10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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f2=2;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*  ***    *      *
int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include * **** **    **

int * *  * ******* *****   
int d=1000;

int main(){
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*** * * * *   * ** * ** **  ******   * %d", numdigits, sum);
** *    ** *    *    **  * *  **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* *** *      *   ***    **  n,digits = 0,sum = 0;
* ***   ***   **   ***  *****    ***       **   **** * 
****  **  ** * *      *     ***   {
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* * ************  *    *   * **   ***** **** * *
 *   *** ** **  * ** *   *  *  * ** * *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* ***  ***** **  ** * ***   *  *  a,digits=0,sum=0;
****** ** * *   **  **  *  **  * ** ******  ** **** 
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 *         **  *  *  ** * 
* *  *  * ** *      **     **   (a>0);

* *** *  * ** * * * * *  **   *     *****     %d",digits,sum);
*     *****   *  **  *    *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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***   * **  *  *  * *** 
int main * 
{
int  ** *   * 
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
    **  **   ** *****   **   n,digits = 0,sum = 0;
   ***  *   **  *  ***   *  ** ** * *     ******   ********
*****    *  ** * *  * * *******  {
 *  * *  ***** * ***    *** **   ****    *   ** *** ** = sum + n%10;
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 * * ** ** *** * **  ** **  * * * *  * ** *  **  **  ** *   *
   ** ***   ******  *** ** *  while (n > 0);
** ** ** * * ***   **** * ****  ** ****** * * ** ***  *    
 * **** * ***** * *****  ** **  *  ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 ** *   **     * ** **  *  *** **** a=1,b,c,d,e,f,g;
  ****** * * **    * ** *****   *   *  **  ** * **    
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    }
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*  * ** *   *** * ****      **   *     *  %d %d %d\n",c,d,e,f);
 * *     * ** *    **    **  **     *      %d",a,c+d+e+f);
    ** **   *    *****  ***    * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 * *  ***   **  * **** ***   * * **** * ***   num,digits,sum=0;
*   *** ***  * * * *      ***    * *  ******    *  ******    **** *  
*   *   ** * ********  * ** *  *    *  ****  **   ****  ****  *  *  * *    * ** ***  &num);
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  *      ***  *  **  *   *
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 **   ** * * *   * ** *   *      *   * **   ** *   ***     ** ** *** *  * *  *** *   = num / 10;
** * * * * ***** *     ***** **  * * * **  *** *********     **** ** ***  ***
    }
 ** ***         **  **   **  **  *  *** %d", digits,sum);

** ** **** * ** ** * *   **  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output