10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
* *  * * *****  **
int main (void)
{
int   ****  * * 
***   *  * *     *****   ** *
* *****
 * ***
 **  
* *** 
    
   * 
    *
***  ****
**  **   **   *** *   *** ***     ***
if  *  *** ** *   ******  ** ***
***
else **   * ** * *  * *
f2=2;
else if *    *
* **
else f2=4;
 ** *** * * **  * *    
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
  **   *   ** *  * * **   ** a,b,c,d,e,f;
** * **    *****     **     count=1;
** * **  * *   ***     *** *** ***     * ***           **
** *  ***   **** *       ** * *  ** * 
* **   *** ** **    *  * *** ** * *****
***  * **     * ****  ***   ***   *** *
*  * ** * **** *********  **  **    **  *   * *** *
*  **** ***   ***    ****  * *     
 *** *  ** * ** **  *       *** *  * ** *  
    {
  **  *  *****   ** **   *  * *  *** ** ****  *  ***  * ***  *** **
 ****  ****     * * *** *  **  *   ** * **   *  * *** ******* *
    }

 * ****   *****   * *  **** * **       %d",count,f);
   ** ** * ** * ***  ****** *   * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
 * *      **** *    *** 
int main()
{
****  *     **   * **   * *  *  n,digits = 0,sum = 0;
* **  ******  ***  ******  * ** * *******  **      
  **  * *  ****  ** ***  {
 *    *     ** *   **   ****** ***      ******* *  *   * = sum + n%10;
 *  *  * **  *  * ** *   ***    ***** * ** * ***** ***   ** **
** *  * **** * *   * * * *** **  **  *** *** **    * **
  **  *   **  *   * * *   ****   while (n > 0);
*  ******  * **   * **  * **** * **** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include   ***  *    *** 

int     ***   ****** ** *  
int d=1000;

int main(){
    *    *  *** * * *** **  *  * **   *   *  * *   *  
  *** **  *** * *****  ** *   * * * * * * *

    *   *** * **** ** *  ***   ** * *   *    ***    ** * *     * * ** = a/d;
* * **** **   ******   * ** *  **  *    *   ***  *   **        ***** ** ** ***    *  *  * **
*  * * ** * * ** *   * ** * **  * *** **  *  **  *   *** = sum + currentdigit;
**   *****  *** **       **** *  **  ** *      ** *  ** * = a - (currentdigit * d);
  *** * *** *** *  ***** ** * ****   * ** *    *******  *  

  *****   **   ** **** ***   **    ******  * *** *** *    *  %d\n", numdigits, sum);

* * * ****       ** **  *
*** *      ***** *  * ** * * *   %d", numdigits, sum);
  *  *** *     * ***  *  ****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*   *     * ** *** ***  * * n,digits = 0,sum = 0;
   * *  * * *  *    *  * ** ** * *  ** ****   ***** **** ** 
*  **  * ** *  **** ** * **** {
 *    * *   ** *  * *  * ** **** ***  *  * *  **  *  *  *  = sum + n%10;
   *** * *   * ******      ** ** *****  * * ** * *  *  
* ** *  *    ***  **   **  * *** *  *  ***   ** *  ****  
 *  * *  * ****    * *  *** while (n > 0);
* * ** * * *** * * *    * *    * ******  *   * ** *
  * ******  *   *    **  * * **   ** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 **  * ** *   *  *  *****  * a,digits=0,sum=0;
 **   *       * **     ** **   *   * * ** ***   *  * 
*** **** **   *** ***   **   * {
  * *  **  ***** * *  * *    *** * * ******   *   *** *  *  * * *
 **    ***  ****  *  ***     **  *  **    * ** *  **   *  ** ****
 * ** *** * **  * ** **     **   **  * *** * ***** * *
  * ***** *  * *     ** *** *
  **  *   *       *   *   * (a>0);

** ***   * *  **  **  ** **** * * *     **  %d",digits,sum);
   * *  * * *   * ** ***   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
* ***          *  
int main * ** *
{
int  ***  * ** 
 *  ***** *** **  ********
  ** *   
 ***  * **
* * *  
*********
 * ** *
**  **
* ***
*    **
  **  *    * *   *** *  *   *  ** **
if   ******   
**  
else * ***  **
 ***
else if  *
* * 
else f2=4;
    *     * *  ** *   ** * 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
***** * * **     ****    ** **  ** n,digits = 0,sum = 0;
***   ** * ** ** **   *  * *** *  *    * ** * *   *
  * **** **  **       *  ** **  *  {
 ** * **** *** *  ******* ** ***** *  ***  **  *  * **** = sum + n%10;
* *   **** **    *   *    *  ** * ** *   * * * * *
 **     * * *  * ***  ** **    *  **** *   **  ***** * *** *** **
*  * **** * **** * *  *  ** while (n > 0);
 *** *  * **       ** * ***  * ******     **  * *******
* **  ******* ***    ** ** *  ** ***** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*  * ** ** *   * * *  **  * * a=1,b,c,d,e,f,g;
*** * *    * ** * *   ** *******  **   ***  *      * 
 *     **   ****** *****  * 
  * ** * ****  **   ** * ** ****  *** *
 *  *       * **   *   ****  *
** * **  ** *   ** * * *** *
  ** *** **** * *  * * *** ** *
    }
    ** *   *** * *   **   **   **  *
  * *  *  ***  ** ********    *     ** * *
 **** * **     * * **  ** ** *****    ***
  **   *    ***** *    * ** *  * *  
 ** ** * ** *   * *   ** ** *  * **** ** %d %d %d\n",c,d,e,f);
   * **  ** ****  ** **  * **  ***  *  * * %d",a,c+d+e+f);
*   **       * *  **    * *  **    * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  **** *  *  **   *  ***   *     **   num,digits,sum=0;
 * *    *   **   * * ***  *    *  *    * ***  * ***  * * *  ** 
    * ** *  *     *     *   * ** **   * *  * * ***   * *     ** *** * **  * * * &num);
*****  * * *   *  * **  *          ****   **
* ** *     ****  *    ** * *   *
   ** *   *  **  ** **     * ***     **** * **     *   * *   ****   ********* += num % 10;
 ** *** *   *  ** ** * **   * * ** ****** *****   *** * *   **        * *    = num / 10;
* * * * ** *  * *   * * *  * ********    **  *** ** *   * * * *   ** **   ***      ** *** 
    }
**    *** *  **   **  *  *    ***** *** ** %d", digits,sum);

   **  **  **  *   * ** **  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output