10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
        **  *       *
int main (void)
{
int   * *  *
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if   **   **    **** ** ** ** *  *
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else  *      * ** * *  
f2=2;
else if *** 
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else f2=4;
*       * *         *   * *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

 *   **  *   **      **** ** *  * *    * %d",count,f);
***   * *  ***   * **    *  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
  *    ** * *  *  * **
int main()
{
     *** ***           *  *  *** n,digits = 0,sum = 0;
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* *   *   *    ** **    *******   {
  ******  **    *   *** *  **    *   * ***   *   *   = sum + n%10;
**   ***    ** *  ******* * * * ** *  * **** *      ****    
****** * ***   **  ** *  ****** *     ** ** * * *  *     * * * *** ** *
     *  ** * ***** ** *  while (n > 0);
   *  * *       ** *  ****   ***     *  ** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *   *  * **  ***

int  * *    * **  ****  ** ***
int d=1000;

int main(){
  **  *  * ****  *** ****  *    ** *   * *   * ** *****  * **
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   * * **     **  *  *   ***  **** * * **   *** *  * * **** * * = a/d;
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   * **  *  ** *  * **  ** *  ********* **      **   = a - (currentdigit * d);
*****   *****  *  ***   * ** **********  **   **     *  ** * 

  *    *    ***   *  * * * **    * ***   *     ** *  ***  ****  * %d\n", numdigits, sum);

**  * *  ** **     ** *   
**  **  *** **   *  *******  *  ** ****  %d", numdigits, sum);
******* *  * ** ***   *  * **   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*  *  **   ***  * ****   *  * n,digits = 0,sum = 0;
** ***    * **     *    *    * ***  *  *    **  
*** **** *** * *  **************  {
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* **  **  * * *****   * * ** ** ** ** ** *    *** 
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 ******* ***  *     **      while (n > 0);
 * * *    ** *  *      * **  *  **** * ********   *  ****
* * *** **   ******    **  * * * * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*  *  *****  ***  **    *  ** a,digits=0,sum=0;
** *  *  **  * * *  ** ** *  *  * * ***      **  *  **
****** *     * ** ** **  *  *  {
* * **** *  *** *** *    * * * *         *  * * ** *** ** **  * 
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 *  *  **** * * ***  ****** *
* ***** *   * ***  *    * ** * * * *  (a>0);

 ** **  *** *   * ***  *    * * ** **    **    %d",digits,sum);
  ***    *  *   * ***** **  ** ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*  * * *      **  *** * *
int main * **
{
int **      
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if  * *** **
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else if  *  
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else f2=4;
  * ** ** *      ***  * * 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
  ****  ********** * ****  ** n,digits = 0,sum = 0;
* * *  * * ** ** *   *   ***  *  ** *  **    ** **  * 
  **   ** **  *  ** *   ** ** {
*****   *** *** * * **  **   *   ********   * *  * ** ***  = sum + n%10;
  **  **      ***  ** * *** ****** *   ** ****  **  *   *** **
*    * *  * * * ** *    *  * *  * * * *   * ***  *  * *  *
 ****  ** ** *** **  **   * * while (n > 0);
 *  * *** * **     * * *  ****   ** *  *   **   *  **  
*       * *   ************ * *  * *****   * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  * **   ** **  ***    a=1,b,c,d,e,f,g;
*  ***   * ** **  *  *  * * *   *    *   *  * *  * **  
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    }
*   *** * ** * **   ** *** * *  *  
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 **** *****   *  * **  ***        * *
 *** *** * ****  *   *** ** * **
 *        ***  **** * *  ** * *  *  **** * %d %d %d\n",c,d,e,f);
 *****  *** * ***   *  *  * ***   * *  *** **  %d",a,c+d+e+f);
*** **  ****** *    *  * **   *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
   **     *    **   * * * ** *       num,digits,sum=0;
 ***   *  **   *  * *  * ** ** **    * ** **   * * ** *  ** * **  ***** *
  **** **  *    ***    * * * *** *  * ** *  *   *** * *   **  * * * *  *   * &num);
 * ** ** *   **    **** *  ******** *** 
    ** *  ** *** *   * *  ****** *
*     * *******   *    *  ** **   ** ****  ** ** ** ***** *  *****   * * ** += num % 10;
  * * ** ** **   *   **  **     * *  * *  * **   *** * * *  * ***    * * *   = num / 10;
**   ** * * * *  *     * *   *****  *  **   * * * *  * **    ***** ****  *  **   
    }
 *  **  *****  ****   *  *** **   **  %d", digits,sum);

 **** ** *   *  *** ** *****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output