10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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***    *   *******  * ** *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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* *** *   **     * *    while (n > 0);
**** *    * ***   * ** *** **   ** **      d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
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int  * *  *   ****   *
int d=1000;

int main(){
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** * ** * * * ****   ***  ****
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** *****    *    * ****  *  *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*     * *    * * * ****** *    n,digits = 0,sum = 0;
*  **     ***** * **   * * *  *   **  * * *   *** **  
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**** *  *     *** ** ***  * **   ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* ****  *     ***     * **  a,digits=0,sum=0;
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* * * *    * ****    ** *   ***  *** *  ****  %d",digits,sum);
 **   *  ** *  **        * *     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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*  **    *    ** * 
int main * *  *
{
int * **** 
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**   ** * * * **     *  *  ** * n,digits = 0,sum = 0;
*  *** ****  *  *    * *  * * * * * *  ****** *** ** **  
     *** *  ***** ** ****  *  {
***   *  ** **     *** ***  *   *     * *     = sum + n%10;
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*   * * * *  * ****       *      *  *  **  **  **** * ***
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  *  * * * **** *  *  ***** ** ******    *  **   * * 
* *   ** ** *   ********* * ** ** **   * * ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
******* *** *   ** **  * ***  * a=1,b,c,d,e,f,g;
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    }
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*     * *   ** ***** **  *** * %d",a,c+d+e+f);
     **      * *    *  * *  **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* * ** **  **    * ** * * *    * **  * num,digits,sum=0;
  **    ** * *   **     * **  **** * ****       *  **** * **   
    * ** *** *    **    ***  ***** **  **** *  ** ****  * *** * *     ********   &num);
**  *   ** **    *  *   *****    **  
* *  ** ****   * ***  *   
*    *  * ** ****  ****     *    ** * ** *    * *   *   * **  *  **** *  += num % 10;
*   *  * * *  ** *** * *     ** * * ****** *  * ***  **  ***   * * ***  * * = num / 10;
**    *******  *    ** *  ** *** * ** *  ** **   * *   ***** ** *** *     *   *    ** 
    }
   * * * * * ** **  **   * ****     * ***    %d", digits,sum);

 ** * * **   * ***  * *** ** ** ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output