10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
*      *      *  ** *
int main (void)
{
int  ** *  *
  *  ** ***** **** * ***  ** * 
**   
*** **   * 
 ***   *
 *  ** 
 ** 
   
 ****  
* *   ****
*  ***** * **   * **     **  ***   * 
if  ***   *    *  *  ** **** ***    *
 *   
else **** ***       ***
f2=2;
else if **
  *
else f2=4;
*  ****  * *  ***  * ***  
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
 **  ****  ** * ***    * *   a,b,c,d,e,f;
**** * ** **** *  *    *   **** count=1;
   **    * * ** * ** ***       *** **       ***  *       **
* * **  ***** **  ** **  **  **
*    *   ***  **      ***   *** ***   *
* * ******  *  ****   *   * *** **   * * *   
*  * * *  ****  *   ** *  * *  **** *** ***
*  *****   **  ***  * ** *  *   *** **
****     ** ** * * ****   *  *** ****  * **
    {
    ***    ***   *  * *  **  **    ** *** * ** *** ** * **
 **   *  * **   * ** * * * * ** *       ** * ** *   ** * **
    }

  * **  *  * * * * * * *      *   ** ** %d",count,f);
*    *   * *  *** *** ** ** **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
*    * **   **   *
int main()
{
  * **  ******     ** ** n,digits = 0,sum = 0;
 **** * ****** * * *   **       **  *    *  ****        
  * * ***  * *   *****   {
*** * * * * *       * *  ***  ****** * ** *  ** ***  ** *    = sum + n%10;
 **  * *     ******  *   * * * *   **  *** ****  * ****   *  *  *  
  * ** **** ** **    ******* *** ****   * *** *     **    ** **
 *** *    **** ** * *** *   while (n > 0);
*    **** *** *       * * **  **            d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include **** *  ** *  ** *** 

int  *   **** ** ***    **
int d=1000;

int main(){
*  *     ****** ***   ** ***  *  * *   **  ** *  * * *
 **  *****    * ****  *    **  

   * *  ****    * **  *  *   ** **    *** * *   *** **  * * ** = a/d;
*   *  * **  * **  **  * **  ** ****** ** ** ***     ** *  *  *  * ***********    * **     *
 *  **** **   * * * **  ***   * *  **   ** * **  ** * = sum + currentdigit;
***   *** *  ** ******* *  *    *   **   ** **  *   = a - (currentdigit * d);
**** **  *   *  ****   **  *  ***** * ***  **** * ****  ** * 

 * * ***     **  * * **  * ** *   * *****    * * *      *  *   ** ***  %d\n", numdigits, sum);

 *    **  ** ***    *   
 ***********   *  *  **       * ***     *  %d", numdigits, sum);
*** ****   * **  **        *      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
* * * *  *   **    *     **** *   n,digits = 0,sum = 0;
  * * *  ***   * * ** **    *     **        * *
 ***  **      ***  * **    {
* *     *  *  ***** *     ***  ***  **    *    * *** *** = sum + n%10;
*  ****** *  **   *   *****    **   * * *   *** ** **  ** 
  **       **    * ***** * **        * * *****  * * * *** 
  *    * *   **  *    * *  ** * while (n > 0);
*   * *  *  *    *   **       ***    * *  *    *   **
*** * ****  *  * *  *  * ** ** * ** *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
 *    *   ***  * ******* * * a,digits=0,sum=0;
* * ***   * **     * *******    ** * * ***  **  *    *   *   
 ** **  *      ******   * ***** {
 ** *   ****     *  * **  *  ** * * ****  **     *    *    ***     *
*** * *  * *  **  * ***  *** *  * * * *   **    *  **  ***  * 
***       *** ** *** **  **     **   *** **  *  *      ****
  ***    ** ****   * * *
** **  * * * ***  **  *    *   (a>0);

** *   ** ** *  *  **  ** *******  %d",digits,sum);
  ***     *  *  * ** * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 * *   *** ** ** * 
int main ** **
{
int  *** ***    *
  * *  *  **   *  ****      
**  *
 ***** 
  *  
**   
* *  
** * *
   
*** * *
 ** **   * *  ** * * * ** ***  ***  *
if    * **** *  
** 
else     * ****
  **
else if  ** *
  *  
else f2=4;
 ** * * **   **   * **      *  
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
   * *  ** *** * * **** n,digits = 0,sum = 0;
** * **  ** *     *    ** * *   ** *     ** * * * 
 *** * **    *   *     *  ***    {
*   **** *****   *  ***  *  * *   ** ** * *****   ** ** = sum + n%10;
****** *** ** * ***  **** * **    * * * ***  ***  ****    *
 * * ***   ****    * **** **** ** *   * *  *  * * ** *   *  * * *
  * *** *  * **  * * ** *  ** while (n > 0);
  ** *   * * * *****  *   ** *******   *   * *
* ** **** * **** ** * ***  **  ** * *  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
* ****  **    *   **  ** a=1,b,c,d,e,f,g;
  *   ********    **   * * ***        ** *  *** ******* 
* * **  * ** * *  ***   **   *** *
 **  * * *     ***   * ***   *** **  *
 ** * **** **   * **  * 
 **  **  **     ** ****    * ****
*  * *** * ***      * ** *   ***  ***  
    }
 ** *****   *  *** * **** *   
** * ***   * * *    * * ** *** *
 *  **   ******* * *      * * *  *  *
** **  *  * ** * * *  *     * *   
** *    ***   *  ***  * ****  *  * * ***    %d %d %d\n",c,d,e,f);
     ** *** *   * *     *  *   *     * %d",a,c+d+e+f);
    ***   ***   *  *  *   ** **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 *** ** * **    * **  * *   * *** num,digits,sum=0;
* * **    *  **  * **     * * ******* *  **  ** **   *  **  * * *    
*     *  *    * * **   **  *   * * **   ***   ** *  **     *****   **     * **  *****   &num);
   *   **  ** *      ******    * * **
   * ****** *** **** *  
 **** * * **********  *** *   ** *  **   *** * *   *******      ****  ***  ***      += num % 10;
** *  *    * *       * * *   *** ***  * *** **    *   **  ** *    * = num / 10;
 ***** **** *    *  *** *  *  * * *  * *     *  *  ** ***   **    *  * *  ****
    }
       *  ** *   *****   **** * *  **  %d", digits,sum);

**    * ** * ***    ** ** * **  *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output