10-26 Exercise 2: Displays the number of its digits and their sum

Question

Write a program that reads an integer (1-4 digits) and displays the number of its digits and their sum. For example, if the number is 1234, the program should display 4 and 10

寫一個輸入四位整數 輸出數字的位數和位數的總和。例如，數字是1234程式會輸出4和10。

More information about Loops here.

 

Example input:

1234

Example output:

4 10

 

Example input 2:

245

Example output:

3 11

 

Answer 1

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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you use loop to solve this question?

Answer 2

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#include<stdio.h>
int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 3

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int main()
{
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*  * * * ** **** ** **   *  *   while (n > 0);
*  ***   ***  **  **** ** *    * *** * **  d\n",digits,sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 4

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#include <stdio.h>
#include    **    **  

int  * * * *   *   **  **  *
int d=1000;

int main(){
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* ****   * **   *     * * ** ** **  *  * *      **  ***  * ** * %d\n", numdigits, sum);

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*      *  ****** ** *   * ****  ** *** *  * %d", numdigits, sum);
   ** * * * * *  *   *** * *** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 5

Hidden content!
#include<stdio.h>
int main()
{
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*  ** *  ******    *  ** *    ***** ********* *  *  *   
****** *      * *  **  ** *   **** ** ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 6

Hidden content!
#include <stdio.h>
int main(void)
{
** ******  *   **  *  * *** * * **  a,digits=0,sum=0;
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**    * * *** ** ** * **     **  * *    * %d",digits,sum);
  *   *  *    * *  **** ***  * 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

Answer 7

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{
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else f2=4;
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}

Comments

prog.c: In function 'main':
prog.c:15:9: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
         ^
prog.c:15:14: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 if (a==0,b==0,c==0)
              ^
prog.c:17:13: error: left-hand operand of comma expression has no effect [-Werror=unused-value]
 else if(a==0,b==0)
             ^
cc1: all warnings being treated as errors

Answer 8

Hidden content!
#include<stdio.h>
int main()
{
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* * *      ***  ***** *  ** **  **  * *** **  ***   * 
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****** ******   *** *   * ** **     **   **    *    *  ** = sum + n%10;
* *  *** **  *  *** * ****    ***** ********* **  *  * 
*   * **  ** ****  *  ** * ** *  * *  * ***** ****  * *
*  ***  *   *       **  *   while (n > 0);
 * *  * *   ** **      * * **    *  **  *  * ****** **   *  *
 **** ** ** ** **** *   **    *  **   *  ** d\n",sum);
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output

Answer 9

Hidden content!
#include <stdio.h>

int main()
{
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  *****  * * **  **   *** **** * * * **  %d",a,c+d+e+f);
    *   ** ****  ****  ***  0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output

---

can you write a simpler version of this?
c=b/1000;
d=(b%1000)/100;
e=(b%100)/10;
f=b%10;

Answer 10

Hidden content!
#include <stdio.h>
int main()
{
   *  *** * *  ** **     **   **   num,digits,sum=0;
  *  * * **  ** ** * * *****  ** *** *** ** * ** * *    ** *****  **
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***   *  ***    *  * **   *
****   *** ** * ** ** ** *  ** * **  ****  **   **   *****  *  ***  * *** *   *** += num % 10;
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** ** * *** *  *** *       ***  ** *    *** **  ** *   ** * *   * **   ***** *  ****
    }
 **  **  *** **** ****  *****  * * *    * %d", digits,sum);

   **   *  ***** * *    * ** 0;
}

Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output