10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
**  *  * *     ***  
int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include  ***  ** *   *

int **   *      *  **  ** **  
int d=1000;

int main(){
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**   **    ****** * ***    * **   **   %d", numdigits, sum);
* *** * * *** **  *   ** *** **   *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
*  ***** ** ***   ** * ***  * n,digits = 0,sum = 0;
* *    * * **  ***** ****  **** ** *** * ******
**** * * **** *** ***   {
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 **** * ****  * ** ***    ** *** **   * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* ***   * **   *     **  * * *  a,digits=0,sum=0;
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**  * * **    ** *** *    *   (a>0);

 ****   **  *    **   * *** ** **** ****** %d",digits,sum);
 * **** ** *      *   *  ** ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main   **  
{
int *** *
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else if ** *
    
else f2=4;
** *   ** *    *** **  *
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**   *  *  **  * * ***   ***** ** n,digits = 0,sum = 0;
** *  *   *  *  *  ** *** **  ***** **** ** **  ***     * 
        * **** * *  * *******   {
  **   *  ** *  * * ** **   * **  ** * *  **** *  *     * *   = sum + n%10;
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*    *** ** *  *   *  **  ** while (n > 0);
 ** ******* **    *   * * * *  *    *  *   * * * *** ***  
 *  *    ***   *** **** * *  **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*      *    * *  ****** * * a=1,b,c,d,e,f,g;
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    }
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**  *  **     *   ***   ** *** ********* * %d",a,c+d+e+f);
*** *  ***    * *****  *  ** *  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
* * *   * *** * *  ****** * *** ** * num,digits,sum=0;
 ** * *  * **** *     * * *** *  ***  *   ***** ****   **   *** 
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***    *  **  ** *   *  *   *
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    }
 * * *  **   ***  *****  *    **** *   * %d", digits,sum);

*** *   * * ***     ****  **    0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output