
   ***  **    ** *   * ***  *   *   
** * *  *  * * ** **  ** *** * *     * **  *  
  *     ***        ** ***   ** *****  *   ** * 
   **** *  * ** *     **   **    *
    *  * *    **   * *      * *  *  ****
    {
*  *  **** **** *  *** **** *****  ** **   *   * *       * * ***
*** **     *** * *****    *  ** ***  ***  * **     ****  * 
    }

*    **  **       **  *** **    ** *   * %d",count,f);
** ** ****** * *  **  * *   **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
   ****   * **  * *** 
int main()
{
**  ** * *      * **  *  n,digits = 0,sum = 0;
 ** *   **  * **   * ** **        ****  *  * *** ** *
 *  *    **** **  *** ** ***  {
 *   *** * ** *   * * ***    ** *      *** *****  * * ** ** *** = sum + n%10;
** ***  *** *  *   **  * * * *   *  *  *  ***  ** * * * *** *
 *     *   *  * **** **     ***** *****  ** ** ** * * * * ****
***  *   *   ****   * * ***  while (n > 0);
 ** **     *    ***  *    * *   *     *  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include * ****  *      

int         *   ** **   *
int d=1000;

int main(){
**   *  ** ****    * ***  *** ***   *** *    * **  * ****   
 *** * * * **   ******   *   *** *  * * *

***  *   * ***   *    ***   ** *** *  ********* ***  ** = a/d;
* * *** ** *   **   *  ***   *  *** ******  ** ***  **     ***   **   ** * * *  *** *  
*  ***** ***  * * *** * *    * **  *  ** ** *   *      * = sum + currentdigit;
* * *   *  **** **** * ** * * *   *****    * **   * ** * = a - (currentdigit * d);
**  ***** ** ***  *   **** * ** ** * *     *****   * **

   * * *    *******     ***  ** * * * ******   **    ** *  **   * *  %d\n", numdigits, sum);

*   **  *** ***  *****    *
   **  **   *  ** **  ** * * ** *  %d", numdigits, sum);
******* ** ******    *   * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**     *  **** *  **  *** *  n,digits = 0,sum = 0;
**       **  **  * * *** * **   *   *    ***  **  *     
*****  ** *      * **      *  {
*   ***      **   * *      * ***  **   * ** *****    *  ** * = sum + n%10;
 * ** * **   *  **   * ***** * **  *  **     * * ***   **  *     *
  **  *   ***  *    *    *   **** * * * ** **  *  **** *** * ****
* *  *   ***  **   * * **   while (n > 0);
*  ***** ***** *   ***  *** * * *   * *  * *  *
 * *  *   ***  *  ***  ***** **   ** ***** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
******* *    **    *   * *** *  a,digits=0,sum=0;
**   ******** *    ****  *  *    *  * * ** **   ***
** *  *     *  * * *  *   {
    * * *      *  *** *   * *** ***** * *****  * * **** ** 
  **  ***** **  *  *  *  * **  *     ***** *  *
**  **  * **   *      ** *****  ** * ** **** * ***  * *  **  *
 * * ***    *** * * *  * *  ***  
** *  *  *******  ***  *   *   ** (a>0);

 * **** * **   * * *    * *  * * * ** **  %d",digits,sum);
* * ** ***    * *    * ****   ** ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 *** * ***    *** **
int main     
{
int **  *  **  *
 *   *  *   ** *  *  *  *       
*   **
 *** **  
** 
 **  * 
  ** * 
 * ** 
 **
  *   
 *** ******  *    *** *  * *     
if *** * *  * **
 **
else  * ******
 ** 
else if   ** 
** 
else f2=4;
** **          *    **   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 * ** *    *  ******* *** * ***  n,digits = 0,sum = 0;
* **   **** *    **   **  **  * *** *****   **  *    
  ** ** ***  ****   * ** * ****  {
 * * ****  ** * ****  *  *     **  * **  *    **     ** **   *  = sum + n%10;
 **   **   ****     *  ** * **  ** *** ***** * *  *  * ** **  
 ** ** *       *   * *  * *   ** * *    *  ** ** ** ***   
*    *****  ** ***   ****   while (n > 0);
 * ***   * *    ** *** * ******  ** *** *     *  ****
* * ** ***  *  *   ** *    *   ***  ***   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 * * **   *   ** **  **  * *  ** a=1,b,c,d,e,f,g;
  *** *** * * *** *  **  ***** * *   * **  **  *    * * * 
**  * **** *  **  *   *      *  * 
* * *     *  *****   ******   *  * *** 
  * ****  ****  ** ** *** **  
**   ** * **  *  ** *******   
  *****  **  * ***   *  **   * *  *  
    }
*********    * *   ** ****** ** 
** *** ****  **  **** ** *  ** **   * 
*   *   * *  ** *** *  ******  **  ** **
  **** * *  * ***  **   * * **
 *  * *** *  *   * *****   **** ***** ********   %d %d %d\n",c,d,e,f);
*** *****  ***  *  * * ** *   * ****     %d",a,c+d+e+f);
* *  *    *  *  *    **  *  ** *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
***   ** *  ***  **  ***     *    * num,digits,sum=0;
*  *  * **      ** *** ** **  *  **** **** **** * * * **** **  
*   * *    **  ** * *   **  *   * *** ** *   * *  *   **   * ** * *  ***** *  ****  *  &num);
* *** *  ** ** * *   *   * * ** * ****
 ***  * *     * ****  *   ** 
*  * *  * *    ****   ***   *   *  * **  **   ** *  ****  *   * *  **  *** **  **   * += num % 10;
   * * * ****   *   *   ***   **  **  * *  * **** *  * *     ** * *** ****  ** = num / 10;
  ** *   *  *   * * **         * * **  * *   *  *   ** ******    *  *    **   *  **
    }
*** ** * ********* *** * *  ** ******* **  * %d", digits,sum);

 * * *** ***  *  ***** *** ********   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output