10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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else f2=4;
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

Hidden content!
#include<stdio.h>
int main()
{
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*   **   **  *       ** * * *   0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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* *** * ** * * * **** *   *  while (n > 0);
*****   ** * ***** *** ***    * **** * *** d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
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int  *  *  ** * *  *    ***
int d=1000;

int main(){
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  * *   *      * *   ***    * *  ****   %d", numdigits, sum);
 **** **   ***** **   * *    * * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
 * ** *** **** *    **   ****   n,digits = 0,sum = 0;
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**** **   ***  **  ***  ** **   {
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 ** ***  * *** *   **   * **     *  *    * d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
* * *  *   *     ** *   a,digits=0,sum=0;
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* * *   *** ** *****   * **** **  **  ** %d",digits,sum);
* *   *   ***  *   * * ** ** * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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** ** *   ****     ** *  *
int main  
{
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
****  **  *  ** *** ** n,digits = 0,sum = 0;
***   *  ********* ** ** ** ***      * *  *        
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**  *** **** *  *     *  * *  * *   *  * ** **  **
 *  ***  **  * *** * ** **  * *** *  *   d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
*  * ******* *  ** ** **  a=1,b,c,d,e,f,g;
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**** **   ** *  ** *   *** *** ** %d",a,c+d+e+f);
  *** **  * ***** *   **  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
 ** *   **  *** ***  * *  **** ** * **  num,digits,sum=0;
*** **   ***** *      *       ** *   **  *** * ****  ******  * 
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**** ** * **  *****  *  *    ** ***** *   *  * *
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*      **** * **   *  ** *** *  *** ***   *  ***  * * *   **   *        ***** += num % 10;
* *   *   ***     * *  *  * *** ****** **  ****    * **  **** **** ****  * * ** = num / 10;
**    * * ****    * * ** *****  **** **  * *   *     **** *   ***   **    ** 
    }
 ***  * ****    * * * *  * ** *  * *** %d", digits,sum);

*  ****   **     *  ** *  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output