10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

Hidden content!
*   * *****  *  
int main (void)
{
int ** **  **
***  ** ***   **   **   * * **
 ** * 
* **   **
  **
*  * *****
* * *
 *******  
  *
 *    
*  ****     **     * *   **  * *** 
if  *  *     * **   **** ***   ** *   *
   *
else     *****   ** *** *
f2=2;
else if *** 
 * **
else f2=4;
 ****  *    ******** *** 
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
**   *   *  * **    * ***  * ** *  a,b,c,d,e,f;
**   *  ******   * ** **  * count=1;
** * * *   ** **  *  **    *       *   *****  **  ***  *
 *******     * * **** ****   
* * **  **  ******* **  **** **** *** ** 
*  *  * **   ** **  * **    ****  *** ***
   ** * * ****       * * **  **   * ** ***   * 
***** *  ** * **    **  * *** * ** ** 
* *  * **   **  * ** ** ****   *****   ***
    {
*  *** ** * *  **    * ***** * *****  *** ***    * * *** 
** *****  *****  *      * * *  ***** ** ** **  *******  ** ** 
    }

 * * *  **** **  * *  **** *** *  %d",count,f);
 ***   * *   ****** * * * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

Hidden content!
   * * *** * *  *
int main()
{
 *    *** *  * * ***** * ** * *  * * n,digits = 0,sum = 0;
 * *   *   ** *****  ****   ******* * *  ** * * *   **  ***
  * * *** ** * *   **   * {
 **    * **  **  **  *  * ***      * * ****** ***  * * ** = sum + n%10;
   * *** * *** **  * *  ** *  ** **** **** **    ***   *
    ***      * * * *** *    *    **  *  * *  **    *  *   *
** *   ** ** ***** * *** *  **  while (n > 0);
 *   ** *  ** ** **** * **  ***** *    d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

Hidden content!
#include <stdio.h>
#include      ** *   *

int    * ** **  ***    ** ***
int d=1000;

int main(){
** ** *  *  * *****  * *   ** **    **** **    *   
 * **  * ****   ******** ** ** *   *  ** *

 ** **  * *** * *  * ** * *  * ** *** **  ****  * ***********  = a/d;
* **   * *  *   **  ** *  *    **   *  **  **** * * *** * **   ** * *** **   *    *  *   * 
**    *    *  *      **  ** * * ********* * *****     * = sum + currentdigit;
*** **  *  * **   **   * *** ** *** * **  * **  *   * = a - (currentdigit * d);
   * *    **        * *   * * * **  ****  **     **  * 

 ***** ** ** * *   ***** * ** ***  ***  * * ***** * *        **   **** %d\n", numdigits, sum);

   **   * *** ****   ***    
** * * * * **** *  * *  *** * **   * %d", numdigits, sum);
** * * * ****   **  *    **  *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
** *  ** *    ** * *  * * n,digits = 0,sum = 0;
  *   *** *  * * ** *      *   * *   **  * **  **    * 
**  ***  *    ***    **     *   {
*  ***     ***  **  *     ** *** *  **  ***   **    = sum + n%10;
 * *** *   ***   ** * * ** **  *  **   *   **   ** 
   *  **      *  *** *  * **    ***    ******   **  * 
 * *** *  * **   ******  while (n > 0);
*** *  * ********* *   *********** **    ***  *** *  **
 * ***  *** *  *    * *        * *** * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*  **    *    **    ** * *  a,digits=0,sum=0;
 * *    ***** **** * *   * *     * ****  ** **  *  *
** **** ****** *      * *      {
    *** **   **   **  * * *    *   *  *** *** ** * *  ****   
 *     **      **    * * * * **  *** ***   *   *      ***  
* *   *      *     * * *  ***  * * * ** * *  ****     *    ***
  *      * * ** *    ** * **
**     * * *  *  *  *   * *** (a>0);

*   ** *** **  ******  *******  * * **  %d",digits,sum);
*   * *****        * ****  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

Hidden content!
 **     *    *** ** *****
int main *    
{
int    *** **
***  **** *      *** * *  ** *   
**  * *
  * **
 **
    **
*   * 
    ** 
* * *
 *  
 *   * ****   **   * ** **   * ** 
if   * ** ****
****
else ** *   
***  
else if     
  *
else f2=4;
*  *****   ** * ** **   
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
** * **  ****  * *  *  * * * n,digits = 0,sum = 0;
*    ******* ** ** * ******  * ** *******  ****   ** 
 * **  ** *** **** **  * * * {
*** * **  * * ***   ***   * ** *  ***** ** **   ** *** = sum + n%10;
 * * ******  ** * ****  ********* ** * *  * ** * ** 
  *** ****   **  **** *   **  *** * ** * *      **  ***   **
*  ***    *** **  ****  ** while (n > 0);
* *** *****   **    ** * ****  **   **  **** *    *** *
***** *      *** * * **   **** * *  * * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
**** **   * * **  *   *  ****  a=1,b,c,d,e,f,g;
 **  * * * *    * * **  *  *  **  * ********  ** *****   
*     **   * *   ******    *****  
* ****  *  ** *   *    *    ******* *  *** *
 *** * * *   ***  * ***  *
* *****  ***    ****   * **  
     *       *  ** **** ****    
    }
 ** *** *  ** ******  *   *   * * 
* *** ***  *****  * * **       ***
 ** **    *  * * **** **   ** *** 
 ** * **  * *  * *   *  *   *** **   
 *   *   **  ****       *    **     ****  *       * %d %d %d\n",c,d,e,f);
 ** * *    **  * * ** **      * ** %d",a,c+d+e+f);
 *    **   ** * * *** *  **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
*    **      * ** * *   **    ****  ** num,digits,sum=0;
*  * *     **      ** ******  *      * * * * * *   *  *     
**  ***  *    *  * **  *  ** * * * **** *  *  *  **  ** *  *     *** *   *  &num);
**    ** **    *   * * *** *** **  **** ** * *
*  *   * ******** *    *
      *    *   *        **  ** *    * *  * *   *** *  **   * *   **   *  += num % 10;
* *  *** **      ** **** * ** ** *  *  * ****   ** *      ***** *     ** ** = num / 10;
   * ***  * **   * ** *** ** * ** **  *   ****   * ** *      * *   *   **   ** * 
    }
 ***** * ** * * ** *      *  * * ***   ** %d", digits,sum);

* *** ****  *    *** *   *  **   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output