10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
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{
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f2=2;
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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
** **  ** ** *** * ***  * * a,b,c,d,e,f;
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**     * **  * ** **** *     **   *   ** %d",count,f);
**      **    *** *  * **** **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*  *   ** * * ** **  
int main()
{
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** *  ****  ***  ****   ***      ** ** ** *   *  **
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*    ** * * *       * **   while (n > 0);
******    **** **   *  ***  *   *** * * **  *  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **  ** **  * * *

int * *  ** *** *  **   * *
int d=1000;

int main(){
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*     * *   * *  *  *** **  **   ****  ***** * * ******* = sum + currentdigit;
**  ********* *  ** ** *********   *** *  ***   * * ***  ** = a - (currentdigit * d);
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 ***    ***  * **    ** *** * * *** *  *     * *** ****  * **   ** %d\n", numdigits, sum);

**** *  * *  **** **    * *
** *      ***     ***   ***  * * *** *** * * %d", numdigits, sum);
  * ***      * * *   ***  *** * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 * *******  * ***   *    *  n,digits = 0,sum = 0;
 **  *    *  **  ** * *****  **   * * *  * **   **   **  
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*  * **    *    *** ** ** *  * **  * while (n > 0);
*     **    **********    **    ** * * *   *   * 
    **         * * * *  ***   *****  *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  **   **     **   ** *  *  ** a,digits=0,sum=0;
    ***** **  * * **  *   *  * * **** **  ** *  **   *
*** * * * *  **   * **** {
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** ** ***** *   * *  * **  
**  ***   ***  *   **   *** ****** (a>0);

  ** *       *    *   **    *     ** *   %d",digits,sum);
***   ***     **  *   **** *   *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
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int main   ** 
{
int  * *** *
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else f2=4;
** * **    **  **  ****   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 * * *   *  *****     *   n,digits = 0,sum = 0;
*** **   *    * *  ***  *    ***      *  *  ** * * *
  *   ** *** ** **** ** ***     {
 * *   ** *  *  *****  *    *** * * * **   *** ***  = sum + n%10;
  *      *****  ***** **  ***** *   *  * **** * **** * **
 * *** *  ***  *** *      *** ** ***  * * ***  **    *
** * * ** * **  ** ***   * while (n > 0);
    *   ** *  * * ***  *  **  *  * ***  ****** *  ** *** 
 * *  * * *  ** ***   ** **  *   **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  * *****  *  *  *  **  * ** a=1,b,c,d,e,f,g;
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    }
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* ** **  ** * *  **  **  *  **     * **   *  %d %d %d\n",c,d,e,f);
  *** **    * ****   *   **** * ** *** %d",a,c+d+e+f);
 *  * *   *   ***   *** *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
** ******  * *** **  *   *    *   num,digits,sum=0;
  *  **  ** *  *  ****     **** ** ** * *** * * *  * *** *** *
   * * *********    *****  *  ** *** *   ** *   ** * ******* *   ** ******    &num);
   **   * * ** ** *   *   * ****  **** *  ** *  
 ** * * *********  **   ***   * ** 
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*****  ********  ****  ****   * *   ******* * * ****** * *  *     * *    **** * = num / 10;
*  * *  * **   ** *** * ***   **    *   **  * *  ** * *****  ** ***** 
    }
  * * **** *     ***     * **  *    **  %d", digits,sum);

* **   **     * ** ***  ** * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output