10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

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#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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int d=1000;

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* ***** ******   * **  * * *** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
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**   *  ** **  *   * *******  *     *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
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**   * *   ***  ** *** ** ****   *   ***  %d",digits,sum);
*** *** ** ** *  * **** *  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main  ** 
{
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else f2=4;
**  * *** **   *   ** ** ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
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    **** *   *** *** * * **** *****   ** * * *  * *  
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**** *  * * *  * *  *****  *  ** * *  **  * ****    * *  * 
****   ***  *   **     *   **  while (n > 0);
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  ***** *  ** *  *****  *     **** ***  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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  * ******** * * * ***   * **   ** * * %d",a,c+d+e+f);
*** * * * **  **  *  *** *  ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ** ****  * * *  ****  *********  *   * num,digits,sum=0;
    **   * * *** *    **  *        *   *********  * ***   **  **   **  
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    }
** **** * * ** *  * * ** **** %d", digits,sum);

*  ******* *     * ***    * ** * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output