10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
***  ** *   *** *    ***
int main (void)
{
int          **
 * * ** ** **  **   *  ***   
 ****
     **** 
 *     
** ** 
* **  
  *  ***
***
 * ***
 ** *********    *** *  ****    ***
if *****         **  ***  **   * ***
     
else *   *  **    * ****
f2=2;
else if **    
    
else f2=4;
 *  ****** ** ** *      * **   *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
******  *    ***   **  * ** * a,b,c,d,e,f;
  * *  **  ***  ***    * ** count=1;
 *     **   **     ** ** * *    *  *    *** * ** 
****   * *  ******  **  *  
  * ******   ** *** *** * **  * * * 
***  *    ** *** **** ***  *    * *** * **  * *** 
* * ***  ******   *   **    * *  **** * * *    ** * 
    ***    ***** *   **  **  ** * *
 *     * * * * *    *    ********   
    {
** *** * **   ******* * * * *     ** ****  * *  * *********  *  
 * *  *  * * *****  **   ***    **   **  * **** **   **
    }

**   ** ***     ***** ***  * ** ***   * *  %d",count,f);
** *** *  *     *  * ***  *********  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 **  *****  **  
int main()
{
**** **    *   * ** **  * ** n,digits = 0,sum = 0;
** *  *** **  **  * **  * *   *   *   **  ***     ** ***  * *** *
* ** *  *** ** ****   *  **     {
  **     **  ***  ***  ** **  *    ** ** * **   ** **** * *** = sum + n%10;
 ** * * *** *** **** * **     * ******  ** *  ***  ** **
 **    *  * **   * * ****  **   **  ** **  *   ******* 
**    **      * **    **   while (n > 0);
** **  *  **   ********* *   * ** **  ** * d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include *  *    *    *

int  ******    * ***   * *
int d=1000;

int main(){
 ****** * * * * ***   *  *   * *   **    **       
** * ** **  ***  * * **  ** ***   *  * *    * 

  * *  * **   **** * *  ***    **  *** **    *  * ** * * *   *  *  * = a/d;
  ***  *  *  * * ***   * *  *****    *** *    *     * *  *  *   ** ** *   ** ** **   
     *  *** *  **    ** *       **   *  *    ******     = sum + currentdigit;
* *  * ** **   *** ** *** *** * * * ** * *      *****   * * = a - (currentdigit * d);
*** *  *    * ** **  ****    *       * *  **      *  *** 

 *** **** ** *    * ***   *****    ******** ****** *** *  *  ** ***** %d\n", numdigits, sum);

* * **** **** **    ***  ***  **
* *    **  *    * *   * *  * *   * **   *  %d", numdigits, sum);
*   ***   *** * * **** *** ** * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**    * **  **  * ********   *   **** n,digits = 0,sum = 0;
 * **  *  *   ***   *   **  ** ***  * **** **  *** * *  
*    *** *  * ******  ***   *  * {
 ** *  ***  *  *    **   *       **  ***    * *  * * * * = sum + n%10;
  **** **  *    *  ** ** * * *** *** * *    **** *    *
 ** **    ****** *   * *  * ****   * * **** **   ** ** 
 * *     **  * **    ** *** *  while (n > 0);
  ** * * *  * ***   **  ***** *  **   * *        *** *****
 *   ** **  * * ** *  **   ** * **  * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
** ** ** * *    *** **   *   a,digits=0,sum=0;
*     ** **  *  *  *   **  ** * * *   *** ** ** **
**** *  ** * * *  * *    * {
* ***  ** ***  * * **  *** *   *  *    *  *   * ***  **  ** 
*  *  * * * * *    *** ** ***  * **       ****    ***   **
*     * **  * *    * * ***   * *** *  ***  *     *   *  ****
* * *   ***** **  *  **   **  *
  *     * *    ** ** * ***  * * (a>0);

   ***  * ** ** **    * *    * ***   *  * %d",digits,sum);
  * *  ** *** **  ** ****  ** * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
*      ***** *  *  ** **  
int main  **
{
int ** ***  ** 
  **  ***  * ****  * ***** *
*** * *
* *   
** ***
 *  *    
  *  *
   *** *
 ***
*** * *** *
 *  *  *   *   ***  *   ***   **   
if    ** *  *  
 *** 
else **   *   
 * *
else if ** **
* ***
else f2=4;
* **   * ***** *  **     **   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
* *** * *   * ***** *  **   n,digits = 0,sum = 0;
** * **  *****  * *** * * *** * **  * ***** *  **  **  *
** ***** ** **** *** **   *  {
****      * **** **  ** *   *  ** **  *****  *   * = sum + n%10;
 *   **   * ** ** ****   * *     *        *
 ***  *  ******        * *   * *** * * *****    * ** *   *
* *     ** **     *  * **   while (n > 0);
*  * ** **  *    **    ** *   ** ****   ****   **    * *** 
  * *******  * *   *** *** *** ****  *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
 *** ** * ** *****  *  *  * * *  a=1,b,c,d,e,f,g;
*  **  *     *         *  ***** ** *** *** ** *** * *  **
*    ** **  * * ***   ***   **** *
**  * ***  ***      * *****  *   * **
 * *** **** * *  *  *  **
  * **  *    **** * ** *  * 
*      * ** * *  *********** ** **
    }
   ** *  *     ** ** *  *   *  
   ** * * * *** ** ***** * *****  *
*   *  ****  ******   *   *   *  **  
    **  ***        *  * **   *****
*** *  *** ** * * * ******  *  **** ** %d %d %d\n",c,d,e,f);
* *******   *           **  ********* %d",a,c+d+e+f);
  *** *  *  *  ** * ***  **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*    **   *  *    *  * * ** **   *** * num,digits,sum=0;
 * ** ***** *  * **  ** *  *   * *  * *******  *  ******** *  * *    *   *
 *   * ***** *   *   ** *   ********      * **       *   *    ***   **  *** &num);
*       **    ****  * *  * * * * * *   * * *  * * *
**   * ******* *   *  *  ** 
** * ***  * *   * ***** * *  ** * * ** **        **  *** *  ** ****   += num % 10;
*  ****  *   * ***      ***  *   *     * ** * **   **** *******  * *** ****    = num / 10;
  ***** *  **      **** ** **   **   *** ** ***   *  ****  *******  **  ** *  **
    }
** ******   *  * * **   *  *  *   * * %d", digits,sum);

  * *  *  *** ***   **  **  * *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output