10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

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#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
*** * *   *  * *  * * ****  ** n,digits = 0,sum = 0;
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}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include ***   * **** **

int  *    **     *  ***  
int d=1000;

int main(){
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* *  ** ******  *   ***    ** * ***** * * * * *  **** = a - (currentdigit * d);
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*** *    *** *  **     *** **
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**     *    * **  *  * * ** *  * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
**  ***  * ** * *  **** *** n,digits = 0,sum = 0;
*** * **** *  **  *** * **  * *** *   ****  *
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 * * *   *** *  *  *     ** * **  *   **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
*** * ** * * * ** ** * * ***  a,digits=0,sum=0;
** ** *  ** * * ***   **    ******* ***    *   *** * 
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  *   * * * *   *   *  ******** * ** ** * %d",digits,sum);
******   ****  * ***  * ** * * *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main *  
{
int *** **  
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*****   *    *  * *   ***
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
 **  ** **** *    **   ***   n,digits = 0,sum = 0;
*  * ******** ***   * *  * **   * *  * ** ** *  *  ***
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* *** * *  * ******    while (n > 0);
 *  *  ** *  *  ***  * *   *    ** * * * *** *  
* *   *   ** ** * *   *   ***** *  **  d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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* * *   * *    ****  *   **** *   ** ** %d",a,c+d+e+f);
** * **   *****    ** *  * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 *** ****     **  ** ***   * * *  ** **  num,digits,sum=0;
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*  **** ** *  *  ** *   * ** *
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**   **** *  * * * **    *  *    **  * *** *   *  ** *****  * **   ****   ** = num / 10;
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    }
 *    ***   *** *   * * **    ***  **    * %d", digits,sum);

**   * *** *  * *** ** *   * * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output