10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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int main (void)
{
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f2=2;
else if * 
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else f2=4;
***  * *****  **** ****** *
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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    }

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   ** **** *   ****   * *    *  ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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* ***  **  **      * * * 
int main()
{
    * **  *  * ****  **   * * ** n,digits = 0,sum = 0;
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   **      ** *    * ** **  ** * while (n > 0);
* * * * **** *    **** **     * *** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include   *  *** *  *  

int **** * *  ** *   *  * ***
int d=1000;

int main(){
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  * *** * *  ** * ***  *  **  *  * * ** ** * *     = a - (currentdigit * d);
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 **  **  * * * * ***  *** 
  *     **    * *  *    *  * * ** * ** ** %d", numdigits, sum);
  *  **  * * **  *** ** *  *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
  ** ***  ** *** *  ** * n,digits = 0,sum = 0;
 * **  ***    **    * ** * *****  **** **  **** ** *****
* *   **** *  **** *    **     *   {
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 *** * *  **** * **        **  **    **  * **    ****
    *  ****   **  * ** *  **  *  **  *** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
  *  * *       *   *  *  * *  * a,digits=0,sum=0;
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     *     *        *** *  
  *     *   *           **** *  (a>0);

*** * ****  ***** *** *      * *** ***  *   %d",digits,sum);
 **** **  *  ***     **      0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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int main  *  
{
int ****** 
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else f2=4;
*******  *  * ** *   **  ***  ** 
}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
**** *   *****  **** * **** ** * n,digits = 0,sum = 0;
****        ** **  * **  ** **  *  *** **  * **** **  * **  
*    ***** ** **** ********** {
***    **** * * *  *     ** *   **   * **    *  * ** **  **** = sum + n%10;
** ** *  * * ** *   **  ******  * ***  *  * **  * ** * 
*  * *   * * *    ** * *   *** * * *  * **  *   *   *****
* **** **   *  * ***  *** ** while (n > 0);
**   ***  *** ***  * **   *  **  **   ** **   *** ***
*  * * ** *   *** *******   * *     * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
  *    *** *  ***** ***  *** a=1,b,c,d,e,f,g;
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    }
**** *****   *****  *   ** 
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** ** ****  ***   * **  ***** *  ** *  %d %d %d\n",c,d,e,f);
* * *** *       * *   * * * *  * * *** * %d",a,c+d+e+f);
*   * **  ****** * * **    ***** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
  * * * * *  **    **   * *  * **  num,digits,sum=0;
   ** **    *** **  *          **  **   ** *     * *   **** ** * ** *
* **** * **      **  ** *******       * *   * *  ****  *** *  ******   * *   * &num);
*     **   *  * ** * ** *    **   **  *  
** * ***    **** *     **** 
 * **    * * ***  *   *        * ** ****** **  *  ******     * ***  *  *   += num % 10;
    *** * * *     ** *  *** * ***    *  **  **       *  *  *  *****  * *** *    = num / 10;
     ** ** **** *** * *  ****  *    * **  *  *   **** ** * * ** *** * *** * **** *
    }
  * *   ***   * ** *  * **   **     %d", digits,sum);

 ** * *  *   ****  **   ***** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output