10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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**  * * *   **    *  * * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include  ** ** ** *** * **

int *** * *             *
int d=1000;

int main(){
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**  ******  * * *****  ***** **    *    **** %d", numdigits, sum);
      *   ***  *  * *  * **** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*   *  *** * * **** * ** * **** n,digits = 0,sum = 0;
 *    * *   ** ******  ****  *  **** ** *  ** * *  
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*  *   *** * *** *** ****    while (n > 0);
**** * **** *** *      *   ** * ****  * ** * *      *  
 * * ** ****  *  ***** *       * *** *  * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
   *******  **  *  *     * *  * * a,digits=0,sum=0;
 **    *    * *  * *  ** * **  * **     *  *     * 
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*** ** * *  ****   * ******  (a>0);

 ***   * *  ****** **  * **  *  * * *  ***  %d",digits,sum);
* **** *** *** ******* **     * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
        **   *** 
int main *** 
{
int  *  ** *** 
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
    ** ** *  **** *** *     ****** n,digits = 0,sum = 0;
** * *  * **  * *      * *   *   * * ** **  ***** * 
   *  * *      ** ** *   **    ** * {
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**   **  * *  ***  * *  *   * ******    ** *  *  *** *
*   * * ** * *   ** * * * ** *       **   *    *   *  * *   ** 
 ****   *    * * ** *      while (n > 0);
** **     *   ***    **  **   ** *****   * ** **** ** *
  **  * * **       * * *  *  *      d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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******   **       *  *  ******   ******* * *  * * * 
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*    **** * *** * **** *    ******* **  * * %d",a,c+d+e+f);
   *** **  ***  *  ***** * **     0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  **  *   ***  * * *   * *****    num,digits,sum=0;
    * *  **  ** * * *     ** *  ** *** * * **** **    * *** *** *       * 
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   * ** * *  * * **  ******* *  * ***    *   ** **   ****  * *****  ** *   * ***  += num % 10;
  *   ****   **** *    *  *   * **    **  * ****  *  ***  * **    ***   **  = num / 10;
 **  *** *  * * ****  *** ***  *  * *** *** *** **   * *** *  * *     ** *   *  ** 
    }
* * * *   * *** ** *       *  ***  *   *  %d", digits,sum);

* ** * * * *  *** *    *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output